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BROAD CLASSIFICATION OF STATISTICS
Descriptive Statistics
Measures of Central Tendency
• Mean
• Median
• Mode
DR K.SENTHILKUMAR
ASSISTANT PROFESSOR
GOVERNMENT COLLEGE OF EDUCATION
ORATHANAD, THANJAVUR
TAMILNADU, INDIA.
9445450204
n
f
• Mean
•Median
• Mode = 3( Medain ) – 2(Mean)
Measures of Dispersion
Standard deviation
T – test formula
Inferential Statistics
Chi Square Test
F TEST (ANOVA)
CI X F fx
25 - 29 27 1 27
30 - 34 32 2 64
35 - 39 37 4 148
40 - 44 42 8 336
45 - 49 47 11 517
50 - 54 52 9 468
55 - 59 57 7 399
60 - 64 62 4 248
65 - 69 67 3 201
70 - 74 72 1 72
50 2480 49.6
MEAN
n
f

fx = 2480
N = 50
fx = 2480/50
=49.6
CI X F X' fd
25 - 29 27 1 -4 -4
30 - 34 32 2 -3 -6
35 - 39 37 4 -2 -8
40 - 44 42 8 -1 -8 26
45 - 49 47 11 0 0
50 - 54 52 9 1 9
55 - 59 57 7 2 14
60 - 64 62 4 3 12
65 - 69 67 3 4 12
70 - 74 72 1 5 5 52
26
mean
CI F cf
25 - 29 1 1
30 - 34 2 3
35 - 39 4 7
40 - 44 8 15
45 - 49 11 26
50 - 54 9 35
55 - 59 7 42
60 - 64 4 46
65 - 69 3 49
70 - 74 1 50
MEDAIN
L = 44.5
N/2 = 50/2
= 25
CF = 15
F = 11
I = 5
M = 44.5 +(25 – 15/11) 5
=44.5 +(10/11)5
=44.5 + 50/11
=44.5 + 4.55
=49.05
• Mode = 3( Medain ) – 2(Mean)
=3(49.05) – 2 (49.6)
=148 .5 – 99.2
=49.3
CI X F X'=X - M FX FX'
25 - 29 27 1 -22.6 27 -22.6 22.6
30 - 34 32 2 -17.6 64 -35.2 35.2
35 - 39 37 4 -12.6 148 -50.4 50.4
40 - 44 42 8 -7.6 336 -60.8 60.8
45 - 49 47 11 -2.6 517 -28.6 28.6
50 - 54 52 9 2.4 468 21.6 21.6
55 - 59 57 7 7.4 399 51.8 51.8
60 - 64 62 4 12.4 248 49.6 49.6
65 - 69 67 3 17.4 201 52.2 52.2
70 - 74 72 1 22.4 72 22.4 22.4
395.2
AVERAGE DEVIATION
CI X F X' fx' fx''
25 - 29 27 1 -4 -4 16
30 - 34 32 2 -3 -6 18
35 - 39 37 4 -2 -8 16
40 - 44 42 8 -1 -8 8
45 - 49 47 11 0 0 0
50 - 54 52 9 1 9 9
55 - 59 57 7 2 14 28
60 - 64 62 4 3 12 36
65 - 69 67 3 4 12 48
70 - 74 72 1 5 5 25
26 204
STANDARD DEVIATION
∑fx’’= 204
∑fx = 26
∑f = 50 = 5* 204/50 – 26 *26 /50
= 5*4.08 – 676/2500
= 5*4.08 – 0.270
= 5* 3.81
= 5*1.95
= 9.75
t = test
MEAN S.D
HIGHT 46.675 4.47
FLOWER 32.547 7.64
fo 18 16 8 42/3 =14
fe 14 14 14
fo-fe 4 2 -6
(fo-fe)2 16 4 36
fo-fe/fe 16/14 4/14. 4/36.
1.143 0.286 2.57 3.142
F TEST (ANOVA)
x1 x2 x3 xx1 xx2 xx3
32 29 31 1024 841 961
24 27 38 576 729 1444
41 34 29 1681 1156 841
19 39 42 361 1521 1764
35 18 45 1225 324 2025
46 42 34 2116 1764 1156
28 44 38 784 1936 1444
27 31 31 729 961 961
37 29 34 1369 841 1156
13 21 28 169 441 784
302 314 350 10034 10514 12536
F - ANOVA

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BROAD CLASSIFICATION OF STATISTICS Descriptive Statistics

  • 1. BROAD CLASSIFICATION OF STATISTICS Descriptive Statistics Measures of Central Tendency • Mean • Median • Mode DR K.SENTHILKUMAR ASSISTANT PROFESSOR GOVERNMENT COLLEGE OF EDUCATION ORATHANAD, THANJAVUR TAMILNADU, INDIA. 9445450204
  • 4. T – test formula
  • 7.
  • 8.
  • 9. CI X F fx 25 - 29 27 1 27 30 - 34 32 2 64 35 - 39 37 4 148 40 - 44 42 8 336 45 - 49 47 11 517 50 - 54 52 9 468 55 - 59 57 7 399 60 - 64 62 4 248 65 - 69 67 3 201 70 - 74 72 1 72 50 2480 49.6 MEAN
  • 10. n f  fx = 2480 N = 50 fx = 2480/50 =49.6
  • 11. CI X F X' fd 25 - 29 27 1 -4 -4 30 - 34 32 2 -3 -6 35 - 39 37 4 -2 -8 40 - 44 42 8 -1 -8 26 45 - 49 47 11 0 0 50 - 54 52 9 1 9 55 - 59 57 7 2 14 60 - 64 62 4 3 12 65 - 69 67 3 4 12 70 - 74 72 1 5 5 52 26 mean
  • 12. CI F cf 25 - 29 1 1 30 - 34 2 3 35 - 39 4 7 40 - 44 8 15 45 - 49 11 26 50 - 54 9 35 55 - 59 7 42 60 - 64 4 46 65 - 69 3 49 70 - 74 1 50 MEDAIN
  • 13. L = 44.5 N/2 = 50/2 = 25 CF = 15 F = 11 I = 5 M = 44.5 +(25 – 15/11) 5 =44.5 +(10/11)5 =44.5 + 50/11 =44.5 + 4.55 =49.05
  • 14. • Mode = 3( Medain ) – 2(Mean) =3(49.05) – 2 (49.6) =148 .5 – 99.2 =49.3
  • 15. CI X F X'=X - M FX FX' 25 - 29 27 1 -22.6 27 -22.6 22.6 30 - 34 32 2 -17.6 64 -35.2 35.2 35 - 39 37 4 -12.6 148 -50.4 50.4 40 - 44 42 8 -7.6 336 -60.8 60.8 45 - 49 47 11 -2.6 517 -28.6 28.6 50 - 54 52 9 2.4 468 21.6 21.6 55 - 59 57 7 7.4 399 51.8 51.8 60 - 64 62 4 12.4 248 49.6 49.6 65 - 69 67 3 17.4 201 52.2 52.2 70 - 74 72 1 22.4 72 22.4 22.4 395.2 AVERAGE DEVIATION
  • 16. CI X F X' fx' fx'' 25 - 29 27 1 -4 -4 16 30 - 34 32 2 -3 -6 18 35 - 39 37 4 -2 -8 16 40 - 44 42 8 -1 -8 8 45 - 49 47 11 0 0 0 50 - 54 52 9 1 9 9 55 - 59 57 7 2 14 28 60 - 64 62 4 3 12 36 65 - 69 67 3 4 12 48 70 - 74 72 1 5 5 25 26 204 STANDARD DEVIATION
  • 17. ∑fx’’= 204 ∑fx = 26 ∑f = 50 = 5* 204/50 – 26 *26 /50 = 5*4.08 – 676/2500 = 5*4.08 – 0.270 = 5* 3.81 = 5*1.95 = 9.75
  • 18. t = test MEAN S.D HIGHT 46.675 4.47 FLOWER 32.547 7.64
  • 19.
  • 20. fo 18 16 8 42/3 =14 fe 14 14 14 fo-fe 4 2 -6 (fo-fe)2 16 4 36 fo-fe/fe 16/14 4/14. 4/36. 1.143 0.286 2.57 3.142
  • 22. x1 x2 x3 xx1 xx2 xx3 32 29 31 1024 841 961 24 27 38 576 729 1444 41 34 29 1681 1156 841 19 39 42 361 1521 1764 35 18 45 1225 324 2025 46 42 34 2116 1764 1156 28 44 38 784 1936 1444 27 31 31 729 961 961 37 29 34 1369 841 1156 13 21 28 169 441 784 302 314 350 10034 10514 12536 F - ANOVA