Answer The mechanisms of phosphorylation and oxidation are directly.pdf

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Answer: The mechanisms of phosphorylation and oxidation are directly coupled. Normally ATP synthase complex enable synthesis of ATP by pumping protons from mitochondria matrix at complexes, I, III and IV total 2 ATP are produced per one complex thereby 2H+ are driven via proton motive force to produce 1 ATP. The mechanisms of phosphorylation and oxidation are not directly coupled but proton transport & phosphorylation are directly coupled. The P/O ratio for NADH in the oxidative phosphorylation is 2.5 ATP/NADH (recent research has revealed this information i.e. P/O ratios of 2.5 ATP/NADH). Succinate is going to generate “1.5 ATP/FADH2“ because oxidation of FADH2 is going to pump 6 H+ per FADH2 to generate ATP using F0-F1 complex (Fernandez –Moran complex) in the presence of ATP synthase. Therefore, the net energy is higher than the energy required to pump H+ ions through ATP synthase to generate ATP. Solution Answer: The mechanisms of phosphorylation and oxidation are directly coupled. Normally ATP synthase complex enable synthesis of ATP by pumping protons from mitochondria matrix at complexes, I, III and IV total 2 ATP are produced per one complex thereby 2H+ are driven via proton motive force to produce 1 ATP. The mechanisms of phosphorylation and oxidation are not directly coupled but proton transport & phosphorylation are directly coupled. The P/O ratio for NADH in the oxidative phosphorylation is 2.5 ATP/NADH (recent research has revealed this information i.e. P/O ratios of 2.5 ATP/NADH). Succinate is going to generate “1.5 ATP/FADH2“ because oxidation of FADH2 is going to pump 6 H+ per FADH2 to generate ATP using F0-F1 complex (Fernandez –Moran complex) in the presence of ATP synthase. Therefore, the net energy is higher than the energy required to pump H+ ions through ATP synthase to generate ATP..

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You have to leave solids and liquids out of the equation. This leaves only product B for the product, nothing for the reactants. Initially there was no product B. At equilibrium: you determine the molarity by multiplying 2.5% by (0.5M/10L)= .00125 = which rounds to answer E) 1.3e-3 it was a trick question. Solution You have to leave solids and liquids out of the equation. This leaves only product B for the product, nothing for the reactants. Initially there was no product B. At equilibrium: you determine the molarity by multiplying 2.5% by (0.5M/10L)= .00125 = which rounds to answer E) 1.3e-3 it was a trick question..

You have to leave solids and liquids out of the equation. This lea.pdf

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Tungsten is a body centered cubic latticeSolutionTungsten is a.pdf

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This is the final code which meets your requirement.Than you Card.java import java.util.Random; public class Card { //declaring instance variables private String suit; private int face_value; public static int count=52; //Creating an instance of Random class reference Random rand; //Default Constructor public Card() { super(); //Passing random class object to the Random class reference rand = new Random(); } //Getters and setters public String getSuit() { return suit; } public void setSuit(String suit) { this.suit = suit; } public int getFace_value() { return face_value; } public void setFace_value(int face_value) { this.face_value = face_value; } public int getCount() { return count; } //This shuffle() method will shuffle the deck public void shuffle() { //Picking a card from the deck randomly and find its face value and suit this.face_value = 1 + rand.nextInt((9) + 1); int suit_random_value = 1 + rand.nextInt((3) + 1); if(suit_random_value==1) { this.suit=\"Clubs\"; } else if(suit_random_value==2) { this.suit=\"hearts\"; } else if(suit_random_value==3) { this.suit=\"Spades\"; } else if(suit_random_value==4) { this.suit=\"diamonds\"; } this.count=count-1; } } ________________________________________________________________________ DriverClass.java public class DriverClass { public static void main(String[] args) { //creating an array which can hold 52 Card class Objects Card c[]=new Card[52]; //Creating 52 card class objects and storing them into an array for(int i=0;i<52;i++) { //Creating Card class Object c[i]=new Card(); } //Displaying each card face value and its suit. for(int i=0;i<52;i++) { //Shuffling the deck before every card picking from the deck c[i].shuffle(); //Displaying randomly picked card face value and its suit System.out.println(c[i].getFace_value()+\" of \"+c[i].getSuit()+\" Cards remaining \"+c[i].getCount()); } } } _________________________________________________________________________ Output: 8 of diamonds Cards remaining 51 4 of Clubs Cards remaining 50 9 of Clubs Cards remaining 49 7 of Spades Cards remaining 48 9 of diamonds Cards remaining 47 7 of diamonds Cards remaining 46 4 of diamonds Cards remaining 45 9 of Clubs Cards remaining 44 5 of hearts Cards remaining 43 7 of Spades Cards remaining 42 10 of Clubs Cards remaining 41 7 of diamonds Cards remaining 40 8 of diamonds Cards remaining 39 6 of hearts Cards remaining 38 4 of hearts Cards remaining 37 6 of Spades Cards remaining 36 4 of Clubs Cards remaining 35 3 of diamonds Cards remaining 34 9 of diamonds Cards remaining 33 3 of diamonds Cards remaining 32 5 of Spades Cards remaining 31 4 of Clubs Cards remaining 30 3 of Spades Cards remaining 29 6 of diamonds Cards remaining 28 3 of hearts Cards remaining 27 9 of hearts Cards remaining 26 7 of hearts Cards remaining 25 3 of hearts Cards remaining 24 10 of Clubs Cards remaining 23 2 of hearts Cards remaining 22 9 of Clubs Cards remaining 21 8 of diamonds Cards remaining 20 8 of Clubs Cards remaining 19 2 of h.

This is the final code which meets your requirement.Than youCard.j.pdf

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Statistics is the mathematical science involving the collection, analysis and interpretation of data. A number of specialties have evolved to apply statistical theory and methods to various disciplines. Certain topics have \"statistical\" in their name but relate to manipulations of probability distributions rather than to statistical analysis. · Actuarial science is the discipline that applies mathematical and statistical methods to assess risk in the insurance and financeindustries. · Astrostatistics is the discipline that applies statistical analysis to the understanding of astronomical data. · Biostatistics is a branch of biology that studies biological phenomena and observations by means of statistical analysis, and includes medical statistics. · Business analytics is a rapidly developing business process that applies statistical methods to data sets (often very large) to develop new insights and understanding of business performance & opportunities · Chemometrics is the science of relating measurements made on a chemical system or process to the state of the system via application of mathematical or statistical methods. · Demography is the statistical study of all populations. It can be a very general science that can be applied to any kind of dynamic population, that is, one that changes over time or space. · Econometrics is a branch of economics that applies statistical methods to the empirical study of economic theories and relationships. · Environmental statistics is the application of statistical methods to environmental science. Weather, climate, air and water quality are included, as are studies of plant and animal populations. · Epidemiology is the study of factors affecting the health and illness of populations, and serves as the foundation and logic of interventions made in the interest of public health and preventive medicine. · Geostatistics is a branch of geography that deals with the analysis of data from disciplines such as petroleum geology, hydrogeology, hydrology, meteorology,oceanography, geochemistry, geography. · Machine Learning · Operations research (or Operational Research) is an interdisciplinary branch of applied mathematics and formal science that uses methods such as mathematical modeling, statistics, and algorithms to arrive at optimal or near optimal solutions to complex problems. · Population ecology is a sub-field of ecology that deals with the dynamics of species populations and how these populations interact with the environment. · Psychometric is the theory and technique of educational and psychological measurement of knowledge, abilities, attitudes, and personality traits. · Quality control reviews the factors involved in manufacturing and production; it can make use of statistical sampling of product items to aid decisions in process control or in accepting deliveries. · Quantitative psychology is the science of statistically explaining and changing mental processes and behaviors in humans. · Reliabi.

Statistics is the mathematical science involving the collection, ana.pdf

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Secondary phloem Apples (Malus communis, M. pumila, & M. sylvestris), pears (Pyrus communis) and quince (Cydonia oblonga) belong to the rose family (Rosaceae), and include literally hundreds of cultivated varieties. In the apple, the original ancestral species is obscured by so many cultivated variations throughout the centuries that some authors lump them all into one species, Malus domestica. They all originated in western Asia (or Eurasia) and are characterized by fleshy fruits called pomes. In the pome, a thick, fleshy hypanthium layer (also called the floral cup or calyx tube) surrounds (and is fused with) the seed-bearing ovary or core. The sepals, petals and stamens arise from the rim of the hypanthium. Since the ovary is situated below the attachment of the sepals, petals and stamens, it is termed \"inferior\" in technical plant taxonomy books. The fleshy hypanthium of a rose (Rosa) surrounds a cluster of small one-seeded achenes. Since the achenes represent separate ripened ovaries all derived from a single flower, the entire structure (called a rose hip) can be considered an aggregate fruit or etaerio. Rose hips are eaten raw and are ground up as a supplemental source of vitamin C (ascorbic acid). Bing cherries (Prunus avium) showing the long stalk (pedicel) and fleshy drupe containng a hard, stony, seed-bearing endocarp. Sweet cherries such as these are usually considered to belong to P. avium, while sour cherries belong to the P. cerasus group. There are literally hundreds of varieties of cherries. Maraschino cherries are made from sweet cherries which have been bleached, deseeded, and soaked in a sugar solution to which red food coloring and flavoring have been added. Maraschino cherries are commonly covered with chocolate, placed as a decorative topping in ice cream sundies, and in mixed drinks. The raspberry or hindberry is the edible fruit of a multitude of plant species in the genus Rubus, most of which are in the subgenusIdaeobatus; the name also applies to these plants themselves. Raspberries are perennial, with woody stems. Raspberries are grown for the fresh fruit market and for commercial processing into individually quick frozen (IQF) fruit, purée, juice, or as dried fruit used in a variety of grocery products. Traditionally, raspberries were a mid-summer crop, but with new technology, cultivars, and transportation, they can now be obtained year-round. Raspberries need ample sun and water for optimal development. Raspberries thrive in well-drained soil with a pH of between 6 and 7 with ample organic matter to assist in retaining water. While moisture is essential, wet and heavy soils or excess irrigation can bring on Phytophthora root rot which is one of the most serious pest problems facing red raspberry. As a cultivated plant in moist temperate regions, it is easy to grow and has a tendency to spread unless pruned. Escaped raspberries frequently appear as garden weeds, spread by seeds found in bird droppings. An indiv.

Secondary phloemApples (Malus communis, M. pumila, & M. sylvestr.pdf

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Polygon .java package chegg2;public class Polygon { Var.pdf

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probability that the trajectory falls between 1.2 and 1.4 =(1.4-1.2).pdf

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Output: Fibonacci till 20: 0 1 1 2 3 5 8 13 21 34 55 89 144 233 377 610 987 1597 2584 4181 Program: import java.util.*; import java.lang.*; import java.io.*; public class Main { public static void main (String[] args) throws java.lang.Exception { final int LIMIT = 20; int[] fib = new int[LIMIT]; // init fib 0 and first val fib[0] = 0; fib[1] = 1; for (int i = 2; i < LIMIT; ++i) { fib[i] = fib[i - 1] + fib[i - 2]; } System.out.println(\"Fibonacci till \" + LIMIT + \":\"); for (int i = 0; i < LIMIT; ++i) { System.out.println(fib[i]); } } } Iterative solution is more efficient than recursive. The iterative solution do not compute the same values again and again as recursive solution. Also because we are not using recursion the os stack is not used hence computation is faster. Solution Output: Fibonacci till 20: 0 1 1 2 3 5 8 13 21 34 55 89 144 233 377 610 987 1597 2584 4181 Program: import java.util.*; import java.lang.*; import java.io.*; public class Main { public static void main (String[] args) throws java.lang.Exception { final int LIMIT = 20; int[] fib = new int[LIMIT]; // init fib 0 and first val fib[0] = 0; fib[1] = 1; for (int i = 2; i < LIMIT; ++i) { fib[i] = fib[i - 1] + fib[i - 2]; } System.out.println(\"Fibonacci till \" + LIMIT + \":\"); for (int i = 0; i < LIMIT; ++i) { System.out.println(fib[i]); } } } Iterative solution is more efficient than recursive. The iterative solution do not compute the same values again and again as recursive solution. Also because we are not using recursion the os stack is not used hence computation is faster..

OutputFibonacci till 20 0 1 1 2 3 5 8 13 21 .pdf

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Matter is made up of electrically charge particle but the Constituents of objects have opposite charges, adding up to electric neutrality overall. Think of it in this way that two bring two nucleus very close together we need a lot of energy because when we talk about nucleus it\'s only the +ve(protons) charge we are talking about. That is why the fusion of two atoms is very tough task. But in case of atoms or molecules that are the smallest entity of matter that can individually exist; it always contain equal number of proton and electron and hence are electrically neutral on a whole. Atom being neutral on whole there no force on other atoms Solution Matter is made up of electrically charge particle but the Constituents of objects have opposite charges, adding up to electric neutrality overall. Think of it in this way that two bring two nucleus very close together we need a lot of energy because when we talk about nucleus it\'s only the +ve(protons) charge we are talking about. That is why the fusion of two atoms is very tough task. But in case of atoms or molecules that are the smallest entity of matter that can individually exist; it always contain equal number of proton and electron and hence are electrically neutral on a whole. Atom being neutral on whole there no force on other atoms.

Matter is made up of electrically charge particle but the Constituen.pdf

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JUnit is a Regression Testing Framework used by developers to implement unit testing in Java, and accelerate programming speed and increase the quality of code. JUnit Framework can be easily integrated with either of the following Features of JUnit Test Framework JUnit test framework provides the following important features Fixtures Fixtures is a fixed state of a set of objects used as a baseline for running tests. The purpose of a test fixture is to ensure that there is a well-known and fixed environment in which tests are run so that results are repeatable Test Suites A test suite bundles a few unit test cases and runs them together. In JUnit, both @RunWith and @Suite annotation are used to run the suite test. Test Runners Test runner is used for executing the test cases. Here is an example that assumes the test class TestJunit already exists. JUnit Classes JUnit classes are important classes, used in writing and testing JUnits. Some of the important classes are Assert Contains a set of assert methods. TestCase Contains a test case that defines the fixture to run multiple tests. TestResult Contains methods to collect the results of executing a test case. Solution JUnit is a Regression Testing Framework used by developers to implement unit testing in Java, and accelerate programming speed and increase the quality of code. JUnit Framework can be easily integrated with either of the following Features of JUnit Test Framework JUnit test framework provides the following important features Fixtures Fixtures is a fixed state of a set of objects used as a baseline for running tests. The purpose of a test fixture is to ensure that there is a well-known and fixed environment in which tests are run so that results are repeatable Test Suites A test suite bundles a few unit test cases and runs them together. In JUnit, both @RunWith and @Suite annotation are used to run the suite test. Test Runners Test runner is used for executing the test cases. Here is an example that assumes the test class TestJunit already exists. JUnit Classes JUnit classes are important classes, used in writing and testing JUnits. Some of the important classes are Assert Contains a set of assert methods. TestCase Contains a test case that defines the fixture to run multiple tests. TestResult Contains methods to collect the results of executing a test case..

JUnit is a Regression Testing Framework used by developers to implem.pdf

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Intitially take a graph sheet and plot the points and the whole figure as it is. Next draw the velocity diagram.Due to technical issues, I am not able to upload the graphical representation. Apply corialis acceleration component at link 6. Solution Intitially take a graph sheet and plot the points and the whole figure as it is. Next draw the velocity diagram.Due to technical issues, I am not able to upload the graphical representation. Apply corialis acceleration component at link 6..

Intitially take a graph sheet and plot the points and the whole figu.pdf

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Incapsula Enterprise is the best mitigation service provider with the gold award winner and the other two with silver and bronze award are F5 Silverline DDOS Protection and Arbor Cloud respectively With DDoS attacks growing in complexity and size daily, you need a DDoS protection service with a robust network and variety of mitigation techniques to thwart any attacks directed at your site. We found that Incapsula Enterprise, F5 Silverline DDoS Protection and Arbor Cloud offered the best protection. Incapsula’s growing global network and scrubbing capacities equip it with the size needed to prevent large-scale volumetric attacks,27 data centers are connected which are located all over the world, the service is prepared for even the most advanced DDoS attacks. In addition to enormous network capacity and a high number of data centers, Incapsula hosts a variety of mitigation techniques that intercept application layer, volumetric and protocol attacks. With the recent acquisition of Defense.net, F5 has adjusted its service to offer cloud-based mitigation technique, on-site and hybrid deployment methods,both hardware and the cloud is used, F5 Silverline Protection is equipped for sophisticated DDoS attacks. This service surpasses Incapsula in scrubbing capacity, it provides 2TB of bandwidth to filter, clean and remove infected traffic. While the service does not offer unlimited mitigation, this protection service can be used on-demand or always on, customizing it to fit the needs of any company. Third one comes Arbor Cloud which offers a large network and scrubbing capacity and have 1.14TB of bandwidth, this server prepare the system for specialised volumetric attacks.variety of protection techniques are provided by this service including IP blocking, rate limiting, automatic bot discernment and more. While the cloud-based mitigation techniques are impressive, Arbor is known for its hardware. The service is in a unique position, it\'s hardware is the challenge for it\'s competitors similar mitigation techniques is provided by all DDOS mitigation service providers to keep an eye on any attacks and constant monitoring, they differ in price, deployment methods and network size.It is not necessary that bigger mean better, the services that offer larger networks and more mitigation technologies allow for more customization that you employ the best protection service for your IT infrastructure. Solution Incapsula Enterprise is the best mitigation service provider with the gold award winner and the other two with silver and bronze award are F5 Silverline DDOS Protection and Arbor Cloud respectively With DDoS attacks growing in complexity and size daily, you need a DDoS protection service with a robust network and variety of mitigation techniques to thwart any attacks directed at your site. We found that Incapsula Enterprise, F5 Silverline DDoS Protection and Arbor Cloud offered the best protection. Incapsula’s growing global network and scrubbing capacit.

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Go with the most obvious one first... Carboxylic Acids: will have a really broad and large absorption range in the 3500-2500cm-1 area (aka. the \"valley of the acid\") as well as a carbonyl peak in the 1700cm-1 area. That would be spectrum 4. Alcohols:will also have a strong and broad absorption in the 3500-3000cm-1 region, but nowhere near as broad as the acid. It just looks like a really fat absorption line, rather than a well... Anyway, the characteristic spectrum for the alcohol is spectrum 5. Amines:lucky for you, the amine given in this question is a primary amine. There\'s going to be two N-H stretching peaks in the 3300cm-1 region. There\'s also no carbonyl on the structure given, so there should be no C=O stretching at 1700cm-1.This is spectrum 3. Don\'t worry about the small absorption in the 1500-1700cm-1 area. Now for the fine details... The ester and aldehyde spectra are pretty similar, but aldehydes absorb at around 2750cm-1. It\'s not totally clear on the spectra in the question but it looks like there\'s a 2750cm-1 absorption in spectrum 2, so I\'d say that spectrum 2 is the aldehyde, and spectrum 1 is the ester. Summary: Spectrum 1 = structure B Spectrum 2 = structure E Spectrum 3 = structure C Spectrum 4 = structure D Spectrum 5 = structure A Solution Go with the most obvious one first... Carboxylic Acids: will have a really broad and large absorption range in the 3500-2500cm-1 area (aka. the \"valley of the acid\") as well as a carbonyl peak in the 1700cm-1 area. That would be spectrum 4. Alcohols:will also have a strong and broad absorption in the 3500-3000cm-1 region, but nowhere near as broad as the acid. It just looks like a really fat absorption line, rather than a well... Anyway, the characteristic spectrum for the alcohol is spectrum 5. Amines:lucky for you, the amine given in this question is a primary amine. There\'s going to be two N-H stretching peaks in the 3300cm-1 region. There\'s also no carbonyl on the structure given, so there should be no C=O stretching at 1700cm-1.This is spectrum 3. Don\'t worry about the small absorption in the 1500-1700cm-1 area. Now for the fine details... The ester and aldehyde spectra are pretty similar, but aldehydes absorb at around 2750cm-1. It\'s not totally clear on the spectra in the question but it looks like there\'s a 2750cm-1 absorption in spectrum 2, so I\'d say that spectrum 2 is the aldehyde, and spectrum 1 is the ester. Summary: Spectrum 1 = structure B Spectrum 2 = structure E Spectrum 3 = structure C Spectrum 4 = structure D Spectrum 5 = structure A.

Go with the most obvious one first...Carboxylic Acids will have a.pdf

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Flexible benefit plans gives employees a choice between qualified benefits (non taxable) and cash. An example of qualified benefits is medical plans. Flexible benefit plans includes health insurance and retirement benefits. The 2 main types of flexible benefit plans are cafeteria plans and flexible spending accounts. Under the cafeteria plan, employees have the option of choosing from several different benefit packages. Employees can select the option of receiving some or all of the employer\'s nontaxable benefits or receiving cash or other taxable benefits. The benefits offered under cafeteria plans are health and group insurance, medical reimbursement schemes for non-insured expenses and vacation days. Flexible spending accounts (FSA) is another prevalant flexible benefit plan. FSA is a tax deferred savings account. These accounts are formed by employers and helps the employee in meeting certain medical expenses that are not a part of employer\'s insurance plan. Solution Flexible benefit plans gives employees a choice between qualified benefits (non taxable) and cash. An example of qualified benefits is medical plans. Flexible benefit plans includes health insurance and retirement benefits. The 2 main types of flexible benefit plans are cafeteria plans and flexible spending accounts. Under the cafeteria plan, employees have the option of choosing from several different benefit packages. Employees can select the option of receiving some or all of the employer\'s nontaxable benefits or receiving cash or other taxable benefits. The benefits offered under cafeteria plans are health and group insurance, medical reimbursement schemes for non-insured expenses and vacation days. Flexible spending accounts (FSA) is another prevalant flexible benefit plan. FSA is a tax deferred savings account. These accounts are formed by employers and helps the employee in meeting certain medical expenses that are not a part of employer\'s insurance plan..

Flexible benefit plans gives employees a choice between qualified be.pdf

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f(x) = cos(x)Solutionf(x) = cos(x).pdf

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Environment: Let assume the environment is a grid of colored tiles(WHITE,BLUE,GREEN,BLACK,YELLOW).Robot is standing on a tile.Every tile has a(X,Y) Position We use a function getTileColor(x,y) to know color of current tile(x,y position). ALGORITHM: TRESUREHUNT(x,y) 1. color=getColor(x,y) 2. IF color=YELLOW 3. Return \"tiles\"+x+y+\" Is a tresure\" 4. ELSE IF color=WHITE 5. TRESUREHUNT(x,y-1) // move to front tile by decrementing y by 1 6 ELSE IF color=BLUE 7. TRESUREHUNT(x-1,y) // move to left bydecrementing x by 1 8. ELSE IF color=GREEN 9. TRESUREHUNT(x+1,y) // move to right tile by incrementing x by 1 10. ELSE IF color=BLACK 11. TRESUREHUNT(x,y+2) // move to front tile by incrementint y by 2 12. ELSE 13. Return \"Unsucessfull\" 12.END iF C++ CODE //for simplicity i represent entite grid in a 2;D array .Each cell is viewed as a tile.It contains arbitary color values,0-BLACK //1-BLUE,2;GREEN,14;YELLOW,15-WHITE //accordingly the x,y value is changed. if current cell(tile)=15(WHITE) robot moves to front tile. // so x=x-1 and y=y #include #include void tresurehunt(int x,int y); int grid[][7]={ {1, 1, 1, 14,2, 0, 15}, {0, 1, 1, 1, 0, 0, 2}, {2, 2 ,1, 0, 15,14,1}, {15,15,14,0, 1, 2, 1}, {15,0, 0, 1, 2, 2, 14}, {14,14,14,15,0, 2, 2}, {15,15,15,1, 1, 2, 1}}; int main() { tresurehunt(4,4); return 0; } void tresurehunt(int x,int y) { //int color=getpixel(x,y); int color=grid[x][y]; if(color==YELLOW) { cout<<\"Tresure is in:\"< Solution Environment: Let assume the environment is a grid of colored tiles(WHITE,BLUE,GREEN,BLACK,YELLOW).Robot is standing on a tile.Every tile has a(X,Y) Position We use a function getTileColor(x,y) to know color of current tile(x,y position). ALGORITHM: TRESUREHUNT(x,y) 1. color=getColor(x,y) 2. IF color=YELLOW 3. Return \"tiles\"+x+y+\" Is a tresure\" 4. ELSE IF color=WHITE 5. TRESUREHUNT(x,y-1) // move to front tile by decrementing y by 1 6 ELSE IF color=BLUE 7. TRESUREHUNT(x-1,y) // move to left bydecrementing x by 1 8. ELSE IF color=GREEN 9. TRESUREHUNT(x+1,y) // move to right tile by incrementing x by 1 10. ELSE IF color=BLACK 11. TRESUREHUNT(x,y+2) // move to front tile by incrementint y by 2 12. ELSE 13. Return \"Unsucessfull\" 12.END iF C++ CODE //for simplicity i represent entite grid in a 2;D array .Each cell is viewed as a tile.It contains arbitary color values,0-BLACK //1-BLUE,2;GREEN,14;YELLOW,15-WHITE //accordingly the x,y value is changed. if current cell(tile)=15(WHITE) robot moves to front tile. // so x=x-1 and y=y #include #include void tresurehunt(int x,int y); int grid[][7]={ {1, 1, 1, 14,2, 0, 15}, {0, 1, 1, 1, 0, 0, 2}, {2, 2 ,1, 0, 15,14,1}, {15,15,14,0, 1, 2, 1}, {15,0, 0, 1, 2, 2, 14}, {14,14,14,15,0, 2, 2}, {15,15,15,1, 1, 2, 1}}; int main() { tresurehunt(4,4); return 0; } void tresurehunt(int x,int y) { //int color=getpixel(x,y); int color=grid[x][y]; if(color==YELLOW) { cout<<\"Tresure is in:\"<.

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Classification of organisms is based upon a number of physical and physiological features. The structure and organization of reproductive organs remains in important feature usually used to distinguish organisms. Some of the features can be discussed as below: 1. Fruiting body: A very broad classification can be made on the basis whether the fruiting body is present or not. Presence of a fleshy or modified cover around the seed is a characteristic feature of angiosperms whereas a naked seed located directly above a vegetative structure of a plant is a feature of gymnosperms. 2. Spores sacs: Spore releasing sacs are characteristic features found on the lower scales of the leaf blades of lower and higher ferns. Their arrangement and mode of release determines the nature, frequency and ease of sexual reproduction in these lower plants. 3. Pollens: Higher plants, including both angiosperms and gymnosperms utilize pollen grains for sexual reproduction. The mode of transfer of pollen determines the geographical range of pollination in plants. Sulphur shower is a critical example for sexual reproduction in pines (gymnosperms) which distinguishes them from other trees. 4. Sporocarp: A sporocarp or a fruiting body is a bulging of the vegetative extension from the main structure of a lower fungi which contains a group of cells which either follow meiotic division or mitotic division and serve as the reproductive structures. Their growth and nature can be monitored microscopically and the fungus can be thus classified appropriately. Some algae also contain a unique localization and arrangement of haploid cells called spores which can be present in singles or doublets and thus represent a very unique discrimination from other organisms. These, these set of information provide an insight into usability of features of a reproductive structure for classification of organisms. Solution Classification of organisms is based upon a number of physical and physiological features. The structure and organization of reproductive organs remains in important feature usually used to distinguish organisms. Some of the features can be discussed as below: 1. Fruiting body: A very broad classification can be made on the basis whether the fruiting body is present or not. Presence of a fleshy or modified cover around the seed is a characteristic feature of angiosperms whereas a naked seed located directly above a vegetative structure of a plant is a feature of gymnosperms. 2. Spores sacs: Spore releasing sacs are characteristic features found on the lower scales of the leaf blades of lower and higher ferns. Their arrangement and mode of release determines the nature, frequency and ease of sexual reproduction in these lower plants. 3. Pollens: Higher plants, including both angiosperms and gymnosperms utilize pollen grains for sexual reproduction. The mode of transfer of pollen determines the geographical range of pollination in plants. Sulphur shower is a critical example for.

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Assets=Liabilities+Paid in capital+Retained earnings1..pdf

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Hypothesis Test for population variance If we have a sample fro.pdf

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Answer The mechanisms of phosphorylation and oxidation are directly.pdf

1. Answer: The mechanisms of phosphorylation and oxidation are directly coupled. Normally ATP synthase complex enable synthesis of ATP by pumping protons from mitochondria matrix at complexes, I, III and IV total 2 ATP are produced per one complex thereby 2H+ are driven via proton motive force to produce 1 ATP. The mechanisms of phosphorylation and oxidation are not directly coupled but proton transport & phosphorylation are directly coupled. The P/O ratio for NADH in the oxidative phosphorylation is 2.5 ATP/NADH (recent research has revealed this information i.e. P/O ratios of 2.5 ATP/NADH). Succinate is going to generate “1.5 ATP/FADH2“ because oxidation of FADH2 is going to pump 6 H+ per FADH2 to generate ATP using F0-F1 complex (Fernandez –Moran complex) in the presence of ATP synthase. Therefore, the net energy is higher than the energy required to pump H+ ions through ATP synthase to generate ATP. Solution Answer: The mechanisms of phosphorylation and oxidation are directly coupled. Normally ATP synthase complex enable synthesis of ATP by pumping protons from mitochondria matrix at complexes, I, III and IV total 2 ATP are produced per one complex thereby 2H+ are driven via proton motive force to produce 1 ATP. The mechanisms of phosphorylation and oxidation are not directly coupled but proton transport & phosphorylation are directly coupled. The P/O ratio for NADH in the oxidative phosphorylation is 2.5 ATP/NADH (recent research has revealed this information i.e. P/O ratios of 2.5 ATP/NADH). Succinate is going to generate “1.5 ATP/FADH2“ because oxidation of FADH2 is going to pump 6 H+ per FADH2 to generate ATP using F0-F1 complex (Fernandez –Moran complex) in the presence of ATP synthase. Therefore, the net energy is higher than the energy required to pump H+ ions through ATP synthase to generate ATP.

Answer The mechanisms of phosphorylation and oxidation are directly.pdf

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