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cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
cperez.eps@ceu.es
molina.eps@ceu.es
STATICALLY inDETERMINATE SYSTEMS. Complex geometry
DIRECT STIFFNESS METHOD
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
cperez.eps@ceu.es
molina.eps@ceu.es
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
PREVIOUSLY ON AE1
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
1.- DIRECT STIFFNESS METHOD (matrix formulation)
GENERAL METHOD (computers use it)
AUTOMATED PROCESS
WE DO NOT HAVE TO THINK
MANY NUMBERS SO WE HAVE TO BE
VERY CAREFUL ORGANIZING THE
INFORMATION
WE DO NOT NEGLECT AXIAL EFFECT: BARS GET LONGER AND SHORTER
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
First example. DIRECT STIFFNESS METHOD
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
[K] x [∆] = [F]
GLOBAL
STIFFNESS
MATRIX
MOVEMENTS
MATRIX
FORCES
MATRIX
KEY MATRIX EQUATION
Frame
geometry
all the frame information will be included in it
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
MOVEMENTS MATRIX (always 3 numbers per joint in 2D frames)
uA
D A
vA
gA
uC
D C
vC
gC
[D] = uD
D D
vD
gD
uB
D B
vB
gB
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
MOVEMENTS MATRIX (always 3 numbers per joint in 2D frames)
uA
D A
vA
gA
uC
D C
vC
gC
[D] = uD
D D
vD
gD
uB
D B
vB
gB
In this example which of these elements are ZERO?
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
FORCES MATRIX
(made up as the addition of 3 elements or 3 submatrices)
[F] = [-fe] + [P] + [R]
Fixed end forces and
moments (effect of
the load applied
along the bars)
Reaction
forces
Punctual loads
applied at the
joints
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
FIXED END FORCES
SUBMATRIX
[-fe] only external load along the
bar in the beam CD
0 0
[-fe]C
-qL/2 -30
-qL^2/12 -30
[-fe]CD
= 0 = 0
[-fe]D
-qL/2 -30
qL^2/12 30
SINGLE FIXED END FORCES AND MOMENTS MATRIX
For every bar we should compute the effect of the loads applied along
the bars in the bars ends: forces and moments
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
FIXED END FORCES
SUBMATRIX
[-fe] only external load along the
bar in the beam CD
0 0
[-fe]C
-qL/2 -30
-qL^2/12 -30
[-fe]CD
= 0 = 0
[-fe]D
-qL/2 -30
qL^2/12 30
[-fe] AC = 0
[-fe] DB = 0
SINGLE FIXED END FORCES AND MOMENTS MATRIX
For every bar we should compute the effect of the loads applied along
the bars in the bars ends: forces and moments
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
STRUCTURAL ANALYSIS I
2016/2017 CLASS 6
FORCES MATRIX
(the assembled force matrix
has 3 numbers per joint, same
as movements matrix)
[-fe] [R] [P]
0 RxA 0 RxA
A
0 RyA 0 RyA
0 MA 0 MA
0 0 4 4
C
-30 0 0 -30
-30 0 0 -45
[F] = 0 + 0 + 0 = 0
D
-30 0 0 -30
30 0 0 45
0 RxB 0 RxB
B
0 RyB 0 RyB
0 MB 0 MB
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
GLOBAL (or master) STIFFNESS MATRIX
[𝐾]𝐴𝐴 [𝐾]𝐴𝐶 [𝐾]𝐴𝐷 [𝐾]𝐴𝐵
[𝐾]𝐶𝐴 [𝐾]𝐶𝐶 [𝐾]𝐶𝐷 [𝐾]𝐶𝐵
[𝐾]𝐷𝐴 [𝐾]𝐷𝐶 [𝐾]𝐷𝐷 [𝐾]𝐷𝐵
[𝐾]𝐵𝐴 [𝐾]𝐵𝐶 [𝐾]𝐵𝐷 [𝐾]𝐵𝐵
𝑥
[𝜕𝐴]
[𝜕𝐶]
[𝜕𝐷]
[𝜕𝐵]
=
[𝐹𝐴]
[𝐹𝐶]
[𝐹𝐷]
[𝐹𝐵]
12 submatrices
Each submatrix 9 elements
[K] x [∆] = [F]
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
GLOBAL (or master) STIFFNESS MATRIX
[𝐾]𝐴𝐴 [𝐾]𝐴𝐶 [𝐾]𝐴𝐷 [𝐾]𝐴𝐵
[𝐾]𝐶𝐴 [𝐾]𝐶𝐶 [𝐾]𝐶𝐷 [𝐾]𝐶𝐵
[𝐾]𝐷𝐴 [𝐾]𝐷𝐶 [𝐾]𝐷𝐷 [𝐾]𝐷𝐵
[𝐾]𝐵𝐴 [𝐾]𝐵𝐶 [𝐾]𝐵𝐷 [𝐾]𝐵𝐵
𝑥
[𝜕𝐴]
[𝜕𝐶]
[𝜕𝐷]
[𝜕𝐵]
=
[𝐹𝐴]
[𝐹𝐶]
[𝐹𝐷]
[𝐹𝐵]
[K]AA links movements at A with forces at A
[K]AC links movements at C with forces at A
[K]AD links movements at D with forces at A
[K]AB links movements at B with forces at A
[K]CA links movements at A with forces at C
[K]CC links movements at C with forces at C
[K]CD links movements at D with forces at C
[………………………………………………..
[K] x [∆] = [F]
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
SINGLE BAR STIFFNESS MATRIX
How many single bar stifnees matrices do you have to consider in this frame?
How many numbers does it contain?...
[k] x [∂] = [f]
BAR
STIFFNESS
MATRIX
BAR
MOVEMENTS
MATRIX
BAR
FORCES
MATRIX
bar
geometry
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
We can write down 3 bar stiffness matrices
because we have 3 bars
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
every single stiffness matrix have 36 element
organized in 4 submatrices
𝐸𝐴
𝐿
0 0
−𝐸𝐴
𝐿
0 0
0
12𝐸𝐼
𝐿3
6𝐸𝐼
𝐿2 0
−12𝐸𝐼
𝐿3
6𝐸𝐼
𝐿2
0
6𝐸𝐼
𝐿2
4𝐸𝐼
𝐿
0
−6𝐸𝐼
𝐿2
2𝐸𝐼
𝐿
−𝐸𝐴
𝐿
0 0
𝐸𝐴
𝐿
0 0
0
−12𝐸𝐼
𝐿3
−6𝐸𝐼
𝐿2 0
12𝐸𝐼
𝐿3
−6𝐸𝐼
𝐿2
0
6𝐸𝐼
𝐿2
2𝐸𝐼
𝐿
0
−6𝐸𝐼
𝐿2
4𝐸𝐼
𝐿
𝑥
𝑢1
𝑣1
𝜃1
𝑢2
𝑣2
𝜃2
=
𝑁1
𝑉1
𝑀1
𝑁2
𝑉2
𝑀2
1 2
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
When the bar is horizontal and we consider the first joint in the
left and the second in the right, the bar local coordinate system is
the same as the global coordinate system
𝐸𝐴
𝐿
0 0
−𝐸𝐴
𝐿
0 0
0
12𝐸𝐼
𝐿3
6𝐸𝐼
𝐿2 0
−12𝐸𝐼
𝐿3
6𝐸𝐼
𝐿2
0
6𝐸𝐼
𝐿2
4𝐸𝐼
𝐿
0
−6𝐸𝐼
𝐿2
2𝐸𝐼
𝐿
−𝐸𝐴
𝐿
0 0
𝐸𝐴
𝐿
0 0
0
−12𝐸𝐼
𝐿3
−6𝐸𝐼
𝐿2 0
12𝐸𝐼
𝐿3
−6𝐸𝐼
𝐿2
0
6𝐸𝐼
𝐿2
2𝐸𝐼
𝐿
0
−6𝐸𝐼
𝐿2
4𝐸𝐼
𝐿
𝑥
𝑢1
𝑣1
𝜃1
𝑢2
𝑣2
𝜃2
=
𝑁1
𝑉1
𝑀1
𝑁2
𝑉2
𝑀2
1 2
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
When the bar is NOT horizontal the bar local coordinate system is
NOT the same as the global coordinate system
1
2
90º
270º
2
1
1
1
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
TRANSFORMATION MATRIX
𝑇 =
𝑐𝑜𝑠 𝛼 𝑠𝑒𝑛 𝛼 0 0 0 0
−𝑠𝑒𝑛 𝛼 cos 𝛼 0 0 0 0
0 0 1 0 0 0
0 0 0 cos 𝛼 𝑠𝑒𝑛 𝛼 0
0 0 0 −𝑠𝑒𝑛 𝛼 cos 𝛼 0
0 0 0 0 0 1
THE ANGLE IS THE KEY!
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
𝑘11 𝑘12 𝑘13 −𝑘11 −𝑘12 𝑘13
𝑘12 𝑘22 𝑘23 −𝑘12 −𝑘22 𝑘23
𝑘13 𝑘23 𝑘33 −𝑘13 −𝑘23 𝑘36
−𝑘11 −𝑘12 −𝑘13 𝑘11 𝑘12 −𝑘13
−𝑘12 −𝑘22 −𝑘23 𝑘12 𝑘22 −𝑘23
𝑘13 𝑘23 𝑘36 −𝑘13 −𝑘23 𝑘33
𝑥
𝑢1
𝑣1
𝜃1
𝑢2
𝑣2
𝜃2
=
𝑓𝑥1
𝑓𝑦1
𝑀1
𝑓𝑥2
𝑓𝑦2
𝑀2
[k]coordenadas globales x [∂]globales = [f]globales
k11 = EA cos2 α / L + 12 EI sen2 α /L3
k12 = (EA/L - 12 EI /L3 ) x sen α x cos α
k13 = - 6EI sen α /L2
k22 = EA sen2 α / L + 12 EI cos2 α /L3
k23 = 6 EI cos α /L2
k33 = 4EI /L
k36 = 2EI /L
SINGLE BAR MATRIX
IN GLOBAL COORDINATES
THE ANGLE IS THE KEY!
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
[kAA]barra AC [kAC]barra AC
6000 0 -9000 -6000 0 -9000
0 600000 0 0 -600000 0
-9000 0 18000 9000 0 9000
-6000 0 9000 6000 0 9000
0 -600000 0 0 600000 0
-9000 0 9000 9000 0 18000
[kCA]barra AC [kCC]barra AC
[k]AC
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
[kCC]barra CD [kCD]barra CD
300000 0 0 -300000 0 0
0 750 2250 0 -750 2250
0 2250 9000 0 -2250 4500
-300000 0 0 300000 0 0
0 -750 -2250 0 750 -2250
0 2250 4500 0 -2250 9000
[kDC]barra CD [kDD]barra CD
[k]CD
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
[kDD]barra DB [kDB]barra DB
6000 0 9000 -6000 0 9000
0 600000 0 0 -600000 0
9000 0 18000 -9000 0 9000
-6000 0 -9000 6000 0 -9000
0 -600000 0 0 600000 0
9000 0 9000 -9000 0 18000
[kBD]barra DB [kBB]barra DB
[k]BD
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
[𝐾]𝐴𝐴 [𝐾]𝐴𝐶 [𝐾]𝐴𝐷 [𝐾]𝐴𝐵
[𝐾]𝐶𝐴 [𝐾]𝐶𝐶 [𝐾]𝐶𝐷 [𝐾]𝐶𝐵
[𝐾]𝐷𝐴 [𝐾]𝐷𝐶 [𝐾]𝐷𝐷 [𝐾]𝐷𝐵
[𝐾]𝐵𝐴 [𝐾]𝐵𝐶 [𝐾]𝐵𝐷 [𝐾]𝐵𝐵
GLOBAL STIFFNESS MATRIX [K] // ASSEMBLE MATRIX
WHICH SUBMATRICES ARE ZERO?
WHICH SUBMATRICES ARE THE ADDITION OF TWO?
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
GLOBAL STIFFNESS MATRIX [K] // ASSEMBLE MATRIX
6000 0 -9000 -6000 0 -9000 0 0 0 0 0 0
0 600000 0 0 -600000 0 0 0 0 0 0 0
-9000 0 18000 9000 0 9000 0 0 0 0 0 0
-6000 0 9000 306000 0 9000 -300000 0 0 0 0 0
0 -600000 0 0 600750 2250 0 -750 2250 0 0 0
-9000 0 9000 9000 2250 27000 0 -2250 4500 0 0 0
0 0 0 -300000 0 0 306000 0 9000 -6000 0 9000
0 0 0 0 -750 -2250 0 600750 -2250 0 -600000 0
0 0 0 0 2250 4500 9000 -2250 27000 -9000 0 9000
0 0 0 0 0 0 -6000 0 -9000 6000 0 -9000
0 0 0 0 0 0 0 -600000 0 0 600000 0
0 0 0 0 0 0 9000 0 9000 -9000 0 18000
[K]GLOBAL
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
GLOBAL STIFFNESS MATRIX [K] // ASSEMBLE MATRIX
6000 0 -9000 -6000 0 -9000 0 0 0 0 0 0
0 600000 0 0 -600000 0 0 0 0 0 0 0
-9000 0 18000 9000 0 9000 0 0 0 0 0 0
-6000 0 9000 306000 0 9000 -300000 0 0 0 0 0
0 -600000 0 0 600750 2250 0 -750 2250 0 0 0
-9000 0 9000 9000 2250 27000 0 -2250 4500 0 0 0
0 0 0 -300000 0 0 306000 0 9000 -6000 0 9000
0 0 0 0 -750 -2250 0 600750 -2250 0 -600000 0
0 0 0 0 2250 4500 9000 -2250 27000 -9000 0 9000
0 0 0 0 0 0 -6000 0 -9000 6000 0 -9000
0 0 0 0 0 0 0 -600000 0 0 600000 0
0 0 0 0 0 0 9000 0 9000 -9000 0 18000
[K]GLOBAL
AA AC AD AB
CA CC CD CB
DA
BA
DC DD DB
BC BD BB
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
GLOBAL STIFFNESS MATRIX EQUATION
6000 0 -9000 -6000 0 -9000 0 0 0 0 0 0 0 RxA
0 600000 0 0 -600000 0 0 0 0 0 0 0 0 RyA
-9000 0 18000 9000 0 9000 0 0 0 0 0 0 0 MA
-6000 0 9000 306000 0 9000 -300000 0 0 0 0 0 uC 4
0 -600000 0 0 600750 2250 0 -750 2250 0 0 0 vC -30
-9000 0 9000 9000 2250 27000 0 -2250 4500 0 0 0 qC -30
0 0 0 -300000 0 0 306000 0 9000 -6000 0 9000 x uD = 0
0 0 0 0 -750 -2250 0 600750 -2250 0 -600000 0 vD -30
0 0 0 0 2250 4500 9000 -2250 27000 -9000 0 9000 qD 30
0 0 0 0 0 0 -6000 0 -9000 6000 0 -9000 0 RxB
0 0 0 0 0 0 0 -600000 0 0 600000 0 0 RyB
0 0 0 0 0 0 9000 0 9000 -9000 0 18000 0 MB
[K] x [∆] = [F]
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
STRUCTURAL ANALYSIS I
2017/2018 CLASS 7
GLOBAL STIFFNESS MATRIX EQUATION
6000 0 -9000 -6000 0 -9000 0 0 0 0 0 0 0 RxA
0 600000 0 0 -600000 0 0 0 0 0 0 0 0 RyA
-9000 0 18000 9000 0 9000 0 0 0 0 0 0 0 MA
-6000 0 9000 306000 0 9000 -300000 0 0 0 0 0 uC 4
0 -600000 0 0 600750 2250 0 -750 2250 0 0 0 vC -30
-9000 0 9000 9000 2250 27000 0 -2250 4500 0 0 0 qC -30
0 0 0 -300000 0 0 306000 0 9000 -6000 0 9000 x uD = 0
0 0 0 0 -750 -2250 0 600750 -2250 0 -600000 0 vD -30
0 0 0 0 2250 4500 9000 -2250 27000 -9000 0 9000 qD 30
0 0 0 0 0 0 -6000 0 -9000 6000 0 -9000 0 RxB
0 0 0 0 0 0 0 -600000 0 0 600000 0 0 RyB
0 0 0 0 0 0 9000 0 9000 -9000 0 18000 0 MB
[K] x [∆] = [F]
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
REDUCED STIFFNESS MATRIX EQUATION
306000 0 9000 -300000 0 0 uC 4
0 600750 2250 0 -750 2250 vC -30
9000 2250 27000 0 -2250 4500 qC -30
-300000 0 0 306000 0 9000 x uD = 0
0 -750 -2250 0
60075
0 -2250 vD -30
0 2250 4500 9000 -2250 27000 qD 30
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
STRUCTURAL ANALYSIS I
2017/2018 CLASS 7
SOLVED EQUATION: MOVEMENTS VALUES
uC 0,000607 m
vC -0,000049 m
qC -0,001510 rad
uD = 0,000561 m
vD -0,000051 m
qD 0,001176 rad
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
GLOBAL EQUATION: ONCE WE KNOW THE MOVEMENTS
WE CAN CALCULATE THE REACTION FORCES
6000 0 -9000 -6000 0 -9000 0 0 0 0 0 0 0 RxA
0 600000 0 0 -600000 0 0 0 0 0 0 0 0 RyA
-9000 0 18000 9000 0 9000 0 0 0 0 0 0 0 MA
-6000 0 9000 306000 0 9000 -300000 0 0 0 0 0 uC 4
0 -600000 0 0 600750 2250 0 -750 2250 0 0 0 vC -30
-9000 0 9000 9000 2250 27000 0 -2250 4500 0 0 0 qC -30
0 0 0 -300000 0 0 306000 0 9000 -6000 0 9000 x uD = 0
0 0 0 0 -750 -2250 0 600750 -2250 0 -600000 0 vD -30
0 0 0 0 2250 4500 9000 -2250 27000 -9000 0 9000 qD 30
0 0 0 0 0 0 -6000 0 -9000 6000 0 -9000 0 RxB
0 0 0 0 0 0 0 -600000 0 0 600000 0 0 RyB
0 0 0 0 0 0 9000 0 9000 -9000 0 18000 0 MB
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
GLOBAL EQUATION: ONCE WE KNOW THE MOVEMENTS
WE CAN CALCULATE THE REACTION FORCES
RxA 9,94 kN
RyA 29,25 kN
MA -8,12 kNm
RxB = -13,94 kN
RyB 30,75 kN
MB 15,626 kNm
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
ONCE WE KNOW THE REACTION FORCES WE CAN
CALCULATE THE INTERNAL FORCES
A B
C D
6 m
3
m
30 x 30 cm 30 x 30 cm
30 x 30 cm
4 kN
29,25 kN 30,75 kN
9,94 kN 13,94 kN
8,12 kNm 15,626 kNm
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
STRUCTURAL ANALYSIS I
2017/2018 CLASS 7
A B
C D
-13,94 kN
-29,25 kN -30,75 kN
-19,92 kN
15,92 kN
-29,25 kN
30,75 kN
A B
C
A B
C D
ESFUERZOSAXILES
ESFUERZOSCORTANTES
DEFORMADA
A B
C D
-21,7 kNm
8,12 kNm
-26,194 kNm
21,053 kNm
15,63 kNm
MOMENTOSFLECTORES
-12,5 mm
v = -0,049 mm
u = 0,607 mm
v = -0,051 mm
u = 0,560 mm
21,078 kNm
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
A B
C D
UPN80
30 x 30 cm 30 x 30 cm
30 x 30 cm
E= 20 kN/mm 2
E= 210 kN/mm 2
10kN/m
4 kN
WHAT’S THE EFFECT OF THE DIAGONAL BRACING?
WHICH MATRICES WOULD VARY?
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
[K] x [∆] = [F]
GLOBAL
STIFFNESS
MATRIX
MOVEMENTS
MATRIX
FORCES
MATRIX
KEY MATRIX EQUATION
Frame
geometry
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
THE ONLY BAR SINGLE MATRIX WE SHOULD INCLUDE IS AD
[kAA]barra AD [kAD]barra AD
27550 13771 -13 -27550 -13771 -13
13771 6894 27 -13771 -6894 27
-13 27 133 13 -27 66
-27550 -13771 13 27550 13771 13
-13771 -6894 -27 13771 6894 -27
-13 27 66 13 -27 133
[kDA]barra DA [kDD]barra DD
[k]AD
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
AD
DA
AA
DD
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
306000 0 9000 -300000 0 0 uC 4
0 600750 2250 0 -750 2250 vC -30
9000 2250 27000 0 -2250 4500 qC -30
-300000 0 0 333550 13771 9013 x uD = 0
0 -750 -2250 13771 607644 -2277 vD -30
0 2250 4500 9013 -2277 27133 qD 30
[K]reducida, en coordenadas globales [ Δ]reducida [F]reducida
[K]reduced, in global coordinates [ Δ]reduced [F]reduced
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
uC 0,000185 m
vC -0,000050 m
qC -0,001388 rad
uD = 0,000133 m
vD -0,000053 m
qD 0,001291 rad
RxA 8,42 kN
RyA 28,35 kN
MA -10,74 kNm
RxB = -12,42 kN
RyB 31,65 kN
MB 12,82 kNm
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
A
B
C D
UPN80
30 x 30 cm 30 x 30 cm
30 x 30 cm
E= 20 kN/mm 2
E= 210 kN/mm 2
10kN/m
4 kN
28,34 kN 31,65 kN
8,42 kN 12,42 kN
10,74 kNm 12,82 kNm
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
STRUCTURAL ANALYSIS I
2017/2018 CLASS 7
A B
C
D
-15,38 kN
-29,79 kN -31,65 kN
-12,42 kN
11,38kN
-29,79 kN
30,21 kN
A B
C
A B
C
D
ESFUERZOSAXILES
ESFUERZOSCORTANTES
DEFORMADA
A B
C
-23,32 kNm
10,83 kNm
-24,61 kNm
21,02 kNm
12,82 kNm
MOMENTOSFLECTORES
-12,5 mm
v = -0,049 mm
u = 0,18 mm
v = -0,052 mm
u = 0,130 mm
+3,29 kN
-0,039 kN
21,05 kNm
0,17 kNm
0,08 kNm
ANALYZE THE EFFECT OF THE BRACING
ANALYZE THE VERTICAL DISPLACEMENTS AT C AND D IN BOTH FRAMES
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
cperez.eps@ceu.es
federico.prietomunoz@ceu.es
IN WHICH ONE THE WIND FACES LEFT?
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
BRACING IS VERY IMPORTANT IN STEEL STRUCTURES
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
BRACING IS VERY IMPORTANT IN HIGHRISES
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
NOWADAYS WE CAN BUILD EVERYTHING WE CAN DRAW
WE SHOULD MEASURE IF THE EFFORT IS WORTH IT
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
cperez.eps@ceu.es
molina.eps@ceu.es
STRUCTURAL ANALYSIS I
DEGREE IN ARCHITECTURE
Year 3 Term 1
DIRECT STIFFNESS METHOD
TODAY’S WORDS

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AE1_22_23_CLASS_MATRIX.pptx

  • 1. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD cperez.eps@ceu.es molina.eps@ceu.es STATICALLY inDETERMINATE SYSTEMS. Complex geometry DIRECT STIFFNESS METHOD
  • 2. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD cperez.eps@ceu.es molina.eps@ceu.es
  • 3. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD PREVIOUSLY ON AE1
  • 4. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD
  • 5. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD
  • 6. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD 1.- DIRECT STIFFNESS METHOD (matrix formulation) GENERAL METHOD (computers use it) AUTOMATED PROCESS WE DO NOT HAVE TO THINK MANY NUMBERS SO WE HAVE TO BE VERY CAREFUL ORGANIZING THE INFORMATION WE DO NOT NEGLECT AXIAL EFFECT: BARS GET LONGER AND SHORTER
  • 7. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD First example. DIRECT STIFFNESS METHOD
  • 8. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD [K] x [∆] = [F] GLOBAL STIFFNESS MATRIX MOVEMENTS MATRIX FORCES MATRIX KEY MATRIX EQUATION Frame geometry all the frame information will be included in it
  • 9. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD MOVEMENTS MATRIX (always 3 numbers per joint in 2D frames) uA D A vA gA uC D C vC gC [D] = uD D D vD gD uB D B vB gB
  • 10. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD MOVEMENTS MATRIX (always 3 numbers per joint in 2D frames) uA D A vA gA uC D C vC gC [D] = uD D D vD gD uB D B vB gB In this example which of these elements are ZERO?
  • 11. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD FORCES MATRIX (made up as the addition of 3 elements or 3 submatrices) [F] = [-fe] + [P] + [R] Fixed end forces and moments (effect of the load applied along the bars) Reaction forces Punctual loads applied at the joints
  • 12. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD FIXED END FORCES SUBMATRIX [-fe] only external load along the bar in the beam CD 0 0 [-fe]C -qL/2 -30 -qL^2/12 -30 [-fe]CD = 0 = 0 [-fe]D -qL/2 -30 qL^2/12 30 SINGLE FIXED END FORCES AND MOMENTS MATRIX For every bar we should compute the effect of the loads applied along the bars in the bars ends: forces and moments
  • 13. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD
  • 14. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD FIXED END FORCES SUBMATRIX [-fe] only external load along the bar in the beam CD 0 0 [-fe]C -qL/2 -30 -qL^2/12 -30 [-fe]CD = 0 = 0 [-fe]D -qL/2 -30 qL^2/12 30 [-fe] AC = 0 [-fe] DB = 0 SINGLE FIXED END FORCES AND MOMENTS MATRIX For every bar we should compute the effect of the loads applied along the bars in the bars ends: forces and moments
  • 15. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD STRUCTURAL ANALYSIS I 2016/2017 CLASS 6 FORCES MATRIX (the assembled force matrix has 3 numbers per joint, same as movements matrix) [-fe] [R] [P] 0 RxA 0 RxA A 0 RyA 0 RyA 0 MA 0 MA 0 0 4 4 C -30 0 0 -30 -30 0 0 -45 [F] = 0 + 0 + 0 = 0 D -30 0 0 -30 30 0 0 45 0 RxB 0 RxB B 0 RyB 0 RyB 0 MB 0 MB
  • 16. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD GLOBAL (or master) STIFFNESS MATRIX [𝐾]𝐴𝐴 [𝐾]𝐴𝐶 [𝐾]𝐴𝐷 [𝐾]𝐴𝐵 [𝐾]𝐶𝐴 [𝐾]𝐶𝐶 [𝐾]𝐶𝐷 [𝐾]𝐶𝐵 [𝐾]𝐷𝐴 [𝐾]𝐷𝐶 [𝐾]𝐷𝐷 [𝐾]𝐷𝐵 [𝐾]𝐵𝐴 [𝐾]𝐵𝐶 [𝐾]𝐵𝐷 [𝐾]𝐵𝐵 𝑥 [𝜕𝐴] [𝜕𝐶] [𝜕𝐷] [𝜕𝐵] = [𝐹𝐴] [𝐹𝐶] [𝐹𝐷] [𝐹𝐵] 12 submatrices Each submatrix 9 elements [K] x [∆] = [F]
  • 17. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD GLOBAL (or master) STIFFNESS MATRIX [𝐾]𝐴𝐴 [𝐾]𝐴𝐶 [𝐾]𝐴𝐷 [𝐾]𝐴𝐵 [𝐾]𝐶𝐴 [𝐾]𝐶𝐶 [𝐾]𝐶𝐷 [𝐾]𝐶𝐵 [𝐾]𝐷𝐴 [𝐾]𝐷𝐶 [𝐾]𝐷𝐷 [𝐾]𝐷𝐵 [𝐾]𝐵𝐴 [𝐾]𝐵𝐶 [𝐾]𝐵𝐷 [𝐾]𝐵𝐵 𝑥 [𝜕𝐴] [𝜕𝐶] [𝜕𝐷] [𝜕𝐵] = [𝐹𝐴] [𝐹𝐶] [𝐹𝐷] [𝐹𝐵] [K]AA links movements at A with forces at A [K]AC links movements at C with forces at A [K]AD links movements at D with forces at A [K]AB links movements at B with forces at A [K]CA links movements at A with forces at C [K]CC links movements at C with forces at C [K]CD links movements at D with forces at C [……………………………………………….. [K] x [∆] = [F]
  • 18. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD SINGLE BAR STIFFNESS MATRIX How many single bar stifnees matrices do you have to consider in this frame? How many numbers does it contain?... [k] x [∂] = [f] BAR STIFFNESS MATRIX BAR MOVEMENTS MATRIX BAR FORCES MATRIX bar geometry
  • 19. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD We can write down 3 bar stiffness matrices because we have 3 bars
  • 20. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD every single stiffness matrix have 36 element organized in 4 submatrices 𝐸𝐴 𝐿 0 0 −𝐸𝐴 𝐿 0 0 0 12𝐸𝐼 𝐿3 6𝐸𝐼 𝐿2 0 −12𝐸𝐼 𝐿3 6𝐸𝐼 𝐿2 0 6𝐸𝐼 𝐿2 4𝐸𝐼 𝐿 0 −6𝐸𝐼 𝐿2 2𝐸𝐼 𝐿 −𝐸𝐴 𝐿 0 0 𝐸𝐴 𝐿 0 0 0 −12𝐸𝐼 𝐿3 −6𝐸𝐼 𝐿2 0 12𝐸𝐼 𝐿3 −6𝐸𝐼 𝐿2 0 6𝐸𝐼 𝐿2 2𝐸𝐼 𝐿 0 −6𝐸𝐼 𝐿2 4𝐸𝐼 𝐿 𝑥 𝑢1 𝑣1 𝜃1 𝑢2 𝑣2 𝜃2 = 𝑁1 𝑉1 𝑀1 𝑁2 𝑉2 𝑀2 1 2
  • 21. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD When the bar is horizontal and we consider the first joint in the left and the second in the right, the bar local coordinate system is the same as the global coordinate system 𝐸𝐴 𝐿 0 0 −𝐸𝐴 𝐿 0 0 0 12𝐸𝐼 𝐿3 6𝐸𝐼 𝐿2 0 −12𝐸𝐼 𝐿3 6𝐸𝐼 𝐿2 0 6𝐸𝐼 𝐿2 4𝐸𝐼 𝐿 0 −6𝐸𝐼 𝐿2 2𝐸𝐼 𝐿 −𝐸𝐴 𝐿 0 0 𝐸𝐴 𝐿 0 0 0 −12𝐸𝐼 𝐿3 −6𝐸𝐼 𝐿2 0 12𝐸𝐼 𝐿3 −6𝐸𝐼 𝐿2 0 6𝐸𝐼 𝐿2 2𝐸𝐼 𝐿 0 −6𝐸𝐼 𝐿2 4𝐸𝐼 𝐿 𝑥 𝑢1 𝑣1 𝜃1 𝑢2 𝑣2 𝜃2 = 𝑁1 𝑉1 𝑀1 𝑁2 𝑉2 𝑀2 1 2
  • 22. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD When the bar is NOT horizontal the bar local coordinate system is NOT the same as the global coordinate system 1 2 90º 270º 2 1 1 1
  • 23. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD TRANSFORMATION MATRIX 𝑇 = 𝑐𝑜𝑠 𝛼 𝑠𝑒𝑛 𝛼 0 0 0 0 −𝑠𝑒𝑛 𝛼 cos 𝛼 0 0 0 0 0 0 1 0 0 0 0 0 0 cos 𝛼 𝑠𝑒𝑛 𝛼 0 0 0 0 −𝑠𝑒𝑛 𝛼 cos 𝛼 0 0 0 0 0 0 1 THE ANGLE IS THE KEY!
  • 24. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD 𝑘11 𝑘12 𝑘13 −𝑘11 −𝑘12 𝑘13 𝑘12 𝑘22 𝑘23 −𝑘12 −𝑘22 𝑘23 𝑘13 𝑘23 𝑘33 −𝑘13 −𝑘23 𝑘36 −𝑘11 −𝑘12 −𝑘13 𝑘11 𝑘12 −𝑘13 −𝑘12 −𝑘22 −𝑘23 𝑘12 𝑘22 −𝑘23 𝑘13 𝑘23 𝑘36 −𝑘13 −𝑘23 𝑘33 𝑥 𝑢1 𝑣1 𝜃1 𝑢2 𝑣2 𝜃2 = 𝑓𝑥1 𝑓𝑦1 𝑀1 𝑓𝑥2 𝑓𝑦2 𝑀2 [k]coordenadas globales x [∂]globales = [f]globales k11 = EA cos2 α / L + 12 EI sen2 α /L3 k12 = (EA/L - 12 EI /L3 ) x sen α x cos α k13 = - 6EI sen α /L2 k22 = EA sen2 α / L + 12 EI cos2 α /L3 k23 = 6 EI cos α /L2 k33 = 4EI /L k36 = 2EI /L SINGLE BAR MATRIX IN GLOBAL COORDINATES THE ANGLE IS THE KEY!
  • 25. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD [kAA]barra AC [kAC]barra AC 6000 0 -9000 -6000 0 -9000 0 600000 0 0 -600000 0 -9000 0 18000 9000 0 9000 -6000 0 9000 6000 0 9000 0 -600000 0 0 600000 0 -9000 0 9000 9000 0 18000 [kCA]barra AC [kCC]barra AC [k]AC
  • 26. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD [kCC]barra CD [kCD]barra CD 300000 0 0 -300000 0 0 0 750 2250 0 -750 2250 0 2250 9000 0 -2250 4500 -300000 0 0 300000 0 0 0 -750 -2250 0 750 -2250 0 2250 4500 0 -2250 9000 [kDC]barra CD [kDD]barra CD [k]CD
  • 27. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD [kDD]barra DB [kDB]barra DB 6000 0 9000 -6000 0 9000 0 600000 0 0 -600000 0 9000 0 18000 -9000 0 9000 -6000 0 -9000 6000 0 -9000 0 -600000 0 0 600000 0 9000 0 9000 -9000 0 18000 [kBD]barra DB [kBB]barra DB [k]BD
  • 28. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD [𝐾]𝐴𝐴 [𝐾]𝐴𝐶 [𝐾]𝐴𝐷 [𝐾]𝐴𝐵 [𝐾]𝐶𝐴 [𝐾]𝐶𝐶 [𝐾]𝐶𝐷 [𝐾]𝐶𝐵 [𝐾]𝐷𝐴 [𝐾]𝐷𝐶 [𝐾]𝐷𝐷 [𝐾]𝐷𝐵 [𝐾]𝐵𝐴 [𝐾]𝐵𝐶 [𝐾]𝐵𝐷 [𝐾]𝐵𝐵 GLOBAL STIFFNESS MATRIX [K] // ASSEMBLE MATRIX WHICH SUBMATRICES ARE ZERO? WHICH SUBMATRICES ARE THE ADDITION OF TWO?
  • 29. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD GLOBAL STIFFNESS MATRIX [K] // ASSEMBLE MATRIX 6000 0 -9000 -6000 0 -9000 0 0 0 0 0 0 0 600000 0 0 -600000 0 0 0 0 0 0 0 -9000 0 18000 9000 0 9000 0 0 0 0 0 0 -6000 0 9000 306000 0 9000 -300000 0 0 0 0 0 0 -600000 0 0 600750 2250 0 -750 2250 0 0 0 -9000 0 9000 9000 2250 27000 0 -2250 4500 0 0 0 0 0 0 -300000 0 0 306000 0 9000 -6000 0 9000 0 0 0 0 -750 -2250 0 600750 -2250 0 -600000 0 0 0 0 0 2250 4500 9000 -2250 27000 -9000 0 9000 0 0 0 0 0 0 -6000 0 -9000 6000 0 -9000 0 0 0 0 0 0 0 -600000 0 0 600000 0 0 0 0 0 0 0 9000 0 9000 -9000 0 18000 [K]GLOBAL
  • 30. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD GLOBAL STIFFNESS MATRIX [K] // ASSEMBLE MATRIX 6000 0 -9000 -6000 0 -9000 0 0 0 0 0 0 0 600000 0 0 -600000 0 0 0 0 0 0 0 -9000 0 18000 9000 0 9000 0 0 0 0 0 0 -6000 0 9000 306000 0 9000 -300000 0 0 0 0 0 0 -600000 0 0 600750 2250 0 -750 2250 0 0 0 -9000 0 9000 9000 2250 27000 0 -2250 4500 0 0 0 0 0 0 -300000 0 0 306000 0 9000 -6000 0 9000 0 0 0 0 -750 -2250 0 600750 -2250 0 -600000 0 0 0 0 0 2250 4500 9000 -2250 27000 -9000 0 9000 0 0 0 0 0 0 -6000 0 -9000 6000 0 -9000 0 0 0 0 0 0 0 -600000 0 0 600000 0 0 0 0 0 0 0 9000 0 9000 -9000 0 18000 [K]GLOBAL AA AC AD AB CA CC CD CB DA BA DC DD DB BC BD BB
  • 31. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD GLOBAL STIFFNESS MATRIX EQUATION 6000 0 -9000 -6000 0 -9000 0 0 0 0 0 0 0 RxA 0 600000 0 0 -600000 0 0 0 0 0 0 0 0 RyA -9000 0 18000 9000 0 9000 0 0 0 0 0 0 0 MA -6000 0 9000 306000 0 9000 -300000 0 0 0 0 0 uC 4 0 -600000 0 0 600750 2250 0 -750 2250 0 0 0 vC -30 -9000 0 9000 9000 2250 27000 0 -2250 4500 0 0 0 qC -30 0 0 0 -300000 0 0 306000 0 9000 -6000 0 9000 x uD = 0 0 0 0 0 -750 -2250 0 600750 -2250 0 -600000 0 vD -30 0 0 0 0 2250 4500 9000 -2250 27000 -9000 0 9000 qD 30 0 0 0 0 0 0 -6000 0 -9000 6000 0 -9000 0 RxB 0 0 0 0 0 0 0 -600000 0 0 600000 0 0 RyB 0 0 0 0 0 0 9000 0 9000 -9000 0 18000 0 MB [K] x [∆] = [F]
  • 32. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD STRUCTURAL ANALYSIS I 2017/2018 CLASS 7 GLOBAL STIFFNESS MATRIX EQUATION 6000 0 -9000 -6000 0 -9000 0 0 0 0 0 0 0 RxA 0 600000 0 0 -600000 0 0 0 0 0 0 0 0 RyA -9000 0 18000 9000 0 9000 0 0 0 0 0 0 0 MA -6000 0 9000 306000 0 9000 -300000 0 0 0 0 0 uC 4 0 -600000 0 0 600750 2250 0 -750 2250 0 0 0 vC -30 -9000 0 9000 9000 2250 27000 0 -2250 4500 0 0 0 qC -30 0 0 0 -300000 0 0 306000 0 9000 -6000 0 9000 x uD = 0 0 0 0 0 -750 -2250 0 600750 -2250 0 -600000 0 vD -30 0 0 0 0 2250 4500 9000 -2250 27000 -9000 0 9000 qD 30 0 0 0 0 0 0 -6000 0 -9000 6000 0 -9000 0 RxB 0 0 0 0 0 0 0 -600000 0 0 600000 0 0 RyB 0 0 0 0 0 0 9000 0 9000 -9000 0 18000 0 MB [K] x [∆] = [F]
  • 33. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD REDUCED STIFFNESS MATRIX EQUATION 306000 0 9000 -300000 0 0 uC 4 0 600750 2250 0 -750 2250 vC -30 9000 2250 27000 0 -2250 4500 qC -30 -300000 0 0 306000 0 9000 x uD = 0 0 -750 -2250 0 60075 0 -2250 vD -30 0 2250 4500 9000 -2250 27000 qD 30
  • 34. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD STRUCTURAL ANALYSIS I 2017/2018 CLASS 7 SOLVED EQUATION: MOVEMENTS VALUES uC 0,000607 m vC -0,000049 m qC -0,001510 rad uD = 0,000561 m vD -0,000051 m qD 0,001176 rad
  • 35. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD GLOBAL EQUATION: ONCE WE KNOW THE MOVEMENTS WE CAN CALCULATE THE REACTION FORCES 6000 0 -9000 -6000 0 -9000 0 0 0 0 0 0 0 RxA 0 600000 0 0 -600000 0 0 0 0 0 0 0 0 RyA -9000 0 18000 9000 0 9000 0 0 0 0 0 0 0 MA -6000 0 9000 306000 0 9000 -300000 0 0 0 0 0 uC 4 0 -600000 0 0 600750 2250 0 -750 2250 0 0 0 vC -30 -9000 0 9000 9000 2250 27000 0 -2250 4500 0 0 0 qC -30 0 0 0 -300000 0 0 306000 0 9000 -6000 0 9000 x uD = 0 0 0 0 0 -750 -2250 0 600750 -2250 0 -600000 0 vD -30 0 0 0 0 2250 4500 9000 -2250 27000 -9000 0 9000 qD 30 0 0 0 0 0 0 -6000 0 -9000 6000 0 -9000 0 RxB 0 0 0 0 0 0 0 -600000 0 0 600000 0 0 RyB 0 0 0 0 0 0 9000 0 9000 -9000 0 18000 0 MB
  • 36. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD GLOBAL EQUATION: ONCE WE KNOW THE MOVEMENTS WE CAN CALCULATE THE REACTION FORCES RxA 9,94 kN RyA 29,25 kN MA -8,12 kNm RxB = -13,94 kN RyB 30,75 kN MB 15,626 kNm
  • 37. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD ONCE WE KNOW THE REACTION FORCES WE CAN CALCULATE THE INTERNAL FORCES A B C D 6 m 3 m 30 x 30 cm 30 x 30 cm 30 x 30 cm 4 kN 29,25 kN 30,75 kN 9,94 kN 13,94 kN 8,12 kNm 15,626 kNm
  • 38. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD STRUCTURAL ANALYSIS I 2017/2018 CLASS 7 A B C D -13,94 kN -29,25 kN -30,75 kN -19,92 kN 15,92 kN -29,25 kN 30,75 kN A B C A B C D ESFUERZOSAXILES ESFUERZOSCORTANTES DEFORMADA A B C D -21,7 kNm 8,12 kNm -26,194 kNm 21,053 kNm 15,63 kNm MOMENTOSFLECTORES -12,5 mm v = -0,049 mm u = 0,607 mm v = -0,051 mm u = 0,560 mm 21,078 kNm
  • 39. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD A B C D UPN80 30 x 30 cm 30 x 30 cm 30 x 30 cm E= 20 kN/mm 2 E= 210 kN/mm 2 10kN/m 4 kN WHAT’S THE EFFECT OF THE DIAGONAL BRACING? WHICH MATRICES WOULD VARY?
  • 40. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD [K] x [∆] = [F] GLOBAL STIFFNESS MATRIX MOVEMENTS MATRIX FORCES MATRIX KEY MATRIX EQUATION Frame geometry
  • 41. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD THE ONLY BAR SINGLE MATRIX WE SHOULD INCLUDE IS AD [kAA]barra AD [kAD]barra AD 27550 13771 -13 -27550 -13771 -13 13771 6894 27 -13771 -6894 27 -13 27 133 13 -27 66 -27550 -13771 13 27550 13771 13 -13771 -6894 -27 13771 6894 -27 -13 27 66 13 -27 133 [kDA]barra DA [kDD]barra DD [k]AD
  • 42. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD AD DA AA DD
  • 43. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD 306000 0 9000 -300000 0 0 uC 4 0 600750 2250 0 -750 2250 vC -30 9000 2250 27000 0 -2250 4500 qC -30 -300000 0 0 333550 13771 9013 x uD = 0 0 -750 -2250 13771 607644 -2277 vD -30 0 2250 4500 9013 -2277 27133 qD 30 [K]reducida, en coordenadas globales [ Δ]reducida [F]reducida [K]reduced, in global coordinates [ Δ]reduced [F]reduced
  • 44. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD uC 0,000185 m vC -0,000050 m qC -0,001388 rad uD = 0,000133 m vD -0,000053 m qD 0,001291 rad RxA 8,42 kN RyA 28,35 kN MA -10,74 kNm RxB = -12,42 kN RyB 31,65 kN MB 12,82 kNm
  • 45. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD A B C D UPN80 30 x 30 cm 30 x 30 cm 30 x 30 cm E= 20 kN/mm 2 E= 210 kN/mm 2 10kN/m 4 kN 28,34 kN 31,65 kN 8,42 kN 12,42 kN 10,74 kNm 12,82 kNm
  • 46. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD STRUCTURAL ANALYSIS I 2017/2018 CLASS 7 A B C D -15,38 kN -29,79 kN -31,65 kN -12,42 kN 11,38kN -29,79 kN 30,21 kN A B C A B C D ESFUERZOSAXILES ESFUERZOSCORTANTES DEFORMADA A B C -23,32 kNm 10,83 kNm -24,61 kNm 21,02 kNm 12,82 kNm MOMENTOSFLECTORES -12,5 mm v = -0,049 mm u = 0,18 mm v = -0,052 mm u = 0,130 mm +3,29 kN -0,039 kN 21,05 kNm 0,17 kNm 0,08 kNm ANALYZE THE EFFECT OF THE BRACING ANALYZE THE VERTICAL DISPLACEMENTS AT C AND D IN BOTH FRAMES
  • 47. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD cperez.eps@ceu.es federico.prietomunoz@ceu.es IN WHICH ONE THE WIND FACES LEFT?
  • 48. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD BRACING IS VERY IMPORTANT IN STEEL STRUCTURES
  • 49. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD BRACING IS VERY IMPORTANT IN HIGHRISES
  • 50. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD NOWADAYS WE CAN BUILD EVERYTHING WE CAN DRAW WE SHOULD MEASURE IF THE EFFORT IS WORTH IT
  • 51. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD
  • 52. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD
  • 53. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD
  • 54. cperez.eps@ceu.es molina.eps@ceu.es STRUCTURAL ANALYSIS I DEGREE IN ARCHITECTURE Year 3 Term 1 DIRECT STIFFNESS METHOD TODAY’S WORDS