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AEES DISTANCE LEARNING PROGRAM 2020
CLASS VI
MATHEMATICS
CHAPTER- 10
MENSURATION
MODULE 1 OF 2
PREPARED BY :-
MR. R.S.SINGH
TGT
AECS -3 , MUMBAI
There are some plane figures , we think about their regions and
boundaries.
PERIMETER OF A PLANE FIGURE
Perimeter is the distance covered along the boundary forming a
closed figure when we go round the figure once.
There are some examples of perimeter-
1) Fence of a field.
2) A compound wall on all sides of a house.
3) A track to conduct sports.
PERIMETER OF A RECTANGLE
Length
Breadth Breadth
Length
There is a rectangle having 2 lengths and 2 breadths.
Perimeter of rectangle = length + breadth + length + breadth
= 2 x length + 2 x breadth
= 2 x ( length + breadth)
Example-
A field is 50 metre long and 25 metre wide. Find the perimeter of the
field.
Solution:-
Length of the field = 50 metres
Width of the field = 25 metres
Perimeter of the rectangular field = 2 x (Length + Breadth)
= 2 x (50 metres + 25 metres)
= 2 x 75 metres
= 150 metres
Perimeter of the field is 150 metres.
PERIMETER OF SQUARE
Side
Side Side
Side
In a square all sides are equal in length.
Perimeter of a square = Side + Side + Side + Side
= 4 x Side
Example-
Find the perimeter of a square park of side 70 metres.
Solution:-
Side of the park = 70 metre
Perimeter of square park = 4 x length of a side
= 4 x 70 metre
= 280 metre
Perimeter of square park is 280 m.
TRIANGLE
Triangle is a three sided closed figure. It has three sides, three vertices and
three angles. Sum of all angles of a triangle is 180 degree. It is a two
dimensional figure. It is the smallest polygon. It is one of the basic shapes in
geometry.
Perimeter of triangle = Side + Side + Side
PERIMETER OF EQUILATERAL TRIANGLE
It is an equilateral triangle, its all the three sides are equal in length.
Perimeter of equilateral triangle = Side+Side+Side
= 3 x Side
Example-
Find the perimeter of an equilateral triangle of side 14 cm.
Solution-
Side of equilateral triangle= 14 cm
Perimeter of an equilateral triangle = 3 x Side
= 3 x 14 cm
= 42 cm
Perimeter of equilateral triangle is 42 cm.
Now let us see some examples-
1.Find the perimeter of a rectangular park whose length is 100 m and
breadth 75 m.
Solution-
Length= 100 m Breadth= 75 m
Perimeter = 2 x (length+ Breadth)
= 2 x (100 m + 75 m)
= 2 x (175 m)
= 350 m
Perimeter of rectangular park = 350 m.
2. If the side of an equilateral triangle is 12 cm, then find its perimeter.
Solution
Perimeter of an equilateral triangle= 3 x side
= 3 x 12 cm
= 36 cm
Perimeter of the triangle is 36 cm.
3. Find the perimeter of a square of side 20 cm
Solution-
Perimeter of square = 4 x Side
= 4 x 20 cm
= 80 cm
Perimeter of square is 80 cm.
4. Find the perimeter of a rectangle whose length and breadth are 150 cm
and 1 m respectively.
Solution-
1 m = 100 cm
Perimeter = 2 x (length + breadth)
= 2 x (150 cm + 100 cm)
= 2 x (250 cm)
= 500 cm
Perimeter of the rectangle is 500 cm.
5. Find the cost of fencing a rectangular park at the rate of Rs. 12 per
metre if the length and width of the park are 225 m and 175 m
respectively.
Solution-
Perimeter of rectangular park = 2 x (length + width)
= 2 x (225 m + 175 m)
= 2 x 400 m
= 800 m
Cost of fencing the rectangular park = Rs12 x 800
= Rs. 9600
The cost of fencing the rectangular park is Rs. 9600.

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M02_MENSURATION_PPT.ppt

  • 1. AEES DISTANCE LEARNING PROGRAM 2020 CLASS VI MATHEMATICS CHAPTER- 10 MENSURATION MODULE 1 OF 2 PREPARED BY :- MR. R.S.SINGH TGT AECS -3 , MUMBAI
  • 2. There are some plane figures , we think about their regions and boundaries. PERIMETER OF A PLANE FIGURE Perimeter is the distance covered along the boundary forming a closed figure when we go round the figure once. There are some examples of perimeter- 1) Fence of a field. 2) A compound wall on all sides of a house. 3) A track to conduct sports.
  • 3. PERIMETER OF A RECTANGLE Length Breadth Breadth Length There is a rectangle having 2 lengths and 2 breadths. Perimeter of rectangle = length + breadth + length + breadth = 2 x length + 2 x breadth = 2 x ( length + breadth)
  • 4. Example- A field is 50 metre long and 25 metre wide. Find the perimeter of the field. Solution:- Length of the field = 50 metres Width of the field = 25 metres Perimeter of the rectangular field = 2 x (Length + Breadth) = 2 x (50 metres + 25 metres) = 2 x 75 metres = 150 metres Perimeter of the field is 150 metres.
  • 5. PERIMETER OF SQUARE Side Side Side Side In a square all sides are equal in length. Perimeter of a square = Side + Side + Side + Side = 4 x Side
  • 6. Example- Find the perimeter of a square park of side 70 metres. Solution:- Side of the park = 70 metre Perimeter of square park = 4 x length of a side = 4 x 70 metre = 280 metre Perimeter of square park is 280 m.
  • 7. TRIANGLE Triangle is a three sided closed figure. It has three sides, three vertices and three angles. Sum of all angles of a triangle is 180 degree. It is a two dimensional figure. It is the smallest polygon. It is one of the basic shapes in geometry. Perimeter of triangle = Side + Side + Side
  • 8. PERIMETER OF EQUILATERAL TRIANGLE It is an equilateral triangle, its all the three sides are equal in length. Perimeter of equilateral triangle = Side+Side+Side = 3 x Side
  • 9. Example- Find the perimeter of an equilateral triangle of side 14 cm. Solution- Side of equilateral triangle= 14 cm Perimeter of an equilateral triangle = 3 x Side = 3 x 14 cm = 42 cm Perimeter of equilateral triangle is 42 cm.
  • 10. Now let us see some examples- 1.Find the perimeter of a rectangular park whose length is 100 m and breadth 75 m. Solution- Length= 100 m Breadth= 75 m Perimeter = 2 x (length+ Breadth) = 2 x (100 m + 75 m) = 2 x (175 m) = 350 m Perimeter of rectangular park = 350 m.
  • 11. 2. If the side of an equilateral triangle is 12 cm, then find its perimeter. Solution Perimeter of an equilateral triangle= 3 x side = 3 x 12 cm = 36 cm Perimeter of the triangle is 36 cm. 3. Find the perimeter of a square of side 20 cm Solution- Perimeter of square = 4 x Side = 4 x 20 cm = 80 cm Perimeter of square is 80 cm.
  • 12. 4. Find the perimeter of a rectangle whose length and breadth are 150 cm and 1 m respectively. Solution- 1 m = 100 cm Perimeter = 2 x (length + breadth) = 2 x (150 cm + 100 cm) = 2 x (250 cm) = 500 cm Perimeter of the rectangle is 500 cm.
  • 13. 5. Find the cost of fencing a rectangular park at the rate of Rs. 12 per metre if the length and width of the park are 225 m and 175 m respectively. Solution- Perimeter of rectangular park = 2 x (length + width) = 2 x (225 m + 175 m) = 2 x 400 m = 800 m Cost of fencing the rectangular park = Rs12 x 800 = Rs. 9600 The cost of fencing the rectangular park is Rs. 9600.