Please briefly describe Two types of statics where you will NOT observe a classic Medelian 9.3:3:1 ratio in a F; generation. Solution In dihybridism without epistasis,double heterozygous parents cross-breed and 4 phenotypical forms appear in F2.The proportion is 9 individuals double dominant,3 individuals dominant for the first pair and recessive for the second pair,3 individuals recessive for the first pair and dominant for the second pair, and 1 individual double recessive so the final ratio becomes 9:3:3:1.Considering that the epistatic gene is the second pair and that the recessive genotype of the hypostatic gene implies the lack of the characteristic,in the F2 generation of dominant epistasis,the following phenotypic forms would emerge:13 individuals dominant for the second pair or recessive for the first pair,meaning that,the characteristic is not manifest;3 individuals dominant for the first pair and recessive for the second pair,meaning that the characteristic is manifest.The phenotypical proportion would be 13:3.In recessive epistasis,the phenotypical forms that would emerge in F2 are:9 individuals double dominant and 7 individuals recessive for the first pair or recessive for the second pair,meaning that the characteristic is not manifest. Therefore,the phenotypical proportion would be 9:7. These examples show how epistasis changes phenotypical forms and proportions,from the normal 9:3:3:1 in F2 to 13:3 in dominant epistasis or to 9:7 in recessive epistasis..