Let two numbers be x and y. Assume y>x. i.e., Let y be greater than x Given: the larger of 2 number is 20 more than the smaller y=20+x Four times the larger is 70 more than 5 times the smaller 4y=70+5x substituting y=20+x in 4y=70+5x we get, 4(20+x)=70+5x 80+4x=70+5x (Bringing 4x to R.H.S & 70 to L.H.S,we get) 80-70=5x-4x 10=x x=10 we know that y=20+x which gives y=20+10 y=30 thus, x=10 and y=30 Solution Let two numbers be x and y. Assume y>x. i.e., Let y be greater than x Given: the larger of 2 number is 20 more than the smaller y=20+x Four times the larger is 70 more than 5 times the smaller 4y=70+5x substituting y=20+x in 4y=70+5x we get, 4(20+x)=70+5x 80+4x=70+5x (Bringing 4x to R.H.S & 70 to L.H.S,we get) 80-70=5x-4x 10=x x=10 we know that y=20+x which gives y=20+10 y=30 thus, x=10 and y=30.