Boyle's Low and Charl's low

1. 2/21/2019 Gas Law's - Priyam Study Centre
https://www.priyamstudycentre.com/2018/07/properties-of-gases.html 1/4
     
a page about chemistry and related topics.
Monetize your site
With ads you can count on
468
x60
PHYSICAL CHEMISTRY, PROPERTIES OF GASES
Boyle’s Law:
At constant temperature, the volume of a definite mass of a gas is inversely proportional to its pressure.
That is, the volume of a given quantity of gas, at a constant temperature decrees with the increasing of
pressure and increases with the decreasing pressure.
Let, a Cylinder contain 10 ml of gas, at constant temperature and 1 atm pressure. if the pressure increases
to 2 atm then the volume also decrees to 5 ml.
Mathematical Representation of Boyle's Low:
V ∝ 1/P
∴ PV = K
Where, K is a constant whose value depends upon the,
a. Nature of the Gas. b. Mass of the Gas.
For a given mass of a gas at constant temperature,
P1V1 = P2V2
Where, V1 and V2 are the volume at P1 and P2 are the pressure respectively.
Graphical Representation of Boyle's Low:
The relation between pressure and volume can be represented by an arm of rectangular hyperbola given
below.
As the value of the constant in equation will change with temperature, there will be a separate curve for
each fixed temperature. These curves plotted at different fixed temperature are called isotherms.
At Constant temperature a given mass of gas the product of Pressure and Volume is always same. if the
product of pressure and volume represents in Y axis and Pressure represents X axis a straight line curve is
obtained with parallel to X axis.
This Graph is shows that, at constant temperature the product of pressure and volume is does not depends
on its pressure.
Relation between Pressure and density of a gas:
At constant temperature(T) a definite mass of gas has pressure P1 at volume V1 and pressure P2 at volume
V2.
According to Boyle’s Law,
Gas Law's
Find & compare materials
Find and compare metals, polymers, ceramics, and
composites with Matmatch.
OPEN
758
x90
Graphical Representation of Boyle's Low
Find & compare
materials
320
x50
300
x250
Sea
SEARCH THIS BLOG
Critical Constants of a Gas
Formulation of Kinetic Gas Equation
Van der Waals Equation
Slater's Rules
Rydberg Equation
POPULAR POSTS
LABELS
ACIDS AND BASES
CHEMICAL EQULIBRIUM
DIPOLE MOMENT
INORGANIC CHEMISTRY
ORGANIC CHEMISTRY
OXIDATION REDUCTION REACTION
PHYSICAL CHEMISTRY
PROPERTIES OF ATOMS OR MOLECULES
PROPERTIES OF GASES
RADIOACTIVITY
STRUCTURE OF ATOM
UNSATURATED HYDROCARBON
HOME | LABELS | QUESTIONS AND ANSWER | APPENDIX | CONTACT | ABOUT

2. 2/21/2019 Gas Law's - Priyam Study Centre
https://www.priyamstudycentre.com/2018/07/properties-of-gases.html 2/4
P₁ V1 = P2 V2
or, P1/P2 = V2/V1
Again, Let the mass of the Gas = M
Density D1 at Pressure P1
and Density D2 at Pressure P2
Thus, D1 = M/V1 and D2 = M/V2
or, V1 = M/D1 and V2 = M/D2
Again, P1/P2 = (M/D2) × (D1/M)
= D1/D2
P1/P2 = D1/D2
P/D = Constant(K)
P = K × D
P ∝ D
Thus, at constant temperature density of a definite mass of a gas is Proportional to its Pressure.
At constant pressure a definite mass of gas, with the increasing of temperature, volume also increases and
with decreasing temperature, volume also decreases.
That is, the volume of a given mass of gas at constant pressure is directly proportional to its Kelvin
temperature.
Charl’s Law:
At constant pressure, each degree rise in temperature of a definite mass of a gas, the volume of the gas
expands 1/273.5 of its volume at 00C.
Mathematical Representation of Charl's Low:
If V0 is the volume of the gas at 00C, then 10C rise of temperature the volume of the gas rise V0/273.5
ml.
∴ 10C temperature the volume of the gas,
(V0 + V0/273) ml
= V0 (1 + 1/273) ml.
At t0C temperature the volume of the gas,
Vt = V0 (1+ t/273) ml
= V0 (273 + t°C)/273 ml.
It is convenient to use of the absolute temperature scale on which temperature is measured Kelvin(K). A
reading on this scale is obtained by adding 273 to the Celsius scale value.
Temperature on Kelvin scale is,
T K = 273+t°C
∴ Vt = (V0 × T)/273 = (V0/273) T
Since V0, the volume of a gas at 0°C, has a constant value at a given pressure, the above relation expressed
as,
Vt = K₂₂ T
∴ V ∝ T
Where K2 is constant whose value depends on the, Nature, mass and pressure of the gases.
According to the above relation Charl’s Law states as,
At constant pressure the volume of a given mass of gas is directly proportional to its Kelvin
temperature.
Graphical Representation of Charl's Low:
A typical variation of Volume of a gas with change in its kelvin temperature a straight line plot was
obtained, Called isobars.
Relation between Volume and Temperature of a Gas:
Enter your email address to subscribe to this bl
and receive noti ications of new posts by email
FOLLOW BY EMAIL
Email address...
SUBMIT

FOLLOW US
     
300
x600

3. 2/21/2019 Gas Law's - Priyam Study Centre
https://www.priyamstudycentre.com/2018/07/properties-of-gases.html 3/4
The general term isobar, which means at constant pressure, is assigned to these plots.
Absolute Temperature or Absolute Zero:
Since volume is directly proportional to its Kelvin temperature, the volume of the gas is theoretically zero
at zero Kelvin or - 2730C.
However this is indeed hypothetical because all gases liquefies and then solidity before this low
temperature reached. In fact, no substance exists as a gas at the temperature near Kelvin zero, through the
straight line plots can be extra plotted to zero volume.
The temperature corresponds to zero volume is -2730C.
Relation between temperature and Density of a given gas at constant Pressure:
From the Charl’s Law,
V1/V2 = T1/T2
Again, the mass of the gas is M.
Density D1 and D2 at the Volume V1 and V₂₂ respectively.
Then, V1 = M/D1 and V2 = M/D2
Thus, (M/D1 )/(M/D2 ) = T1/T2
or, D₂/D1 = T1/T2
∴ D ∝ 1/T
Thus at constant pressure, density of a given mass of gases is inversely proportional to its temperature.
Combination of Boyle’s and Charl’s Law:
From Charl's Law,
V ∝ 1/P When T Constant.
From Charl's Law,
V ∝ T When P Constant.
When all the variables taken into account the variation rule states as,
Then, V ∝ T/P
PV/T = K(Constant)
∴ (P1V1)/T1 = (P2V2)/T2 = Constant
PV = KT
Thus the product of the pressure and volume of a given mass of gas is proportional to its Kelvin
temperature.
Problem:
At 1 atm pressure and 300 K temperature, the volume of the gas is 2000 cm3, then calculate the volume
of this gas at 600 K temperature and 2 atm pressure.
Answer:
From the Combination of Boyle's and Charl's Law is,
(P1V1)/T1 = (P2V2)/T2
Here, P1 = 1 atm; V1 = 2000 cm3 and T1 = 300K and P2 = 2 atm; V2= ? and T2 = 600 K.
∴ 1×2000/300 = 2×V₂/600
or, V2 = (1×2000×600)/(300×2)
= 2000 cm3
Graphical Representation of Charl's Low.

4. 2/21/2019 Gas Law's - Priyam Study Centre
https://www.priyamstudycentre.com/2018/07/properties-of-gases.html 4/4
Created By SoraTemplates | Designed By Priyam Study Centre
OLDER ARTICLE 
Comparison Between Ideal And Real Gases
Related Posts :
Critical Constants of Gases
Van der Waals Equation
Ideal and Real Gases
Comparison between Ideal and Real Gases
Ideal Gas Equation
SPONSORED SEARCHES
Compare Energy Pressure Measurement
Density Measurement Temperature Thermometer
Labels PHYSICAL CHEMISTRY PROPERTIES OF GASES     Save
See Also:
Inorganic Chemistry Questions and Answers
Organic Chemistry Questions and Answers
Physical Chemistry Questions and Answers
Privacy Policy for www.priyamstudycentre.com
If you require any more information or have any
questions about our privacy policy, please feel free to
contact us by email at pandakajal42@gmail.com.
Read More
PRIVACY POLICY
In this Blog the style of presentation and arrangeme
of different topic of Chemistry.
During the last few years, the board students in
Chemistry of the
Read More
ABOUT
     