Multiplexing and spreading techniques are used to combine multiple signals over a shared medium such as a communications channel. Frequency division multiplexing (FDM) combines signals by assigning each signal a unique, non-overlapping frequency band. Time division multiplexing (TDM) divides the available time on a channel into time slots that are allocated to individual signals in a cyclical, non-overlapping manner. Spread spectrum techniques like frequency-hopping spread spectrum (FHSS) and direct-sequence spread spectrum (DSSS) spread signals across a wider bandwidth to improve interference resistance and security.
2. 2
Sharing Medium
M
U
X
D
E
M
U
X
A link is divided into channels
n signals
(input)
n signals
(output)
1 link, n channels
Multiplexer Demultiplexer
3. 3
Frequency Division Multiplexing (FDM)
Medium BW > Channel BW
Each signal is modulated to a different
carrier frequency
E.g., broadcast radio
Channel allocated even if no data
An analog multiplexing technique to combine signals
7. 7
Guard Bands
Strips of unused bandwidth to prevent signals from
overlapping
FDM
3 kHz
f
FDM
(no guard band)
FDM
(with guard band)
f
3 kHz 3 kHz 3 kHz
f
3 kHz 3 kHz 3 kHz
f
3 kHz
f
3 kHz 3 kHz 3 kHz
8. 8
FDM: Example 1
Five voice channels, each with 3-kHz
bandwidth, are to be multiplexed together.
If there is a need for a guard band of 1.5 kHz,
what is the minimum bandwidth of the link?
f
3 kHz 3 kHz 3 kHz 3 kHz 3 kHz
1.5 kHz 1.5 kHz 1.5 kHz 1.5 kHz
21 kHz
9. 9
FDM: Example 2
Four digital-data channels, 1 Mbps each,
use a satellite channel of 1 MHz. Design an
appropriate configuration using FDM
11. 11
The Advanced Mobile Phone System (AMPS) uses two
bands. The first band of 824 to 849 MHz is used for
sending, and 869 to 894 MHz is used for receiving.
Each user has a bandwidth of 30 kHz in each direction.
How many people can use their cellular phones
simultaneously?
Solution
Each band is 25 MHz. If we divide 25 MHz by 30 kHz, we
get 833.33. In reality, the band is divided into 832
channels. Of these, 42 channels are used for control,
which means only 790 channels are available for cellular
phone users.
Example
12. 12
Multiplexer Demultiplexer
Wavelength Division Multiplexing (WDM)
WDM is a special case of FDM
1
2
3
1
2
3
1+2+3
Fiber-optic cable
WDM WDM
1
2
3
1
2
3
1+2+3
An analog multiplexing technique to combine optical signals
13. 13
Medium Data Rate > Signal Data Rate
Multiple digital signals interleaved in time
Time slots
are preassigned to sources and fixed
are allocated even if no data
do not have to be evenly distributed among sources
Time Division Multiplexing (TDM)
T
D
M
A
B
C
A
B
C
A
B
C
A
B
C
Frame
Time slot
A digital multiplexing technique to combine data
one unit
14. 14
Conceptual View of TDM
Channel
3
Channel
2
Channel
1
Channel
3
Channel
2
Channel
1
Channel
3
Channel
2
Channel
1
2
3 1
M
U
X
1
2
3
2
3 1
2
3 1
1
2
3
D
E
M
U
X
Data flow
15. 15
TDM Frames
A frame consists of one complete cycle of
time slots
16. 16
TDM: Example
Four 1-Kbps connections are multiplexed together.
A unit is 1 bit. Find:
(1) the duration of 1 bit before multiplexing,
(2) the transmission rate of the link,
(3) the duration of a time slot, and
(4) the duration of a frame?
18. 18
Synchronization
B
C A 1
… 1 0 1 0 …
Synchronization pattern
Multiplexer and demultiplexer must be
synchronized
Framing bits are used to provide synchronization
B
C A 0 B
C A 1 B
C A 0
framing bit
19. 19
Synchronization: Example
Identify all the framing bits from this bit
sequence output by a multiplexer
2 channels
1 unit = 2 bits
0 0 0 1 1 0 1 1 1 0 0 0 0 1 0 0 1 0 1 1
21. 21
TDM of Different Data Rates
Data rate from one source may be faster than the others
More than one time slot can be assigned to certain sources
4 kbps
4 kbps
8 kbps 16 kbps
MUX
A
B
C
1 frame
B
C A
B
Note: assume 1 unit = 1 bit
4 kbps
4 kbps
8 kbps
4 kbps
4 kbps
16 kbps
MUX
A
B
C
22. 22
TDM of Different Data Rates
5 kbps
3 kbps
8 kbps
A
B
A
B A A A A
B B
B B B
A A A A A
1 frame
A
B A A A A
B B
MUX
Note: assume 1 unit = 1 bit
23. 23
5 kbps
3 kbps
A
B
6 kbps
Bit Padding
Different data rates may not be integer
multiples of each other
Solution – Bit padding
9 kbps
Bit
Padding
MUX
A A
B A A
B
B A
A A
B
3000 cycles/s
Extra bit
1 ms
Note: assume 1 unit = 1 bit
A A
B A A
B
B A
A A
A A
A
B
B
B
24. 24
Digital Signal (DS) Hierarchy
T
D
M
T
D
M
T
D
M
DS-1
DS-2
DS-3
DS-4
DS-0
T
D
M
DS-0
…
24
channels
1.544 Mbps
24 DS-0
6.312 Mbps
4 DS-1
44.376 Mbps
7 DS-2
274.176 Mbps
6 DS-3
64 kbps
1 kbps = 1,000 bps
1 Mbps = 1,000 kbps
25. 25
DS Services and T Lines
Service Line
Rate
(Mbps)
Voice
Channels
DS-1 T-1 1.544 24
DS-2 T-2 6.312 96
DS-3 T-3 44.736 672
DS-4 T-4 274.176 4032
DS-0, DS-1, etc, are services
T lines are used to implement these services
28. 28
E Lines
European's version of T lines
Also used in Thailand
E Line
Rate
(Mbps)
Voice
Channels
E-1 2.048 30
E-2 8.448 120
E-3 34.368 480
E-4 139.264 1920