Describe how the lung cancer travels to the first site of metastasis.pdf

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Describe how the lung cancer travels to the first site of metastasis. •Given your primary tumor site, how did lung cancer cells of the primary tumor spread to the initial secondary site? How does lung cancer cell get access to the body during metastasis? What pathway did your cancer cells’ take? Solution answer: metastasis: delopment of secondry malignant growth at a distance from primary site of cancer lung cancer tumor travel process: primary tumor willl be prolification of the clone and invesion of vessel through the metastasis clone evolves and its transport by circulation then its leads to the embolisam finally new tumor formation at the site of metestasis.

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You have been cut! While you wage war in the streets of Gotham for your life, your cells wage war against incoming invaders. Place the following statement concerning the fates of unwanted invaders/immigrants in your body in order: 1.The invader is cut apart while alive and digested in the harsh environment of your new super- max detention/recycling center. Die invader, Die! 2.Contact with one of your cells triggers phagocytosis and a signal trough transmembrane proteins triggers the cytoskeleton. 3.The vesicle containing the bacterium is pinched off. 4.A bacterium that has stormed the outter walls of your body (the skin through the cut) is recognized and tagged as foreign. 5.Other vesicles containing hydrolases, enzmes that depolymerize proteins, carbohydrates, lipids, and nucleic acids, as well as other proteins that act to increase the pH of the larger vesicle that contains the invader arrive on the cell\'s microtubule transportation system and fuse. 6.Kinesin walks its vesicle down the microtubule highways into the cytoplasm. 7.Actin polymerizes to form rods that push out the membrane to form fingers or pseudopods that begin to envelop the bacterium. 8.The vesicle containing the bacterium is moved by kinesin. Solution 4A bacterium that has stormed the outter walls of your body (the skin through the cut) is recognized and tagged as foreign. 2Contact with one of your cells triggers phagocytosis and a signal trough transmembrane proteins triggers the cytoskeleton. 7Actin polymerizes to form rods that push out the membrane to form fingers or pseudopods that begin to envelop the bacterium. 3 The vesicle containing the bacterium is pinched off. 8 The vesicle containing the bacterium is moved by kinesin 6 Kinesin walks its vesicle down the microtubule highways into the cytoplasm 5 .Other vesicles containing hydrolases, enzmes that depolymerize proteins, carbohydrates, lipids, and nucleic acids, as well as other proteins that act to increase the pH of the larger vesicle that contains the invader arrive on the cell\'s microtubule transportation system and fuse 1 The invader is cut apart while alive and digested in the harsh environment of your new super- max detention/recycling center..

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Why has Mexico encountered such a significant collapse from an economic perspective? Solution From an economic perspective Mexico had a significant collapse due to two major factors: 1. The first one was a collapse in export demand 2. The second one being the susequent constraints that it had in accessing the International Financial markets. Due to the above factors Mexico started feeling a significant negative effect. As the negative effects increased, the country\'s fiscal position weakened. This was mainly due to the fall in oil revenues. Additionally, a drop in international energy prices brought about by the global recession along with a sharp decline in domestic oil production attributed to the crisis. A downward rigidity in public expenditure was observed which along with the above mentioned factors raised concerns about the sustainability of fiscal policy.All these factors played a major spoilsport and generated doubts about the country’s capacity to finance the growth in the current account deficit for 2009. The Mexican economy was forced to adjust to a new external environment that was characterised by lower foreign currency revenues with a limited access to external borrowing..

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Which of the following is/are true of BOTH natural selection and genetic drift? I. Promotes traits that increase survival or reproduction II. Depends on genetic mutations as the source of variation III. Can lead to evolutionary change Question 5 options: I and III I only I, II, and III II and III I and II I and III I only I, II, and III II and III I and II Solution answer will be I,II and III, because in a population genetic drift and natural selection always play a role together..

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Which of the following information-management systems uses artificial intelligence? A. Polyinstantiation B. Known signature scanning C. Application programming interface D. Knowledge discovery in databases Solution D. Knowledge Discovery in Databases (KDD) is an artificial intelligence method used to identify useful patterns in data; as such, it provides a type of automatic analysis. Answer A is incorrect because polyinstantiation is a technique used to prevent inference violations. Answer B is incorrect because known signature scanning is a method used to detect computer viruses. Answer C is incorrect because the application programming interface (API) is in no way associated with artificial intelligence..

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What steps and tools are used for Pen Testing? Solution Steps for Pen Testing: 1:Attack Surface analysis 2:Threat Modelling 3:Test Configuration 4:automatic and manual scans 5:validation of vulnerabilities 6:false positive elimination 7:proof of concept 8:Check for the service/version running on the particular port. 9:Search the vulnerability in the service/version. 10:Exploit the target using tools. Tools used for Pen Testing 1:Metasploit 2:Wireshark 3:W3af 4:core Impact 5:Back track.

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which event in this life cycle is comparable to fertilizarion? 9. Distinguish among the various groups of fungi as outlined in the table below: Asexual Spores Fruiting Body Structure (microscopic) Giving sexual stage) Rise to Sexually Produced Spore (large; asexually produced spores from sporangium. Zygomycota Ascomycota Basidiomycota Solution Structure Fruiting body Asexual spores Zygomycetes Chitin,chitosan,polyglucornic acid No fleshy fruiting body reproduce by conjugation, sporangiospores, conidia Ascomycetes Chitin,both alpha and beta Glucans,glactomannoproteins ascus asexually produced spores from sporangium, ascospores, conidia Basisiomycetes Chitin,beta Glucans basidia contain basidium, the spore forming bodies, basidiospores,conidia.

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what is the value of nursing education Solution The main value of nursing education is to deliver efficient ethical based health care to the patients suffering from various devastating disease finally to implement clinical protocol & clinical trials on the patients’ with moral & ethical aspects to collect epidemiological clinical data. As a clinical nurse leader is to obtain a better clinical outcome is main value of \"nursing education\" by respecting patent’s autonomy. The main characteristics are to develop a strategic plan to implement a “do” and “step “policy to active organizational goals, allocation of resources as a clinical nurse leader. The other aspects of nursing education is to implement the treatment protocols, epidemiological studies of disease, and disorders within time- frame using interdisciplinary teams and according ethical based informatics. The responsibilities are allocated to each RN, LPN to obtain an efficient health out come from patient and within the community. Nursing education is crucial to inform the fellow nurses about the current organizational philosophy of nursing in clinical services. Finally, collecting the patient data and monitoring, analysis & evaluation is essential using nursing informatics to develop future prospects to prevent diseases. Nursing education has specific impact on the role of health care workers and clinicians to maintain efficient patient’s electronic health care records using information technology tools. In order to automate the aspects of acquisition of patient health information and management.

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Using a Fabry-Perot interferometer, we can Observe small objects. Detect fine optical spectrum lines. Examine optical quality of lens. Measure light speed in different media. Solution ANSWER is : B) Detect fine optical spectrum lines It consists of two highly reflective and strictly parallel plates called an etalon. Because of the high reflectivity of the plates of the etalon, the successive multiple reflections of light waves diminish very slowly in intensity and form very narrow, sharp fringes. These may be used to reveal hyperfine structures in line spectra..

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The major type of interactive forces between molecules of HCl are: ionic covalent hydrogen bonding dipole-dipole attractions dispersion forces Solution Dipole - Dipole attraction is the major type of interactive forces between HCl molecules. these interaction are basically the electrostatic interaction between the permanent dipoles in the mlecules. this interaction occurs when the partially negatively charged part of one molecule (in case of HCl it is Cl- ) interacts with partially positive charge of the other molecule (H+ in case of HCl)..

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Tetrad Analysis You should be able to explain and you should know examples of these: 1) Incomplete dominance 2) dominant negative 3) co-dominance, 4) pleotropic effect 5) epistasis 6) suppressors 7) developmental noise 8) norm of reaction (phenotypic plasticity). 9) You should be able to explain the biochemistry of ABO blood type and epistasis between h and I genes. Solution 1) incompletes dominance is a form of intermediate inheritance in which one allele for a specific trait is not completely exprssed over its paired allele. It leads to the formation of a third phenotype in which the expressed physical trait is a combination of phenotypes of noth alleles.Example is a flower that is pink in colour due to cross pollination between a red and a white flower,when neither the white or red alleles are dominant. 2. dominant negative is used to describe a gene that has a dominant effect similar to that described genetically,one copy of the gene gives a mutant phenotype effect and a negative copy and the negative effect in that it prevents.For example a protein that functional as a dimer.A mutation that removes the functional domain but reatins the dimerization domain would cause a dominant negatice phenotype because some part of the dimer would be missing functional domains. 3. Co dominance is a type of dominance in which both the alleles in a gene pair in a heterozygote are fully expressed. The human ABO blood groups provide an example of co dominance. 4. Pleiotropric effect is to have multiple effects from the same gene.Example , marfan gene is pleiotropic .it had many effects such as long fingers and toes,disslocation of the lens of the eye. 5.epistasis is a phenomena in which the effect of one gene is dependant on the prsesnce of one or more modifier genes.In case of dominant epistasis there is complete dominance at both gene pairs however when one gene is dominant it hides the phenotype of the other gene. in recessive epistasis recessive genes at one locus mask the phenotypic expression of other gene locus. example, the gene for male pattern baldness is epistatic to the gene for red hair..

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Security Implications What are the implications of Shannon’s work on security? Shannon, C. (1948, July). A Mathematical Theory of Communication. The Bell System Technical Journal, 27(3), 379-423. Solution Implications of Shannon’s work on security :- 1) Shannon\'s work on cryptography security systems. 2) Shannon proved the cryptographic one-time password is unbreakable in his classified research that was later published in October 1949. 3) He can proved the unbreakable system must have essentially the same characteristics as the one-time padssword system. the key must be truly random as large as the plaintext information never reused in whole or part of the kept secret key value. 4) The one-time password system by the Soviets was partially broken by the National Security Agency but this was because of misuses of the one-time password by Soviet cryptographic technicians..

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Protect tissues Spinal cord functions to includes pituitary gland skin includes Controls Nervous Integumentary includes 16. Endocrine ncludes bones 15 functions in support Body Systems Muscular includes functions in ovarie Urinary Digestive Circulatory posture in includes bladder filters males functions in includes breaks down ncludes 11 from Heart stomach (2 to be Word Bank into females, brain, kidneys, regulate temperature, skeletal, ligaments, wastes, transport, food, thyroid, esophagus, testes, coordination, absorbed reproductive, movement, blood Solution 1. Coordination 2. Brain 3. Regulate temperature 4. Ligaments 5. Skeletal 6. Movement 7. Kidney 8. Waste 9. Blood 10. Transport 11. Food 12. Esophagus 13. Females 14. Testes 15. Reproductive 16. Thyroid.

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Present and explain each step in human perception process. To what extent we perceive the real world differently, how do we manage that (all types of perceptual selections) and why (such as protecting ourselves) Solution Perception starts with visualization. The main sensory component of vision involves the gathering and recording of light scattered from objects in the surrounding scene, and the forming of a two - dimensional function on the photoreceptors. Human eyes can perceive visible light. It involves receiving signals in the nervous system. These signals form chemical and physical stimulation. Perception starts with processing sensory input which transforms these low-level information to higher-level information. The next step is processing as per a person\'s knowledge and concepts. We perceive the real world based on our knowledge and experience. The process of perception begins with an object in the real world, termed the distal stimulus ordistal object. Our knowledge of the distal stimulus influences how we percieve the real world. We manage all types of perceptual selections by looking for familiar cues when we face an unknown distal stimulus. We do this to bind our senses and stimulate our high level information..

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please help with this genetics problem You have 3 Serratia strains (A, B, C) that contain different mutations in a pathway for making prodigiosin. When grown by themselves A, B, and C are all white. You are given the information that C feeds A and B through diffusion, and A feeds B through the air. If you streak out the strains A, C, B in this order and next to each other on one plate, what color would you observe at day 4? A: pink. B: pink. C: pink A: red. B: red. C: white. A: red. B: red in colonies close to C. C: white. A: red. B: white. C: white. A: red in colonies close to C. B: red. C: white If these strains are plated together, which strain(s) will be able to produce the product of CANDY? Strain Sweet Has a defective y and n enzyme. Strain Sour has a defective s enzyme Neither can feed the other Sour and Sweet can feed each other Sour strain can feed Sweet strain but Sweet cannot feed sour Sweet strain can feed Sour strain but Sour cannot feed sweet Solution 5) The prodigiosin is a red pigment. In the pigment production pathway C feeds A and B through diffusion. Therefore, C is white, B is red colored colony located near C and A is red colored colony. 6) Sweet strain have defective \'y\' and \'n\' enzymes and sour strain contains defective \'s\' enzyme. In both the sweet and sour candy production starts with colony A. With the defective ;y\' and \'n\' enzymes sweet strain cannot feed sour strain, but with defective \'s\' enzyme, sour strain can feed sweet strain. Option C is correct..

please help with this genetics problem You have 3 Serratia strains (.pdf

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Please briefly describe Two types of statics where you will NOT observe a classic Medelian 9.3:3:1 ratio in a F; generation. Solution In dihybridism without epistasis,double heterozygous parents cross-breed and 4 phenotypical forms appear in F2.The proportion is 9 individuals double dominant,3 individuals dominant for the first pair and recessive for the second pair,3 individuals recessive for the first pair and dominant for the second pair, and 1 individual double recessive so the final ratio becomes 9:3:3:1.Considering that the epistatic gene is the second pair and that the recessive genotype of the hypostatic gene implies the lack of the characteristic,in the F2 generation of dominant epistasis,the following phenotypic forms would emerge:13 individuals dominant for the second pair or recessive for the first pair,meaning that,the characteristic is not manifest;3 individuals dominant for the first pair and recessive for the second pair,meaning that the characteristic is manifest.The phenotypical proportion would be 13:3.In recessive epistasis,the phenotypical forms that would emerge in F2 are:9 individuals double dominant and 7 individuals recessive for the first pair or recessive for the second pair,meaning that the characteristic is not manifest. Therefore,the phenotypical proportion would be 9:7. These examples show how epistasis changes phenotypical forms and proportions,from the normal 9:3:3:1 in F2 to 13:3 in dominant epistasis or to 9:7 in recessive epistasis..

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Northwest Bakery produces seven types of loaf bread and distributes the bread to local grocery stores each day of the week. Juanita Gomez is the marketing manager for Northwest Bakery and she is trying to figure out how to improve sales. She may want to discontinue some types of bread or add new types. She asked the production department to record the production levels of the seven types of bread and Bob McGeorge, the production manager, put these data in a file named Northwest Bakery. The file is attached. Juanita has just asked you, who has just been hired in the marketing department, to do some analysis on the data. She would like: 1. (5 pts) A chart showing percentages of each type of bread produced. 2. (7 pts) A table showing the average amount of each type of bread produced per day and the variability of the production of each type of bread. 3. (8 pts) She also mentioned that Bob would like to see a chart of average daily production so he can better manage workloads of the production staff. 4. Produce the appropriate charts, graphs and tables in Excel 5. (5 pts) Compile a brief report in a Word document explaining what you did and include the charts, graphs and/or tables in the document.Day of WeekWhiteWheatMultigrainDark RyeCinnamon RaisinSour DoughLight OatSunday496490403251114108228Monday786611570373165148304Tuesday5474744242651 44104256Wednesday51344338031210092180Thursday817669622375181152308Friday375390 29920612488172Saturday700678564366173136248Sunday597502457276140144312Monday53 6530428261135112356Tuesday675703605289201188356Wednesday421433336212100104224 Thursday867576541298152144304Friday506461406254135116264Saturday4703523772088492 172Sunday748643599341153148316Monday376367310199128104208Tuesday6326465863401 74160264Wednesday591504408238140120276Thursday656497415221107120212Friday81767 3644249200180348Saturday653571557316129140224 Solution Day of Week White Wheat Multigrain Dark Rye Cinnamon Raisin Sour Dough Light Oat Sunday 496 490 403 251 114 108 228 Monday 786 611 570 373 165 148 304 Tuesday 547 474 424 265 144 104 256 Wednesday 513 443 380 312 100 92 180 Thursday 817 669 622 375 181 152 308 Friday 375 390 299 206 124 88 172 Saturday 700 678 564 366 173 136 248 Sunday 597 502 457 276 140 144 312 Monday 536 530 428 261 135 112 356 Tuesday 675 703 605 289 201 188 356 Wednesday 421 433 336 212 100 104 224 Thursday 867 576 541 298 152 144 304 Friday 506 461 406 254 135 116 264 Saturday 470 352 377 208 84 92 172 Sunday 748 643 599 341 153 148 316 Monday 376 367 310 199 128 104 208 Tuesday 632 646 586 340 174 160 264 Wednesday 591 504 408 238 140 120 276 Thursday 656 497 415 221 107 120 212 Friday 817 673 644 249 200 180 348 Saturday 653 571 557 316 129 140 224 Total 12779 11213 9931 5850 2979 2700 5532 Percentage 25.06 21.99 19.48 11.5 5.84 5.3 10.9 Day of Week White Wheat Multigrain Dark Rye Cinnamon Raisin Sour Dough Light Oat Average Sunday 496 490 403 251 114 108 228 298.57 Monday 786 611 570 373 165 148 304 422.43 Tuesday.

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Interface four common anode seven-segment LEDs to the PIC18F452 microcontroller using PORTB and PORTC. Write instructions to display a four-digit number stored in data registers starting from REG20 (address 20H). Solution instructions STA LDA LHLD SHLD MOV A, X Binary Octal Decimal Hexadecimal0000000000111100102220011333010044401015550110666011177710001088100 1119910101210A10111311B11001412C11011513D11101614E11111715F.

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