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cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
18/19 CLASS 3
cperez.eps@ceu.es
molina.eps@ceu.es
BOURDEAUX HOUSE. OMA 1998
STATICALLY inDETERMINATE BEAMS AND FRAMES
COMPATIBILITY METHOD
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
18/19 CLASS 3
TEST 1:
STATICALLY DETERMINATE SYSTEM
STATICALLY INDETERMINATE STRUCTURES
COMPATIBILITY METHOD
ASSIGNMENT 2 year 17/18
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
18/19 CLASS 3
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
18/19 CLASS 3
IS THIS A STATICALLY DETERMINATE SYSTEM?
WHAT HAPPENS IF WE REMOVE THE CABLE AF?
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
18/19 CLASS 3
WHICH LOADS AFFECT THE CABLE AXIAL FORCE?
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
18/19 CLASS 3
WHICH PART OF THE SYSTEM IS AFFECTED BY THE DISTRIBUTED LOAD q?
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
18/19 CLASS 3
REMEMBER:
THE LOAD FOLLOWS THE SHORTEST WAY
TO REACH THE GROUND
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
18/19 CLASS 3
CABLE AXIAL FORCE?
Equilibrium equation:
MG = 0
- P x 6a + P x 4 a + N x 2a = 0
N = P
Gy = 3P
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
18/19 CLASS 3
WHICH BARS ARE NOT GOING TO WORK?
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
18/19 CLASS 3
BARS AXIAL FORCES? (JOINTS EQUILIBRIUM)
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
18/19 CLASS 3
WHAT HAPPENS IN THIS KIND OF FOUNDATIONS?
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
18/19 CLASS 3
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
18/19 CLASS 3
STRUCTURAL ANALYSIS I
2017/2018 CLASS 3
DO THESE RESLTS MAKE SENSE?
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
18/19 CLASS 3
+
CAN WE APPLY THE SUPERPOSITION PRINCIPLE?
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
18/19 CLASS 3
WHICH DISPLACEMENTS CAN WE CALCULATE MORE EASILY?
WHY ARE THESE TWO DIAGRAMS USEFUL
TO COMPUTE THE DISPLACEMENTS?
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
18/19 CLASS 3
VERTICAL DISPLACEMENT AT F
ONLY THE CABLE AXIAL FORCE AFFECTS IT
vF = N x L / EA
vF = 3P x 6a / 65971,5
F goes up
vF varies from 1,81 mm to 3,8 mm
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
18/19 CLASS 3HORIZONTAL DISPLACEMENT AT G
ONLY THE COLUMN BG BENDING MOMENT AFFECTS IT
uG = 4,5qa x (6a + 4 x 4,5a + 3a)/(6x 52857) x 3a
uG varies between 11,49 and 55,37 mm
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
18/19 CLASS 3HORIZONTAL DISPLACEMENT AT D
ONLY THE COLUMN BG BENDING MOMENT AFFECTS IT
uD = 4,5qa2 x (3a + 4 x 1,5a + 0)/(6x 52857) x 3a
uD varies between 3,83 and 18,46 mm
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
18/19 CLASS 3VERTICAL DISPLACEMENT AT D
THE COLUMN BG AND THE BEAM CD BENDING MOMENTS AFFECTS IT
vD = 3qa2 + 4 x 3a + 3a)/(6x 52857) x 3a +
(4,5qa2 x 3a + 4 x 1,125qa2 x 1,5a + 0)/(6x11970) x 3a
vD varies between -16,1 and -77,7 mm
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
18/19 CLASS 3VERTICAL DISPLACEMENT AT J
THE TRUSS AND THE CABLE AXIAL FORCE AFFECT IT
vJ = S (N* x N x L / EA)for each bar + P x (-3) /65951
vJ varies between -12,21 and -25,67 mm
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
18/19 CLASS 3VERTICAL DISPLACEMENT AT I
THE TRUSS AND THE CABLE AXIAL FORCE AFFECT IT
vJ = S (N* x N x L / EA)for each bar + P x (+2) /65951
vJ varies between 4,81 and 10,11 mm
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
18/19 CLASS 3
REMEMBER!
IN BEAMS A COLUMNS WE ONLY CONSIDER MOVEMENTS
PRODUCED BY BENDING MOMENTS. WE NEGLECT SHEAR
FORCE AND AXIAL FORCE DEFORMATIONS. WE ASSUME BARS
ARE INEXTENSIBLE
UNLESS CABLES OR TRUSSES ARE INVOLVED
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
18/19 CLASS 3
2.- STATICALLY INDETERMINATE BEAMS. COMPATIBILITY METHOD.
WHAT HAPPENS WHEN THE BEAM IS STATICALLY INDETERMINATE?
EQUILIBRIUM EQUATIONS ARE NOT ENOUGH TO SOLVE IT
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
18/19 CLASS 3
WE CAN CONSIDER THE SYSTEM AS AN ADDITION OF TWO STATICALLY DETERMINATE ONES!
DIVIDE TO WIN!!!!
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
18/19 CLASS 3
STRUCTURAL ANALYSIS I
2017/2018 CLASS 3
cperez.eps@ceu.es
federico.prietomunoz@ceu.es
DIVIDE TO WIN!!!!
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
18/19 CLASS 3
WE NEED TO KNOW THE BEAM CROSS SECTION TO CALCULATE THE REACTION FORCES…
IN STATICALLY INDETERMINATE SYSTEMS THE RESULT IS DIFFERENT DEPENDING ON THE
CROSS SECTION DIMENSIONS…
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
18/19 CLASS 3
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
18/19 CLASS 3
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
18/19 CLASS 3
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
18/19 CLASS 3
cperez.eps@ceu.es
federico.prietomunoz@ceu.es
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
18/19 CLASS 3
2.- STATICALLY INDETERMINATE BEAMS. COMPATIBILITY METHOD.
THINK IN AHOTHER WAY TO SOLVE IT! AND OF COURSE GET THE SAME RESULTS….
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
18/19 CLASS 3
ANALYZE THE DIFFERENCES
VERTICAL REACTION FORCES?
HORIZONTAL REACTION FORCES?
DISPLACEMENTS?
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
18/19 CLASS 3
cperez.eps@ceu.es
molina.eps@ceu.es
BOURDEAUX HOUSE. OMA 1998
ASSIGNMENT 2 year 18/19

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