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Basics_3e_Chapter_12_Depreciation.pptx
1.
Because learning changes
everything.® Slides to accompany Basics of Engineering Economy Third edition by Leland Blank and Anthony Tarquin Chapter 12 Depreciation Methods © 2021 McGraw Hill. All rights reserved. Authorized only for instructor use in the classroom. No reproduction or further distribution permitted without the prior written consent of McGraw Hill.
2.
© McGraw Hill
2 Chapter 12 – Depreciation Methods PURPOSE Use a specific method to reduce the book value of capital invested in an asset (by depreciation) or natural resource (by depletion) TOPICS • Depreciation terms. • Straight line. • Declining balance. • MACRS in USA. • Two more methods. • Switching methods. • Spreadsheet usage. • Depletion methods.
3.
© McGraw Hill
3 Section 12.1 – Depreciation - Overview Definition: Depreciation reflects the reduction in value of an asset over time. Depreciation represents the loss in value due to: • Use, and wear and tear on the asset. • Deterioration over time. • Obsolescence. • Technological replacement. Depreciation represents the diminishing amount of capital invested in the asset. Deprecation amount is NOT actual cash flow and may not reflect actual usage patterns of the asset.
4.
© McGraw Hill
4 Section 12.1 – Terminology 1 In most countries, depreciation is a tax deductible expense. It reduces income tax liability for a corporation, even though it is not an actual cash flow. General relation is: Taxes = (income − expenses − depreciation)(tax rate) Two types of depreciation used by corporations: • Book depreciation - Used internal to the corporation for financial and accounting purposes. • Tax depreciation - Per government regulations, specified methods are used in calculating taxes. In economic analyses, tax depreciation is usually the type applied.
5.
© McGraw Hill
5 Section 12.1 – Terminology 2 First cost, B – Total cost of asset including purchase, installation fees, training, etc. Book Value, BV Remaining, undepreciated investment after all depreciation to date is removed. Recovery period, n – Depreciable life in years. Tax and book depreciation lives are often different. Salvage, S Estimated market value (MV) at end of recovery period.
6.
© McGraw Hill
6 Section 12.1 – Terminology 3 Some additional terms Depreciation rate, d – Fraction of first cost removed each year. (Rate is dt when it varies each year.) Half-year convention –Assumes asset is placed into initial service or disposed of in midyear, regardless of when it actually occurs. (Applies to US-required MACRS method.) Types of depreciable property Tangible – Income-producing, tangible property of a corporation, for example, vehicles, equipment, etc. (Also called personal property.) Real – Real estate and its improvements, such as, buildings, factories, other construction. Note: Land itself is not depreciable.
7.
© McGraw Hill
7 Section 12.1 – Different Depreciation Methods Some methods used in the US and other countries Straight Line (SL) • Standard against which other methods are compared. • Book value decreases linearly over time. Declining Balance (DB) • Accelerated write-off compared to SL method. • Defers part of tax liability to later in recovery period. Modified Accelerated Cost Recovery System (MACRS) • Required tax depreciation method in US, with few exceptions.
8.
© McGraw Hill
8 Section 12.1 – Section 179 Deduction • Exception to regular depreciation methods provided by government as an economic incentive to make new capital investments. • Good for new, small and medium-sized businesses. • Allows full depreciation of initial cost of newly-installed asset in first year of ownership. • Limits vary considerably over the years ($500,000 in 2015; $1 M in 2018; currently indexed for inflation annually). • Any amount above allowed 179 deduction limit is depreciated over the asset’s recovery period.
9.
© McGraw Hill
9 Section 12.1 – Summary of Notation B = First cost or basis for depreciation n = Recovery period in years S = Estimated salvage value at end of recovery period t = year, t = 1, 2, …, n Dt = Depreciation charge for year t dt = Depreciation rate for year t (simply d if rate is the same each year) BVt = Book value after t years of depreciation
10.
© McGraw Hill
10 Section 12.2 – Straight Line & Example 12.1 1 ( ) t d B S D n B S dt = d = 1/n (constant each year) BVt = B − (t × Dt) = BVt-1 − Dt t = 1, 2, …, n Dt based on time, not usage Spreadsheet function to display Dt = SLN(B,S,n) Example 12.1 • First cost is $50,000 with life of 5 years and estimated salvage of $10,000. • Plot SL book value. B = $50,000 S = $10,000 n = 5 years
11.
© McGraw Hill
11 Section 12.2 – Straight Line & Example 12.1 2 SL depreciation: Dt = (50,000 − 10,000)/5 = $8000 SL book value: BVt = BVt-1 − Dt Year, t Dt, $ BVt, $ 0 8000 50,000 1 8000 42,000 2 8000 34,000 3 8000 26,000 4 8000 18,000 5 8000 10,000 Spreadsheet function: = SLN(50000,10000,5) displays Dt of $8000.
12.
© McGraw Hill
12 Section 12.3 – Declining Balance (DB) - Intro • DB write-off of asset value is accelerated compared to SL. • Larger annual depreciation amounts in the early years of recovery period. • Also called fixed percentage or uniform percentage method. • Annual depreciation Dt equals book value at beginning of year BVt-1 (which is same as end of previous year) times fixed rate d. Dt = d × BVt-1
13.
© McGraw Hill
13 Section 12.3 – DB and DDB Models Values of d are related to SL depreciation rate 2 times SL rate: d = 2/n. • This is dmax and is largest allowed. • Model now called double declining balance (DDB). Example: If n = 5, dmax = 2/n = 0.4; that is, 40% of BV is removed each year. • 150% of SL rate: d = 1.5/n. • If d is 100% of SL rate, d = 1/n, which is SL depreciation. Notation reminder for DB and DDB • d = fixed percentage of BV removed each year. • dt = depreciation rate for each year t.
14.
© McGraw Hill
14 Section 12.3 – DB Depreciation and Book Value Annual depreciation determined in either of 2 ways • Using book value of previous year. t t D d BV 1 • Using first cost basis B. 1 (1 ) t t D d B d Annual book value determined in either of 2 ways • Using first cost basis B. t t BV B(1 d) • Using accumulated depreciation for years j = 1 to t. t j j BV B D
15.
© McGraw Hill
15 Section 12.3 – BV Graphs for Comparison Characteristic BV plots of SL, DB and DDB Access the text alternative for slide images.
16.
© McGraw Hill
16 Section 12.3 – DB - Formulas and Functions Annual depreciation rate for each year t, relative to first cost B, is: t t d d d 1 1 Salvage value is not used in DB method formulas. • If a salvage value is estimated, and estimated S > implied S, stop depreciating when estimated S value is reached. • Implied salvage is book value in year n: n n Implied S BV B 1 d Spreadsheet function for DDB: = DDB(B,S,n,t,d) for DB: = DB(B,S,n,t) where d is between 1 and 2
17.
© McGraw Hill
17 Section 12.3 – Declining Balance - Example 12.2 1 B = $80,000 S = $10,000 n = 5 years Develop BV graphs for two methods: DB at 150% SL rate and DDB DB rate: d = 1.5/5 = 0.3 DDB rate: dmax = 2/5 = 0.4 Year, t Declining Balance, d = 0.30 at Dt Declining Balance, d = 0.30 at BVt Double Declining Balance, d = 0.40 at Dt Double Declining Balance, d = 0.40 at BVt 0 $80,000 $80,000 1 $24,000 56,000 $32,000 48,000 2 16,800 39,200 19,200 28,800 3 11,760 27,440 11,520 17,280 4 8,232 19,208 6,912 10,368 5 5,762 13,446 368 10,000
18.
© McGraw Hill
18 Section 12.3 – Declining Balance - Example 12.2 2 Spreadsheet function: = DDB(80000,10000,5,t,factor) where: t = 1, 2, 3, 4, 5 for each year Factor = 1.5 for 150% of SL rate = 2 for DDB How was the salvage of $10,000 used? • Neither method used the estimated S to calculate Dt or BVt, except … • For DDB, depreciation in year 5 is limited, since BV5 would go below S = $10,000. • Only a $368 write-off is allowed in year 5, which is much less than the calculated amount of D5 = d(BV4) = 0.4(10,368) = $4,147 Double Declining Balance, d = 0.40 at Dt Double Declining Balance, d = 0.40 at BVt $80,000 $32,000 48,000 19,200 28,800 11,520 17,280 6,912 10,368 368 10,000
19.
© McGraw Hill
19 Section 12.3 – Declining Balance - Example 12.2 3 Access the text alternative for slide images.
20.
© McGraw Hill
20 Section 12.4 – MACRS Overview • MACRS became the only allowed tax depreciation method in the US in 1986. • Statutory depreciation rates dt are tabulated (Table 12.2). • Rates are derived using the DDB or DB method initially with a switch to SL at the optimal time. • Recovery period n is prescribed and tabulated by asset types (Table 12.4). • MACRS incorporates the half-year convention into the rates and recovery period. • MACRS does not utilize the estimated S, since the entire basis B is always depreciated to zero.
21.
© McGraw Hill
21 Section 12.4 – MACRS - Tangible Property Rates Table 12.2 Access the text alternative for slide images.
22.
© McGraw Hill
22 Section 12.4 – MACRS Formulas – Dt and BVt • MACRS is required for tax depreciation purposes. • Any method can be applied for book depreciation within the corporation. • Depreciation formula is ultra simple: Dt = dt × B • Book value after t years is based on BVt − 1 or B: 1 BV BV D t t t for 1,2,..., j j B D j t
23.
© McGraw Hill
23 Section 12.4 – MACRS Recovery Periods • Tangible Property Recovery Periods – n set at 3, 5, 7, 10, 15 and 20 years. • For n = 3, 5, 7, and 10 – Depreciation rates start with DDB method, and switch to SL rates to ensure faster write-off of B. • For n = 15 and 20 – Depreciation rates start with150% DB method, and switch to SL rates to ensure faster write-off of B. • Half-year (Mid-year) convention – Built in to allow only 50% of first year depreciation; leftover amount is removed in year n+1. (This removes some of the advantage of accelerated depreciation. Check it out on next slide.)
24.
© McGraw Hill
24 Section 12.4 – MACRS Rates – Real Property • Real property includes buildings and permanent improvements (not land). • MACRS rates utilize SL method for n = 39 years with half-year convention built in. • Depreciation rates in % are: Year 1 d1= 1.391% Years t = 2-39 dt = 2.564% Year 40 d40 = 1.177% Total is 100%
25.
© McGraw Hill
25 Section 12.4 – MACRS - Example 12.3 1 Use MACRS to depreciate asset with B = $400,000 n = 3 years S = $20,000 Access the text alternative for slide images.
26.
© McGraw Hill
26 Section 12.4 – MACRS - Example 12.3 2 Compare MACRS tax depreciation with DDB book depreciation after 2 and 3 years. Year Rate MACRS Tax Depreciation MACRS Book Value DDBs Book Depreciation DDBs Book Value 0 $400,000 $400,000 1 0.3333 $133,320 266,680 $266,667 133,333 2 0.4445 177,800 88,880 88,889 44,444 3 0.1481 59,240 29,640 24,444 20,000 4 0.0741 29,640 0 • Depreciation amounts and book values vary significantly. • MACRS BV after 2 years is ~2 times DDB BV. • DDB stops at S = $20,000, resulting in reduced D3 value.
27.
© McGraw Hill
27 Section 12.4 – MACRS - Example 12.3 3 0 100,000 200,000 300,000 400,000 0 1 2 3 4 Year Book value, $ DDB MACRS • MACRS always depreciates to $0; estimated S > 0 ignored. • DDB method depreciates to an implied S or estimated S at end of the recovery period. • MACRS depreciation in year 1 is ½ the DDB or DB amount due to implicit half-year convention. • MACRS takes one additional year for write-off (half-year convention) Access the text alternative for slide images.
28.
© McGraw Hill
28 Section 12.4 – MACRS - Recovery Period Systems GDS and ADS (GDS is used in this text) GDS (General Depreciation System) • Used for most assets. • Tabulates MACRS-allowed years for different types of assets. • Recovery ranges from 3 to 39 years; 7 years is default recovery period. ADS (Alternative Depreciation System) • Uses SL depreciation instead of MACRS rates. • Recovery period is longer than for GDS. • Removes early-life tax advantage of MACRS rates. • Good for start-up businesses with lower revenues. Note: See Table 12.4 for values of GDS and ADS
29.
© McGraw Hill
29 Section 12.5 – Unit-of-Production Depreciation • SL, DB, DDB, and MACRS models all reduce asset value based on time. • UOP model is based on usage over time. • Usage is commonly volume, hours, units, etc. • Depreciation charge for each year t is: Actual usuage for year basis salvage Total lifetime usuage t t D
30.
© McGraw Hill
30 Section 12.5 – Unit-of-Production - Example 12.4 B = $200,000 n = 5 year Total usage estimate = 3 M 3 m Actual usage in 1000 3 m is shown. Determine Dt and BVt using UOP. In the following table, read ‘m3’ as m cubed. Year, t Actual Usage, 1000 m3 Annual Depreciation, Dt, $ Cumulative Depreciation, $ Book Value, $ 1 420 28,000 28,000 172,000 2 630 42,000 70,000 130,000 3 630 42,000 112,000 88,000 4 660 44,000 156,000 44,000 5 660 44,000 200,000 0 Total 3,000 200,000 For example: D2 = (630/3000) × (200,000) = $42,000 Note: If more than 3000 3 m used, no more depreciation.
31.
© McGraw Hill
31 Section 12.5 – Sum-of-Years-Digits Depreciation • One of earlier accelerated write-off models when compared to SL depreciation. • Larger depreciation amounts in early years. • First determine the sum of digits from 1 to n, or SUM. SUM = n(n + 1)/2 • Depreciation charge for each year t is: Depreciable years remaining basis salvage Sum of years digits t D 1 SUM n t B S Spreadsheet function for Dt: = SYD(B,S,n,t)
32.
© McGraw Hill
32 Section 12.5 – SYD Depreciation - Example • Let B = $100,000, n = 10 and S = 0 SUM = 10(11)/2 = 55 D1 = [(10-1+1)/55] × 100,000 = $18,182 Largest, year 1 D5 = [(10-5+1)/55] × 100,000 = $10,909 Smaller amount D10 = [(10-10+1)/55] × 100,000 = $1818 Lowest, year n Function: = SYD(100000,0,10,t) for t = 1, 2,…, 10
33.
© McGraw Hill
33 Section 12.6 – Switching Between Methods • Objective of switching methods is to maximize PW of total depreciation. The relation to maximize is: ( , , ) 1 PW t n D t t D P F i t • Maximizing PWD will minimize PW of taxes paid over entire recovery period. • As mentioned earlier, MACRS includes embedded switching from DDB (n = 3, 5, 7, and 10) or 150% DB (n = 15 and 20) to SL rates to improve the tax deduction.
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34 Section 12.6 – Rules for Switching General rules for switching between two methods Usually, DB method to SL method works best 1. Switch to new method in year that its Dt exceeds the current method’s Dt. 2. Can switch only one time during recovery period. 3. Never depreciate below estimated S, if there is one (Not a problem for MACRS, since all of B is removed.) 4. When no switch is made, the BVt is used as the basis for next year’s depreciation calculation and switching decision in year t+1. Note: MACRS uses these rules to determine the annual rates, with the half-year convention imposed in years 1 and n+1.
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35 Section 12.6 – Switching - Relations for Steps 1 and 2 Procedure to switch from DDB to SL 1. For each year t, compute the two depreciation charges. For DBB: DDB 1 (BV ) t D d For SL: 1 SL BV 1 t D n t 2. The depreciation for each year is DDB SL max[ , ] t D D D VDB function displays annual Dt for DB-to-SL switch. (Illustrated in next section.)
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36 Section 12.6 – Switching DDB-to-SL - Example 12.5 1 B = $100,000 n = 5 years i = 15% per year Apply DDB-to-SL switching and determine PWD Access the text alternative for slide images.
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37 Section 12.6 – Switching Methods – Example 12.5 2 Year t DDB Model at DDDB DDB Model at BVt SL Model DSL Larger Dt (P/F,15% ,t) Factor Present Worth of Dt 0 — $100,000 1 $40,000 60,000 $20,000 $ 40,000 0.8696 $34,784 2 24,000 36,000 15,000 24,000 0.7561 18,146 3 14,400 21,600 12,000 14,400 0.6575 9,468 4* 8,640 12,960 10,800 10,800 0.5718 6,175 5 5,184 7,776 10,800 0.4972 5,370 Totals $92,224 10,800 $73,943 * Year of switch to SL • PW of depreciation with switching at i = 15% is $73,943 • PW for SL: PWD = 20,000(P/A,15%,5) = $67,044
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38 Section 12.7 – Spreadsheet Functions 1 Functions for depreciation calculations • Straight Line: = SLN(B,S,n) Same Dt value each year. Double Declining Balance: = DDB(B,S,n,t,d) • Different value for each year t = 1, 2, …, n. • Fixed rate d is an entry between 1 (SL) and 2 (DDB). • Entry of d is optional; assumed 2 for DDB, if omitted. • Entry of d = 1.5 applies the 150% DB method.
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39 Section 12.7 – Spreadsheet Functions 2 More functions for depreciation calculations MACRS: = VDB(B,0,n,MAX(0,t-1.5),MIN(n,t-0.5),d) • There is no function to calculate MACRS directly; use VDB. • Salvage value S is entered as zero. • MAX and MIN functions replace start and end periods. • Rate d is entered as 2 (DDB) for MACRS recovery periods of n = 3, 5, 7, and 10 years. • Rate d is entered as 1.5 (150% DB) for MACRS recovery periods of n = 15 and 20 years. Switching: = VDB(B,S,n,start_pd,end_pd,d) • VDB automatically switches from DB or DDB to SL to max PWD. • Optional rate d is between 1 and 2; DDB assumed, if omitted. • start_pd and end_pd are always one year apart.
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40 Section 12.7 – Spreadsheet - SL - Example 12.6 1 B = $500,000 S = $5,000 n = 5 years (a) Straight Line function: = SLN(500000,5000,5) Access the text alternative for slide images.
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41 Section 12.7 – Spreadsheet - DDB/DB - Example 12.6 2 B = $500,000 S = $5,000 n = 5 years (b) DDB function:= DDB(500000,5000,5,t,2) Optional (c) 150% DB function: = DDB(500000,5000,5,t,1.5) Not optional Access the text alternative for slide images.
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42 Section 12.7 – Spreadsheet - MACRS - Example 12.6 3 B = $500,000 S = $5,000 n = 5 years (d) MACRS function (for t = 1, 2, 3, 4, 5, 6) = VDB(500000,0,5,MAX(0,t-1.5),MIN(5,t-0.5),2) Salvage, S = 0 is required in VDB function Factor Insert 2 for n = 3, 5, 7, 10 Insert 1.5 for n = 15, 20 MACRS using VDB function, year 6 = VDB (500000,0,5,MAX(O,Al2-1.5),MIN(5,A12-0.5),2) Access the text alternative for slide images.
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43 Section 12.7 – Spreadsheet - MACRS - Example 12.6 4 B = $500,000 S = $5,000 n = 5 years (e) DDB-to-SL switch function: = VDB(500000,5000,5,t,t+1) Salvage, S = 5000 is required as an entry now in VDB function Switch from DDB to SL occurs in year 4 VDB function for switching, years 3 to 4 = VBD(500000,5000,5,A 9,A 10) Access the text alternative for slide images.
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44 Section 12.7 – Spreadsheet - MACRS - Example 12.6 5 (f) Graph of BV versus years for all 5 models Conclusions: DDB-to-SL switch is most accelerated. MACRS ignores S completely; may cause recaptured depreciation (RD) when sold.
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45 Section 12.8 – Depletion - Overview Depreciation is applied to assets that can be replaced – computers, machines, etc. Depletion applies to natural resources not easily replaced, such as: • Forests (timber). • Geothermal deposits. • Mineral deposits and quarries (gold and other ores, gravel, copper, zinc, etc.). • Oil and gas wells. Two methods of depletion: • Percentage depletion. • Cost depletion.
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46 Section 12.8 – Percentage Depletion • This method is a special consideration for natural resources. • Constant percentage of resource’s gross income (GI) is depleted each year, provided it does not exceed 50% of the firm’s taxable income. Deposit Percentage Sulfur, uranium, lead, nickel. Zinc, and some other ores and minerals 22% Gold, silver. copper. iron ore, and some oil shale 15 Oil and natural gas wells 15 Coal, lignite, sodium chloride 10 Gravel, sand, some stones 5 Most other minerals, metallic ores 14 • Annual depletion allowance is: Percentage depletion = allowed percentage × GI • Total depletion may exceed first cost of resource.
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47 Section 12.8 – Percentage Depletion - Example 12.7 Gold mine costs $10 M. Gross income per year was: GI = $8 M for years 1 to 5 GI = $5 M thereafter Determine annual depletion Assume annual depletion will not exceed 50% of TI. Percentage depletion for gold is 15% of GI. Years 1 to 5: Depletion = 0.15(8 M) = $1.2 M Years 6+: Depletion = 0.15(5 M) = $750,000 Years to recover initial cost of $10 M: • Years 1 to 5 recovers 1.2 M × 5 = $6 M • $4 M left at $750,000 per year • Total recovery in 5 + (4 M/0.75 M) = 10.3 years
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48 Section 12.8 – Cost Depletion • Annual depletion based on level of activity or usage of natural resource. • Initially, calculate the cost depletion factor pt using: First cost Resource capacity t p • Annual cost depletion charge is: pt × annual activity level • Total cost depletion can not exceed first cost of resource. • If resource capacity changes (re-estimated), new pt is determined.
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49 Section 12.8 – Cost Depletion - Example 12.8 • $700,000 paid for timber cutting rights. • Estimated 350 M board-feet will be harvested. • 15 M and 22 M board-feet are harvested in years 1 and 2, respectively. Determine cost depletion amounts. pt = 700,000/350 = $2,000/M board-feet Year 1: Depletion = 2,000(15) = $30,000 Year 2: Depletion = 2,000(22) = $44,000 After 2 years, re-estimate due to pine bark beetle damage indicates remaining timber at only 250 M board-feet. Find new pt. New pt = (700,000 − 74,000)/250 = $2,504/M board-feet
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