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A jar contains 60 nickels and dimes worth $4.30. How many of each kind of coin are in the jar?
Solution
0.05N + 0.10D = 4.30 and
N + D = 60
So lets solve!
N = 60 -D
So...
0.05(60-D) + 0.10D = 4.30
3 - 0.05D + 0.10D = 4.30
0.05D = 1.30
D = 26
Since we have 26 Dimes, we have 60-26 = 34 nickels

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A jar contains 60 nickels and dimes worth $4.30. How many of each ki.pdf

  • 1. A jar contains 60 nickels and dimes worth $4.30. How many of each kind of coin are in the jar? Solution 0.05N + 0.10D = 4.30 and N + D = 60 So lets solve! N = 60 -D So... 0.05(60-D) + 0.10D = 4.30 3 - 0.05D + 0.10D = 4.30 0.05D = 1.30 D = 26 Since we have 26 Dimes, we have 60-26 = 34 nickels