Find the general expression for the slope of a line tangent to the curve of y=3x^2+2x at the point P(x,y). Then find the slopes for x=-3 and x=1.5. Sketch the curve and tangent lines. I need mtan,slope for -3, slope for 1.5 and sketch. Solution slope - dy/dx = 6x+2 slope for x=-3 = 6(-3)+2 = -16 and slope for x=1.5 = 6(1.5)+2 = 11.

1. Find the general expression for the slope of a line tangent to the curve of y=3x^2+2x at the point
P(x,y). Then find the slopes for x=-3 and x=1.5. Sketch the curve and tangent lines. I need
mtan,slope for -3, slope for 1.5 and sketch.
Solution
slope - dy/dx = 6x+2
slope for x=-3 = 6(-3)+2 = -16
and slope for x=1.5 = 6(1.5)+2 = 11