please help with this genetics problem You have 3 Serratia strains (A, B, C) that contain different mutations in a pathway for making prodigiosin. When grown by themselves A, B, and C are all white. You are given the information that C feeds A and B through diffusion, and A feeds B through the air. If you streak out the strains A, C, B in this order and next to each other on one plate, what color would you observe at day 4? A: pink. B: pink. C: pink A: red. B: red. C: white. A: red. B: red in colonies close to C. C: white. A: red. B: white. C: white. A: red in colonies close to C. B: red. C: white If these strains are plated together, which strain(s) will be able to produce the product of CANDY? Strain Sweet Has a defective y and n enzyme. Strain Sour has a defective s enzyme Neither can feed the other Sour and Sweet can feed each other Sour strain can feed Sweet strain but Sweet cannot feed sour Sweet strain can feed Sour strain but Sour cannot feed sweet Solution 5) The prodigiosin is a red pigment. In the pigment production pathway C feeds A and B through diffusion. Therefore, C is white, B is red colored colony located near C and A is red colored colony. 6) Sweet strain have defective \'y\' and \'n\' enzymes and sour strain contains defective \'s\' enzyme. In both the sweet and sour candy production starts with colony A. With the defective ;y\' and \'n\' enzymes sweet strain cannot feed sour strain, but with defective \'s\' enzyme, sour strain can feed sweet strain. Option C is correct..

1. please help with this genetics problem You have 3 Serratia strains (A, B, C) that contain different
mutations in a pathway for making prodigiosin. When grown by themselves A, B, and C are all
white. You are given the information that C feeds A and B through diffusion, and A feeds B
through the air. If you streak out the strains A, C, B in this order and next to each other on one
plate, what color would you observe at day 4? A: pink. B: pink. C: pink A: red. B: red. C:
white. A: red. B: red in colonies close to C. C: white. A: red. B: white. C: white. A: red in
colonies close to C. B: red. C: white If these strains are plated together, which strain(s) will be
able to produce the product of CANDY? Strain Sweet Has a defective y and n enzyme. Strain
Sour has a defective s enzyme Neither can feed the other Sour and Sweet can feed each other
Sour strain can feed Sweet strain but Sweet cannot feed sour Sweet strain can feed Sour strain
but Sour cannot feed sweet
Solution
5)
The prodigiosin is a red pigment. In the pigment production pathway C feeds A and B through
diffusion. Therefore, C is white, B is red colored colony located near C and A is red colored
colony.
6)
Sweet strain have defective 'y' and 'n' enzymes and sour strain contains defective 's' enzyme.
In both the sweet and sour candy production starts with colony A. With the defective ;y' and 'n'
enzymes sweet strain cannot feed sour strain, but with defective 's' enzyme, sour strain can feed
sweet strain. Option C is correct.