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Three Phase Induction Motor Design
1. Contents
LeakageReactance
Course No : EE 3220
Electrical Machine Design
Project on : Three Phase Induction Motor Design
Submitted To:
Dr. Mohammad Shaifur Rahman
Professor,
Dept. of EEE,KUET
Abu Syed MD. Jannatul Islam
Lecturer,
Dept. of EEE,KUET
Nashrah Afroz
Lecturer,
Dept of EEE,KUET
• Submitted By: (GROUP-08)
• 1503014 : Fardeen Ahmed Ifty
• 1503030 : Md. Rownok Rahman
• 1503066 : Md. Rayid Hasan Mojumder
• 1503103 : Md. Shafayet
StatorSlot
Reactance
RotorSlot
Reactance
OverhangLeakage
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Leakage
StatorSlot
Reactance
RotorSlot
Reactance
Overhang
Leakage
Stator Slot Reactance
For a tapered slot,
Ws
Wo
h3 W1=W2
h1
h4
Fig : Tapered Slot
Specific slotpermeance, λss =µ0 [
2ℎ1
3(𝜔 𝑠+𝜔2)
+
2ℎ2
𝜔1+𝜔2
+
2ℎ3
𝜔1+𝜔0
+
ℎ4
𝜔0
]
=4𝜋×10−7
[
2×17
3(16.383+11.933)
+
2×3
11.933+2
+
1
2
]
=1.67×10−6
(Consideringthe height of h2 alsotobe occupied byconductors)
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Leakage
StatorSlot
Reactance
RotorSlot
Reactance
Overhang
Leakage Rotor Slot Reactance
For a parallel sided slot,
Wo
h4
h3
h1h1
Ws
Fig : Parallel Sided Slot
Specific slot permeance, λsr = µ0[
ℎ1
3𝜔 𝑠
+
ℎ2
𝜔 𝑠
+
2ℎ3
𝜔1+𝜔0
+
ℎ4
𝜔0
]
= 4𝜋 ×10−7[
8
3×7.4
+
2×1
7.4+1.5
+
1
1.5
]
=1.57×10−6
Thisreferredtostatorside,ℑ/
sr=ℑ𝑠𝑟 ×
𝐾𝜔𝑠 ×𝑆 𝑠
2
𝐾𝜔𝑟 ×𝑆 𝑟
2
=1.57×10−6
×
0.9332×24
12×22
=1.49×10−6
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Leakage
StatorSlot
Reactance
RotorSlot
Reactance
Overhang
Leakage Rotor Slot Reactance(contd.)
So, total specific slot permeance, λsr = λss + λ’sr
= (1.67+1.49) ×10-6
= 3.16×10-6
Slot leakage reactance, χs = 8πf Tph
2
(
λ 𝑠
𝑝𝑞
)
= 8π×50×2802
×0.152×(
3.16×10−6
4×2
)
= 5.92 Ω
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Leakage
StatorSlot
Reactance
RotorSlot
Reactance
Overhang
Leakage
Termination
Overhang Reactance
0.45
0.5
0.55
0.6
0.65
0.7
0.75
0.8
0.85
0.9
0.95
1
0.5 0.55 0.6 0.65 0.7 0.75 0.8 0.85 0.9 0.95 1
120˚ spread
Ratio[
𝐶𝑜𝑖𝑙 𝑆𝑝𝑎𝑛
𝑃𝑜𝑙𝑒 𝑃𝑖𝑡𝑐ℎ
]
Factor,K
0.875
0.833
Fig : Slot leakage factor
We have , L0λ0 = µ0Ks(
𝜏2
𝜋𝑌𝑠𝑠
)
Now, ratio
𝑐𝑜𝑖𝑙 𝑠𝑝𝑎𝑛
𝑝𝑜𝑙𝑒 𝑝𝑖𝑡𝑐 ℎ
=
5
6
= 0.833
Corresponding to this the value of Ks from Figure is 0.875
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Leakage
StatorSlot
Reactance
RotorSlot
Reactance
Overhang
Leakage
End
Overhang Reactance(Contd.)
We have , L0λ0 = µ0Ks(
𝜏2
𝜋𝑌𝑠𝑠
)
Now, ratio
𝑐𝑜𝑖𝑙 𝑠𝑝𝑎𝑛
𝑝𝑜𝑙𝑒 𝑝𝑖𝑡𝑐 ℎ
=
5
6
= 0.833
Corresponding to this the value of Ks from Figure is 0.875
L0λ0 = 4𝜋 × 10−7
×
0.875×0.1012
𝜋×16.68×10−3
= 2.14×10-7
Overhang leakage reactance, χ0 = 8πf Ts
2 L0λ0
𝑝𝑞 𝑠
= 8π×50×2802
×(
2.14×10−7
4×2
)
= 2.64 Ω
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Leakage
StatorSlot
Reactance
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Reactance
Overhang
Leakage
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End
Slot
Leakage
Reactance
=5.92 Ω
Overhang Reactance
=2.64 Ω
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Leakage
StatorSlot
Reactance
RotorSlot
Reactance
Overhang
Leakage
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