This is an educational document providing theory and worked examples related to basic stress and strain analysis for simple structural elements and mechanical systems.
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The peer-reviewed International Journal of Engineering Inventions (IJEI) is started with a mission to encourage contribution to research in Science and Technology. Encourage and motivate researchers in challenging areas of Sciences and Technology.
This Report presents a review of the definition of the equivalent crack concept by defining the relationship between two correlated theories, which are fracture mechanics and damage mechanics based on Mazars static damage model and derived in the framework of the thermodynamics of irreversible processes, an energetic equivalence between the two descriptions is proposed. This paper also presents an example of combined damage and fracture calculation on a concrete specimen, the energy consumption during crack propagation, modelled with damage mechanics, is computed. Finally, the paper provide a comparison for the fracture energy according to the damage model with experiments and linear elastic fracture mechanics
The peer-reviewed International Journal of Engineering Inventions (IJEI) is started with a mission to encourage contribution to research in Science and Technology. Encourage and motivate researchers in challenging areas of Sciences and Technology.
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Tension and Compression in Bars.pdf
1. Oyelade Akintoye.O.
(PhD)
Civil and Environmental Engineering Department,
University of Lagos.
Mechanics of Materials 1
Tension and Compression in Bars
2. Content
01
四个
重要思想
Civil and Environmental Engineering, UNILAG
Direct
Stresses
and
Strains
Hookes’s
Law
Stresses
and
Deformat
ion
(Tempera
ture)
Method
of
superpos
ition
Stress
and
Strain
Transfor
mation
Stresses
on
inclined
planes
Principal
Stresses
(Mohr’s
Circle)
Stresses
in Thin
Cylinders
and
Spheres.
3. Textbooks
02
四个
重要思想
Civil and Environmental Engineering, UNILAG
Mechanics of Materials 1
E. J. Hearn
Engineering Mechanics 2
Mechanics of Materials
Dietmar Gross · Werner Hauger ·Jörg Schröder · Wolfgang A. Wall
Javier Bonet
4. Direct Stresses and Strains
03
四个
重要思想
Introduction
Civil and Environmental Engineering, UNILAG
Static: External and internal forces acting on structures can
be determined with the aid of the equilibrium conditions
alone.
Real physical bodies were approximated by rigid bodies: if
not, deformation is an important component to determine in
practical problems.
The geometry of deformation is given by kinematic
equations; they connect the displacements and the strains.
5. Direct Stresses and Strains
04
四个
重要思想
Civil and Environmental Engineering, UNILAG
In addition to the deformations, the stressing of structural
members is of great practical importance
The stress resultants alone, allow no statement regarding the
load carrying ability of a structure: a slender rod or a stocky
rod: state of stress
The stresses and strains are connected in the Constitutive
equations. These equations describe the behaviour of the
material and can be obtained only from experiments.
Introduction
Assumption: Deformations and strains are very small
6. Direct Stresses and Strains
05
四个
重要思想
Civil and Environmental Engineering, UNILAG
The solution of problems is based on three different types of
equations:
a) equilibrium conditions,
b) kinematic relations and
c) constitutive equations.
In statically determinate system, these equations are
uncoupled.
In statically indeterminate systems, the equilibrium
conditions, the kinematic relations and Hooke’s law
represent a system of coupled equations.
Introduction
7. Direct Stresses and Strains
07
四个
重要思想
Civil and Environmental Engineering, UNILAG
The brain is wider than the sky
Emily Dickinson
8. Direct Stresses and Strains
08
四个
重要思想
Civil and Environmental Engineering, UNILAG
Normal stress and normal force N.
Stress
σ
9. Direct Stresses and Strains
09
四个
重要思想
Civil and Environmental Engineering, UNILAG
In the case of a positive normal force N (tension) the stress
σ is then positive (tensile stress). Reversely, if the normal
force is negative (compression) the stress is also negative
(compressive stress).
Stress
Normal Force:
N
N A
A
F
A
σ σ
σ
= → =
=
10. Direct Stresses and Strains
10
四个
重要思想
Civil and Environmental Engineering, UNILAG
The component τ which acts in the direction of the surface is
called shear stress
Stress
cos
A
A
ϕ
∗
=
Equilibrium of forces:
: cos sin 0,
: sin cos 0
tan
tan 0
A A F
A A
F
A
σ ϕ τ ϕ
σ ϕ τ ϕ
σ τ ϕ
σ ϕ τ
∗ ∗
∗ ∗
→ + − =
↑ − =
+ =
− =
11. Direct Stresses and Strains
11
四个
重要思想
Civil and Environmental Engineering, UNILAG
Solving these two equations for σ and τ yields
Stress
2 2
1 tan
,
1 tan 1 tan
F F
A A
ϕ
σ τ
ϕ ϕ
=
+ +
( )
0 0
1 cos2 , sin 2
2 2
σ σ
σ ϕ τ ϕ
=
+ =
σ0 = F/A ( normal stress in a section perpendicular to the axis)
It is practical to write these equations in a different form. Using
the standard trigonometric relations
( )
2 2
2
1 1 1
cos , cos 1 cos2 , sin cos sin 2
2 2
1 tan
ϕ ϕ ϕ ϕ ϕ ϕ
ϕ
= =
+ =
+
12. Direct Stresses and Strains
12
四个
重要思想
Civil and Environmental Engineering, UNILAG
Stress
The concentrated force produces high stresses near its point of
application . This phenomenon is known as Stress concentration.
The high stresses decay rapidly towards the average value σ0 as we
increase the distance from the end of the bar. This fact is referred to
as Saint-Venant’s principle
13. Direct Stresses and Strains
13
四个
重要思想
Civil and Environmental Engineering, UNILAG
A bar with a constant cross-sectional area which has the
undeformed length l. Under the action of tensile forces it
gets slightly longer. The elongation is denoted by Δl and is
assumed to be much smaller than the original length l. The
ratio between the elongation and the original (undeformed)
length:
Strain
l
l
ε
∇
= 1
l l ε
∇
14. Direct Stresses and Strains
14
四个
重要思想
Civil and Environmental Engineering, UNILAG
Find the strain ?
Strain
( )
du
x
dx
ε =
15. Direct Stresses and Strains
15
四个
重要思想
Civil and Environmental Engineering, UNILAG
If the displacement u(x) is known, the strain ε(x)
can be determined through differentiation.
Reversely, if ε(x) is known, the displacement u(x) is
obtained through integration.
The displacement u(x) and the strain ε(x) describe
the geometry of the deformation.
Strain
( )
du
x
dx
ε = Kinematic
relation
16. Direct Stresses and Strains
16
四个
重要思想
Civil and Environmental Engineering, UNILAG
Stresses are quantities derived from statics; they are
a measure for the stressing in the material of a
structure. On the other hand, strains are kinematic
quantities; they measure the deformation of the
body
Constitutive Law
The physical relation that connects these quantities
is called Constitutive law. It describes the behaviour
of the material of the body under a load.
17. Direct Stresses and Strains
17
四个
重要思想
Civil and Environmental Engineering, UNILAG
Constitutive Law
proportional limit σP
yield stress σY
true stress or
physical stress σt
E
σ ε
=
A material is said to be elastic if it returns to its
original, unloaded dimensions when load is
removed.
18. Direct Stresses and Strains
18
四个
重要思想
Civil and Environmental Engineering, UNILAG
Constitutive Law
The modulus of elasticity E is a constant which
depends on the material and which can be
determined with the aid of a tension test
E
σ ε
=
This relation is valid for tension and for
compression: the modulus of elasticity has the same
value for tension and compression.
The proportionality factor E is called modulus of
elasticity or Young’s. The constitutive law is called
Hooke’s law after Robert Hooke (1635–1703).
19. Direct Stresses and Strains
19
四个
重要思想
Civil and Environmental Engineering, UNILAG
Constitutive Law
E
σ
ε =
Changes of the length and thus strains are not only
caused by forces but also by changes of the
temperature.
T T T
ε α
= ∆
T T
E
σ
ε α
= + ∆ ( )
T T x
E
σ
ε α
= + ∆
( )
T
E T
σ ε α
= − ∆
20. Single Bar under Tension or Compression
19
四个
重要思想
Civil and Environmental Engineering, UNILAG
Three different types of equations to determine
the stresses and the strains in a bar:
• the equilibrium condition,
• the kinematic relation and
• Hooke’s law.
0
N dN n dx N
+ + − =
21. Single Bar under Tension or Compression
20
四个
重要思想
Civil and Environmental Engineering, UNILAG
equilibrium condition
0
dN
n
dx
+ =
du
dx
ε = kinematic relation
Hooke’s law
T T
E
σ
ε α
= + ∆
22. Single Bar under Tension or Compression
21
四个
重要思想
Civil and Environmental Engineering, UNILAG
constitutive law
for the bar
:
T
du N N
T
dx EA A
α σ
= + ∆ =
0
dN
n
dx
+ =
( ) ( )
0 0
0
l l
T
du N
u l u l T dx
dx EA
α
= − =∆ = + ∆
∫ ∫
T
Fl
l Tl
EA
α
∆= + ∆
23. Single Bar under Tension or Compression
22
四个
重要思想
Civil and Environmental Engineering, UNILAG
In a statically determinate system we can always
calculate the normal force N(x) with the aid of the
equilibrium condition. Subsequently, the strain ε(x)
follows from σ = N/A and Hooke’s law ε = σ/E. Finally,
integration yields the displacement u(x) and the
elongation Δl. A change of the temperature causes only
thermal strains (no stresses!) in a statically determinate
system.
24. Single Bar under Tension or Compression
23
四个
重要思想
Civil and Environmental Engineering, UNILAG
In a statically indeterminate problem the normal force
cannot be calculated from the equilibrium condition
alone. In such problems the basic equations
(equilibrium condition, kinematic relation and Hooke´s
law) are a system of coupled equations and have to be
solved simultaneously. A change of the temperature in
general causes additional stresses; they are called
thermal stresses.
25. Single Bar under Tension or Compression
24
四个
重要思想
Civil and Environmental Engineering, UNILAG
T
du N
T
dx EA
α
= + ∆ 0
dN
n
dx
+ =
( )
T
N EA u T
α
′
= − ∆
( )
T
N EA u T n
α
′ ′′ ′
= − ∆ =
−
T
EAu n EA T
α
′′ ′
=
− + ∆
EAu n
′′ = −
26. Single Bar under Tension or Compression
25
四个
重要思想
Civil and Environmental Engineering, UNILAG
( )
( )
N x
x
A
σ =
l x
W W
l
∗ −
= ( ) 1
W x
x
A l
σ
= −
0
1
1
2
l
W x Wl
l dx
EA l EA
∆
= − =
∫
27. Single Bar under Tension or Compression
26
四个
重要思想
Civil and Environmental Engineering, UNILAG
1
1 2
cos 0
,
sin 0 tan sin
s
s
S S F F
S S
F S
α
α α α
+ =
=
− =
− + =
Statically Determinate
Systems of Bars
28. Single Bar under Tension or Compression
27
四个
重要思想
Civil and Environmental Engineering, UNILAG
1 1 2 2
1 2
,
tan sin cos
S l S l
Fl Fl
l l
EA EA EA EA
α α α
∆ = =
− ∆ = =
T
Fl
l Tl
EA
α
∆= + ∆
( )
1
3
2
2
,
tan
1 cos
sin tan sin cos
Fl
u l
EA
Fl
l u
v
EA
α
α
α α α α
=∆ =
+
∆
= + =
30. Single Bar under Tension or Compression
29
四个
重要思想
Civil and Environmental Engineering, UNILAG
A rigid beam (weight W) is mounted on three elastic
bars. Determine the angle of slope of the beam that is
caused by its weight after the structure has been
assembled.
31. Single Bar under Tension or Compression
30
四个
重要思想
Civil and Environmental Engineering, UNILAG
1 2 3
,
4cos 2
W W
S S S
α
=
=
− =
−
3 3
1 1
1 2 3
2
,
2
4 cos
S l
S l Wl Wl
l l l
EA EA EA
EA α
∆ =
∆ = =
− ∆ = =
−
Equilibrium eqn
1
3 , , tan
cos
B A
B A
l v v
v l v
a
β
α
∆ −
=
∆ = =
( )
3
3
cot 2cos 1
, tan ,
cot 4cos
W
l
a
EA
α α
β β β
α α
−
= ≈ =