A slideshow of a presentation on data analysis.

1. FLORENCE NIGHTINGALE
• -The lady with the data.
• Team Members:
• Tahsina Moni Tia(19204002)
• Mehnaz Binte Alam(19204009)
• Sadia Afrin Alma(192040011)
• Tanvirul Hoque Toufiq(19204014)
• Md. Saifur Rahman Hridoy(19204017)
• Md. Minhazul Islam Moin(19204020)
• Nilufar Yeasmin Shila(19204022)
• Sumaya Binte Faruque(19204023)
• Sadia Rukaya(19204087)
• Illen Khan Momi(19204094)

2. DATA VISUALIZATION
Tables and diagrams fill the pages of Nightingale’s notes
and records. Hundreds of years before the Adobe
Creative Cloud hit the market and “infographics” were
something we all needed, Nightingale made data
beautiful.
Her most famous design, which we use in varying forms
today, was the “coxcomb.” The coxcomb is similar to a
pie chart, but more intricate. In a pie chart the size of
the ‘slices’ represent a proportion of data, while in a
coxcomb the length, which the slice extends radially
from the center-point, represents the first layer of data.

3. SET-B QUESTION-1

4. 26
51
40
36
26
61
84
65 Q.1(A) Q.1(C)
72 AM= 63.16667 MEDIAN= 58.5
49 GM= 57.11059 MODE= 26
58 HM= 51.69372
52 So, AM>GM>HM Q.1(D)
81 SD= 29.86416
57 MEAN= 63.16667
151 Q.1(B) COV= 47.27835
134 Q3= 76.5
78 D4= 52 Q.1€
39 P80= 81.6 SKEWNESS=1.227448
59 KURTOSIS 1.867184
26
84
41
33
71
93
72
66
104
34
52

6. Year Bright SunshineCloud Coverage SCATTER DIAGRAM:
1996 4.5 5.4
1997 5.6 5.8
1998 6.8 5.5
1999 5 6.1
2000 4.6 6.1
2001 3.5 6.5
2002 2.5 6.7
2003 2.1 6.6
2004 2.9 6.1
2005 3.2 5.3
2006 2.1 6.6
2007 4.7 6.3
2008 4.2 6.4
2009 5.6 5.8
2010 3.4 6.4
2011 3.5 6.3
2012 2.9 6.2
2013 4.8 5.7
Pairwise Correlation(BRIGHT SUNSHINE,CLOUD COVERAGE)= -0.61469 COMMENT:Moderate degree of negative.
Pairwise Correlation(CLOUD COVERAGE,BRIGHT SUNSHINE)= -0.61469 COMMENT:Moderate degree of negative.
Pairwise Correlation(YEAR,BRIGHT SUNSHINE)= -0.29756 COMMENT:Moderate degree of negative.
Pairwise Correlation(YEAR,CLOUD COVERAGE)= 0.239199 COMMENT:Moderate degree of Positive.
Coefficient of Determination,R^2= 0.37784 COMMENT: 37% of Cloud Coverage can be explained by the variable of the B.S.
SUMMARY OUTPUT
Regression Statistics
Multiple R 0.614687
R Square 0.37784
Adjusted R Square0.338955
Standard Error0.348312
Observations 18
ANOVA
df SS MS F Significance F
Regression 1 1.178862 1.178862 9.716876 0.006636
Residual 16 1.941138 0.121321
Total 17 3.12
CoefficientsStandard Error t Stat P-value Lower 95%Upper 95% Lower 95.0% Upper 95.0%
Intercept 6.903566 0.270543 25.51746 2.17E-14 6.330041 7.477092 6.330041272 7.477092
X Variable 1 -0.20117 0.064536 -3.11719 0.006636 -0.33798 -0.06436 -0.337981243 -0.06436
Estimation Of cloud coverage for the bright sunshine with 6 hours/day:
Bright Sunshine= 6
CLOUD COVERAGE= 5.697
Estimation of Regression line:
Now, The Regression line is Y=6.903-0.201X
0
1
2
3
4
5
6
7
8
0 1 2 3 4 5 6 7 8
Scatter Diagram

8. Matr A= 1 1 1 -1 1 Mat X= X1 Mat C= 7
1 -1 1 -1 1 X2 3
1 1 -1 -1 1 X3 1
1 1 -1 -1 -1 X4 -9
1 1 1 1 -1 X5 5
so, Mat X= (A)^-1 * C (A)^-1= -0.5 0.5 0.5 0 0.5 (A)^-1*C= 1
0.5 -0.5 0 0 0 2
0.5 0 -0.5 0 0 3
-0.5 0 0.5 -0.5 0.5 4
0 0 0.5 -0.5 0 5
X1 1
X2 2
so= X3 = 3
X4 4
X5 5

10. X Y Trapezoidalrulesimpson's(1/3) simpson's(3/8)
X0 0 Y0 0.3989 0.3989 0.3989 0.3989
X1 0.3267 Y1 0.3782 0.7564 1.5128 1.1346
X2 0.6534 Y2 0.3222 0.6444 0.6444 0.9666
X3 0.9801 Y3 0.2467 0.4934 0.9868 0.4934
X4 1.3068 Y4 0.1698 0.3396 0.3396 0.5094
X5 1.6335 Y5 0.105 0.21 0.42 0.315
X6 1.9602 Y6 0.0584 0.0584 0.0584 0.0584
sum= 2.9011 4.3609 3.8763
result= 0.94778937 0.94980402 0.949790408
error= 0.232697895 0.020629474 0.022062368
h= 0.3267
acturalvalue= 0.95

11. DATE AQI
1 53
2 54
3 72
4 80
5 80
6 127
7 80
8 52
9 46
10 70
11 110
12 138
13 92
14 98
15 131
16 121
17 106
18 74
19 59
20 99
21 97
22 71
23 75
24 101
25 151
26 156
27 167
28 107
29 42
30 90
53 54
72
80 80
127
80
52
46
70
110
138
92
98
131
121
106
74
59
99 97
71 75
101
151
156
167
107
42
90
0
20
40
60
80
100
120
140
160
180
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
Line Diagram

12. Mat A= Mat B=
2 1 2 1 1 2 1 4 3 1
3 1 2 2 3 3 1 2 0 2
4 2 3 4 2 1 5 0 2 1
2 3 1 2 1 1 1 2 0 1
1 2 2 0
2 0 1 1
Mat(B*A)
28 14 20 23 20 18
12 9 8 9 9 10
20 12 17 15 10 13
10 6 7 7 8 9
16 7 12 13 11 10
10 7 8 8 5 6
Mat(A*B) 19 14 14 9
25 24 22 12
29 32 23 16
15 20 11 12
If AB is a non singular matrix then the determinant value of this matrix will not be 0
I AB I = -1348
(AB)^-1 = 0.225519 -0.34718 0.302671 -0.22552
-0.13947 -0.11424 0.247033 -0.11053
-0.1543 0.448071 -0.36499 0.154303
0.091988 0.21365 -0.45549 0.408012

22. THANK YOU