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PROBABILITY DISTRIBUTION
β—¦Objectives:
At the end of the lesson, the students will be able to:
β—¦ define the probability distribution of discrete random variable;
β—¦ familiarize themselves with the steps of constructing probability
distribution of discrete random variable;
β—¦ construct probability distribution of discrete random variable.
Probability is
the
mathematics of
chance.
𝐴 π‘£π‘Žπ‘Ÿπ‘–π‘Žπ‘π‘™π‘’ 𝑖𝑠 π‘ π‘Žπ‘–π‘‘ π‘‘π‘œ 𝑏𝑒 π‘‘π‘–π‘ π‘π‘Ÿπ‘’π‘‘π‘’ π‘Žπ‘›π‘‘ π‘Ÿπ‘Žπ‘›π‘‘π‘œπ‘š 𝑖𝑓 𝑖𝑑 π‘π‘Žπ‘› π‘‘π‘Žπ‘˜π‘’
π‘œπ‘›π‘™π‘¦ π‘π‘’π‘Ÿπ‘‘π‘Žπ‘–π‘› π‘£π‘Žπ‘™π‘’π‘’π‘  π‘‘β„Žπ‘Žπ‘‘ π‘œπ‘π‘π‘’π‘Ÿ 𝑏𝑦 π‘β„Žπ‘Žπ‘›π‘π‘’.
𝐴 π‘£π‘Žπ‘Ÿπ‘–π‘Žπ‘π‘™π‘’ 𝑖𝑠 π‘‘π‘’π‘›π‘œπ‘‘π‘’π‘‘ 𝑏𝑦 π‘Žπ‘› π‘’π‘π‘π‘’π‘Ÿ βˆ’ π‘π‘Žπ‘ π‘’ π‘™π‘’π‘‘π‘‘π‘’π‘Ÿ π‘Žπ‘›π‘‘ 𝑖𝑑𝑠 π‘π‘œπ‘ π‘ π‘–π‘π‘™π‘’
π‘£π‘Žπ‘™π‘’π‘’π‘  𝑏𝑦 π‘‘β„Žπ‘’ π‘ π‘Žπ‘šπ‘’ π‘™π‘œπ‘€π‘’π‘Ÿ βˆ’ π‘π‘Žπ‘ π‘’ π‘™π‘’π‘‘π‘‘π‘’π‘Ÿπ‘ .
𝐿𝑒𝑑, 𝑋 = π‘›π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ β„Žπ‘’π‘Žπ‘‘π‘ 
π‘₯ = 0,1,2
Consider tossing two fair coins, and you record the number
of heads obtained.
Probability distributions
βˆ’π‘–π‘  π‘Ž π‘‘π‘–π‘ π‘π‘™π‘Žπ‘¦ π‘œπ‘“ π‘Žπ‘™π‘™ π‘‘β„Žπ‘’ π‘π‘œπ‘ π‘ π‘–π‘π‘™π‘’ π‘£π‘Žπ‘™π‘’π‘’π‘  π‘Žπ‘›π‘‘ π‘‘β„Žπ‘’π‘–π‘Ÿ
π‘π‘œπ‘Ÿπ‘Ÿπ‘’π‘ π‘π‘œπ‘›π‘‘π‘–π‘›π‘” π‘π‘Ÿπ‘œπ‘π‘Žπ‘π‘–π‘™π‘–π‘‘π‘–π‘’π‘  𝑖𝑛 π‘Ž 𝑔𝑖𝑣𝑒𝑛 π‘π‘Ÿπ‘œπ‘π‘Žπ‘π‘–π‘™π‘–π‘‘π‘¦ π‘‘π‘Ÿπ‘–π‘Žπ‘™π‘ .
βˆ’ π‘‘β„Žπ‘’ π‘’π‘ π‘’π‘Žπ‘™ π‘šπ‘’π‘‘β„Žπ‘œπ‘‘ π‘œπ‘“ π‘‘π‘–π‘ π‘π‘™π‘Žπ‘¦
𝑖𝑠 𝑏𝑦 π‘‘π‘Žπ‘π‘’π‘™π‘Žπ‘‘π‘–π‘œπ‘› 𝑖𝑛 π‘Ž π‘π‘Ÿπ‘œπ‘π‘Žπ‘π‘–π‘™π‘–π‘‘π‘¦ π‘‘π‘–π‘ π‘‘π‘Ÿπ‘–π‘π‘’π‘‘π‘–π‘œπ‘›
π‘‘π‘Žπ‘π‘™π‘’.
𝐿𝑒𝑑, 𝑋 = π‘›π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ β„Žπ‘’π‘Žπ‘‘π‘ 
π‘₯ = 0,1,2
Consider tossing two fair coins, and you record the number
of heads obtained.
x
Probability P(X=x)
π·π‘Ÿπ‘Žπ‘€ 𝑒𝑝 π‘‘β„Žπ‘’ π‘π‘Ÿπ‘œπ‘π‘Žπ‘π‘–π‘™π‘–π‘‘π‘¦ π‘‘π‘–π‘ π‘‘π‘Ÿπ‘–π‘π‘’π‘‘π‘–π‘œπ‘›
0 1 2
1
4
2
4
1
4
π‘‡π‘œπ‘‘π‘Žπ‘™
1
πΎπ‘’π‘¦π‘π‘œπ‘–π‘›π‘‘β€Ό!
Properties of Probability
Distribution.
(1)Sum of probabilities is
always equal to 1.
(2) Probability is always
positive.
x 0 1 2 3 4 5
P(X=x)
πŸ”
πŸ‘πŸ”
𝟏𝟎
πŸ‘πŸ”
πŸ–
πŸ‘πŸ”
πŸ”
πŸ‘πŸ”
πŸ’
πŸ‘πŸ”
𝟐
πŸ‘πŸ”
Two ordinary fair dice are thrown.
The resulting score is found as follows.
β€’ If the two dice show different numbers, the score is the smaller of the
two numbers.
β€’ If the two dice show equal numbers, the score is 0 .
Draw up the probability distribution for the score.
Example 1
x 1 2 3 4 5 6
1
2
3
4
5
6
At a garden centre, there is a display of roses:
25 are red
20 are white
15 are pink
5 are orange
Three roses are chosen at random.
π‘Ž. π·π‘Ÿπ‘Žπ‘€ 𝑒𝑝 π‘‘β„Žπ‘’ π‘π‘Ÿπ‘œπ‘π‘Žπ‘π‘–π‘™π‘–π‘‘π‘¦ π‘‘π‘–π‘ π‘‘π‘Ÿπ‘–π‘π‘’π‘‘π‘–π‘œπ‘› π‘‘π‘Žπ‘π‘™π‘’ π‘“π‘œπ‘Ÿ π‘‘β„Žπ‘’ π‘›π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“
π‘Ÿπ‘’π‘‘ π‘Ÿπ‘œπ‘ π‘’π‘  𝑠𝑒𝑙𝑒𝑐𝑑𝑒𝑑.
𝑏. 𝐹𝑖𝑛𝑑 π‘‘β„Žπ‘’ π‘π‘Ÿπ‘œπ‘π‘Žπ‘π‘–π‘™π‘–π‘‘π‘¦ π‘‘β„Žπ‘Žπ‘‘ π‘Žπ‘‘ π‘™π‘’π‘Žπ‘ π‘‘ π‘œπ‘›π‘’ π‘Ÿπ‘’π‘‘ π‘Ÿπ‘œπ‘ π‘’ 𝑖𝑠 𝑠𝑒𝑙𝑒𝑐𝑑𝑒𝑑.
𝑃 𝑅 β‰₯ 1 = 0.446 + 0.275 + 0.0527 = 0.774
Example 2
1 1 1 2 3
1
2
3
X
1 1 1 2 3
2 2 2 4 6
3 3 3 6 9
A fair 5 βˆ’ sided spinner has sides numbered 1,1,1,2,3. A fair three-sided has
sides numbered 1,2,3. Both spinners are spun once and the score is the
product of the numbers on the sides the spinners land on.
Draw up the probability distribution table for the score.
Example 3
A fair 4 βˆ’ sided die, numbered 1,2,3 and 5 is rolled twice.
The random variable X is the sum of the two numbers on which the
die comes to rest.
Draw up the probability distribution table for X and find P(X>6).
x
P(X=x)
+ 1 2 3 5
1
2
3
5
2 3 4 6
3 4 5 7
4 5 6 8
6 7 8 10
𝟐 πŸ‘ πŸ’ πŸ“ πŸ” πŸ• πŸ– 𝟏𝟎
𝟏
πŸπŸ”
𝟐
πŸπŸ”
πŸ‘
πŸπŸ”
𝟐
πŸπŸ”
πŸ‘
πŸπŸ”
𝟐
πŸπŸ”
𝟐
πŸπŸ”
𝟏
πŸπŸ”
𝒃. 𝑷 𝑿 > πŸ” = 𝑷 𝑿 = πŸ•, πŸ–, 𝟏𝟎
=
πŸ“
πŸπŸ”
Activity
Set A consists of ten digits 0,0,0,0,0,0,2,2,2,4
Set B consists of the seven digits 0,0,0,0,2,2,2
One digit is chosen at random from each set.
The random variable X is defined
as the sum of these two digits.
Draw up the probability distribution for the score.
Homework
π‘‡β„Žπ‘Žπ‘›π‘˜ π‘Œπ‘œπ‘’!

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Prob distribution.pptx

  • 2. β—¦Objectives: At the end of the lesson, the students will be able to: β—¦ define the probability distribution of discrete random variable; β—¦ familiarize themselves with the steps of constructing probability distribution of discrete random variable; β—¦ construct probability distribution of discrete random variable.
  • 4. 𝐴 π‘£π‘Žπ‘Ÿπ‘–π‘Žπ‘π‘™π‘’ 𝑖𝑠 π‘ π‘Žπ‘–π‘‘ π‘‘π‘œ 𝑏𝑒 π‘‘π‘–π‘ π‘π‘Ÿπ‘’π‘‘π‘’ π‘Žπ‘›π‘‘ π‘Ÿπ‘Žπ‘›π‘‘π‘œπ‘š 𝑖𝑓 𝑖𝑑 π‘π‘Žπ‘› π‘‘π‘Žπ‘˜π‘’ π‘œπ‘›π‘™π‘¦ π‘π‘’π‘Ÿπ‘‘π‘Žπ‘–π‘› π‘£π‘Žπ‘™π‘’π‘’π‘  π‘‘β„Žπ‘Žπ‘‘ π‘œπ‘π‘π‘’π‘Ÿ 𝑏𝑦 π‘β„Žπ‘Žπ‘›π‘π‘’. 𝐴 π‘£π‘Žπ‘Ÿπ‘–π‘Žπ‘π‘™π‘’ 𝑖𝑠 π‘‘π‘’π‘›π‘œπ‘‘π‘’π‘‘ 𝑏𝑦 π‘Žπ‘› π‘’π‘π‘π‘’π‘Ÿ βˆ’ π‘π‘Žπ‘ π‘’ π‘™π‘’π‘‘π‘‘π‘’π‘Ÿ π‘Žπ‘›π‘‘ 𝑖𝑑𝑠 π‘π‘œπ‘ π‘ π‘–π‘π‘™π‘’ π‘£π‘Žπ‘™π‘’π‘’π‘  𝑏𝑦 π‘‘β„Žπ‘’ π‘ π‘Žπ‘šπ‘’ π‘™π‘œπ‘€π‘’π‘Ÿ βˆ’ π‘π‘Žπ‘ π‘’ π‘™π‘’π‘‘π‘‘π‘’π‘Ÿπ‘ . 𝐿𝑒𝑑, 𝑋 = π‘›π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ β„Žπ‘’π‘Žπ‘‘π‘  π‘₯ = 0,1,2 Consider tossing two fair coins, and you record the number of heads obtained.
  • 5. Probability distributions βˆ’π‘–π‘  π‘Ž π‘‘π‘–π‘ π‘π‘™π‘Žπ‘¦ π‘œπ‘“ π‘Žπ‘™π‘™ π‘‘β„Žπ‘’ π‘π‘œπ‘ π‘ π‘–π‘π‘™π‘’ π‘£π‘Žπ‘™π‘’π‘’π‘  π‘Žπ‘›π‘‘ π‘‘β„Žπ‘’π‘–π‘Ÿ π‘π‘œπ‘Ÿπ‘Ÿπ‘’π‘ π‘π‘œπ‘›π‘‘π‘–π‘›π‘” π‘π‘Ÿπ‘œπ‘π‘Žπ‘π‘–π‘™π‘–π‘‘π‘–π‘’π‘  𝑖𝑛 π‘Ž 𝑔𝑖𝑣𝑒𝑛 π‘π‘Ÿπ‘œπ‘π‘Žπ‘π‘–π‘™π‘–π‘‘π‘¦ π‘‘π‘Ÿπ‘–π‘Žπ‘™π‘ . βˆ’ π‘‘β„Žπ‘’ π‘’π‘ π‘’π‘Žπ‘™ π‘šπ‘’π‘‘β„Žπ‘œπ‘‘ π‘œπ‘“ π‘‘π‘–π‘ π‘π‘™π‘Žπ‘¦ 𝑖𝑠 𝑏𝑦 π‘‘π‘Žπ‘π‘’π‘™π‘Žπ‘‘π‘–π‘œπ‘› 𝑖𝑛 π‘Ž π‘π‘Ÿπ‘œπ‘π‘Žπ‘π‘–π‘™π‘–π‘‘π‘¦ π‘‘π‘–π‘ π‘‘π‘Ÿπ‘–π‘π‘’π‘‘π‘–π‘œπ‘› π‘‘π‘Žπ‘π‘™π‘’.
  • 6. 𝐿𝑒𝑑, 𝑋 = π‘›π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ β„Žπ‘’π‘Žπ‘‘π‘  π‘₯ = 0,1,2 Consider tossing two fair coins, and you record the number of heads obtained. x Probability P(X=x) π·π‘Ÿπ‘Žπ‘€ 𝑒𝑝 π‘‘β„Žπ‘’ π‘π‘Ÿπ‘œπ‘π‘Žπ‘π‘–π‘™π‘–π‘‘π‘¦ π‘‘π‘–π‘ π‘‘π‘Ÿπ‘–π‘π‘’π‘‘π‘–π‘œπ‘› 0 1 2 1 4 2 4 1 4 π‘‡π‘œπ‘‘π‘Žπ‘™ 1
  • 8. x 0 1 2 3 4 5 P(X=x) πŸ” πŸ‘πŸ” 𝟏𝟎 πŸ‘πŸ” πŸ– πŸ‘πŸ” πŸ” πŸ‘πŸ” πŸ’ πŸ‘πŸ” 𝟐 πŸ‘πŸ” Two ordinary fair dice are thrown. The resulting score is found as follows. β€’ If the two dice show different numbers, the score is the smaller of the two numbers. β€’ If the two dice show equal numbers, the score is 0 . Draw up the probability distribution for the score. Example 1 x 1 2 3 4 5 6 1 2 3 4 5 6
  • 9. At a garden centre, there is a display of roses: 25 are red 20 are white 15 are pink 5 are orange Three roses are chosen at random. π‘Ž. π·π‘Ÿπ‘Žπ‘€ 𝑒𝑝 π‘‘β„Žπ‘’ π‘π‘Ÿπ‘œπ‘π‘Žπ‘π‘–π‘™π‘–π‘‘π‘¦ π‘‘π‘–π‘ π‘‘π‘Ÿπ‘–π‘π‘’π‘‘π‘–π‘œπ‘› π‘‘π‘Žπ‘π‘™π‘’ π‘“π‘œπ‘Ÿ π‘‘β„Žπ‘’ π‘›π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘Ÿπ‘’π‘‘ π‘Ÿπ‘œπ‘ π‘’π‘  𝑠𝑒𝑙𝑒𝑐𝑑𝑒𝑑. 𝑏. 𝐹𝑖𝑛𝑑 π‘‘β„Žπ‘’ π‘π‘Ÿπ‘œπ‘π‘Žπ‘π‘–π‘™π‘–π‘‘π‘¦ π‘‘β„Žπ‘Žπ‘‘ π‘Žπ‘‘ π‘™π‘’π‘Žπ‘ π‘‘ π‘œπ‘›π‘’ π‘Ÿπ‘’π‘‘ π‘Ÿπ‘œπ‘ π‘’ 𝑖𝑠 𝑠𝑒𝑙𝑒𝑐𝑑𝑒𝑑. 𝑃 𝑅 β‰₯ 1 = 0.446 + 0.275 + 0.0527 = 0.774 Example 2
  • 10. 1 1 1 2 3 1 2 3 X 1 1 1 2 3 2 2 2 4 6 3 3 3 6 9 A fair 5 βˆ’ sided spinner has sides numbered 1,1,1,2,3. A fair three-sided has sides numbered 1,2,3. Both spinners are spun once and the score is the product of the numbers on the sides the spinners land on. Draw up the probability distribution table for the score. Example 3
  • 11. A fair 4 βˆ’ sided die, numbered 1,2,3 and 5 is rolled twice. The random variable X is the sum of the two numbers on which the die comes to rest. Draw up the probability distribution table for X and find P(X>6). x P(X=x) + 1 2 3 5 1 2 3 5 2 3 4 6 3 4 5 7 4 5 6 8 6 7 8 10 𝟐 πŸ‘ πŸ’ πŸ“ πŸ” πŸ• πŸ– 𝟏𝟎 𝟏 πŸπŸ” 𝟐 πŸπŸ” πŸ‘ πŸπŸ” 𝟐 πŸπŸ” πŸ‘ πŸπŸ” 𝟐 πŸπŸ” 𝟐 πŸπŸ” 𝟏 πŸπŸ” 𝒃. 𝑷 𝑿 > πŸ” = 𝑷 𝑿 = πŸ•, πŸ–, 𝟏𝟎 = πŸ“ πŸπŸ” Activity
  • 12. Set A consists of ten digits 0,0,0,0,0,0,2,2,2,4 Set B consists of the seven digits 0,0,0,0,2,2,2 One digit is chosen at random from each set. The random variable X is defined as the sum of these two digits. Draw up the probability distribution for the score. Homework