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04 - 15 Jan - Heap Sort
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Neeldhara Misra
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04 - 15 Jan - Heap Sort
1.
CS 321. Algorithm
Analysis & Design Lecture 4 Heap Sort
2.
4 9 2
1 8 5 6
3.
4 9 2
1 8 5 6
4.
4 9 2 1 8
5 6
5.
4 9 2 1 8
5 6
6.
4 9 21 8 5
6
7.
4 9 21 8 5
6
8.
4 9 21 8 5 6
9.
4 9 21 8 5 6
10.
4 9 21 8 5 6
11.
4 9 21 8 5 6
12.
4 9 21 8 5 6
13.
4 9 21 8 5 6
14.
4 9 21 85 6
15.
4 9 21 85 6
16.
4 921 85
6
17.
4 921 85
6 Can we speed up the find-min operations?
18.
4 9 21 8 5 6 Organize the elements
so that finding minimum is “easy”.
19.
4 9 21 8 5 6 Organize the elements
so that deleting the minimum element is “easy”.
20.
Store a set
of n distinct numbers. Inserting a new element and deleting the minimum element can be done in time proportional to (log n). GOAL
21.
All jumbled up 4
9 2 1 8
22.
All jumbled up 4
9 2 1 8 3
23.
All jumbled up 4
9 2 1 8 3 6
24.
All jumbled up 4
9 2 1 8 3 Insert: O(1) 6
25.
All jumbled up 4
9 2 1 8 3 Insert: O(1) Delete-Min: O(n) 6
26.
All sorted 9 8
6 3 1
27.
All sorted 9 8
6 3
28.
All sorted 9 8
6 3 Delete-Min: O(1)
29.
All sorted 9 8
6 3 Delete-Min: O(1) 4
30.
All sorted 9 8
6 3 Delete-Min: O(1) 47
31.
All sorted 9 8
6 3 Insert: O(n) Delete-Min: O(1) 47
32.
In-between? Invariant: The first
element of the array is the minimum.
33.
In-between? Invariant: The first
element of the array is the minimum.
34.
In-between? Invariant: The first
element of the array is the minimum.
35.
In-between? Invariant: The first
element of the array is the minimum.
36.
In-between? Invariant: The first
element of the array is the minimum.
37.
In-between? Invariant: The first
element of the array is the minimum.
38.
In-between? Invariant: The first
element of the array is the minimum.
39.
In-between? Invariant: The first
element of the array is the minimum.
40.
4 9 21 8 5 6
41.
6 1 59 24 8 x is a
child of y: x is larger than y.
42.
6 1 59 24 8
43.
6 1 59 24 8
44.
6 1 59 24 8
45.
61 5924 8
46.
61 5924 8 6 1 59 24 8
47.
61 5924 8 6 1 59 24 8 1 2
3 4 5 6 7 1 2 3 4 5 6 7
48.
61 5924 8 6 1 59 24 8 1 2
3 4 5 6 7 1 2 3 4 5 6 7 left-child(i) = 2i
49.
61 5924 8 6 1 4 1 2 4 1
2 3 4 5 6 7
50.
61 5924 8 6 1 4 1 2 4 1
2 3 4 5 6 7 left-child(i) = 2i
51.
left-child(i) = 2i
52.
left-child(i) = 2i i 2i
53.
left-child(i) = 2i i+k 2i
+ 2k i 2i
54.
6 1 59 24 8 Delete Min
55.
6 1 5 9 24 8 Delete Min
56.
6 1 5 9 24 8 Delete Min
57.
6 1 5 9 24 8 Delete Min
58.
6 1 5 9 24 8 Delete Min
59.
6 1 5 9 24 8 Delete Min
60.
6 1 5 9 2 4 8 Delete Min
61.
6 1 2 9 54 8 Delete Min
62.
6 2 9 54 8 Insert
63.
6 3 2 9 54 8 Insert
64.
6 3 2 9 54 8 Insert
65.
6 3 2 9 54 8 Insert
66.
6 3 2 9 5 4 8 Insert
67.
6 3 2 9 5 4 8 Insert
68.
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