Solution of Linear Inequalities by graphical method

1. Math’s Project
Submitted To:
Joseph Sir

3. Question No: 01

4. Solve the following system of linear inequality
graphically:
x + y ≤ 10,
3x – 4y ≤ 26
x≥0
y≥0

6. • x + y = 10
x 2 1 6
y 8 9 4
• 3x - 4y = 24
x 0 8 4
y -6 0 -3

7. de.
• Hence, the solution of the given system of linear
inequalities is represented by the common shaded
region

8. Question No:
02

9. Solve the following system of linear inequality
graphically:
3x+2y ≥ 150
x + 4y ≥ 80

10. 3x+2y ≤ 150
3x+2y = 150
X 50 30
Y 0 30

11. x + 4y ≥ 80
x + 4y = 80
X 0 40
Y 20 10

12. 70
3x+2y ≥ 150
50
40 x + 4y ≥ 80
30
20
10
-70 -60 - 50 -40 -30 -20 -10 0 10 20 30 40 50 60 70 80
-10
-20
-30
-40
-50
-60

13. Thankyou..
Done By:
Justine Jose