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Gibbs flow transport for Bayesian inference
Jeremy Heng
ESSEC Business School
Joint work with Arnaud Doucet (Oxford) & Yvo Pokern (UCL)
SciCADE 2019
Selected topics in computation and dynamics: machine learning and
multiscale methods
Innsbruck
22 July 2019
Jeremy Heng Flow transport 1/ 23
Problem specification
• Target distribution on Rd
⇡(dx) =
(x) dx
Z
where : Rd
! R+ can be evaluated pointwise and
Z =
Z
Rd
(x) dx
is unknown
• Problem 1: Obtain consistent estimator of ⇡(') :=
R
Rd '(x) ⇡(dx)
• Problem 2: Obtain unbiased and consistent estimator of Z
• Main challenge: dimension d is typically large
Jeremy Heng Flow transport 2/ 23
Motivation: Bayesian computation
• Prior distribution ⇡0 on unknown parameters of a model
• Likelihood function L : Rd
! R+ of data y
• Bayes update gives posterior distribution on Rd
⇡(dx) =
⇡0(x)L(x) dx
Z
,
where Z =
R
Rd ⇡0(x)L(x) dx is the marginal likelihood of y
• Problem: ⇡(') and Z are typically intractable
• Main challenge: complex models require large number of
parameters d
Jeremy Heng Flow transport 3/ 23
Monte Carlo methods
• Typically sampling from ⇡ is intractable, so we rely on Markov
chain Monte Carlo (MCMC) methods
• MCMC constructs a ⇡-invariant Markov transition kernel
K : Rd
⇥ B(Rd
) ! [0, 1]
• Sample X0 ⇠ ⇡0 and iterate Xn ⇠ K(Xn 1, ·) until convergence
• MCMC methods have been successful in many applications, but can
also fail in practice, for e.g. when ⇡ is highly multi-modal
Jeremy Heng Flow transport 4/ 23
Annealed importance sampling
• If ⇡0 and ⇡ are distant, define bridges
⇡ m
(dx) =
⇡0(x)L(x) m
dx
Z( m)
,
with 0 = 0 < 1 < . . . < M = 1 so
that ⇡1 = ⇡
• Initialize X0 ⇠ ⇡0 and move Xm ⇠ Km(Xm 1, ·) for m = 1, . . . , M,
where Km is ⇡ m -invariant
• Annealed importance sampling constructs w : (Rd
)M+1
! R+ so
that
⇡(') =
E ['(XM )w(X0:M )]
E [w(X0:M )]
, Z = E [w(X0:M )]
• AIS (Neal, 2001) and SMC samplers (Del Moral et al., 2006) are
considered state-of-the-art in statistics and machine learning
Jeremy Heng Flow transport 5/ 23
Jarzynski nonequilibrium equality
• Consider M ! 1, i.e. define the curve
of distribution {⇡t}t2[0,1]
⇡t(dx) =
⇡0(x)L(x) (t)
dx
Z(t)
,
where : [0, 1] ! [0, 1] is a strictly
increasing C1
function
• Initialize X0 ⇠ ⇡0 and run time-inhomogenous Langevin dynamics
dXt =
1
2
r log ⇡t(Xt)dt + dWt, t 2 [0, 1]
• Jarzynski equality (Jarzynski, 1997; Crooks, 1998) constructs
w : C([0, 1], Rd
) ! R+ so that
⇡(') =
E
⇥
'(X1)w(X[0,1])
⇤
E
⇥
w(X[0,1])
⇤ , Z = E
⇥
w(X[0,1])
⇤
Jeremy Heng Flow transport 6/ 23
Optimal dynamics
• Dynamical lag kLaw(Xt) ⇡tk impacts variance of estimators
• Vaikuntanathan & Jarzynski (2011) considered adding drift
f : [0, 1] ⇥ Rd
! Rd
to reduce lag
dXt = f (t, Xt)dt +
1
2
r log ⇡t(Xt)dt + dWt, t 2 [0, 1], X0 ⇠ ⇡0
• An optimal choice of f results in zero lag, i.e. Xt ⇠ ⇡t for t 2 [0, 1],
and zero variance estimator of Z
• Any optimal choice f satisfies Liouville PDE/continuity equation
r · (⇡t(x)f (t, x)) = @t⇡t(x)
• Zero lag also achieved by running deterministic dynamics
dXt = f (t, Xt)dt, X0 ⇠ ⇡0
• Main idea: solve Liouville PDE for f and run ODE to get trajectory
Jeremy Heng Flow transport 7/ 23
Time evolution of distributions
• Time evolution of ⇡t is given by
@t⇡t(x) = 0
(t) (log L(x) It) ⇡t(x),
where
It =
1
0(t)
d
dt
log Z(t)
!
= E⇡t
[log L(Xt)] < 1
• Integrating recovers path sampling (Gelman and Meng, 1998) or
thermodynamic integration (Kirkwood, 1935) identity
log
✓
Z(1)
Z(0)
◆
=
Z 1
0
0
(t)It dt.
Jeremy Heng Flow transport 8/ 23
Defining the flow transport problem
• We want to solve the Liouville equation
r · (⇡t(x)f (t, x)) = @t⇡t(x),
for a drift f ... but not all solutions will work!
• Validity relies on following result:
Theorem. Ambrosio et al. (2005)
Under the following assumptions:
A1 f is locally Lipschitz;
A2
R 1
0
R
Rd |f (t, x)|⇡t(x) dx dt < 1;
Eulerian Liouville PDE () Lagrangian ODE
• Define flow transport problem as solving Liouville for f that
satisfies [A1] & [A2]
Jeremy Heng Flow transport 9/ 23
Ill-posedness and regularization
• Under-determined: consider ⇡t = N((0, 0) , I2) for t 2 [0, 1],
f (x1, x2) = (0, 0) and f (x1, x2) = ( x2, x1)
are both solutions
• Regularization: seek minimal kinetic energy solution
argminf
⇢Z 1
0
Z
Rd
|f (t, x)|2
⇡t(x) dx dt : f solves Liouville
Euler-Lagrange
=) f ⇤
(t, x) = r t(x) where r · (⇡t(x)r t(x)) = @t⇡t(x)
• Analytical solution available when distributions are (mixtures of)
Gaussians (Reich, 2012)
Jeremy Heng Flow transport 10/ 23
Flow transport problem on R
• Minimal kinetic energy solution
f (t, x) =
R x
1
@t⇡t(u) du
⇡t(x)
• Checking Liouville
r · (⇡t(x)f (t, x)) = @x
Z x
1
@t⇡t(u) du = @t⇡t(x)
A1 For f to be locally Lipschitz, assume
⇡0, L 2 C1
(R, R+) =) f 2 C1
([0, 1] ⇥ R, R)
A2 For integrability of
R 1
0
R
Rd |f (t, x)|⇡t(x) dx dt < 1, necessarily
|⇡tf |(t, x) =
Z x
1
@t⇡t(u) du ! 0 as |x| ! 1
since
R 1
1
@t⇡t(u) du = 0
• Optimality: f (t, x) = r t(x) holds trivially
Jeremy Heng Flow transport 11/ 23
Flow transport problem on R
• Re-write solution as
f (t, x) =
0
(t)It {Ft(x) Ix
t /It}
⇡t(x)
where Ix
t = E⇡t
[ ( 1,x] log L(Xt)] and Ft is CDF of ⇡t
• Speed is controlled by 0
(t) and ⇡t(x)
• Sign is given by di↵erence between Ft(x) and Ix
t /It 2 [0, 1]
Jeremy Heng Flow transport 12/ 23
Flow transport problem on Rd
, d 1
• Multivariate solution for d = 3
(⇡tf1)(t, x1:3) =
Z x1
1
@t⇡t(u1, x2, x3) du1
+ g1(t, x1)
Z 1
1
@t⇡t(u1, x2, x3) du1
(⇡tf2)(t, x1:3) = g0
1(t, x1)
Z 1
1
Z x2
1
@t⇡t(u1, u2, x3) du1:2
+ g0
1(t, x1)g2(t, x2)
Z 1
1
Z 1
1
@t⇡t(u1, u2, x3) du1:2
(⇡tf3)(t, x1:3) = g0
1(t, x1)g0
2(t, x2)
Z 1
1
Z 1
1
Z x3
1
@t⇡t(u1, u2, u3) du1:3
where g1, g2 2 C2
([0, 1] ⇥ R, [0, 1])
Jeremy Heng Flow transport 13/ 23
Flow transport problem on Rd
, d 1
• Checking Liouville
@x1 (⇡tf1)(t, x1:3) = @t⇡t(x1, x2, x3)
+ g0
1(t, x1)
Z 1
1
@t⇡t(u1, x2, x3) du1
@x2 (⇡tf2)(t, x1:3) = g0
1(t, x1)
Z 1
1
@t⇡t(u1, x2, x3) du1:2
+ g0
1(t, x1)g0
2(t, x2)
Z 1
1
Z 1
1
@t⇡t(u1, u2, x3) du1:2
@x3 (⇡tf3)(t, x1:3) = g0
1(t, x1)g0
2(t, x2)
Z 1
1
Z 1
1
@t⇡t(u1, u2, x3) du1:2
• Taking divergence gives telescopic sum
r · (⇡tf )(t, x1:3) =
3X
i=1
@xi
(⇡tfi )(t, x1:3) = @t⇡t(x1:3)
Jeremy Heng Flow transport 14/ 23
Flow transport problem on Rd
, d 1
A1 For f to be locally Lipschitz, assume
⇡0, L 2 C1
(Rd
, R+) =) f 2 C1
([0, 1] ⇥ Rd
, Rd
)
A2 For integrability of
R 1
0
R
Rd |f (t, x)|⇡t(x) dx dt < 1, necessarily
|⇡tf |(t, x)| ! 0 as |x| ! 1
if {gi } are non-decreasing functions with tail behaviour
gi (t, xi ) ! 0 as xi ! 1,
gi (t, xi ) ! 1 as xi ! 1
• Choosing gi (t, xi ) = Ft(xi ) as marginal CDF of ⇡t allows f to
decouple if distributions are independent
Jeremy Heng Flow transport 15/ 23
Approximate Gibbs flow transport
• Solution involved integrals of increasing dimension as it tracks
increasing conditional distributions
⇡t(x1|x2:d ), ⇡t(x2|3:d ), . . . , ⇡t(xd ), xi 2 R
• Trade-o↵ accuracy for computational tractability: track full
conditional distributions
⇡t(xi |x i ), xi 2 R
• System of Liouville equations
@xi
·
n
⇡t(xi |x i )˜fi (t, x)
o
= @t⇡t(xi |x i ),
each defined on (0, 1) ⇥ R
Jeremy Heng Flow transport 16/ 23
Approximate Gibbs flow transport
• The solution is
˜fi (t, x) =
R xi
1
@t⇡t(ui |x i ) dui
⇡t(xi |x i )
• If ⇡0, L 2 C1
(Rd
, R+) with appropriate tail behaviour, the ODE
dXt = ˜f (t, Xt)dt, X0 ⇠ ⇡0
admits a unique solution on [0, 1], referred to as Gibbs flow
Jeremy Heng Flow transport 17/ 23
Error control
• Define local error
"t(x) = @t⇡t(x) + r · (⇡t(x)˜f (t, x))
= @t⇡t(x)
dX
i=1
@t⇡t(xi |x i )⇡t(x i )
• Gibbs flow exploits local independence:
⇡t(x) =
dY
i=1
⇡t(xi ) =) "t(x) = 0
• If Gibbs flow induces {˜⇡t}t2[0,1] with ˜⇡0 = ⇡0
k˜⇡t ⇡tk2
L2  t
Z t
0
k"uk2
L2 du · exp
✓
1 +
Z t
0
kr · ˜f (u, ·) k1 du
◆
Jeremy Heng Flow transport 18/ 23
Numerical implementation of Gibbs flow
• Implementation of the Gibbs flow involves one-dimensional
quadrature and numerical integration
• Previously, we considered the forward Euler scheme
Ym = Ym 1 + t ˜f (tm 1, Ym 1) = m(Ym 1)
• To get Law(Ym), we need Jacobian determinant of m which
typically costs O(d3
)
• In contrast, this scheme that cycles through each dimension
Ym[i] = Ym 1[i] + t ˜f (tm 1, Ym[1 : i 1], Ym 1[i : d])
Ym = m,d · · · m,1(Ym 1)
is also order one, but costs O(d)
Jeremy Heng Flow transport 19/ 23
Mixture modelling example
• Lack of identifiability induces ⇡ on R4
with 4! = 24 well-separated
and identical modes
• Gibbs flow approximation
t =0.0006
x1
x2
−10 −5 0 5 10
−10
−5
0
5
10
t =0.0058
x1
x2
−10 −5 0 5 10
−10
−5
0
5
10
t =0.0542
x1
x2
−10 −5 0 5 10
−10
−5
0
5
10
t =1.0000
x1
x2
−10 −5 0 5 10
−10
−5
0
5
10
Jeremy Heng Flow transport 20/ 23
Mixture modelling example
• Proportion of samples in each of the 24 modes
0.00
0.01
0.02
0.03
0.04
1 2 3 4 5 6 7 8 9 101112131415161718192021222324
Mode
Proportionofparticles
• Pearson’s Chi-squared test for uniformity gives p-value of 0.85
Jeremy Heng Flow transport 21/ 23
Cox point process model
• E↵ective sample size % in dimension d
• AIS: AIS with HMC moves
• GF-SIS: Gibbs flow
• GF-AIS: Gibbs flow with HMC moves
0
25
50
75
100
0.00 0.25 0.50 0.75 1.00
time
ESS%
method AIS GF−SIS GF−AIS
d = 100
0
25
50
75
100
0.00 0.25 0.50 0.75 1.00
time
ESS%
method AIS GF−SIS GF−AIS
d = 225
0
25
50
75
100
0.00 0.25 0.50 0.75 1.00
time
ESS%
method AIS GF−SIS GF−AIS
d = 400
Jeremy Heng Flow transport 22/ 23
End
• Slides will be uploaded to my webpage
• Heng, J., Doucet, A., & Pokern, Y. (2015). Gibbs Flow for
Approximate Transport with Applications to Bayesian Computation.
arXiv preprint arXiv:1509.08787.
• Updated article and R package coming soon!
Jeremy Heng Flow transport 23/ 23

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Gibbs flow transport for Bayesian inference

  • 1. Gibbs flow transport for Bayesian inference Jeremy Heng ESSEC Business School Joint work with Arnaud Doucet (Oxford) & Yvo Pokern (UCL) SciCADE 2019 Selected topics in computation and dynamics: machine learning and multiscale methods Innsbruck 22 July 2019 Jeremy Heng Flow transport 1/ 23
  • 2. Problem specification • Target distribution on Rd ⇡(dx) = (x) dx Z where : Rd ! R+ can be evaluated pointwise and Z = Z Rd (x) dx is unknown • Problem 1: Obtain consistent estimator of ⇡(') := R Rd '(x) ⇡(dx) • Problem 2: Obtain unbiased and consistent estimator of Z • Main challenge: dimension d is typically large Jeremy Heng Flow transport 2/ 23
  • 3. Motivation: Bayesian computation • Prior distribution ⇡0 on unknown parameters of a model • Likelihood function L : Rd ! R+ of data y • Bayes update gives posterior distribution on Rd ⇡(dx) = ⇡0(x)L(x) dx Z , where Z = R Rd ⇡0(x)L(x) dx is the marginal likelihood of y • Problem: ⇡(') and Z are typically intractable • Main challenge: complex models require large number of parameters d Jeremy Heng Flow transport 3/ 23
  • 4. Monte Carlo methods • Typically sampling from ⇡ is intractable, so we rely on Markov chain Monte Carlo (MCMC) methods • MCMC constructs a ⇡-invariant Markov transition kernel K : Rd ⇥ B(Rd ) ! [0, 1] • Sample X0 ⇠ ⇡0 and iterate Xn ⇠ K(Xn 1, ·) until convergence • MCMC methods have been successful in many applications, but can also fail in practice, for e.g. when ⇡ is highly multi-modal Jeremy Heng Flow transport 4/ 23
  • 5. Annealed importance sampling • If ⇡0 and ⇡ are distant, define bridges ⇡ m (dx) = ⇡0(x)L(x) m dx Z( m) , with 0 = 0 < 1 < . . . < M = 1 so that ⇡1 = ⇡ • Initialize X0 ⇠ ⇡0 and move Xm ⇠ Km(Xm 1, ·) for m = 1, . . . , M, where Km is ⇡ m -invariant • Annealed importance sampling constructs w : (Rd )M+1 ! R+ so that ⇡(') = E ['(XM )w(X0:M )] E [w(X0:M )] , Z = E [w(X0:M )] • AIS (Neal, 2001) and SMC samplers (Del Moral et al., 2006) are considered state-of-the-art in statistics and machine learning Jeremy Heng Flow transport 5/ 23
  • 6. Jarzynski nonequilibrium equality • Consider M ! 1, i.e. define the curve of distribution {⇡t}t2[0,1] ⇡t(dx) = ⇡0(x)L(x) (t) dx Z(t) , where : [0, 1] ! [0, 1] is a strictly increasing C1 function • Initialize X0 ⇠ ⇡0 and run time-inhomogenous Langevin dynamics dXt = 1 2 r log ⇡t(Xt)dt + dWt, t 2 [0, 1] • Jarzynski equality (Jarzynski, 1997; Crooks, 1998) constructs w : C([0, 1], Rd ) ! R+ so that ⇡(') = E ⇥ '(X1)w(X[0,1]) ⇤ E ⇥ w(X[0,1]) ⇤ , Z = E ⇥ w(X[0,1]) ⇤ Jeremy Heng Flow transport 6/ 23
  • 7. Optimal dynamics • Dynamical lag kLaw(Xt) ⇡tk impacts variance of estimators • Vaikuntanathan & Jarzynski (2011) considered adding drift f : [0, 1] ⇥ Rd ! Rd to reduce lag dXt = f (t, Xt)dt + 1 2 r log ⇡t(Xt)dt + dWt, t 2 [0, 1], X0 ⇠ ⇡0 • An optimal choice of f results in zero lag, i.e. Xt ⇠ ⇡t for t 2 [0, 1], and zero variance estimator of Z • Any optimal choice f satisfies Liouville PDE/continuity equation r · (⇡t(x)f (t, x)) = @t⇡t(x) • Zero lag also achieved by running deterministic dynamics dXt = f (t, Xt)dt, X0 ⇠ ⇡0 • Main idea: solve Liouville PDE for f and run ODE to get trajectory Jeremy Heng Flow transport 7/ 23
  • 8. Time evolution of distributions • Time evolution of ⇡t is given by @t⇡t(x) = 0 (t) (log L(x) It) ⇡t(x), where It = 1 0(t) d dt log Z(t) ! = E⇡t [log L(Xt)] < 1 • Integrating recovers path sampling (Gelman and Meng, 1998) or thermodynamic integration (Kirkwood, 1935) identity log ✓ Z(1) Z(0) ◆ = Z 1 0 0 (t)It dt. Jeremy Heng Flow transport 8/ 23
  • 9. Defining the flow transport problem • We want to solve the Liouville equation r · (⇡t(x)f (t, x)) = @t⇡t(x), for a drift f ... but not all solutions will work! • Validity relies on following result: Theorem. Ambrosio et al. (2005) Under the following assumptions: A1 f is locally Lipschitz; A2 R 1 0 R Rd |f (t, x)|⇡t(x) dx dt < 1; Eulerian Liouville PDE () Lagrangian ODE • Define flow transport problem as solving Liouville for f that satisfies [A1] & [A2] Jeremy Heng Flow transport 9/ 23
  • 10. Ill-posedness and regularization • Under-determined: consider ⇡t = N((0, 0) , I2) for t 2 [0, 1], f (x1, x2) = (0, 0) and f (x1, x2) = ( x2, x1) are both solutions • Regularization: seek minimal kinetic energy solution argminf ⇢Z 1 0 Z Rd |f (t, x)|2 ⇡t(x) dx dt : f solves Liouville Euler-Lagrange =) f ⇤ (t, x) = r t(x) where r · (⇡t(x)r t(x)) = @t⇡t(x) • Analytical solution available when distributions are (mixtures of) Gaussians (Reich, 2012) Jeremy Heng Flow transport 10/ 23
  • 11. Flow transport problem on R • Minimal kinetic energy solution f (t, x) = R x 1 @t⇡t(u) du ⇡t(x) • Checking Liouville r · (⇡t(x)f (t, x)) = @x Z x 1 @t⇡t(u) du = @t⇡t(x) A1 For f to be locally Lipschitz, assume ⇡0, L 2 C1 (R, R+) =) f 2 C1 ([0, 1] ⇥ R, R) A2 For integrability of R 1 0 R Rd |f (t, x)|⇡t(x) dx dt < 1, necessarily |⇡tf |(t, x) = Z x 1 @t⇡t(u) du ! 0 as |x| ! 1 since R 1 1 @t⇡t(u) du = 0 • Optimality: f (t, x) = r t(x) holds trivially Jeremy Heng Flow transport 11/ 23
  • 12. Flow transport problem on R • Re-write solution as f (t, x) = 0 (t)It {Ft(x) Ix t /It} ⇡t(x) where Ix t = E⇡t [ ( 1,x] log L(Xt)] and Ft is CDF of ⇡t • Speed is controlled by 0 (t) and ⇡t(x) • Sign is given by di↵erence between Ft(x) and Ix t /It 2 [0, 1] Jeremy Heng Flow transport 12/ 23
  • 13. Flow transport problem on Rd , d 1 • Multivariate solution for d = 3 (⇡tf1)(t, x1:3) = Z x1 1 @t⇡t(u1, x2, x3) du1 + g1(t, x1) Z 1 1 @t⇡t(u1, x2, x3) du1 (⇡tf2)(t, x1:3) = g0 1(t, x1) Z 1 1 Z x2 1 @t⇡t(u1, u2, x3) du1:2 + g0 1(t, x1)g2(t, x2) Z 1 1 Z 1 1 @t⇡t(u1, u2, x3) du1:2 (⇡tf3)(t, x1:3) = g0 1(t, x1)g0 2(t, x2) Z 1 1 Z 1 1 Z x3 1 @t⇡t(u1, u2, u3) du1:3 where g1, g2 2 C2 ([0, 1] ⇥ R, [0, 1]) Jeremy Heng Flow transport 13/ 23
  • 14. Flow transport problem on Rd , d 1 • Checking Liouville @x1 (⇡tf1)(t, x1:3) = @t⇡t(x1, x2, x3) + g0 1(t, x1) Z 1 1 @t⇡t(u1, x2, x3) du1 @x2 (⇡tf2)(t, x1:3) = g0 1(t, x1) Z 1 1 @t⇡t(u1, x2, x3) du1:2 + g0 1(t, x1)g0 2(t, x2) Z 1 1 Z 1 1 @t⇡t(u1, u2, x3) du1:2 @x3 (⇡tf3)(t, x1:3) = g0 1(t, x1)g0 2(t, x2) Z 1 1 Z 1 1 @t⇡t(u1, u2, x3) du1:2 • Taking divergence gives telescopic sum r · (⇡tf )(t, x1:3) = 3X i=1 @xi (⇡tfi )(t, x1:3) = @t⇡t(x1:3) Jeremy Heng Flow transport 14/ 23
  • 15. Flow transport problem on Rd , d 1 A1 For f to be locally Lipschitz, assume ⇡0, L 2 C1 (Rd , R+) =) f 2 C1 ([0, 1] ⇥ Rd , Rd ) A2 For integrability of R 1 0 R Rd |f (t, x)|⇡t(x) dx dt < 1, necessarily |⇡tf |(t, x)| ! 0 as |x| ! 1 if {gi } are non-decreasing functions with tail behaviour gi (t, xi ) ! 0 as xi ! 1, gi (t, xi ) ! 1 as xi ! 1 • Choosing gi (t, xi ) = Ft(xi ) as marginal CDF of ⇡t allows f to decouple if distributions are independent Jeremy Heng Flow transport 15/ 23
  • 16. Approximate Gibbs flow transport • Solution involved integrals of increasing dimension as it tracks increasing conditional distributions ⇡t(x1|x2:d ), ⇡t(x2|3:d ), . . . , ⇡t(xd ), xi 2 R • Trade-o↵ accuracy for computational tractability: track full conditional distributions ⇡t(xi |x i ), xi 2 R • System of Liouville equations @xi · n ⇡t(xi |x i )˜fi (t, x) o = @t⇡t(xi |x i ), each defined on (0, 1) ⇥ R Jeremy Heng Flow transport 16/ 23
  • 17. Approximate Gibbs flow transport • The solution is ˜fi (t, x) = R xi 1 @t⇡t(ui |x i ) dui ⇡t(xi |x i ) • If ⇡0, L 2 C1 (Rd , R+) with appropriate tail behaviour, the ODE dXt = ˜f (t, Xt)dt, X0 ⇠ ⇡0 admits a unique solution on [0, 1], referred to as Gibbs flow Jeremy Heng Flow transport 17/ 23
  • 18. Error control • Define local error "t(x) = @t⇡t(x) + r · (⇡t(x)˜f (t, x)) = @t⇡t(x) dX i=1 @t⇡t(xi |x i )⇡t(x i ) • Gibbs flow exploits local independence: ⇡t(x) = dY i=1 ⇡t(xi ) =) "t(x) = 0 • If Gibbs flow induces {˜⇡t}t2[0,1] with ˜⇡0 = ⇡0 k˜⇡t ⇡tk2 L2  t Z t 0 k"uk2 L2 du · exp ✓ 1 + Z t 0 kr · ˜f (u, ·) k1 du ◆ Jeremy Heng Flow transport 18/ 23
  • 19. Numerical implementation of Gibbs flow • Implementation of the Gibbs flow involves one-dimensional quadrature and numerical integration • Previously, we considered the forward Euler scheme Ym = Ym 1 + t ˜f (tm 1, Ym 1) = m(Ym 1) • To get Law(Ym), we need Jacobian determinant of m which typically costs O(d3 ) • In contrast, this scheme that cycles through each dimension Ym[i] = Ym 1[i] + t ˜f (tm 1, Ym[1 : i 1], Ym 1[i : d]) Ym = m,d · · · m,1(Ym 1) is also order one, but costs O(d) Jeremy Heng Flow transport 19/ 23
  • 20. Mixture modelling example • Lack of identifiability induces ⇡ on R4 with 4! = 24 well-separated and identical modes • Gibbs flow approximation t =0.0006 x1 x2 −10 −5 0 5 10 −10 −5 0 5 10 t =0.0058 x1 x2 −10 −5 0 5 10 −10 −5 0 5 10 t =0.0542 x1 x2 −10 −5 0 5 10 −10 −5 0 5 10 t =1.0000 x1 x2 −10 −5 0 5 10 −10 −5 0 5 10 Jeremy Heng Flow transport 20/ 23
  • 21. Mixture modelling example • Proportion of samples in each of the 24 modes 0.00 0.01 0.02 0.03 0.04 1 2 3 4 5 6 7 8 9 101112131415161718192021222324 Mode Proportionofparticles • Pearson’s Chi-squared test for uniformity gives p-value of 0.85 Jeremy Heng Flow transport 21/ 23
  • 22. Cox point process model • E↵ective sample size % in dimension d • AIS: AIS with HMC moves • GF-SIS: Gibbs flow • GF-AIS: Gibbs flow with HMC moves 0 25 50 75 100 0.00 0.25 0.50 0.75 1.00 time ESS% method AIS GF−SIS GF−AIS d = 100 0 25 50 75 100 0.00 0.25 0.50 0.75 1.00 time ESS% method AIS GF−SIS GF−AIS d = 225 0 25 50 75 100 0.00 0.25 0.50 0.75 1.00 time ESS% method AIS GF−SIS GF−AIS d = 400 Jeremy Heng Flow transport 22/ 23
  • 23. End • Slides will be uploaded to my webpage • Heng, J., Doucet, A., & Pokern, Y. (2015). Gibbs Flow for Approximate Transport with Applications to Bayesian Computation. arXiv preprint arXiv:1509.08787. • Updated article and R package coming soon! Jeremy Heng Flow transport 23/ 23