The document discusses the microstructure analysis and grain size calculation of various steel materials including AISI 1045, SS304, and malleable cast iron. For AISI 1045 and SS304, the microstructures were analyzed at 20x magnification and the phase compositions were calculated using lever rule and Fiji applications. The grain sizes were determined using the Jeffries intercept and Heyn intercept methods. For malleable cast iron, the microstructure was analyzed at 20x and the grain sizes were calculated using both Jeffries and Heyn intercept methods at magnifications of 200x and 500x.

1. AISI 1045
BAB IV
ANALISA DATA DAN PEMBAHASAN
4.1 Analisa Data dan Pembahasan
4.1.1 Gambar StrukturMikro
Gambar 4.1 Mikrostruktur AISI1045 20X
4.1.2 Perhitungan Fasa
4.1.2.1 BerdasarkandiagramFasa Fe – Fe3c
% wt C = 0,45 %
% Fe = [(6,67 – 0,45)/(6,67 – 0,008)] * 100%
% Fe = (6,22/6,662) * 100%
% Fe = 0,933 * 100%
% Fe = 93,3%

2. 4.2.2.2 Berdasarkan aplikasi Fiji
Gambar 4.3 fasa di AISI 1045
4.1.3 Perhitungan GrainSize
4.1.3.1 Metode Jeffries
AISI1045 perbesaran500X

3. N1 = 32
N2 = 19
Perbesaran= 50x
M = 500
4.1.3.2 heynnintercept
AISI1045 perbesaran500X
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19 20
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32
F = M^2/5000
= 500^2/5000
= 50
Na = F(N1+N2/2)
= 50(32+19/2)
= 2075
G = [3,322 log(Na)]
= [3,322 log(2075)]-2,95
= 8,0691

4. LT = panjanggaris uji (keliling) =500 mm
Perbesaran50x,M = 500
N = butir yangterpotonggarisuji
P = batasbutiryang terpotonggarisuji = 102
D1 = 26,53 mm
D2 = 53,05 mm
D3 = 79,58 mm
Syarat * 100 < P < 140
*P < 100 → M harus diperkecil
*P > 140 → M harus diperbesar
Single phase
NL = N/(LT/M)
PL = P/(LT/M)
L3 = 1/NL = 1/PL
G = [- 6,6457 log L3] – 3,298 (mm)
1
2
3
PL = P/(LT/M)
= 102/(500/500)
= 102
L3 = 1/PL
= 1/102
= 9,8039x10^-3
G = [- 6,6457 logL3] – 3,298
= [-6,6457 log9,8039x10^-3] – 3,298
= 10,0506

5. 4.2 pembahasan
4.2.1 struktur mikro (yg didapat dibandingkandg jurnal fasanya, gambar dr jurnal di
cantumin dan dibahas ada apa aja strukturnya dan terbentuknyadr apa berdasarkan
diagram fasa)
4.2.2 perbandingan perhitunganfasa (1045) dibandingkan perhitunganleverrule dan
aplikasi fiji
4.2.3 grain size (dari grain size bisa mengetahui apa dan bandingkan perhitunganheynn
dan jeffrieskalaubeda/sama knp)

6. SS304
BAB IV
ANALISA DATA DAN PEMBAHASAN
4.1 Analisa Data dan Pembahasan
4.1.1 Gambar StrukturMikro
Gambar 4.1 Mikrostruktur SS304 20X
4.1.3 Perhitungan GrainSize
4.1.3.1 Metode Jeffries
Perbesaran50x

7. N1 = 11
N2 = 9
M = 500
F = 50
Na = f (n1+n2/2)
1 2
3
4
5
6
7
8
9
10
11
Na = 50 ( 11 + 9/2)
= 775

8. 4.1.3.2 heynnintercept
P = 17 𝑃𝑙 =
𝑝
𝐿𝑡: 𝑀⁄ = 17
18,26:20⁄ = 12,03
D1 = 5 Cm 𝐿3 = 1
𝑃𝑙⁄ = 1
12,03⁄ = 0,0831
D2= 3 Cm 𝐺 = −6,646 log0,0831 + 3,298
D3= 1 Cm = 3,38 = 4
M = 20
∑Lt = (2𝑥3,14𝑥2,5) + (2𝑥3,14𝑥1,5) + (2𝑥3,14𝑥0,5)
= 18,26 𝑐𝑚2
Didapatnilai ASTMG adalah4

9. 4.2 pembahasan
4.2.1 struktur mikro (yg didapat dibandingkandg jurnal fasanya, gambar dr jurnal di
cantumin dan dibahas ada apa aja strukturnya dan terbentuknyadr apa berdasarkan
diagram fasa)
4.2.2 perbandingan perhitunganfasa (1045) dibandingkan perhitunganleverrule dan
aplikasi fiji
4.2.3 grain size (dari grain size bisa mengetahui apa dan bandingkan perhitunganheynn
dan jeffrieskalaubeda/sama knp)

10. Besi Cor Malleable
BAB IV
ANALISA DATA DAN PEMBAHASAN
4.1 Analisa Data dan Pembahasan
4.1.1 Gambar StrukturMikro
Besi Cor Malleable
Gambar 4.3 Mikrostruktur Besi Cor Melleable20X
4.1.3 Perhitungan GrainSize

11. N1 = 31
N2 = 23
M = 200 dan 500
F = 8 dan 50
Na = f (n1+n2/2)
BESI COR METODE JEFFRIES
PERBESARAN 50X
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31
Na = 8 ( 31 + 23/2)
= 340
Na = 50 ( 31 + 23/2)
= 2125

12. BESI COR METODE JEFFRIESPERBESARAN 20X
N1 = 64
N2 = 24
Perbesaran = 20x
M = 200
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2
3
4
3
5
6
7
33
8
733
9733
10733
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3
123
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F = M2
/5000
= 2002
/5000
= 8
Na = F(N1+N2/2)
= 8(64+24/2)
= 608
G = [3,322 log(Na)] –2.95
= [3,322 log(608)]-2,95
= 6,29812769

13. 4.1.3.2 heynnintercept
Heyn Intercept Method Perbesaran 50x
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969
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7071
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555
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𝑃𝐿 =
𝑃
𝐿𝑡
𝑀⁄
𝑃𝐿 =
101
500
500⁄
𝑃𝐿 = 101
𝐿3 =
1
𝑃𝐿
𝐿3 = 9,9009𝑥10−3
𝐺 = [−6,6457 log 𝐿3] − 3,298
G = 10,02211855

14. Heyn Intercept Method Perbesara 20x
LT = panjanggaris uji (keliling) =500 mm
Perbesaran20x,M =200
N = butir yangterpotonggarisuji = -
P = batasbutiryang terpotonggarisuji = 102
D1 = 26,53 mm
D2 = 53,05 mm
D3 = 79,58 mm
PL = P/(LT/M)
= 102/(500/200)
= 40,8
L3 = 1/PL
= 1/40.8
=2.45098x10-2
_
20
30
52
G = [- 6,6457 logL3] – 3,298
= [-6,6457 log2.45098x10-2
] – 3,298
= 7.405964708

15. 4.1.3.1 Metode Jeffries
N1 = 31
N2 = 23
BESI COR METODE JEFFRIES
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2
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5
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8 9
10
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30
31
Na = 8 ( 31 + 23/2)
= 340
Na = 50 ( 31 + 23/2)
= 2125

16. M = 200 dan 500
F = 8 dan 50
Na = f (n1+n2/2)
4.2 pembahasan
4.2.1 struktur mikro (yg didapat dibandingkandg jurnal fasanya, gambar dr jurnal di
cantumin dan dibahas ada apa aja strukturnya dan terbentuknyadr apa berdasarkan
diagram fasa)
4.2.2 perbandingan perhitunganfasa (1045) dibandingkan perhitunganleverrule dan
aplikasi fiji
4.2.3 grain size (dari grain size bisa mengetahui apa dan bandingkan perhitunganheynn
dan jeffrieskalaubeda/sama knp)