algebra complex number solve z7 =1 Solution According to the fundamental theorem of algebra, the equation z7=1 has 7 roots, called the roots of unity. Only one of them is obvious: z=1. The other six require polar form. First write 1 in polar form: 1 = ePi*in, where n is any integer. Then set z7=ePi*in and take the seventh root: z=ePi*in/7 Now substitute in values for n. You only need the values n=0,1,2,3,4,5, and 6, because the answer will repeat itself for all other n (due to the periodicity of complex exponentials). For n=0, you get the obvious solution, z0=e0=1. For n=1, you get z1=ePi*i/7, which you can write in standard form using Euler\'s identity: z1=cos(Pi/7)+i sin(Pi/7) In this way, you get the seven seventh roots of unity. If you graph them in the complex plane, you will find they all lie equally spaced on the unit circle..

1. algebra complex number
solve z7 =1
Solution
According to the fundamental theorem of algebra, the equation z7=1 has 7 roots, called the roots
of unity. Only one of them is obvious: z=1. The other six require polar form. First write 1 in
polar form:
1 = ePi*in, where n is any integer.
Then set
z7=ePi*in
and take the seventh root:
z=ePi*in/7
Now substitute in values for n. You only need the values n=0,1,2,3,4,5, and 6, because the
answer will repeat itself for all other n (due to the periodicity of complex exponentials).
For n=0, you get the obvious solution,
z0=e0=1.
For n=1, you get
z1=ePi*i/7,
which you can write in standard form using Euler's identity:
z1=cos(Pi/7)+i sin(Pi/7)
In this way, you get the seven seventh roots of unity.
If you graph them in the complex plane, you will find they all lie equally spaced on the unit
circle.