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Covalent bonds Solution Covalent bonds.
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option E .Na2co3 hydrolysyes and gives NaoH which is a strong base. disscoation of weak acid Ch3cooh is increases in a basic medium Solution option E .Na2co3 hydrolysyes and gives NaoH which is a strong base. disscoation of weak acid Ch3cooh is increases in a basic medium.
option E .Na2co3 hydrolysyes and gives NaoH which.pdf
option E .Na2co3 hydrolysyes and gives NaoH which.pdf
anokhilalmobile
non polar molecules such as lipids and cholestrol Solution non polar molecules such as lipids and cholestrol.
non polar molecules such as lipids and cholestrol.pdf
non polar molecules such as lipids and cholestrol.pdf
anokhilalmobile
moles = molarity x volume = 4.25 mol/L x 2.50 L = 10.63 mol Solution moles = molarity x volume = 4.25 mol/L x 2.50 L = 10.63 mol.
moles = molarity x volume = 4.25 molL x 2.50 L =.pdf
moles = molarity x volume = 4.25 molL x 2.50 L =.pdf
anokhilalmobile
London/dispersion/van der Waals forces - these are weak interactions that occur in a matter of nanoseconds when one atom in a bond temporarily takes more of the electron density than the other one, causing a temporary dipole - i.e. this can happen even when you have a C-H bond that is normally nonpolar. Solution London/dispersion/van der Waals forces - these are weak interactions that occur in a matter of nanoseconds when one atom in a bond temporarily takes more of the electron density than the other one, causing a temporary dipole - i.e. this can happen even when you have a C-H bond that is normally nonpolar..
Londondispersionvan der Waals forces - these ar.pdf
Londondispersionvan der Waals forces - these ar.pdf
anokhilalmobile
[H2SO4] = 0 because H2SO4 is a strong acid. first consider Ka2: Ka2 = [H+][SO42-]/[HSO4-] = 1.3X10^-2 From the starting condition, let x = [SO42-]. Then, [H+] = 0.14+ x, and [HSO4-] = 0.14 - x. now the value in Ka2 expression: 1.3X10^-2 = (0.14 +x) (x) / (0.14-x) 1.82 X10^-3 - 1.3X10^-2x = 0.14 x + x^2 x^2 + 0.153 x – 1.82 X10^-3 = 0 solve the above equation we will get; x = 0.0111 thus; x = [SO42-]=0.0111 Then, [H+] = 0.14 + 0.0111 = 0.1511 , and [HSO4-] = 0.14 – x = 0.14- 0.0111= 0.1289 Solution [H2SO4] = 0 because H2SO4 is a strong acid. first consider Ka2: Ka2 = [H+][SO42-]/[HSO4-] = 1.3X10^-2 From the starting condition, let x = [SO42-]. Then, [H+] = 0.14+ x, and [HSO4-] = 0.14 - x. now the value in Ka2 expression: 1.3X10^-2 = (0.14 +x) (x) / (0.14-x) 1.82 X10^-3 - 1.3X10^-2x = 0.14 x + x^2 x^2 + 0.153 x – 1.82 X10^-3 = 0 solve the above equation we will get; x = 0.0111 thus; x = [SO42-]=0.0111 Then, [H+] = 0.14 + 0.0111 = 0.1511 , and [HSO4-] = 0.14 – x = 0.14- 0.0111= 0.1289.
[H2SO4] = 0 because H2SO4 is a strong acid. first consider Ka2.pdf
[H2SO4] = 0 because H2SO4 is a strong acid. first consider Ka2.pdf
anokhilalmobile
You ordered a chest X-ray and saw fluid buildup in her right lung. She also has thick whitish yellow exudates on her tonsils. Finally, her weak pulse made you order an MRI and it revealed myocarditis. Given all this evidence, you asked the parents if they had given their children routine vaccinations. When they said no, you knew exactly what it was. Describe the cause of Ashley’s illness and how you know. ans: Ashley\'s illness is due to the bacterial infection caused by the bacteria Corynebacterium diptheriae.This is causing Ashley to suffer.This bacteria causes infection which led to die the cells of tonsils and throat.Thats why she is having throat infection.And as they have skipped the vaccination process she got infected as she has less resistance or immunity. ELEK test is performed for toxin detection and EIA for detecting toxin in isolates., immumnochromatographic strip test specific test for detecting toxins in specimens and isolates. This organism is transmitted by animlas or main cause is transmission for infected person by coughing or sneezing. Ashley\'s innate immunity would produce antibodies against the bacteria . Solution You ordered a chest X-ray and saw fluid buildup in her right lung. She also has thick whitish yellow exudates on her tonsils. Finally, her weak pulse made you order an MRI and it revealed myocarditis. Given all this evidence, you asked the parents if they had given their children routine vaccinations. When they said no, you knew exactly what it was. Describe the cause of Ashley’s illness and how you know. ans: Ashley\'s illness is due to the bacterial infection caused by the bacteria Corynebacterium diptheriae.This is causing Ashley to suffer.This bacteria causes infection which led to die the cells of tonsils and throat.Thats why she is having throat infection.And as they have skipped the vaccination process she got infected as she has less resistance or immunity. ELEK test is performed for toxin detection and EIA for detecting toxin in isolates., immumnochromatographic strip test specific test for detecting toxins in specimens and isolates. This organism is transmitted by animlas or main cause is transmission for infected person by coughing or sneezing. Ashley\'s innate immunity would produce antibodies against the bacteria ..
You ordered a chest X-ray and saw fluid buildup in her right lung. S.pdf
You ordered a chest X-ray and saw fluid buildup in her right lung. S.pdf
anokhilalmobile
why would you be the best candidate for the nursing program? STATEMENT OF PURPOSE I am applying for program at xxx University in order to explore the best practices and techniques in Nursing. From the time of bachelor degree I have gained a lot of experience, knowledge and skill in technological advancements . I have a passion to learn profoundly the principles and tools relating to xxx Nursing. I am also exated in learning the finest approaches in Nursing that can be used to readily and competently build and maintain Nursing and patient applications. I had successfully completed Masters Degree (M.Sc) with first class from xxx University. I perceived that I should procure some constructive and functional experience working in a research environment. I enjoy every minute to my academic work and participation in innovative projects. I have realized that being part of the research team can direct me to achieve my aim to become a research scientist in Nursing .This enables me to have access and discuss ideas with world famous research scientists. I am hopeful that my ambition and vision will be fulfilled since I have a strong feeling of competitive potential and excellent academic credentials. I have a great passion for Nursing from my bachelor studies. During my period of study at xxxxxxxxxxx , I excelled in courses like Biochemistry, Molecular and Cell Biology, Microbiology, Immunology, Bioprocess Principles and Engineering, Bio and Chemical Thermodynamics, Enzyme Engineering. This provided a firm foundation and took me a step closer towards the field of Nursing to fulfill my goal. The fascinations and promises held out by various areas in Biochemistry, Engineering and Molecular Biology captivated me. I am well acquainted with Nursing techniques. During my Masters program I have done project entitled “xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx”. While conducting the above project , I had gained on hand experience on xxxxxxxxxxxxx. I have real practical and operational experience during my training at research laboratory at xxxx.. I have the ability to organize time efficiently and meticulous preparation is my asset. I have experience in medical la techniques, Immunological Techniques, plant tissue culture and transformation. I am proficient in three “R” of English, and xxx languages. I also engaged in many social activities and extracurricular activities in xxx university campus. I am totally aware of nursing program in Nursing of xxx University which will enable me to work with the famous research team with contemporary technology. I am much excited and have the zeal to join in your research program, with my Nursing profile. I strongly believe that I will definitely contribute and learn in this xxxxxx specialization in xxxxx University. I am confident that I will attain well defined career goal in this field and hope part of esteemed institution. Yours truly, xxxxx One of the greatest points of interest in picking nursing as a profession is the expan.
why would you be the best candidate for the nursing programSTATEM.pdf
why would you be the best candidate for the nursing programSTATEM.pdf
anokhilalmobile
when the data value is passed between two different operating system with different machines they main problem faced by us: 1)one operating system may access the file different way and the other operating in other ways one operating system may case sensitive file system and other user non case sensitive file system. 2) each may different transfer protocol and data transfer speed 3)each will hava different hardware architecture problem to be solved : userinterface : both system may have different user interface so we be able support the interface of other operating system to send data values interconnection: to send data inter connectionn is very very important.the interconnection should done between two different operating systems and both should support the data sending and recieving security: while sending the data security is important .when data is transfered between two similar operating system then it is easy to implement connection security between them but coming to these it much difficult to implement Solution when the data value is passed between two different operating system with different machines they main problem faced by us: 1)one operating system may access the file different way and the other operating in other ways one operating system may case sensitive file system and other user non case sensitive file system. 2) each may different transfer protocol and data transfer speed 3)each will hava different hardware architecture problem to be solved : userinterface : both system may have different user interface so we be able support the interface of other operating system to send data values interconnection: to send data inter connectionn is very very important.the interconnection should done between two different operating systems and both should support the data sending and recieving security: while sending the data security is important .when data is transfered between two similar operating system then it is easy to implement connection security between them but coming to these it much difficult to implement.
when the data value is passed between two different operating system.pdf
when the data value is passed between two different operating system.pdf
anokhilalmobile
Recommended
option E .Na2co3 hydrolysyes and gives NaoH which is a strong base. disscoation of weak acid Ch3cooh is increases in a basic medium Solution option E .Na2co3 hydrolysyes and gives NaoH which is a strong base. disscoation of weak acid Ch3cooh is increases in a basic medium.
option E .Na2co3 hydrolysyes and gives NaoH which.pdf
option E .Na2co3 hydrolysyes and gives NaoH which.pdf
anokhilalmobile
non polar molecules such as lipids and cholestrol Solution non polar molecules such as lipids and cholestrol.
non polar molecules such as lipids and cholestrol.pdf
non polar molecules such as lipids and cholestrol.pdf
anokhilalmobile
moles = molarity x volume = 4.25 mol/L x 2.50 L = 10.63 mol Solution moles = molarity x volume = 4.25 mol/L x 2.50 L = 10.63 mol.
moles = molarity x volume = 4.25 molL x 2.50 L =.pdf
moles = molarity x volume = 4.25 molL x 2.50 L =.pdf
anokhilalmobile
London/dispersion/van der Waals forces - these are weak interactions that occur in a matter of nanoseconds when one atom in a bond temporarily takes more of the electron density than the other one, causing a temporary dipole - i.e. this can happen even when you have a C-H bond that is normally nonpolar. Solution London/dispersion/van der Waals forces - these are weak interactions that occur in a matter of nanoseconds when one atom in a bond temporarily takes more of the electron density than the other one, causing a temporary dipole - i.e. this can happen even when you have a C-H bond that is normally nonpolar..
Londondispersionvan der Waals forces - these ar.pdf
Londondispersionvan der Waals forces - these ar.pdf
anokhilalmobile
[H2SO4] = 0 because H2SO4 is a strong acid. first consider Ka2: Ka2 = [H+][SO42-]/[HSO4-] = 1.3X10^-2 From the starting condition, let x = [SO42-]. Then, [H+] = 0.14+ x, and [HSO4-] = 0.14 - x. now the value in Ka2 expression: 1.3X10^-2 = (0.14 +x) (x) / (0.14-x) 1.82 X10^-3 - 1.3X10^-2x = 0.14 x + x^2 x^2 + 0.153 x – 1.82 X10^-3 = 0 solve the above equation we will get; x = 0.0111 thus; x = [SO42-]=0.0111 Then, [H+] = 0.14 + 0.0111 = 0.1511 , and [HSO4-] = 0.14 – x = 0.14- 0.0111= 0.1289 Solution [H2SO4] = 0 because H2SO4 is a strong acid. first consider Ka2: Ka2 = [H+][SO42-]/[HSO4-] = 1.3X10^-2 From the starting condition, let x = [SO42-]. Then, [H+] = 0.14+ x, and [HSO4-] = 0.14 - x. now the value in Ka2 expression: 1.3X10^-2 = (0.14 +x) (x) / (0.14-x) 1.82 X10^-3 - 1.3X10^-2x = 0.14 x + x^2 x^2 + 0.153 x – 1.82 X10^-3 = 0 solve the above equation we will get; x = 0.0111 thus; x = [SO42-]=0.0111 Then, [H+] = 0.14 + 0.0111 = 0.1511 , and [HSO4-] = 0.14 – x = 0.14- 0.0111= 0.1289.
[H2SO4] = 0 because H2SO4 is a strong acid. first consider Ka2.pdf
[H2SO4] = 0 because H2SO4 is a strong acid. first consider Ka2.pdf
anokhilalmobile
You ordered a chest X-ray and saw fluid buildup in her right lung. She also has thick whitish yellow exudates on her tonsils. Finally, her weak pulse made you order an MRI and it revealed myocarditis. Given all this evidence, you asked the parents if they had given their children routine vaccinations. When they said no, you knew exactly what it was. Describe the cause of Ashley’s illness and how you know. ans: Ashley\'s illness is due to the bacterial infection caused by the bacteria Corynebacterium diptheriae.This is causing Ashley to suffer.This bacteria causes infection which led to die the cells of tonsils and throat.Thats why she is having throat infection.And as they have skipped the vaccination process she got infected as she has less resistance or immunity. ELEK test is performed for toxin detection and EIA for detecting toxin in isolates., immumnochromatographic strip test specific test for detecting toxins in specimens and isolates. This organism is transmitted by animlas or main cause is transmission for infected person by coughing or sneezing. Ashley\'s innate immunity would produce antibodies against the bacteria . Solution You ordered a chest X-ray and saw fluid buildup in her right lung. She also has thick whitish yellow exudates on her tonsils. Finally, her weak pulse made you order an MRI and it revealed myocarditis. Given all this evidence, you asked the parents if they had given their children routine vaccinations. When they said no, you knew exactly what it was. Describe the cause of Ashley’s illness and how you know. ans: Ashley\'s illness is due to the bacterial infection caused by the bacteria Corynebacterium diptheriae.This is causing Ashley to suffer.This bacteria causes infection which led to die the cells of tonsils and throat.Thats why she is having throat infection.And as they have skipped the vaccination process she got infected as she has less resistance or immunity. ELEK test is performed for toxin detection and EIA for detecting toxin in isolates., immumnochromatographic strip test specific test for detecting toxins in specimens and isolates. This organism is transmitted by animlas or main cause is transmission for infected person by coughing or sneezing. Ashley\'s innate immunity would produce antibodies against the bacteria ..
You ordered a chest X-ray and saw fluid buildup in her right lung. S.pdf
You ordered a chest X-ray and saw fluid buildup in her right lung. S.pdf
anokhilalmobile
why would you be the best candidate for the nursing program? STATEMENT OF PURPOSE I am applying for program at xxx University in order to explore the best practices and techniques in Nursing. From the time of bachelor degree I have gained a lot of experience, knowledge and skill in technological advancements . I have a passion to learn profoundly the principles and tools relating to xxx Nursing. I am also exated in learning the finest approaches in Nursing that can be used to readily and competently build and maintain Nursing and patient applications. I had successfully completed Masters Degree (M.Sc) with first class from xxx University. I perceived that I should procure some constructive and functional experience working in a research environment. I enjoy every minute to my academic work and participation in innovative projects. I have realized that being part of the research team can direct me to achieve my aim to become a research scientist in Nursing .This enables me to have access and discuss ideas with world famous research scientists. I am hopeful that my ambition and vision will be fulfilled since I have a strong feeling of competitive potential and excellent academic credentials. I have a great passion for Nursing from my bachelor studies. During my period of study at xxxxxxxxxxx , I excelled in courses like Biochemistry, Molecular and Cell Biology, Microbiology, Immunology, Bioprocess Principles and Engineering, Bio and Chemical Thermodynamics, Enzyme Engineering. This provided a firm foundation and took me a step closer towards the field of Nursing to fulfill my goal. The fascinations and promises held out by various areas in Biochemistry, Engineering and Molecular Biology captivated me. I am well acquainted with Nursing techniques. During my Masters program I have done project entitled “xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx”. While conducting the above project , I had gained on hand experience on xxxxxxxxxxxxx. I have real practical and operational experience during my training at research laboratory at xxxx.. I have the ability to organize time efficiently and meticulous preparation is my asset. I have experience in medical la techniques, Immunological Techniques, plant tissue culture and transformation. I am proficient in three “R” of English, and xxx languages. I also engaged in many social activities and extracurricular activities in xxx university campus. I am totally aware of nursing program in Nursing of xxx University which will enable me to work with the famous research team with contemporary technology. I am much excited and have the zeal to join in your research program, with my Nursing profile. I strongly believe that I will definitely contribute and learn in this xxxxxx specialization in xxxxx University. I am confident that I will attain well defined career goal in this field and hope part of esteemed institution. Yours truly, xxxxx One of the greatest points of interest in picking nursing as a profession is the expan.
why would you be the best candidate for the nursing programSTATEM.pdf
why would you be the best candidate for the nursing programSTATEM.pdf
anokhilalmobile
when the data value is passed between two different operating system with different machines they main problem faced by us: 1)one operating system may access the file different way and the other operating in other ways one operating system may case sensitive file system and other user non case sensitive file system. 2) each may different transfer protocol and data transfer speed 3)each will hava different hardware architecture problem to be solved : userinterface : both system may have different user interface so we be able support the interface of other operating system to send data values interconnection: to send data inter connectionn is very very important.the interconnection should done between two different operating systems and both should support the data sending and recieving security: while sending the data security is important .when data is transfered between two similar operating system then it is easy to implement connection security between them but coming to these it much difficult to implement Solution when the data value is passed between two different operating system with different machines they main problem faced by us: 1)one operating system may access the file different way and the other operating in other ways one operating system may case sensitive file system and other user non case sensitive file system. 2) each may different transfer protocol and data transfer speed 3)each will hava different hardware architecture problem to be solved : userinterface : both system may have different user interface so we be able support the interface of other operating system to send data values interconnection: to send data inter connectionn is very very important.the interconnection should done between two different operating systems and both should support the data sending and recieving security: while sending the data security is important .when data is transfered between two similar operating system then it is easy to implement connection security between them but coming to these it much difficult to implement.
when the data value is passed between two different operating system.pdf
when the data value is passed between two different operating system.pdf
anokhilalmobile
Using mathematical induction, STEP 1: The base n = 1 is clearly true since12n Solution Using mathematical induction, STEP 1: The base n = 1 is clearly true since12n.
Using mathematical induction,STEP 1The base n = 1 is clearl.pdf
Using mathematical induction,STEP 1The base n = 1 is clearl.pdf
anokhilalmobile
The process include many steps which could be planning and preparation, detection of incident, initial response, Formulation of response strategy, Foresnsics backups, investigation, Implementation of security measures , Network monitoring, Recovery, reporting and final is follow up. Action or an event never happens on a prescribed or convenient time hence a its always to have a checklist in place and be prepared like what time the issue happend,who reported etc. Then to analyse the situation and which might requite forensics software and other environment support which helps in analysis, gathering and understanding of evidence. And the most important part is duplication which is accomplised by creating duplicate bit by bit to a hard drive.And there are basically two approaches of doing so one is software based and another is hardware based.And in this place hardware based approach has upper hand as it provides speed and integrity.Also it provided the confidence of less risk of data gettting corrupted. Solution The process include many steps which could be planning and preparation, detection of incident, initial response, Formulation of response strategy, Foresnsics backups, investigation, Implementation of security measures , Network monitoring, Recovery, reporting and final is follow up. Action or an event never happens on a prescribed or convenient time hence a its always to have a checklist in place and be prepared like what time the issue happend,who reported etc. Then to analyse the situation and which might requite forensics software and other environment support which helps in analysis, gathering and understanding of evidence. And the most important part is duplication which is accomplised by creating duplicate bit by bit to a hard drive.And there are basically two approaches of doing so one is software based and another is hardware based.And in this place hardware based approach has upper hand as it provides speed and integrity.Also it provided the confidence of less risk of data gettting corrupted..
The process include many steps which could be planning and preparati.pdf
The process include many steps which could be planning and preparati.pdf
anokhilalmobile
The FCPA established criminal and civil penalties for unlawful payments or bribes (or promises of payments) to foreign officials for the purpose of obtaining or keeping business, either directly or indirectly or through agents, to influence any act or decision or to secure any improper advantage in order to obtain or retain business. The FCPA applies to foreign companies listed on a US exchange or required to file accounts with the SEC, as well as by US corporations or US nationals. It also applies to foreign nationals who cause an act in the US (such as a wire transfer or establishment of an e-mail server in the US) which furthers an FCPA offence. Accounting requirements apply to companies required to file periodic reports with the SEC. Requirements cover both systems of internal control and adequate record keeping – non- compliance can be a criminal offence. The US federal authorities are pursuing cases aggressively and assessing large penalties for the violations of FPCA. Companies which may be subject to the FCPA are strongly advised to conduct suitable due diligence on intermediaries, agents or local partners. Local U.S. Embassies or Consulates can provide suitable profiles under the International Company Profile (ICP) service. Managers and lawyers in most companies want to believe they work for clean, ethical organizations that hire law-abiding employees. This positive bias often blinds US business people to the reality of international business, where bribes, kickbacks, and false or unrecorded transactions are common. Corrupt activity also exists in the US of course, but it is more difficult to understand what is going on in foreign countries when your US managers have little or no language ability or cultural context. Some US business people believe and frequently say \"Everyone knows you can\'t do business in (Mexico, China, India, Russia - pick a country) without paying bribes. It is part of their culture. It is crazy to have a US law that makes paying bribes in foreign countries illegal in the USA.\" Even if that were true, the FCPA is part of the legal environment for international business. Compliance is not optional because American management has a low opinion of foreign government officials. Corruption in international business is common and frequently ignored. Investigation, prosecution and punishment under the FCPA is common. Understand your company\'s risk of being involved in international bribery. Your program requires a Standalone International Anti-corruption Compliance policy, and an Executive who is Accountable for the “Tone at the Top”. Train your board, management, employees and third parties who distribute your products Know all the 3rd parties your company uses in business outside the USA and conduct due diligence. Establish a set of internal controls over company expenditures and assets. Do not permit facilitating payments. Plan for the likelihood you will have to conduct high quality international internal inves.
The FCPA established criminal and civil penalties for unlawful payme.pdf
The FCPA established criminal and civil penalties for unlawful payme.pdf
anokhilalmobile
The answer is: (B.) H- and (C.) NH3 Lewis bases are electron pair donors. Both H- and NH3 (the N atom) have lone electron pairs for donation and are thus Lewis bases. Solution The answer is: (B.) H- and (C.) NH3 Lewis bases are electron pair donors. Both H- and NH3 (the N atom) have lone electron pairs for donation and are thus Lewis bases..
The answer is(B.) H- and (C.) NH3Lewis bases are electron pair .pdf
The answer is(B.) H- and (C.) NH3Lewis bases are electron pair .pdf
anokhilalmobile
Spontaneous mutation rates depend on the rate at which DNA transcription occurs. All the three strains given in the question show a higher rate of spontaneous mutation because they have effects in the mutS or mutL genes, which are involved in mismatch repair system. In Salmonella A and B, during infectious stage, the DNA mutations occurs faster when compared to E.coli, because DNA damage does not induce SOS response for DNA repair in Salmonella. The E.Coli strain has a better DNA repair system because the SOS response quickly responds to the DNA damage during infectious phase. E.coli strain has more permeable membrane compared to Salmonella. Solution Spontaneous mutation rates depend on the rate at which DNA transcription occurs. All the three strains given in the question show a higher rate of spontaneous mutation because they have effects in the mutS or mutL genes, which are involved in mismatch repair system. In Salmonella A and B, during infectious stage, the DNA mutations occurs faster when compared to E.coli, because DNA damage does not induce SOS response for DNA repair in Salmonella. The E.Coli strain has a better DNA repair system because the SOS response quickly responds to the DNA damage during infectious phase. E.coli strain has more permeable membrane compared to Salmonella..
Spontaneous mutation rates depend on the rate at which DNA transcrip.pdf
Spontaneous mutation rates depend on the rate at which DNA transcrip.pdf
anokhilalmobile
Sales revenue 100000 Less- COGS 60000 Gross profit 40000 Operating expenses Selling expense Advertising expense 4500 4500 Administrative expense supplies expense 1500 rent expense 4000 salaries expense 9500 utilities expense 1100 16100 Total operating expenses 20600 Operating income 19400 Non operating income and expenses loss of sale on land (3200) Less- interest expense 6900 Net Other Incomes and Expenses (10100) Net income before tax 9300 Less- Income tax 3800 Earnings after tax 5500Income statement Sales revenue 100000 Less- COGS 60000 Gross profit 40000 Operating expenses Selling expense Advertising expense 4500 4500 Administrative expense supplies expense 1500 rent expense 4000 salaries expense 9500 utilities expense 1100 16100 Total operating expenses 20600 Operating income 19400 Non operating income and expenses loss of sale on land (3200) Less- interest expense 6900 Net Other Incomes and Expenses (10100) Net income before tax 9300 Less- Income tax 3800 Earnings after tax 5500 Solution Sales revenue 100000 Less- COGS 60000 Gross profit 40000 Operating expenses Selling expense Advertising expense 4500 4500 Administrative expense supplies expense 1500 rent expense 4000 salaries expense 9500 utilities expense 1100 16100 Total operating expenses 20600 Operating income 19400 Non operating income and expenses loss of sale on land (3200) Less- interest expense 6900 Net Other Incomes and Expenses (10100) Net income before tax 9300 Less- Income tax 3800 Earnings after tax 5500Income statement Sales revenue 100000 Less- COGS 60000 Gross profit 40000 Operating expenses Selling expense Advertising expense 4500 4500 Administrative expense supplies expense 1500 rent expense 4000 salaries expense 9500 utilities expense 1100 16100 Total operating expenses 20600 Operating income 19400 Non operating income and expenses loss of sale on land (3200) Less- interest expense 6900 Net Other Incomes and Expenses (10100) Net income before tax 9300 Less- Income tax 3800 Earnings after tax 5500.
Sales revenue100000Less- COGS60000Gross profit40000Opera.pdf
Sales revenue100000Less- COGS60000Gross profit40000Opera.pdf
anokhilalmobile
D) Counterclockwise answer Solution D) Counterclockwise answer.
D) Counterclockwise answer .pdf
D) Counterclockwise answer .pdf
anokhilalmobile
Please give the differential equation and boundary conditions. Solution Please give the differential equation and boundary conditions..
Please give the differential equation and boundary conditions.So.pdf
Please give the differential equation and boundary conditions.So.pdf
anokhilalmobile
Point.java public class Point { int x,y; double m,n; public Point(){} public double getX() { return x; } public double getY() { return y; } public double getRadius() { return Math.sqrt(x * x + y * y); } public double getAngle() { return Math.atan2(y, x); } public static Point of(int i,int j) { Point p=new Point(); p.x=i; p.y=j; return p; } public static Point ofPolar(double i,double j) { Point p=new Point(); p.m=i; p.n=j; return p; } } PointTest.java import org.junit.*; import static org.junit.Assert.*; public class PointTest { private static final double TOLERANCE = 1E-12; @Test public void testOf1() { Point p = Point.of(1, -1); assertEquals(1, p.getX(), TOLERANCE); assertEquals(-1, p.getY(), TOLERANCE); assertEquals(Math.sqrt(2), p.getRadius(), TOLERANCE); assertEquals(-Math.PI / 4, p.getAngle(), TOLERANCE); } @Test public void testOf2() { Point p = Point.ofPolar(Math.sqrt(2), -Math.PI / 4); assertEquals(1, p.getX(), TOLERANCE); assertEquals(-1, p.getY(), TOLERANCE); assertEquals(Math.sqrt(2), p.getRadius(), TOLERANCE); assertEquals(-Math.PI / 4, p.getAngle(), TOLERANCE); } } Solution Point.java public class Point { int x,y; double m,n; public Point(){} public double getX() { return x; } public double getY() { return y; } public double getRadius() { return Math.sqrt(x * x + y * y); } public double getAngle() { return Math.atan2(y, x); } public static Point of(int i,int j) { Point p=new Point(); p.x=i; p.y=j; return p; } public static Point ofPolar(double i,double j) { Point p=new Point(); p.m=i; p.n=j; return p; } } PointTest.java import org.junit.*; import static org.junit.Assert.*; public class PointTest { private static final double TOLERANCE = 1E-12; @Test public void testOf1() { Point p = Point.of(1, -1); assertEquals(1, p.getX(), TOLERANCE); assertEquals(-1, p.getY(), TOLERANCE); assertEquals(Math.sqrt(2), p.getRadius(), TOLERANCE); assertEquals(-Math.PI / 4, p.getAngle(), TOLERANCE); } @Test public void testOf2() { Point p = Point.ofPolar(Math.sqrt(2), -Math.PI / 4); assertEquals(1, p.getX(), TOLERANCE); assertEquals(-1, p.getY(), TOLERANCE); assertEquals(Math.sqrt(2), p.getRadius(), TOLERANCE); assertEquals(-Math.PI / 4, p.getAngle(), TOLERANCE); } }.
Point.javapublic class Point { int x,y; double m,n; .pdf
Point.javapublic class Point { int x,y; double m,n; .pdf
anokhilalmobile
pKa of H2PO4- is = 7.21 According to Henderson\'s Equation , pH = pKa + log ( [salt] /[acid]) = pKa + log ( [Na2HPO4] / [ KH2PO4 ] ) = 7.21 + log ( 0.135 / 0.185 ) = 7.21 - 0.14 = 7.07 Solution pKa of H2PO4- is = 7.21 According to Henderson\'s Equation , pH = pKa + log ( [salt] /[acid]) = pKa + log ( [Na2HPO4] / [ KH2PO4 ] ) = 7.21 + log ( 0.135 / 0.185 ) = 7.21 - 0.14 = 7.07.
pKa of H2PO4- is = 7.21According to Hendersons Equation ,pH = .pdf
pKa of H2PO4- is = 7.21According to Hendersons Equation ,pH = .pdf
anokhilalmobile
naphthalene, dry ice (solid co2),iodine(gentle heating), arsenic (At high temperature) etc... Solution naphthalene, dry ice (solid co2),iodine(gentle heating), arsenic (At high temperature) etc....
naphthalene, dry ice (solid co2),iodine(gentle heating), arsenic (At.pdf
naphthalene, dry ice (solid co2),iodine(gentle heating), arsenic (At.pdf
anokhilalmobile
Ken is employing Correlational research method Solution Ken is employing Correlational research method.
Ken is employing Correlational research methodSolutionKen is e.pdf
Ken is employing Correlational research methodSolutionKen is e.pdf
anokhilalmobile
Let two numbers be x and y. Assume y>x. i.e., Let y be greater than x Given: the larger of 2 number is 20 more than the smaller y=20+x Four times the larger is 70 more than 5 times the smaller 4y=70+5x substituting y=20+x in 4y=70+5x we get, 4(20+x)=70+5x 80+4x=70+5x (Bringing 4x to R.H.S & 70 to L.H.S,we get) 80-70=5x-4x 10=x x=10 we know that y=20+x which gives y=20+10 y=30 thus, x=10 and y=30 Solution Let two numbers be x and y. Assume y>x. i.e., Let y be greater than x Given: the larger of 2 number is 20 more than the smaller y=20+x Four times the larger is 70 more than 5 times the smaller 4y=70+5x substituting y=20+x in 4y=70+5x we get, 4(20+x)=70+5x 80+4x=70+5x (Bringing 4x to R.H.S & 70 to L.H.S,we get) 80-70=5x-4x 10=x x=10 we know that y=20+x which gives y=20+10 y=30 thus, x=10 and y=30.
Let two numbers be x and y. Assume yx.i.e., Let y be greater than.pdf
Let two numbers be x and y. Assume yx.i.e., Let y be greater than.pdf
anokhilalmobile
International Accounting Standard No. 16: International Accounting Standard No. 16 provides that property, plant and equipment can be accounted for under the cost method or the revaluation method. Under the Cost model of accounting the property, plant and equipment, an item of property, plant and equipment should initially be recorded at cost. Cost includes all costs necessary to bring the asset to working condition for its intended use. This would include not only its original purchase price but also costs of site preparation, delivery and handling, installation, related professional fees for architects and engineers, and the estimated cost of dismantling and removing the asset and restoring the site.If payment for an item of property, plant, and equipment is deferred, interest at a market rate must be recognised or imputed. If an asset is acquired in exchange for another asset (whether similar or dissimilar in nature), the cost will be measured at the fair value unless (a) the exchange transaction lacks commercial substance or (b) the fair value of neither the asset received nor the asset given up is reliably measurable. If the acquired item is not measured at fair value, its cost is measured at the carrying amount of the asset given up. Under the revaluation model, revaluations should be carried out regularly, so that the carrying amount of an asset does not differ materially from its fair value at the balance sheet date. If an item is revalued, the entire class of assets to which that asset belongs should be revalued. If a revaluation results in an increase in value, it should be credited to other comprehensive income and accumulated in equity under the heading \"revaluation surplus\" unless it represents the reversal of a revaluation decrease of the same asset previously recognised as an expense, in which case it should be recognised in profit or loss. A decrease arising as a result of a revaluation should be recognised as an expense to the extent that it exceeds any amount previously credited to the revaluation surplus relating to the same asset. When a revalued asset is disposed of, any revaluation surplus may be transferred directly to retained earnings, or it may be left in equity under the heading revaluation surplus. The transfer to retained earnings should not be made through profit or loss. Solution International Accounting Standard No. 16: International Accounting Standard No. 16 provides that property, plant and equipment can be accounted for under the cost method or the revaluation method. Under the Cost model of accounting the property, plant and equipment, an item of property, plant and equipment should initially be recorded at cost. Cost includes all costs necessary to bring the asset to working condition for its intended use. This would include not only its original purchase price but also costs of site preparation, delivery and handling, installation, related professional fees for architects and engineers, and the estimat.
International Accounting Standard No. 16International Accounting .pdf
International Accounting Standard No. 16International Accounting .pdf
anokhilalmobile
It travel with the speed of light in vacuum or air and it exhibit interference and attenuated in lossy dielectric ANS is 5 Solution It travel with the speed of light in vacuum or air and it exhibit interference and attenuated in lossy dielectric ANS is 5.
It travel with the speed of light in vacuum or air and it exhibit in.pdf
It travel with the speed of light in vacuum or air and it exhibit in.pdf
anokhilalmobile
GeometricObject.java public interface GeometricObject { //Declaring abstract methods public double getPerimeter(); public double getArea(); } ___________________________________________ Circle.java public class Circle implements GeometricObject { //Declaring variable double radius = 1.0; //Declaring constant public static final double PI = 3.14159; //Parameterized constructor public Circle(double radius) { super(); this.radius = radius; } //Setters and getters public double getRadius() { return radius; } public void setRadius(double radius) { this.radius = radius; } //getPerimeter() calculates the perimeter and return it @Override public double getPerimeter() { return 2 * PI * this.radius; } //getArea() calculates area and return it @Override public double getArea() { return PI * this.radius * this.radius; } } ___________________________________________ Resizable.java public interface Resizable { //Declaring abstract method public void resize(int percent); } _________________________________________________ ResizableCircle.java public class ResizableCircle extends Circle implements Resizable { //parameterized ResizableObject public ResizableCircle(double radius) { super(radius); } //resize() method will change the radius of the circle based on percent @Override public void resize(int percent) { double radius=getRadius(); radius=radius+((radius*percent)/100); setRadius(radius); } } ___________________________________________ DriverClass.java import java.text.DecimalFormat; public class DriverClass { public static void main(String[] args) { //DecimalFormat Object is used to format the number DecimalFormat df=new DecimalFormat(\"#.##\"); //Creates an circle object by passing radius as parameter Circle c=new Circle(10); //Displaying the perimeter of the circle System.out.println(\"Perimeter of the Circle :\"+df.format(c.getPerimeter())); //Displaying the area of the circle System.out.println(\"Area of the Circle :\"+df.format(c.getArea())); //creating the object of the Resizable object by passing radius as parameter ResizableCircle rc=new ResizableCircle(20); //Displaying perimeter and area of the circle before resizing the radius System.out.println(\"\ _______Before Resizing the Radius_______\"); System.out.println(\"Perimeter of the Circle :\"+df.format(rc.getPerimeter())); System.out.println(\"Area of the Circle :\"+df.format(rc.getArea())); //Performing the resize rc.resize(50); //Displaying perimeter and area of the circle after resizing the radius System.out.println(\"\ _______After Resizing the Radius_______\"); System.out.println(\"Perimeter of the Circle :\"+df.format(rc.getPerimeter())); System.out.println(\"Area of the Circle :\"+df.format(rc.getArea())); } } ________________________________________________ Output: Perimeter of the Circle :62.83 Area of the Circle :314.16 _______Before Resizing the Radius_______ Perimeter of the Circle :125.66 Area of the Circle :1256.64 _______After Resizing the Radius_______ Perimeter of the Circle :.
GeometricObject.javapublic interface GeometricObject { Declari.pdf
GeometricObject.javapublic interface GeometricObject { Declari.pdf
anokhilalmobile
From this link we can see that group of teens attacked mutiple times at four different places which police called them as mob attacks . From the news reporter from Mag Mile says that lot of innocent citizens and shop keepers are attacked by group of teens. The group of teens created chaos along the city of chicago and Deaborn by beating themselves in streets ,robbing a women late night and beating a man in his face. From the report of ANdrew HOlmes we can see that they assaulted a police officer and robbed some places The police officers have arrested 28 people and out of these 28 people there are 25 juvineleis From these report we can understand that it is preplanned as it not done in one single place but different places . There main is not robbing people but by creating choas they are trying to divert cops towards citizens for helping them SO they can rob people Solution From this link we can see that group of teens attacked mutiple times at four different places which police called them as mob attacks . From the news reporter from Mag Mile says that lot of innocent citizens and shop keepers are attacked by group of teens. The group of teens created chaos along the city of chicago and Deaborn by beating themselves in streets ,robbing a women late night and beating a man in his face. From the report of ANdrew HOlmes we can see that they assaulted a police officer and robbed some places The police officers have arrested 28 people and out of these 28 people there are 25 juvineleis From these report we can understand that it is preplanned as it not done in one single place but different places . There main is not robbing people but by creating choas they are trying to divert cops towards citizens for helping them SO they can rob people.
From this link we can see that group of teens attacked mutiple times.pdf
From this link we can see that group of teens attacked mutiple times.pdf
anokhilalmobile
Answer is D) Solution Answer is D).
Answer is D) .pdf
Answer is D) .pdf
anokhilalmobile
Dispersion forces (answer) Explanation - Dispersion forces have many different names: London forces, Van der Waals forces, instantaneous dipoles. Dispersion forces involve the attraction between temporarily induced dipoles in nonpolar molecules (often disappear within an instant). This polarization can be induced either by a polar molecule or by the repulsion of negatively charged electron clouds in nonpolar molecules. As electrons move around their shells, electron density may randomly be distributed unevenly, creating a partially negative (?-) charge. The opposite side of the molecule then becomes partially positive (?+). The result is a temporary dipole. If this process occurs in two molecules that are close to one another, the two molecules will be attracted to each other, and will form a temporary, non-covalent bond. Solution Dispersion forces (answer) Explanation - Dispersion forces have many different names: London forces, Van der Waals forces, instantaneous dipoles. Dispersion forces involve the attraction between temporarily induced dipoles in nonpolar molecules (often disappear within an instant). This polarization can be induced either by a polar molecule or by the repulsion of negatively charged electron clouds in nonpolar molecules. As electrons move around their shells, electron density may randomly be distributed unevenly, creating a partially negative (?-) charge. The opposite side of the molecule then becomes partially positive (?+). The result is a temporary dipole. If this process occurs in two molecules that are close to one another, the two molecules will be attracted to each other, and will form a temporary, non-covalent bond..
Dispersion forces (answer)Explanation - Dispersion forces have.pdf
Dispersion forces (answer)Explanation - Dispersion forces have.pdf
anokhilalmobile
A. True. The addition of impurities interfer with the ability to form crystaline structures and cause liquids to remain until colder temperaturs, much like putting salt on the roadways. B) True. the compounds will demonstrate a fuzzy melting point when impurities are present, when they are not present the temp sreads throughout the substance and it will seem to convert to a liquid rapidly at a single temperqature rather than over a couple degrees. C) True. the melting point of the addition is not very important as long as it is a minority component. The presence of impurities in the solid crystaline structure lowers the melting point, salt melts at a much higher temp than water, yet lowers the melting point of water, same principal even though water and salt are both inorganic. if the substance is identical then there is not an effect of an impurity being present and the mp is unchanged. D) true for the same reasons, impurities lower melting point. if enough of substance b was added that it became the solvent, mp of solution could rise but it would be lower than substance b mp. Solution A. True. The addition of impurities interfer with the ability to form crystaline structures and cause liquids to remain until colder temperaturs, much like putting salt on the roadways. B) True. the compounds will demonstrate a fuzzy melting point when impurities are present, when they are not present the temp sreads throughout the substance and it will seem to convert to a liquid rapidly at a single temperqature rather than over a couple degrees. C) True. the melting point of the addition is not very important as long as it is a minority component. The presence of impurities in the solid crystaline structure lowers the melting point, salt melts at a much higher temp than water, yet lowers the melting point of water, same principal even though water and salt are both inorganic. if the substance is identical then there is not an effect of an impurity being present and the mp is unchanged. D) true for the same reasons, impurities lower melting point. if enough of substance b was added that it became the solvent, mp of solution could rise but it would be lower than substance b mp..
A. True. The addition of impurities interfer with.pdf
A. True. The addition of impurities interfer with.pdf
anokhilalmobile
This presentation was provided by William Mattingly of the Smithsonian Institution, during the fifth segment of the NISO training series "AI & Prompt Design." Session Five: Named Entity Recognition with LLMs, was held on May 2, 2024.
Mattingly "AI & Prompt Design: Named Entity Recognition"
Mattingly "AI & Prompt Design: Named Entity Recognition"
National Information Standards Organization (NISO)
Fictional Salesman/Saleswoman
FICTIONAL SALESMAN/SALESMAN SNSW 2024.pdf
FICTIONAL SALESMAN/SALESMAN SNSW 2024.pdf
Pondicherry University
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Using mathematical induction, STEP 1: The base n = 1 is clearly true since12n Solution Using mathematical induction, STEP 1: The base n = 1 is clearly true since12n.
Using mathematical induction,STEP 1The base n = 1 is clearl.pdf
Using mathematical induction,STEP 1The base n = 1 is clearl.pdf
anokhilalmobile
The process include many steps which could be planning and preparation, detection of incident, initial response, Formulation of response strategy, Foresnsics backups, investigation, Implementation of security measures , Network monitoring, Recovery, reporting and final is follow up. Action or an event never happens on a prescribed or convenient time hence a its always to have a checklist in place and be prepared like what time the issue happend,who reported etc. Then to analyse the situation and which might requite forensics software and other environment support which helps in analysis, gathering and understanding of evidence. And the most important part is duplication which is accomplised by creating duplicate bit by bit to a hard drive.And there are basically two approaches of doing so one is software based and another is hardware based.And in this place hardware based approach has upper hand as it provides speed and integrity.Also it provided the confidence of less risk of data gettting corrupted. Solution The process include many steps which could be planning and preparation, detection of incident, initial response, Formulation of response strategy, Foresnsics backups, investigation, Implementation of security measures , Network monitoring, Recovery, reporting and final is follow up. Action or an event never happens on a prescribed or convenient time hence a its always to have a checklist in place and be prepared like what time the issue happend,who reported etc. Then to analyse the situation and which might requite forensics software and other environment support which helps in analysis, gathering and understanding of evidence. And the most important part is duplication which is accomplised by creating duplicate bit by bit to a hard drive.And there are basically two approaches of doing so one is software based and another is hardware based.And in this place hardware based approach has upper hand as it provides speed and integrity.Also it provided the confidence of less risk of data gettting corrupted..
The process include many steps which could be planning and preparati.pdf
The process include many steps which could be planning and preparati.pdf
anokhilalmobile
The FCPA established criminal and civil penalties for unlawful payments or bribes (or promises of payments) to foreign officials for the purpose of obtaining or keeping business, either directly or indirectly or through agents, to influence any act or decision or to secure any improper advantage in order to obtain or retain business. The FCPA applies to foreign companies listed on a US exchange or required to file accounts with the SEC, as well as by US corporations or US nationals. It also applies to foreign nationals who cause an act in the US (such as a wire transfer or establishment of an e-mail server in the US) which furthers an FCPA offence. Accounting requirements apply to companies required to file periodic reports with the SEC. Requirements cover both systems of internal control and adequate record keeping – non- compliance can be a criminal offence. The US federal authorities are pursuing cases aggressively and assessing large penalties for the violations of FPCA. Companies which may be subject to the FCPA are strongly advised to conduct suitable due diligence on intermediaries, agents or local partners. Local U.S. Embassies or Consulates can provide suitable profiles under the International Company Profile (ICP) service. Managers and lawyers in most companies want to believe they work for clean, ethical organizations that hire law-abiding employees. This positive bias often blinds US business people to the reality of international business, where bribes, kickbacks, and false or unrecorded transactions are common. Corrupt activity also exists in the US of course, but it is more difficult to understand what is going on in foreign countries when your US managers have little or no language ability or cultural context. Some US business people believe and frequently say \"Everyone knows you can\'t do business in (Mexico, China, India, Russia - pick a country) without paying bribes. It is part of their culture. It is crazy to have a US law that makes paying bribes in foreign countries illegal in the USA.\" Even if that were true, the FCPA is part of the legal environment for international business. Compliance is not optional because American management has a low opinion of foreign government officials. Corruption in international business is common and frequently ignored. Investigation, prosecution and punishment under the FCPA is common. Understand your company\'s risk of being involved in international bribery. Your program requires a Standalone International Anti-corruption Compliance policy, and an Executive who is Accountable for the “Tone at the Top”. Train your board, management, employees and third parties who distribute your products Know all the 3rd parties your company uses in business outside the USA and conduct due diligence. Establish a set of internal controls over company expenditures and assets. Do not permit facilitating payments. Plan for the likelihood you will have to conduct high quality international internal inves.
The FCPA established criminal and civil penalties for unlawful payme.pdf
The FCPA established criminal and civil penalties for unlawful payme.pdf
anokhilalmobile
The answer is: (B.) H- and (C.) NH3 Lewis bases are electron pair donors. Both H- and NH3 (the N atom) have lone electron pairs for donation and are thus Lewis bases. Solution The answer is: (B.) H- and (C.) NH3 Lewis bases are electron pair donors. Both H- and NH3 (the N atom) have lone electron pairs for donation and are thus Lewis bases..
The answer is(B.) H- and (C.) NH3Lewis bases are electron pair .pdf
The answer is(B.) H- and (C.) NH3Lewis bases are electron pair .pdf
anokhilalmobile
Spontaneous mutation rates depend on the rate at which DNA transcription occurs. All the three strains given in the question show a higher rate of spontaneous mutation because they have effects in the mutS or mutL genes, which are involved in mismatch repair system. In Salmonella A and B, during infectious stage, the DNA mutations occurs faster when compared to E.coli, because DNA damage does not induce SOS response for DNA repair in Salmonella. The E.Coli strain has a better DNA repair system because the SOS response quickly responds to the DNA damage during infectious phase. E.coli strain has more permeable membrane compared to Salmonella. Solution Spontaneous mutation rates depend on the rate at which DNA transcription occurs. All the three strains given in the question show a higher rate of spontaneous mutation because they have effects in the mutS or mutL genes, which are involved in mismatch repair system. In Salmonella A and B, during infectious stage, the DNA mutations occurs faster when compared to E.coli, because DNA damage does not induce SOS response for DNA repair in Salmonella. The E.Coli strain has a better DNA repair system because the SOS response quickly responds to the DNA damage during infectious phase. E.coli strain has more permeable membrane compared to Salmonella..
Spontaneous mutation rates depend on the rate at which DNA transcrip.pdf
Spontaneous mutation rates depend on the rate at which DNA transcrip.pdf
anokhilalmobile
Sales revenue 100000 Less- COGS 60000 Gross profit 40000 Operating expenses Selling expense Advertising expense 4500 4500 Administrative expense supplies expense 1500 rent expense 4000 salaries expense 9500 utilities expense 1100 16100 Total operating expenses 20600 Operating income 19400 Non operating income and expenses loss of sale on land (3200) Less- interest expense 6900 Net Other Incomes and Expenses (10100) Net income before tax 9300 Less- Income tax 3800 Earnings after tax 5500Income statement Sales revenue 100000 Less- COGS 60000 Gross profit 40000 Operating expenses Selling expense Advertising expense 4500 4500 Administrative expense supplies expense 1500 rent expense 4000 salaries expense 9500 utilities expense 1100 16100 Total operating expenses 20600 Operating income 19400 Non operating income and expenses loss of sale on land (3200) Less- interest expense 6900 Net Other Incomes and Expenses (10100) Net income before tax 9300 Less- Income tax 3800 Earnings after tax 5500 Solution Sales revenue 100000 Less- COGS 60000 Gross profit 40000 Operating expenses Selling expense Advertising expense 4500 4500 Administrative expense supplies expense 1500 rent expense 4000 salaries expense 9500 utilities expense 1100 16100 Total operating expenses 20600 Operating income 19400 Non operating income and expenses loss of sale on land (3200) Less- interest expense 6900 Net Other Incomes and Expenses (10100) Net income before tax 9300 Less- Income tax 3800 Earnings after tax 5500Income statement Sales revenue 100000 Less- COGS 60000 Gross profit 40000 Operating expenses Selling expense Advertising expense 4500 4500 Administrative expense supplies expense 1500 rent expense 4000 salaries expense 9500 utilities expense 1100 16100 Total operating expenses 20600 Operating income 19400 Non operating income and expenses loss of sale on land (3200) Less- interest expense 6900 Net Other Incomes and Expenses (10100) Net income before tax 9300 Less- Income tax 3800 Earnings after tax 5500.
Sales revenue100000Less- COGS60000Gross profit40000Opera.pdf
Sales revenue100000Less- COGS60000Gross profit40000Opera.pdf
anokhilalmobile
D) Counterclockwise answer Solution D) Counterclockwise answer.
D) Counterclockwise answer .pdf
D) Counterclockwise answer .pdf
anokhilalmobile
Please give the differential equation and boundary conditions. Solution Please give the differential equation and boundary conditions..
Please give the differential equation and boundary conditions.So.pdf
Please give the differential equation and boundary conditions.So.pdf
anokhilalmobile
Point.java public class Point { int x,y; double m,n; public Point(){} public double getX() { return x; } public double getY() { return y; } public double getRadius() { return Math.sqrt(x * x + y * y); } public double getAngle() { return Math.atan2(y, x); } public static Point of(int i,int j) { Point p=new Point(); p.x=i; p.y=j; return p; } public static Point ofPolar(double i,double j) { Point p=new Point(); p.m=i; p.n=j; return p; } } PointTest.java import org.junit.*; import static org.junit.Assert.*; public class PointTest { private static final double TOLERANCE = 1E-12; @Test public void testOf1() { Point p = Point.of(1, -1); assertEquals(1, p.getX(), TOLERANCE); assertEquals(-1, p.getY(), TOLERANCE); assertEquals(Math.sqrt(2), p.getRadius(), TOLERANCE); assertEquals(-Math.PI / 4, p.getAngle(), TOLERANCE); } @Test public void testOf2() { Point p = Point.ofPolar(Math.sqrt(2), -Math.PI / 4); assertEquals(1, p.getX(), TOLERANCE); assertEquals(-1, p.getY(), TOLERANCE); assertEquals(Math.sqrt(2), p.getRadius(), TOLERANCE); assertEquals(-Math.PI / 4, p.getAngle(), TOLERANCE); } } Solution Point.java public class Point { int x,y; double m,n; public Point(){} public double getX() { return x; } public double getY() { return y; } public double getRadius() { return Math.sqrt(x * x + y * y); } public double getAngle() { return Math.atan2(y, x); } public static Point of(int i,int j) { Point p=new Point(); p.x=i; p.y=j; return p; } public static Point ofPolar(double i,double j) { Point p=new Point(); p.m=i; p.n=j; return p; } } PointTest.java import org.junit.*; import static org.junit.Assert.*; public class PointTest { private static final double TOLERANCE = 1E-12; @Test public void testOf1() { Point p = Point.of(1, -1); assertEquals(1, p.getX(), TOLERANCE); assertEquals(-1, p.getY(), TOLERANCE); assertEquals(Math.sqrt(2), p.getRadius(), TOLERANCE); assertEquals(-Math.PI / 4, p.getAngle(), TOLERANCE); } @Test public void testOf2() { Point p = Point.ofPolar(Math.sqrt(2), -Math.PI / 4); assertEquals(1, p.getX(), TOLERANCE); assertEquals(-1, p.getY(), TOLERANCE); assertEquals(Math.sqrt(2), p.getRadius(), TOLERANCE); assertEquals(-Math.PI / 4, p.getAngle(), TOLERANCE); } }.
Point.javapublic class Point { int x,y; double m,n; .pdf
Point.javapublic class Point { int x,y; double m,n; .pdf
anokhilalmobile
pKa of H2PO4- is = 7.21 According to Henderson\'s Equation , pH = pKa + log ( [salt] /[acid]) = pKa + log ( [Na2HPO4] / [ KH2PO4 ] ) = 7.21 + log ( 0.135 / 0.185 ) = 7.21 - 0.14 = 7.07 Solution pKa of H2PO4- is = 7.21 According to Henderson\'s Equation , pH = pKa + log ( [salt] /[acid]) = pKa + log ( [Na2HPO4] / [ KH2PO4 ] ) = 7.21 + log ( 0.135 / 0.185 ) = 7.21 - 0.14 = 7.07.
pKa of H2PO4- is = 7.21According to Hendersons Equation ,pH = .pdf
pKa of H2PO4- is = 7.21According to Hendersons Equation ,pH = .pdf
anokhilalmobile
naphthalene, dry ice (solid co2),iodine(gentle heating), arsenic (At high temperature) etc... Solution naphthalene, dry ice (solid co2),iodine(gentle heating), arsenic (At high temperature) etc....
naphthalene, dry ice (solid co2),iodine(gentle heating), arsenic (At.pdf
naphthalene, dry ice (solid co2),iodine(gentle heating), arsenic (At.pdf
anokhilalmobile
Ken is employing Correlational research method Solution Ken is employing Correlational research method.
Ken is employing Correlational research methodSolutionKen is e.pdf
Ken is employing Correlational research methodSolutionKen is e.pdf
anokhilalmobile
Let two numbers be x and y. Assume y>x. i.e., Let y be greater than x Given: the larger of 2 number is 20 more than the smaller y=20+x Four times the larger is 70 more than 5 times the smaller 4y=70+5x substituting y=20+x in 4y=70+5x we get, 4(20+x)=70+5x 80+4x=70+5x (Bringing 4x to R.H.S & 70 to L.H.S,we get) 80-70=5x-4x 10=x x=10 we know that y=20+x which gives y=20+10 y=30 thus, x=10 and y=30 Solution Let two numbers be x and y. Assume y>x. i.e., Let y be greater than x Given: the larger of 2 number is 20 more than the smaller y=20+x Four times the larger is 70 more than 5 times the smaller 4y=70+5x substituting y=20+x in 4y=70+5x we get, 4(20+x)=70+5x 80+4x=70+5x (Bringing 4x to R.H.S & 70 to L.H.S,we get) 80-70=5x-4x 10=x x=10 we know that y=20+x which gives y=20+10 y=30 thus, x=10 and y=30.
Let two numbers be x and y. Assume yx.i.e., Let y be greater than.pdf
Let two numbers be x and y. Assume yx.i.e., Let y be greater than.pdf
anokhilalmobile
International Accounting Standard No. 16: International Accounting Standard No. 16 provides that property, plant and equipment can be accounted for under the cost method or the revaluation method. Under the Cost model of accounting the property, plant and equipment, an item of property, plant and equipment should initially be recorded at cost. Cost includes all costs necessary to bring the asset to working condition for its intended use. This would include not only its original purchase price but also costs of site preparation, delivery and handling, installation, related professional fees for architects and engineers, and the estimated cost of dismantling and removing the asset and restoring the site.If payment for an item of property, plant, and equipment is deferred, interest at a market rate must be recognised or imputed. If an asset is acquired in exchange for another asset (whether similar or dissimilar in nature), the cost will be measured at the fair value unless (a) the exchange transaction lacks commercial substance or (b) the fair value of neither the asset received nor the asset given up is reliably measurable. If the acquired item is not measured at fair value, its cost is measured at the carrying amount of the asset given up. Under the revaluation model, revaluations should be carried out regularly, so that the carrying amount of an asset does not differ materially from its fair value at the balance sheet date. If an item is revalued, the entire class of assets to which that asset belongs should be revalued. If a revaluation results in an increase in value, it should be credited to other comprehensive income and accumulated in equity under the heading \"revaluation surplus\" unless it represents the reversal of a revaluation decrease of the same asset previously recognised as an expense, in which case it should be recognised in profit or loss. A decrease arising as a result of a revaluation should be recognised as an expense to the extent that it exceeds any amount previously credited to the revaluation surplus relating to the same asset. When a revalued asset is disposed of, any revaluation surplus may be transferred directly to retained earnings, or it may be left in equity under the heading revaluation surplus. The transfer to retained earnings should not be made through profit or loss. Solution International Accounting Standard No. 16: International Accounting Standard No. 16 provides that property, plant and equipment can be accounted for under the cost method or the revaluation method. Under the Cost model of accounting the property, plant and equipment, an item of property, plant and equipment should initially be recorded at cost. Cost includes all costs necessary to bring the asset to working condition for its intended use. This would include not only its original purchase price but also costs of site preparation, delivery and handling, installation, related professional fees for architects and engineers, and the estimat.
International Accounting Standard No. 16International Accounting .pdf
International Accounting Standard No. 16International Accounting .pdf
anokhilalmobile
It travel with the speed of light in vacuum or air and it exhibit interference and attenuated in lossy dielectric ANS is 5 Solution It travel with the speed of light in vacuum or air and it exhibit interference and attenuated in lossy dielectric ANS is 5.
It travel with the speed of light in vacuum or air and it exhibit in.pdf
It travel with the speed of light in vacuum or air and it exhibit in.pdf
anokhilalmobile
GeometricObject.java public interface GeometricObject { //Declaring abstract methods public double getPerimeter(); public double getArea(); } ___________________________________________ Circle.java public class Circle implements GeometricObject { //Declaring variable double radius = 1.0; //Declaring constant public static final double PI = 3.14159; //Parameterized constructor public Circle(double radius) { super(); this.radius = radius; } //Setters and getters public double getRadius() { return radius; } public void setRadius(double radius) { this.radius = radius; } //getPerimeter() calculates the perimeter and return it @Override public double getPerimeter() { return 2 * PI * this.radius; } //getArea() calculates area and return it @Override public double getArea() { return PI * this.radius * this.radius; } } ___________________________________________ Resizable.java public interface Resizable { //Declaring abstract method public void resize(int percent); } _________________________________________________ ResizableCircle.java public class ResizableCircle extends Circle implements Resizable { //parameterized ResizableObject public ResizableCircle(double radius) { super(radius); } //resize() method will change the radius of the circle based on percent @Override public void resize(int percent) { double radius=getRadius(); radius=radius+((radius*percent)/100); setRadius(radius); } } ___________________________________________ DriverClass.java import java.text.DecimalFormat; public class DriverClass { public static void main(String[] args) { //DecimalFormat Object is used to format the number DecimalFormat df=new DecimalFormat(\"#.##\"); //Creates an circle object by passing radius as parameter Circle c=new Circle(10); //Displaying the perimeter of the circle System.out.println(\"Perimeter of the Circle :\"+df.format(c.getPerimeter())); //Displaying the area of the circle System.out.println(\"Area of the Circle :\"+df.format(c.getArea())); //creating the object of the Resizable object by passing radius as parameter ResizableCircle rc=new ResizableCircle(20); //Displaying perimeter and area of the circle before resizing the radius System.out.println(\"\ _______Before Resizing the Radius_______\"); System.out.println(\"Perimeter of the Circle :\"+df.format(rc.getPerimeter())); System.out.println(\"Area of the Circle :\"+df.format(rc.getArea())); //Performing the resize rc.resize(50); //Displaying perimeter and area of the circle after resizing the radius System.out.println(\"\ _______After Resizing the Radius_______\"); System.out.println(\"Perimeter of the Circle :\"+df.format(rc.getPerimeter())); System.out.println(\"Area of the Circle :\"+df.format(rc.getArea())); } } ________________________________________________ Output: Perimeter of the Circle :62.83 Area of the Circle :314.16 _______Before Resizing the Radius_______ Perimeter of the Circle :125.66 Area of the Circle :1256.64 _______After Resizing the Radius_______ Perimeter of the Circle :.
GeometricObject.javapublic interface GeometricObject { Declari.pdf
GeometricObject.javapublic interface GeometricObject { Declari.pdf
anokhilalmobile
From this link we can see that group of teens attacked mutiple times at four different places which police called them as mob attacks . From the news reporter from Mag Mile says that lot of innocent citizens and shop keepers are attacked by group of teens. The group of teens created chaos along the city of chicago and Deaborn by beating themselves in streets ,robbing a women late night and beating a man in his face. From the report of ANdrew HOlmes we can see that they assaulted a police officer and robbed some places The police officers have arrested 28 people and out of these 28 people there are 25 juvineleis From these report we can understand that it is preplanned as it not done in one single place but different places . There main is not robbing people but by creating choas they are trying to divert cops towards citizens for helping them SO they can rob people Solution From this link we can see that group of teens attacked mutiple times at four different places which police called them as mob attacks . From the news reporter from Mag Mile says that lot of innocent citizens and shop keepers are attacked by group of teens. The group of teens created chaos along the city of chicago and Deaborn by beating themselves in streets ,robbing a women late night and beating a man in his face. From the report of ANdrew HOlmes we can see that they assaulted a police officer and robbed some places The police officers have arrested 28 people and out of these 28 people there are 25 juvineleis From these report we can understand that it is preplanned as it not done in one single place but different places . There main is not robbing people but by creating choas they are trying to divert cops towards citizens for helping them SO they can rob people.
From this link we can see that group of teens attacked mutiple times.pdf
From this link we can see that group of teens attacked mutiple times.pdf
anokhilalmobile
Answer is D) Solution Answer is D).
Answer is D) .pdf
Answer is D) .pdf
anokhilalmobile
Dispersion forces (answer) Explanation - Dispersion forces have many different names: London forces, Van der Waals forces, instantaneous dipoles. Dispersion forces involve the attraction between temporarily induced dipoles in nonpolar molecules (often disappear within an instant). This polarization can be induced either by a polar molecule or by the repulsion of negatively charged electron clouds in nonpolar molecules. As electrons move around their shells, electron density may randomly be distributed unevenly, creating a partially negative (?-) charge. The opposite side of the molecule then becomes partially positive (?+). The result is a temporary dipole. If this process occurs in two molecules that are close to one another, the two molecules will be attracted to each other, and will form a temporary, non-covalent bond. Solution Dispersion forces (answer) Explanation - Dispersion forces have many different names: London forces, Van der Waals forces, instantaneous dipoles. Dispersion forces involve the attraction between temporarily induced dipoles in nonpolar molecules (often disappear within an instant). This polarization can be induced either by a polar molecule or by the repulsion of negatively charged electron clouds in nonpolar molecules. As electrons move around their shells, electron density may randomly be distributed unevenly, creating a partially negative (?-) charge. The opposite side of the molecule then becomes partially positive (?+). The result is a temporary dipole. If this process occurs in two molecules that are close to one another, the two molecules will be attracted to each other, and will form a temporary, non-covalent bond..
Dispersion forces (answer)Explanation - Dispersion forces have.pdf
Dispersion forces (answer)Explanation - Dispersion forces have.pdf
anokhilalmobile
A. True. The addition of impurities interfer with the ability to form crystaline structures and cause liquids to remain until colder temperaturs, much like putting salt on the roadways. B) True. the compounds will demonstrate a fuzzy melting point when impurities are present, when they are not present the temp sreads throughout the substance and it will seem to convert to a liquid rapidly at a single temperqature rather than over a couple degrees. C) True. the melting point of the addition is not very important as long as it is a minority component. The presence of impurities in the solid crystaline structure lowers the melting point, salt melts at a much higher temp than water, yet lowers the melting point of water, same principal even though water and salt are both inorganic. if the substance is identical then there is not an effect of an impurity being present and the mp is unchanged. D) true for the same reasons, impurities lower melting point. if enough of substance b was added that it became the solvent, mp of solution could rise but it would be lower than substance b mp. Solution A. True. The addition of impurities interfer with the ability to form crystaline structures and cause liquids to remain until colder temperaturs, much like putting salt on the roadways. B) True. the compounds will demonstrate a fuzzy melting point when impurities are present, when they are not present the temp sreads throughout the substance and it will seem to convert to a liquid rapidly at a single temperqature rather than over a couple degrees. C) True. the melting point of the addition is not very important as long as it is a minority component. The presence of impurities in the solid crystaline structure lowers the melting point, salt melts at a much higher temp than water, yet lowers the melting point of water, same principal even though water and salt are both inorganic. if the substance is identical then there is not an effect of an impurity being present and the mp is unchanged. D) true for the same reasons, impurities lower melting point. if enough of substance b was added that it became the solvent, mp of solution could rise but it would be lower than substance b mp..
A. True. The addition of impurities interfer with.pdf
A. True. The addition of impurities interfer with.pdf
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