The two planes are perpendicular. Find the value of k. P1: x - y + 2z - 5 = 0 P2: 3x - 2y +kz + 1 = 0 Solution Since the planes are perpendicular, it means that the normals of the planes are also perpendicular. This means that the dot product of the normals must vanish. From the first plane, the normal is [(1, -1, 2)] . From the second plane, the normal is [(3, -2, k)] . Since the dot product vanishes, we get: [(1, -1, 2)\\cdot(3, -2, k)=0] [3+2+2k=0] [2k=-5] This means that [k=-5/2] ..