ENGINEERING MECHANICS, EQUILIBRIUM, STATICS

1. DEVAPRAKASAM DEIVASAGAYAM
Professor of Mechanical Engineering
Room:11, LW, 2nd Floor
School of Mechanical and Building Sciences
Email: devaprakasam.d@vit.ac.in, dr.devaprakasam@gmail.com
MEE1002: Engineering Mechanics (2:1:0:0:3)
Devaprakasam D, Email: devaprakasam.d@vit.ac.in, Ph: +91 9786553933

2. Devaprakasam D, Email: devaprakasam.d@vit.ac.in, Ph: +91 9786553933
Problems

3. Devaprakasam D, Email: devaprakasam.d@vit.ac.in, Ph: +91 9786553933
Problems
A B
C E D
0.6m
0.5
m
0.85 m
W
0.6m
0.25m

4. Devaprakasam D, Email: devaprakasam.d@vit.ac.in, Ph: +91 9786553933
Solution
A B
C E D
0.6m
0.5 m
0.85 m
W
0.6m
0.25m
W= 784.8N
mNMM EE .2.19625.08.784: 
    mEBd 986.085.05.0)(
22

NF
FmNMM
B
BEE
954.198
)986.0(.2.196:


F



5.5990 
 

5. Devaprakasam D, Email: devaprakasam.d@vit.ac.in, Ph: +91 9786553933
Problem

6. Devaprakasam D, Email: devaprakasam.d@vit.ac.in, Ph: +91 9786553933
Solution
200lb
a) MB= rC/B x 200 lb= 4in x 200 lb
MB= 800 lb . in
b) MB= rA/B x P= rA/B P sin θ
800 lb . In = 18 in x P sin 60°
lbP 3.51
60sin18
800


 
c) MB= rA/B x P= rA/B P sin θ
For minimum P, θ=90°
;4.44
90sin18
800
lbP 

 

7. Devaprakasam D, Email: devaprakasam.d@vit.ac.in, Ph: +91 9786553933
Problems

8. Devaprakasam D, Email: devaprakasam.d@vit.ac.in, Ph: +91 9786553933
Solution
TABy
TABx
TAB
MC= TABx (y) +TABy (x)
MC= (0.028)TABx + (0.021) TABy
MC= (0.028)[ (21/75) x1500] + (0.021) [(72/75)x1500]
MC= 42.0 N.m (CCW )

9. Devaprakasam D, Email: devaprakasam.d@vit.ac.in, Ph: +91 9786553933

10. Devaprakasam D, Email: devaprakasam.d@vit.ac.in, Ph: +91 9786553933

11. Devaprakasam D, Email: devaprakasam.d@vit.ac.in, Ph: +91 9786553933

12. Devaprakasam D, Email: devaprakasam.d@vit.ac.in, Ph: +91 9786553933

13. Devaprakasam D, Email: devaprakasam.d@vit.ac.in, Ph: +91 9786553933

14. Devaprakasam D, Email: devaprakasam.d@vit.ac.in, Ph: +91 9786553933

15. Devaprakasam D, Email: devaprakasam.d@vit.ac.in, Ph: +91 9786553933

16. Devaprakasam D, Email: devaprakasam.d@vit.ac.in, Ph: +91 9786553933
Moment of A Couple

17. Devaprakasam D, Email: devaprakasam.d@vit.ac.in, Ph: +91 9786553933
Moment of a Couple
Two couples , one consisting of the forces F1 and
–F1, the other of F2 and –F2, will have equal
moment if F1d1= F2d21

18. Devaprakasam D, Email: devaprakasam.d@vit.ac.in, Ph: +91 9786553933
Equivalent Couples of Moment

19. Devaprakasam D, Email: devaprakasam.d@vit.ac.in, Ph: +91 9786553933
Addition of Couples

20. Devaprakasam D, Email: devaprakasam.d@vit.ac.in, Ph: +91 9786553933
Reduction of System of Force

21. Devaprakasam D, Email: devaprakasam.d@vit.ac.in, Ph: +91 9786553933
Reduction of System of Force
Any force ‘F’ acting on a rigid body can be moved to an arbitrary point ‘O’
provided that a couple is added whose moment is equal to the moment of F
about ‘O’

22. Devaprakasam D, Email: devaprakasam.d@vit.ac.in, Ph: +91 9786553933
Resolution of Force into Force at ‘O’ and a Couple
Any force ‘F’ acting on a rigid body can be moved to an arbitrary point ‘O’
provided that a couple is added whose moment is equal to the moment of F
about ‘O’

23. Devaprakasam D, Email: devaprakasam.d@vit.ac.in, Ph: +91 9786553933
Rigid Body Equilibrium

24. Devaprakasam D, Email: devaprakasam.d@vit.ac.in, Ph: +91 9786553933
Example Problems

25. Devaprakasam D, Email: devaprakasam.d@vit.ac.in, Ph: +91 9786553933
Example Problems

26. Devaprakasam D, Email: devaprakasam.d@vit.ac.in, Ph: +91 9786553933
Example Problems

27. Devaprakasam D, Email: devaprakasam.d@vit.ac.in, Ph: +91 9786553933
Example Problems