Part1. Option 3rd; Somatic cells such as liver cells cannot undergo .pdf

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Part1. Option 3rd; Somatic cells such as liver cells cannot undergo meiosis cell division. Mitotic cells are required to be diploid in number of chromosomes. Sperm cells and germ cells are undergo fusion with other reproductive cells, thus they get diploid chromosomes after fusion. So body’s maximum cells like somatic cells undergo mitosis rather than meiosis. Part2. The S phase includes the duplication of each chromosome. All DNA has duplicated in this section by multiple sites of duplication. Part3. Maternal and parental chromosomes are separated in Anaphase I of meiosis cell division. These are non-identical sister chromatids. Part4. The Anaphase II is responsible for the separation of sister chromatids to form chromosomes. Sister chromatids are chromosomes of either maternal or paternal. Part5. During Prophase I homologous chromosomes physically pair up. This phase includes paring up of chromosomes and homologous recombination. Solution Part1. Option 3rd; Somatic cells such as liver cells cannot undergo meiosis cell division. Mitotic cells are required to be diploid in number of chromosomes. Sperm cells and germ cells are undergo fusion with other reproductive cells, thus they get diploid chromosomes after fusion. So body’s maximum cells like somatic cells undergo mitosis rather than meiosis. Part2. The S phase includes the duplication of each chromosome. All DNA has duplicated in this section by multiple sites of duplication. Part3. Maternal and parental chromosomes are separated in Anaphase I of meiosis cell division. These are non-identical sister chromatids. Part4. The Anaphase II is responsible for the separation of sister chromatids to form chromosomes. Sister chromatids are chromosomes of either maternal or paternal. Part5. During Prophase I homologous chromosomes physically pair up. This phase includes paring up of chromosomes and homologous recombination..

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We use a base (in this case sodium bicarbonate) during the separation of the non-aqueous layer from the aqueous. The base deprotonates unwanted compounds found in the non-aqueous layer; when deprotonated the compounds become more soluble in the aqueous layer then the non- aqueous and \"jump\" into the aqueous layer. Solution We use a base (in this case sodium bicarbonate) during the separation of the non-aqueous layer from the aqueous. The base deprotonates unwanted compounds found in the non-aqueous layer; when deprotonated the compounds become more soluble in the aqueous layer then the non- aqueous and \"jump\" into the aqueous layer..

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There are several ways in which the gene regulation in eukaryotes differ from that in prokaryotes, as follows: 1. Prokaryotes are unicellular organisms and do not have defined nucleus, therefore the DNA resides in the cytoplasm. The gene regulation takes place in cytoplasm only i.e. simultaneous transcription and translation. Whereas, eukaryotes are Complex cell structure with a defined nucleus. The DNA is present in nucleus where its transcription takes place into RNA. RNA passes into cytoplasm where its translation takes place into protein. 2 Prokaryotes have naked DNA which are not associated with any protein or other substances to affect gene regulation. Whereas, in eukaryotes DNA forms nucleosomes by wounding around the histone octamers. They are packed within chromatins. This complex structure controls the gene regulation. 3. In prokaryotes all genes are transcribed be same type of RNA polymerase. Whereas, in eukaryotes, there are three different kind of RNA polymerase (I, II and III) involved in gene regulation which are much bigger and complex than prokaryotic RNA polymerase. 4. In prokaryotes the gene expression regulation occurs primarily at transcription stage only. Whereas, in eukaryotes gene expression regulation may occurs at several levels: · Epigenetics: When DNA uncoils for transcription · Transcription: When RNA is transcribed · Post-transcription: When RNA passes into the cytoplasm · Translation: When RNA translates into protein · Post-translation: After protein synthesis. Solution There are several ways in which the gene regulation in eukaryotes differ from that in prokaryotes, as follows: 1. Prokaryotes are unicellular organisms and do not have defined nucleus, therefore the DNA resides in the cytoplasm. The gene regulation takes place in cytoplasm only i.e. simultaneous transcription and translation. Whereas, eukaryotes are Complex cell structure with a defined nucleus. The DNA is present in nucleus where its transcription takes place into RNA. RNA passes into cytoplasm where its translation takes place into protein. 2 Prokaryotes have naked DNA which are not associated with any protein or other substances to affect gene regulation. Whereas, in eukaryotes DNA forms nucleosomes by wounding around the histone octamers. They are packed within chromatins. This complex structure controls the gene regulation. 3. In prokaryotes all genes are transcribed be same type of RNA polymerase. Whereas, in eukaryotes, there are three different kind of RNA polymerase (I, II and III) involved in gene regulation which are much bigger and complex than prokaryotic RNA polymerase. 4. In prokaryotes the gene expression regulation occurs primarily at transcription stage only. Whereas, in eukaryotes gene expression regulation may occurs at several levels: · Epigenetics: When DNA uncoils for transcription · Transcription: When RNA is transcribed · Post-transcription: When RNA passes into the cytoplasm · Translation: When RNA translates into protei.

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The water must be boiled to remove traces of dissolved carbon dioxide (CO2). CO2 dissolves in water to form carbonic acid (H2CO3): CO2 + H2O => H2CO3 H2CO3 is a weak acid and partially ionizes to give H+ ions: H2CO3 => H+ + HCO3- HCO3- => H+ + CO32- The H+ ions can decompose thiosulfate ions and reduce the concentration of sodium thiosulfate according to the reaction: 2 S2O32- + H+ => HSO3- + S Solution The water must be boiled to remove traces of dissolved carbon dioxide (CO2). CO2 dissolves in water to form carbonic acid (H2CO3): CO2 + H2O => H2CO3 H2CO3 is a weak acid and partially ionizes to give H+ ions: H2CO3 => H+ + HCO3- HCO3- => H+ + CO32- The H+ ions can decompose thiosulfate ions and reduce the concentration of sodium thiosulfate according to the reaction: 2 S2O32- + H+ => HSO3- + S.

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