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A group of college students were surveyed to learn how many times they had visited a dentist in the previous year 12. the probability distribution for Y, the number of the visits, is given by the following table, Y(No. Visits) Probability 0 0.15 1 0.50 2 0.35 Total 1.0 Calculate the mean,, of the number of the visit! Solution To find the mean we will calculate the weighted mean of Y. mean of Y = E(Y) = .15(0) + .50(1) + .35(2) = 1.2.

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A group of college students were surveyed to learn how many times they had visited a dentist in the previous year 12. the probability distribution for Y, the number of the visits, is given by the following table, Y(No. Visits) Probability 0 0.15 1 0.50 2 0.35 Total 1.0 Calculate the mean,, of the number of the visit! Solution To find the mean we will calculate the weighted mean of Y. mean of Y = E(Y) = .15(0) + .50(1) + .35(2) = 1.2

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A group of college students were surveyed to learn how many times th.pdf

  • 1. A group of college students were surveyed to learn how many times they had visited a dentist in the previous year 12. the probability distribution for Y, the number of the visits, is given by the following table, Y(No. Visits) Probability 0 0.15 1 0.50 2 0.35 Total 1.0 Calculate the mean,, of the number of the visit! Solution To find the mean we will calculate the weighted mean of Y. mean of Y = E(Y) = .15(0) + .50(1) + .35(2) = 1.2