Studyadz 3as-physique-c3-32-46

1. 0
‫ﻣﻥ‬
06 1 ‫ﺍﻟﺻﻔﺣﺔ‬
‫ﺍﻟﺸﻌﺒﻴﺔ‬ ‫ﺍﻟﺪﻳﻤﻘﺮﺍﻁﻴﺔ‬ ‫ﺍﻟﺠﺰﺍﺋﺮﻳﺔ‬ ‫ﺍﻟﺠﻤﻬﻮﺭﻳﺔ‬
‫ﺍﻟﺘﺮﺑﻴﺔ‬ ‫ﻣﺪﻳﺮﻳﺔ‬
:
: ‫ﻳﻮﻡ‬
: ‫ﺛﺎﻧﻮﻳﺔ‬
‫ﺩ‬
‫ﻭﺭﺓ‬
:
‫ﻣـــﺎﻱ‬
2018
‫ﺷﻌﺒﺔ‬
:
‫ﺍﻟ‬
‫ﺗﺠﺮﻳﺒﻴﺔ‬ ‫ﻌﻠﻮﻡ‬
‫ﺑﻜﺎﻟﻮﺭﻳﺎ‬
‫ﺗﺠﺮﻳﺒﻲ‬
‫ﺍﺧﺘﺒﺎﺭ‬
: ‫ﻣﺎﺩﺓ‬
‫ﺍﻟﻔﻴﺰﻳﺎﺋﻴﺔ‬ ‫ﺍﻟﻌﻠﻮﻡ‬
: ‫ﺍﻟﻤﺪﺓ‬
3
‫ﺳــﺎﻋﺔ‬
‫ﻭ‬
30
‫ﺩﻗﻴﻘﺔ‬
‫ﺍﻻﻭﻝ‬ ‫ﺍﻟﻤﻮﺿﻮﻉ‬
‫اﳉﺰ‬
‫ء‬
‫اﻻول‬
‫ﻋﻠﻰ‬ :
13
‫ﻳ‬‫ﺰ‬‫اﻟﻔﻴ‬ ) ‫ﻧﻘﻄﺔ‬
‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬
(‫ﺎء‬
): ‫اﻻول‬ ‫ﻳﻦ‬‫ﺮ‬‫اﻟﺘﻤ‬
06
‫ﻧﻘ‬
‫ﺎ‬
‫ط‬
(
‫ﻋ‬ ‫ﺗﺤﺘﻮﻱ‬ ‫ﺩﺍﺭﺍﺕ‬ ‫ﻣﻦ‬ ‫ﺗﺘﻜﻮﻥ‬ ‫ﺍﻟﻜﻬﺮﺑﺎﺋﻴﺔ‬ ‫ﺍﻻﺟﻬﺰﺓ‬ ‫ﺍﻥ‬ ‫ﺣﻴﺚ‬ ‫ﺍﻟﻀﺮﻭﺭﻳﺎﺕ‬ ‫ﺍﻫﻢ‬ ‫ﻣﻦ‬ ‫ﺣﺎﻟﻲ‬ ‫ﻭﻗﺘﻨﺎ‬ ‫ﻓﻲ‬ ‫ﺍﻟﻜﻬﺮﺑﺎء‬ ‫ﺗﻌﺘﺒﺮ‬
‫ﺛﻨﺎ‬ ‫ﻠﻰ‬
‫ﻗﻄﺐ‬ ‫ﺋﻲ‬
-
RC
-
RL
-
LC
-
‫ﺍﻟﻘﻄﺐ‬ ‫ﺛﻨﺎﺋﻲ‬ ‫ﺳﻨﺪﺭﺱ‬
RC
‫ﻭ‬
LC
‫ﺍﻧﻈﺮ‬
‫ﺍﻟﺸﻜﻞ‬
-
1
-
: ‫ﺍﻟﺘﺮﻛﻴﺐ‬ ‫ﻓﻲ‬ ‫ﻣﺴﺘﻌﻤﻠﺔ‬ ‫ﻛﻬﺮﺑﺎﺋﻴﺔ‬ ‫ﻋﻨﺎﺻﺮ‬
ƒ
‫ﺗﻮﺗﺮﻩ‬ ‫ﺣﻘﻴﻘﻲ‬ ‫ﻣﻮﻟﺪ‬
E
‫ﺩﺍﺧﻠﻴﺔ‬ ‫ﻣﻘﺎﻭﻣﺘﻪ‬
r=20Ω
.
ƒ
‫ﺳﻌﺘﻬﻤﺎ‬ ‫ﻣﻜﺜﻔﺔ‬
C
.
ƒ
‫ﻣﻘﺎﻭﻣﺘﻪ‬ ‫ﺍﻭﻣﻲ‬ ‫ﻧﺎﻗﻞ‬
R=40Ω
.
ƒ
‫ﺫﺍﺗﻴﺘﻬﺎ‬ ‫ﻭﺷﻴﻌﺔ‬
L
‫ﺩﺍﺧﻠﻴﺔ‬ ‫ﻣﻘﺎﻭﻣﺘﻬﺎ‬
0
r
.
I
.
‫ﻗﻄﺐ‬ ‫ﺛﻨﺎﺋﻲ‬ ‫ﺩﺭﺍﺳﺔ‬
RC
):
03
( ‫ﻧﻘﺎﻁ‬
‫ﻧ‬
‫ﻭﺿﻊ‬ ‫ﻓﻲ‬ ‫ﻗﺎﻁﻌﺔ‬ ‫ﻀﻊ‬
1
:
1
(
‫ﻣﻜﺜﻔﺔ‬ ‫ﺗﻮﺗﺮ‬ ‫ﻟﺘﻄﻮﺭﺍﺕ‬ ‫ﺍﻟﺘﻔﺎﺿﻠﻴﺔ‬ ‫ﻣﻌﺎﺩﻟﺔ‬ ‫ﺍﻥ‬ ‫ﺑﻴﻦ‬
(t)
c
U
: ‫ﻫﻮ‬
ௗ୙ୡሺ୲ሻ
ୢ୲
൅
ଵ
ୖ஼
Ǥ …ሺ–ሻ ൌ
୉
ୖେ
2
(
‫ﺷﻜﻞ‬ ‫ﻣﻦ‬ ‫ﻣﻌﺎﺩﻟﺔ‬ ‫ﺣﻞ‬ ‫ﻳﻌﻄﻰ‬
:
…ሺ–ሻ ൌ ሺͳ െ ‡஑୲ሻ
‫ﺛﻮﺍﺑﺖ‬ ‫ﻋﺒﺎﺭﺓ‬ ‫ﺍﻋﻂ‬
A
‫ﻭ‬
α
‫؟‬ ‫ﻛﻬﺮﺑﺎﺋﻴﺔ‬ ‫ﺩﺍﺭﺓ‬ ‫ﺛﻮﺍﺑﺖ‬ ‫ﺑﺪﻻﻟﺔ‬
3
(
‫ﺗﻄﻮﺭﺍﺕ‬ ‫ﻣﻨﺤﻨﻰ‬ ‫ﻣﻬﺒﻄﻲ‬ ‫ﺍﻫﺘﺰﺍﺯ‬ ‫ﺭﺍﺳﻢ‬ ‫ﻳﻌﻄﻰ‬
‫ﺑﻴﻦ‬ ‫ﺗﻮﺗﺮ‬
‫ﻣﻜﺜﻔﺔ‬ ‫ﻁﺮﻓﻲ‬
‫ﺷﻜﻞ‬
-
2
-
‫ﺑﺎﺳﺘﻐﻼﻝ‬
: ‫ﺍﻭﺟﺪ‬ ‫ﺍﻟﺒﻴﺎﻥ‬
ƒ
‫ﻗﻴﻤﺔ‬
E
‫؟‬
ƒ
‫ﺩﺍﺭﺓ‬ ‫ﺯﻣﻦ‬ ‫ﺛﺎﺑﺖ‬ ‫ﻗﻴﻤﺔ‬
τ
‫؟‬
ƒ
‫ﻗﻴﻤﺔ‬
C=…..
‫؟‬
4
(
‫ﺗﻴﺎﺭ‬ ‫ﻋﺒﺎﺭﺓ‬ ‫ﺍﻋﻂ‬
i(t)
. ‫ﺍﻻﺑﺘﺪﺍﺋﻴﺔ‬ ‫ﻗﻴﻤﺘﻪ‬ ‫ﻣﺎﻫﻲ‬ ‫؟‬
II
.
‫ﺍﻟﻘﻄﺐ‬ ‫ﺛﻨﺎﺋﻲ‬ ‫ﺩﺭﺍﺳﺔ‬
LC
):
03
( ‫ﻧﻘﺎﻁ‬
‫ﻭﺿﻊ‬ ‫ﺍﻟﻰ‬ ‫ﺍﻟﻘﺎﻁﻌﺔ‬ ‫ﻭﺿﻊ‬ ‫ﻧﻐﻴﺮ‬ ‫ﺍﻟﺪﺍﺋﻢ‬ ‫ﻟﻨﻈﺎﻡ‬ ‫ﻧﺼﻞ‬ ‫ﻋﻨﺪﻣﺎ‬
2
‫ﻭﻧﻌﺘﺒﺮﻩ‬
‫ﺍﺯﻣﻨﺔ‬ ‫ﻣﺒﺪﺍ‬
t=0 s
.
1
(
‫ﺍﻟﺸﺤﻨﺔ‬ ‫ﻟﺘﻐﻴﺮﺍﺕ‬ ‫ﺗﻔﺎﺿﻠﻴﺔ‬ ‫ﻣﻌﺎﺩﻟﺔ‬ ‫ﺍﻛﺘﺐ‬
q(t)
‫؟‬ ‫ﺩﺍﺭﺓ‬ ‫ﻓﻲ‬
2
(
‫؟‬ ‫ﺳﺒﺒﻪ‬ ‫ﻣﻦ‬ ‫؟‬ ‫ﺍﻻﻫﺘﺰﺍﺯ‬ ‫ﻧﻤﻂ‬ ‫ﻣﺎﻫﻮ‬ ‫ﺍﻟﺸﻜﻞ‬ ‫ﺣﺴﺐ‬
‫ﺷﻛﻝ‬
–
1
-
‫ﺷﻛﻝ‬
–
2
-
‫ﺷﻛﻝ‬
–
2
-
‫اﳉﺰ‬
‫اﳉﺰ‬
‫ﺰء‬
‫اﻻول‬
‫اﻻول‬
‫ﻋﻠ‬ :
m
): ‫اﻻول‬ ‫ﻳﻦ‬‫ﺮ‬‫اﻟﺘﻤ‬
): ‫اﻻول‬ ‫ﻳﻦ‬‫ﺮ‬
06
a
‫ﺣﺎﻟﻲ‬ ‫ﻭﻗﺘﻨﺎ‬ ‫ﻓﻲ‬ ‫ﺍﻟﻜﻬﺮﺑﺎء‬ ‫ﺮ‬
‫ﻭﻗﺘﻨﺎ‬ ‫ﻓﻲ‬ ‫ﺮﺑﺎء‬
R
-
LC
LC
-
-
‫ﺛﻨﺎﺋ‬ ‫ﺳﻨﺪﺭﺱ‬
‫ﺳﻨﺪﺭﺱ‬
‫ﺍﻟﺘﺮﻛﻴﺐ‬ ‫ﻓﻲ‬ ‫ﻣﺴﺘﻌﻤﻠﺔ‬ ‫ﺎﺋﻴﺔ‬
‫ﺍﻟﺘﺮ‬ ‫ﻓﻲ‬ ‫ﻣﺴﺘﻌﻤﻠﺔ‬
‫ﺗﻮﺗﺮﻩ‬ ‫ﻘﻲ‬
‫ﻮﺗﺮﻩ‬
E
E
‫ﺩ‬ ‫ﻣﻘﺎﻭﻣﺘﻪ‬
‫ﻣﻘﺎﻭﻣ‬
C
.
‫ﻪ‬
R=40
R=4 Ω
.
.
‫ﺩﺍﺧﻠﻴﺔ‬ ‫ﻣﺘﻬﺎ‬
‫ﺩﺍﺧﻠﻴﺔ‬
0
r
.
.
0
( ‫ﻧﻘﺎﻁ‬
( ‫ﻁ‬
s
‫ﺍﺧﺘﺒﺎ‬
o
‫ﻣﻜﺜﻔﺔ‬ ‫ﺗﻮﺗﺮ‬
‫ﻣﻜﺜﻔﺔ‬
(t)
(t)
c
c
U
U
‫ﻭ‬
α
s
e
d
u
e
d
u
‫ﺷﻛﻝ‬
–
2
3as.ency-education.com

2. 0
‫ﻣﻥ‬
06 2 ‫ﺍﻟﺻﻔﺣﺔ‬
3
(
: ‫ﺍﻭﺟﺪ‬ ‫ﺍﻟﺸﻜﻞ‬ ‫ﺣﺴﺐ‬
ƒ
‫ﺍﻟﺤﺮﻛﺔ‬ ‫ﺩﻭﺭ‬ ‫ﺷﺒﻪ‬ ‫ﻗﻴﻤﺔ‬
T
.
ƒ
‫ﺍﻟﻨﺒﺾ‬ ‫ﻗﻴﻤﺔ‬
ɘ
.
ƒ
‫ﺑ‬
‫ﺈ‬
‫ﻭﺷﻴﻌﺔ‬ ‫ﺫﺍﺗﻴﺔ‬ ‫ﻗﻴﻤﺔ‬ ‫ﺍﺳﺘﻨﺘﺞ‬ ‫ﻣﺎﺩﺭﺳﺖ‬ ‫ﻋﻠﻰ‬ ‫ﻋﺘﻤﺎﺩ‬
L
‫اﻟ‬ ‫ﻳﻦ‬‫ﺮ‬‫اﻟﺘﻤ‬
‫ﺜﺎﱐ‬
):
07
‫ﻧﻘ‬
‫ﺎ‬
(‫ط‬
I
.
‫ﻣﺎﺋﻠﺔ‬ ‫ﻁﺮﻳﻖ‬ ‫ﻋﻠﻰ‬ ‫ﻳﻨﺰﻟﻖ‬ ‫ﺟﺴﻢ‬ ‫ﺣﺮﻛﺔ‬ ‫ﺩﺭﺍﺳﺔ‬
):
04
( ‫ﻧﻘﺎﻁ‬
‫ﺻﻠﺐ‬ ‫ﺟﺴﻢ‬ ‫ﻳﻨﺰﻟﻖ‬
(S)
‫ﻛﺘﻠﺘﻪ‬
m = 100g
‫ﻋﻠﻰ‬
‫ﺑﺰﺍﻭﻳﺔ‬ ‫ﺍﻷﻓﻖ‬ ‫ﻋﻦ‬ ‫ﻣﺎﺋﻞ‬ ‫ﻣﺴﺘﻮ‬ ‫ﻁﻮﻝ‬
α = 20°
‫ﻭﻓﻖ‬
‫ﺍﻟﻤﺤﻮﺭ‬
‫ܤܣ‬
ሬሬሬሬሬԦ
)
‫ﺍﻧﻈﺮ‬
‫ﺑﺎﻟﺘﺼﻮﻳﺮ‬ ‫ﻗﻤﻨﺎ‬ .( ‫ﺍﻟﺸﻜﻞ‬
‫ﺍﻟﻔﻴﺪﻳﻮ‬ ‫ﺷﺮﻳﻂ‬ ‫ﻭﻋﻮﻟﺞ‬ ‫ﺭﻗﻤﻴﺔ‬ ‫ﺑﻜﺎﻣﻴﺮﺍ‬ ‫ﺍﻟﻤﺘﻌﺎﻗﺐ‬
‫ﺑﺒﺮﻣﺠﻴﺔ‬
(Aviméca)
‫ﺍﻵﻟﻲ‬ ‫ﺍﻹﻋﻼﻡ‬ ‫ﺑﺠﻬﺎﺯ‬
‫ﺍﻟﺒﻴﺎﻥ‬ ‫ﺭﺳﻢ‬ ‫ﻋﻠﻰ‬ ‫ﻭﺗﺤﺼﻠﻨﺎ‬
v=f(t)
.
1
–
:‫ﺍﻟﺒﻴﺎﻥ‬ ‫ﻋﻠﻰ‬ ‫ﺑﺎﻻﻋﺘﻤﺎﺩ‬
‫ﺃ‬
–
‫ﺣﺮﻛﺔ‬ ‫ﻁﺒﻴﻌﺔ‬ ‫ﺑﻴﻦ‬
(S)
.
‫ﺏ‬
–
‫ﻟﻠﺘﺴﺎﺭﻉ‬ ‫ﺍﻟﺘﺠﺮﻳﺒﻴﺔ‬ ‫ﺍﻟﻘﻴﻤﺔ‬ ‫ﺍﺳﺘﻨﺘﺞ‬
a
.
‫ﺝ‬
–
‫ﺍﻟﺴﺮﻋﺔ‬ ‫ﻗﻴﻤﺔ‬ ‫ﺍﺳﺘﻨﺘﺞ‬
0
v
‫ﺍﻟﻠﺤﻈﺔ‬ ‫ﻓﻲ‬
t=0
.
‫ﺩ‬
–
:‫ﺍﻟﻠﺤﻈﺘﻴﻦ‬ ‫ﺑﻴﻦ‬ ‫ﺍﻟﻤﻘﻄﻮﻋﺔ‬ ‫ﺍﻟﻤﺴﺎﻓﺔ‬ ‫ﺍﺣﺴﺐ‬
)
= 0,04s
1
t
‫ﻭ‬
= 0,08s
2
t
.(
2
–
:‫ﻣﻬﻤﻠﺔ‬ ‫ﺍﻻﺣﺘﻜﺎﻛﺎﺕ‬ ‫ﺃﻥ‬ ‫ﺑﻔﺮﺽ‬
‫ﺃ‬
–
‫ﺍﻟﻌﺒﺎﺭﺓ‬ ‫ﺃﻭﺟﺪ‬ ‫ﻟﻨﻴﻮﺗﻦ‬ ‫ﺍﻟﺜﺎﻧﻲ‬ ‫ﺍﻟﻘﺎﻧﻮﻥ‬ ‫ﺑﺘﻄﺒﻴﻖ‬
‫ﻟﻠﺘﺴﺎﺭﻉ‬ ‫ﺍﻟﺤﺮﻓﻴﺔ‬
0
a
.‫ﻗﻴﻤﺘﻪ‬ ‫ﺍﺣﺴﺐ‬ ‫ﺛﻢ‬
‫ﺏ‬
–
‫ﺑﻴﻦ‬ ‫ﻗﺎﺭﻥ‬
0
a
‫ﻭ‬
a
‫؟‬
3
-
‫ﺳﺆﺍﻝ‬ ‫ﻣﻦ‬
1
‫ﺳﺆﺍﻝ‬ ‫ﻭ‬
2
‫ﺍﻟﻘﻮﺓ‬ ‫ﺷﺪﺓ‬ ‫ﺃﻭﺟﺪ‬
݂
Ԧ
.‫ﺍﻟﻤﺎﺋﻞ‬ ‫ﺍﻟﻤﺴﺘﻮﻱ‬ ‫ﻋﻠﻰ‬ ‫ﻟﻼﺣﺘﻜﺎﻛﺎﺕ‬ ‫ﺍﻟﻤﻨﻤﺬﺟﺔ‬
:‫ﻳﻌﻄﻰ‬
2
-
g = 10 m.s
‫؛‬
sin 20° = 0,34
.
II
.
‫ﻧﻮﺍﺓ‬ ‫ﺗﻔﻜﻚ‬ ‫ﺩﺭﺍﺳﺔ‬
):
03
( ‫ﻧﻘﺎﻁ‬
‫ﺍﻟﻜﺰﻳﻨﻮﻥ‬ ‫ﻧﻮﺍﺓ‬
Xe
135
54
‫ﺍﻟﻨﺸﺎﻁ‬ ‫ﺍﺷﻌﺎﻋﻴﺔ‬
E
‫ﺍﻟﺴﻴﺰﻳﻮﻡ‬ ‫ﻧﻮﺍﺓ‬ ‫ﺗﻔﻜﻜﻬﺎ‬ ‫ﻋﻦ‬ ‫ﻳﺘﻮﻟﺪ‬
Cs
A
Z
.
‫ﻧﻮﺍﺓ‬ ‫ﻋﻤﺮ‬ ‫ﻧﺼﻒ‬
Xe
135
54
‫ﻫﻮ‬
h
t 2
.
9
2
1
.
1
-
‫ﻣﺤﺪﺩ‬ ‫ﺍﻟﺘﻔﻜﻚ‬ ‫ﻫﺬﺍ‬ ‫ﻣﻌﺎﺩﻟﺔ‬ ‫ﺃﻛﺘﺐ‬
‫ﺍ‬
A
‫ﻭ‬
z
.
2
-
‫ﺍﻟﻜﺰﻳﻨﻮﻥ‬ ‫ﻋﻴﻨﺔ‬ ‫ﻛﺘﻠﺔ‬ ‫ﺃﻥ‬ ‫ﻋﻠﻤﺎ‬
Xe
135
54
‫ﺍﻟﻠﺤﻈﺔ‬ ‫ﻋﻨﺪ‬
t=0
‫ﻫﻲ‬
0
m
‫ﻭﻧﺸﺎﻁﻬﺎ‬
0
A
‫ﺍﻟﻠﺤﻈﺔ‬ ‫ﻭﻋﻨﺪ‬ ,
t=9h
‫ﺍﻟﻨﺸﺎﻁ‬ ‫ﻳﺼﺒﺢ‬
‫ﻟﻠﻌﻴﻨﺔ‬ ‫ﺍﻹﺷﻌﺎﻋﻲ‬
A=284Bq
.
‫ﺃ‬
–
‫ﺍﻟﻨﺸﺎﻁ‬ ‫ﻋﻼﻗﺔ‬ ‫ﺃﻋﻂ‬
A
‫ﺑﺪﻻﻟﺔ‬
0
A
‫ﻭ‬
1/2
t
‫ﻭﺍﻟﺰﻣﻦ‬
t
.
‫ﺑـ‬
-
‫ﻗﻴﻤﺔ‬ ‫ﺃﺣﺴﺐ‬
0
A
‫ﻭﺍﺳﺘﻨﺞ‬
0
m
.
‫ﺟـ‬
-
‫ﻋﻨﺪﻫﺎ‬ ‫ﻳﺘﻔﻜﻚ‬ ‫ﺍﻟﺘﻲ‬ ‫ﺍﻟﻠﺤﻈﺔ‬ ‫ﺣﺪﺩ‬
0
0
75
.‫ﺍﻻﺑﺘﺪﺍﺋﻴﺔ‬ ‫ﺍﻟﻜﺘﻠﺔ‬ ‫ﻣﻦ‬
‫ﺍﻟﻜﺰﻳﻨﻮﻥ‬ ‫ﻧﻮﺍﺓ‬ ‫ﻛﺘﻠﺔ‬ ‫ﻧﻌﻄﻲ‬
kg
Xe
m 25
135
54 10
24
,
2
)
(
u
‫ﺁﻓﻮﻗﺎﺩﺭﻭ‬ ‫ﻋﺪﺩ‬ .
23
10
023
,
6 u
A
N
.
e
n
c
y
-
e
d
u
c
A
.
‫ﺤﻈﺔ‬
t=9h
t=
o
n
.
c
o
m
/
e
x
a
m
s
‫اﻟﺘﻤﺮ‬
s
I
.
‫ﻳﻨﺰﻟﻖ‬
‫ﻳﻨ‬
‫ﻣ‬ ‫ﻣﺴﺘﻮ‬ ‫ﻁﻮﻝ‬
‫ﻣﺴ‬ ‫ﻁﻮﻝ‬
‫ﺍﻟﻤﺤﻮﺭ‬
‫ﻤﺤﻮﺭ‬
‫ܤܣ‬
‫ܤܣ‬
ሬሬ
ሬሬ
ሬሬ
ሬሬ
ሬԦ
ሬ
)
)
‫ﺍﻧﻈ‬
‫ﺭﻗﻤﻴﺔ‬ ‫ﺑﻜﺎﻣﻴﺮﺍ‬ ‫ﺍﻟﻤﺘﻌﺎﻗﺐ‬
‫ﺑﻜﺎﻣﻴﺮﺍ‬ ‫ﻌﺎﻗﺐ‬
‫ﻣﺠﻴﺔ‬
‫ﺔ‬
(
(Aviméca
Aviméca)
)
‫ﺑﺠﻬ‬
‫ﺍﻟﺒﻴﺎﻥ‬ ‫ﺭﺳﻢ‬ ‫ﻋﻠﻰ‬ ‫ﻨﺎ‬
‫ﺍﻟﺒﻴﺎﻥ‬ ‫ﺭﺳﻢ‬ ‫ﻰ‬
=f(t)
f(t)
:‫ﺍﻟﺒﻴﺎﻥ‬ ‫ﻋﻠﻰ‬ ‫ﺎﺩ‬
:‫ﺍﻟﺒﻴﺎﻥ‬ ‫ﻠﻰ‬
‫ﺣﺮﻛﺔ‬ ‫ﺒﻴﻌﺔ‬
‫ﺮﻛﺔ‬
(
(S
S
(
( )
)
S
S
.
‫ﻟﻠﺘﺴﺎﺭﻉ‬ ‫ﺍﻟﺘﺠﺮﻳﺒﻴﺔ‬ ‫ﻴﻤﺔ‬
‫ﻟﻠﺘﺴ‬ ‫ﻟﺘﺠﺮﻳﺒﻴﺔ‬
a
‫ﺴﺮﻋﺔ‬
0
0
v
v
‫ﺍﻟﻠﺤﻈﺔ‬ ‫ﻓﻲ‬
‫ﺍﻟﻠﺤﻈ‬ ‫ﻓﻲ‬
=0
:‫ﺍﻟﻠﺤﻈﺘﻴﻦ‬ ‫ﺑﻴﻦ‬ ‫ﻄﻮﻋﺔ‬
‫ﺍﻟﻠﺤﻈﺘﻴﻦ‬ ‫ﺑﻴﻦ‬ ‫ﺔ‬
= 0,0
2
2
t
t2
2
.(
.(
‫ﺍﻟﻌﺒﺎﺭﺓ‬
‫ﺓ‬
‫ﺍﻟﻨﺸﺎ‬ ‫ﻳﺼﺒﺢ‬
‫ﻳﺼﺒﺢ‬
3as.ency-education.com

3. 0
‫ﻣﻥ‬
06 3 ‫ﺍﻟﺻﻔﺣﺔ‬
‫اﳉﺰ‬
‫ء‬
‫اﻟﺜﺎﱐ‬
‫ﻋﻠﻰ‬ :
)
7
‫ﻧﻘﺎط‬
(
‫ـ‬‫ـ‬‫ـ‬‫ﻴ‬‫اﻟﻜﻤ‬ )
‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬
‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬
‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬
‫ـ‬‫ـ‬‫ـ‬‫ـ‬
(‫ـﺎء‬
‫اﻟﺜﺎﻟﺚ‬ ‫ﻳﻦ‬‫ﺮ‬‫اﻟﺘﻤ‬
:
‫ﺍﻟﺪﺭﺟﺔ‬ ‫ﻓﻲ‬ ‫ﺍﻟﻤﺤﺎﻟﻴﻞ‬ ‫ﻛﻞ‬ ‫ﺗﺆﺧﺬ‬
25°C
.
‫ﺍﻹﺟﻤﺎﻟﻴﺔ‬ ‫ﺍﻟﺠﺰﻳﺌﻴﺔ‬ ‫ﺻﻴﻐﺘﻪ‬ ‫ﻛﺮﺑﻮﻛﺴﻴﻠﻲ‬ ‫ﺣﻤﺾ‬ ‫ﺍﻹﻳﺒﻮﺑﺮﻭﻓﻴﻦ‬
‫ܥ‬ଵଷ‫ܪ‬ଵ଼ܱଶ
‫ﺷﺒﻴﻪ‬ ،‫ﻟﻼﻟﺘﻬﺎﺑﺎﺕ‬ ‫ﺍﻟﻤﻀﺎﺩﺍﺕ‬ ‫ﻣﻦ‬ ‫ﻳﻌﺘﺒﺮ‬ ‫ﺩﻭﺍء‬ ،
‫ﺃﻛﻴﺎﺱ‬ ‫ﻓﻲ‬ ‫ﻣﺴﺤﻮﻕ‬ ‫ﺷﻜﻞ‬ ‫ﻋﻠﻰ‬ ‫ﺍﻟﺼﻴﺪﺍﻟﻴﺎﺕ‬ ‫ﻓﻲ‬ ‫ﺍﻹﻳﺒﻮﺑﺮﻭﻓﻴﻦ‬ ‫ﻣﺴﺘﺤﻀﺮﺍﺕ‬ ‫ﺗﺒﺎﻉ‬ .‫ﻟﻠﺤﺮﺍﺭﺓ‬ ‫ﻭﻣﺨﻔﺾ‬ ‫ﻟﻶﻻﻡ‬ ‫ﻣﺴﻜﻦ‬ ،‫ﺑﺎﻷﺳﺒﺮﻳﻦ‬
‫ﺍﻟﻤﻘﺪﺍﺭ‬ ‫ﺗﺤﻤﻞ‬
200 mg
‫ﺑـ‬ ‫ﺍﻹﻳﺒﻮﺑﺮﻭﻓﻴﻦ‬ ‫ﻟﺤﻤﺾ‬ ‫ﻧﺮﻣﺰ‬ ‫ﺍﻟﻨﺸﺎﻁ‬ ‫ﻫﺬﺍ‬ ‫ﻛﻞ‬ ‫ﻓﻲ‬ .‫ﺍﻟﻤﺎء‬ ‫ﻓﻲ‬ ‫ﻳﺬﻭﺏ‬
ܴ‫ܪܱܱܥ‬
‫ﺍﻟﻤﺮﺍﻓﻖ‬ ‫ﻭﻷﺳﺎﺳﻪ‬
‫ﺑﺎﻟﺮﻣﺰ‬
ܴ‫ܱܱܥ‬ି
:‫ﻳﻌﻄﻰ‬ .
‫ܯ‬ሺܴ‫ܪܱܱܥ‬ሻ ൌ ʹͲ͸݃Ȁ݉‫݈݋‬
.
): ‫ﻛﺮﺑﻮﻛﺴﻴﻠﻲ‬ ‫ﻟﺤﻤﺾ‬ ‫ﺗﻮﺍﺯﻥ‬ ‫ﺛﺎﺑﺖ‬ ‫ﺩﺭﺍﺳﺔ‬
03.5
( ‫ﻧﻘﺎﻁ‬
‫ﺍﻹﻳﺒﻮﺑﺮﻭﻓﻴﻦ‬ ‫ﻛﻴﺲ‬ ‫ﻣﺤﺘﻮﻯ‬ ‫ﻧﺬﻳﺐ‬
mg
200
‫ﻣﺎﺋﻲ‬ ‫ﻣﺤﻠﻮﻝ‬ ‫ﻋﻠﻰ‬ ‫ﻓﻨﺤﺼﻞ‬ ‫ﻣﺎء‬ ‫ﺑﻪ‬ ‫ﺑﻴﺸﺮ‬ ‫ﻓﻲ‬ ‫ﺍﻟﺤﻤﺾ‬ ‫ﻣﻦ‬
0
S
‫ﺍﻟﻤ‬ ‫ﺗﺮﻛﻴﺰﻩ‬
‫ﻮﻟﻲ‬
0
C
‫ﻭﺣﺠﻤﻪ‬
=500 ml
0
V
.
1
–
: ‫ﺃﻥ‬ ‫ﻣﻦ‬ ‫ﺗﺄﻛﺪ‬
= 0.002 mol/l
0
C
.
2
–
‫ﻗﻴﺎﺱ‬ ‫ﺃﻋﻄﻰ‬
pH
‫ﺍﻟﻤﺤﻠﻮﻝ‬
0
S
‫ﺍﻟﻘﻴﻤﺔ‬
pH =3,5
.
‫ﺃ‬
–
‫ﺗ‬
.‫ﻣﺤﺪﻭﺩ‬ ‫ﺍﻟﻤﺎء‬ ‫ﻣﻊ‬ ‫ﺍﻹﻳﺒﻮﺑﺮﻭﻓﻴﻦ‬ ‫ﺣﻤﺾ‬ ‫ﺗﻔﺎﻋﻞ‬ ‫ﺃﻥ‬ ‫ﺍﻟﺘﻘﺪﻡ‬ ‫ﻝ‬ ّ‫ﺑﺠﺪﻭ‬ ‫ﺑﺎﺳﺘﻌﺎﻧﺘﻚ‬ ‫ﺤﻘﻖ‬
‫ﺏ‬
–
‫ﺍﻟﺘﻔﺎﻋﻞ‬ ‫ﻛﺴﺮ‬ ‫ﺍﻛﺘﺐ‬
r
Q
.‫ﻝ‬ ّ‫ﺍﻟﺘﺤﻮ‬ ‫ﻟﻬﺬﺍ‬
‫ﺝ‬
–
‫ﻋﺒﺎﺭﺓ‬ ‫ﺃﻥ‬ ‫ّﻦ‬‫ﻴ‬‫ﺑ‬
r
Q
:‫ﺍﻟﺸﻜﻞ‬ ‫ﻋﻠﻰ‬ ‫ﺗﻜﺘﺐ‬ ‫ﺍﻟﺘﻮﺍﺯﻥ‬ ‫ﻋﻨﺪ‬
ܳ௥Ǥé௤ ൌ
௑೘ೌೣǤఛ೑
మ
௏బǤሺଵିఛ೑ሻ
.
‫ﺣﻴﺚ‬
f
τ
‫ﻭ‬ ‫ﻟﻠﺘﻔﺎﻋﻞ‬ ‫ﺍﻟﻨﻬﺎﺋﻲ‬ ‫ﺍﻟﺘﻘﺪﻡ‬ ‫ﻧﺴﺒﺔ‬ :
max
X
‫ﺑـ‬ ‫ﻋﻨﻪ‬ ‫ﻭﻳﻌﺒﺮ‬ ‫ﺍﻷﻋﻈﻤﻲ‬ ‫ﺍﻟﺘﻘﺪﻡ‬ :
mol
.
‫ﺩ‬
–
‫ﺍﻟﺘﻮﺍﺯﻥ‬ ‫ﺛﺎﺑﺖ‬ ‫ﻗﻴﻤﺔ‬ ‫ﺍﺳﺘﻨﺘﺞ‬
K
.
II
.
‫ﺍﻟﺘﺠﺎﺭﻱ‬ ‫ﺍﻟﺨﻞ‬ ‫ﺣﻤﻀﻴﺔ‬ ‫ﺩﺭﺟﺔ‬
):
03.5
( ‫ﻧﻘﺎﻁ‬
‫ﺣﺠﻤﺎ‬ ‫ﻧﺄﺧﺬ‬ ، ‫ﺍﻟﻜﻴﺲ‬ ‫ﻋﻠﻰ‬ ‫ﺍﻟﻤﺴﺠﻞ‬ ‫ﺍﻟﻤﻘﺪﺍﺭ‬ ‫ﺻﺤﺔ‬ ‫ﻣﻦ‬ ‫ﻟﻠﺘﺤﻘﻖ‬
=100 ml
b
V
‫ﻣﺎﺋﻲ‬ ‫ﻣﺤﻠﻮﻝ‬ ‫ﻣﻦ‬
b
S
‫ﺍﻟﺼﻮﺩﻳﻮﻡ‬ ‫ﻟﻬﻴﺪﺭﻭﻛﺴﻴﺪ‬
ሺܰܽାሺƒ“ሻ ൅ ିሺƒ“ሻሻ
‫ﺍﻟﻤﻮﻟﻲ‬ ‫ﺗﺮﻛﻴﺰﻩ‬.
=0.02 mol/l
b
C
‫ﻣﺎﺋﻲ‬ ‫ﻣﺤﻠﻮﻝ‬ ‫ﻋﻠﻰ‬ ‫ﻓﻨﺤﺼﻞ‬ ‫ﺍﻟﻜﻴﺲ‬ ‫ﻣﺤﺘﻮﻯ‬ ‫ﻛﻠﻴﺎ‬ ‫ﻓﻴﻪ‬ ‫ﻭﻧﺬﻳﺐ‬
S
‫ﺍﻟﻤﺤﻠﻮﻝ‬ ‫ﺣﺠﻢ‬ ‫ﺃﻥ‬ ‫ﻧﻌﺘﺒﺮ‬ )
S
‫ﻫﻮ‬
b
V
‫ﻧﺄﺧﺬ‬ .(
ml
20
‫ﺍﻟﻤﺤﻠﻮﻝ‬ ‫ﻣﻦ‬
S
‫ﺍﻟﻬﻴﺪﺭﻭﺟﻴﻦ‬ ‫ﻛﻠﻮﺭ‬ ‫ﺣﻤﺾ‬ ‫ﺑﻤﺤﻠﻮﻝ‬ ‫ﻭﻧﻌﺎﻳﺮﻩ‬ ‫ﺑﻴﺸﺮ‬ ‫ﻓﻲ‬ ‫ﻭﻧﻀﻌﻪ‬
‫ﺍﻟﻤﻮﻟﻲ‬ ‫ﺗﺮﻛﻴﺰﻩ‬
= 0.02 mol/l
a
C
‫ﺍﻟﻤﻨﺤﻨﻰ‬ ‫ﻋﻠﻰ‬ ‫ﻓﻨﺤﺼﻞ‬
‫ﺍﻟﺒﻴﺎﻧﻲ‬
‫ﺍﻟﺸﻜﻞ‬
–
9
:‫ﻫﻲ‬ ‫ﺍﻟﻤﻌﺎﻳﺮﺓ‬ ‫ﺗﻔﺎﻋﻞ‬ ‫ﻣﻌﺎﺩﻟﺔ‬ ،
‫ܪ‬ଷܱାሺܽ‫ݍ‬ሻ ൅‫ܱܪ‬ିሺܽ‫ݍ‬ሻ ൌʹ‫ܪ‬ଶܱሺℓሻ
.
1
–
.‫ﺍﻟﻤﻌﺎﻳﺮﺓ‬ ‫ﻋﻤﻠﻴﺔ‬ ‫ﺗﺨﻄﻴﻄﻲ‬ ‫ﺑﺸﻜﻞ‬ ‫ﺍﺭﺳﻢ‬
2
–
‫ﺍﻟﻨﻘﻄﺔ‬ ‫ﻫﺬﻩ‬ ‫ﺇﺣﺪﺍﺛﻴﺘﻲ‬ ‫ﺣﺪﺩ‬ ّ‫ﻢ‬‫ﺛ‬ ،‫ﺍﻟﺘﻜﺎﻓﺆ‬ ‫ﻧﻘﻄﺔ‬ ‫ﻑ‬ّ‫ﻋﺮ‬
E
.
3
–
‫ﻟﺸﻮﺍﺭﺩ‬ ‫ﺍﻟﻤﺎﺩﺓ‬ ‫ﻛﻤﻴﺔ‬ ‫ﺟﺪ‬
‫ܱܪ‬ି
ሺܽ‫ݍ‬ሻ
.‫ﻣﻌﺎﻳﺮﺗﻬﺎ‬ ‫ﺗﻤﺖ‬ ‫ﺍﻟﺘﻲ‬
4
–
‫ﻟﺸﻮﺍﺭﺩ‬ ‫ﺍﻷﺻﻠﻴﺔ‬ ‫ﺍﻟﻤﺎﺩﺓ‬ ‫ﻛﻤﻴﺔ‬ ‫ﺟﺪ‬
‫ܱܪ‬ି
ሺܽ‫ݍ‬ሻ
‫ﺍﺳﺘﻨﺘﺞ‬ ‫ﺛﻢ‬ ،
‫ﺍﻟﺤﻤﺾ‬ ‫ﻣﻊ‬ ‫ﺗﻔﺎﻋﻠﺖ‬ ‫ﺍﻟﺘﻲ‬ ‫ﺗﻠﻚ‬
RCOOH
.‫ﺍﻟﻜﻴﺲ‬ ‫ﻓﻲ‬ ‫ﺍﻟﻤﺘﻮﺍﺟﺪ‬
5
–
‫ﺍﺣﺴﺐ‬
m
.‫ﺍﻟﻜﻴﺲ‬ ‫ﻓﻲ‬ ‫ﺍﻟﻤﺘﻮﺍﺟﺪﺓ‬ ‫ﺍﻟﺤﻤﺾ‬ ‫ﻛﺘﻠﺔ‬
‫ﺗﺴﺘﻨﺘﺞ؟‬ ‫ﻣﺎﺫﺍ‬
e
n
c
y
-
e
d
u
c
a
t
i
o
n
.
c
o
m
/
e
x
a
m
s
‫ﺑﺎﻷ‬
‫ﺗﺤﻤﻞ‬
‫ﺗﺤ‬
‫ﺑﺎﻟﺮﻣﺰ‬
‫ﺑﺎﻟﺮﻣﺰ‬
ܱି
‫ﻟﺤﻤ‬ ‫ﺗﻮﺍﺯﻥ‬ ‫ﺛﺎﺑﺖ‬ ‫ﺩﺭﺍﺳﺔ‬
‫ﺗﻮﺍﺯﻥ‬ ‫ﺛﺎﺑﺖ‬ ‫ﺳﺔ‬
a
m
‫ﻛﻴﺲ‬ ‫ﻣﺤﺘﻮﻯ‬ ‫ﻧﺬﻳﺐ‬
‫ﻣﺤﺘﻮﻯ‬ ‫ﺬﻳﺐ‬
0
0
C
C
‫ﻭﺣﺠﻤﻪ‬
‫ﻭﺣﺠﻤﻪ‬
0 ml
ml
: ‫ﺃﻥ‬ ‫ﻣﻦ‬ ‫ﺗﺄﻛﺪ‬
: ‫ﺃﻥ‬ ‫ﻣﻦ‬
2 mol/l
ol/l
‫ﻗﻴﺎﺱ‬ ‫ﻄﻰ‬
‫ﻴﺎﺱ‬
pH
pH
‫ﺍﻟﻤﺤﻠﻮﻝ‬
‫ﺍﻟﻤﺤﻠﻮ‬
0
‫ﺍﻟﺘﻘﺪﻡ‬ ‫ﻝ‬
‫ﺍ‬ ‫ﺑﺠﺪﻭﻝ‬ ‫ﺑﺎﺳﺘﻌﺎﻧﺘﻚ‬
‫ﺑﺠﺪﻭ‬ ‫ﺘﻌﺎﻧﺘﻚ‬
ّ
‫ﺍﻟﺘﻔﺎﻋﻞ‬ ‫ﺴﺮ‬
‫ﺘﻔﺎﻋﻞ‬
r
Q
Q
‫ﺍﻟﺘﺤ‬ ‫ﻟﻬﺬﺍ‬
‫ﻟﻬﺬ‬
Q
‫ﻋ‬ ‫ﺗﻜﺘﺐ‬ ‫ﺍﻟﺘﻮﺍﺯﻥ‬ ‫ﻋﻨﺪ‬
‫ﺗﻜﺘ‬ ‫ﺍﻟﺘﻮﺍﺯﻥ‬
‫ﻭ‬ ‫ﻟﻠﺘﻔﺎﻋﻞ‬ ‫ﻟﻨﻬﺎﺋﻲ‬
‫ﻭ‬ ‫ﻟﻠﺘﻔﺎﻋﻞ‬ ‫ﻲ‬
max
x
Xm
K
( ‫ﻘﺎﻁ‬
‫ﺣﺠﻤﺎ‬ ‫ﻧﺄﺧﺬ‬ ،
‫ﺣﺠﻤﺎ‬ ‫ﺬ‬
=100 ml
00 ml
=0.02 m
=0.02
b
C
C
‫ﻓﻴ‬ ‫ﻭﻧﺬﻳﺐ‬
‫ﻭﻧﺬﻳﺐ‬
‫ﻟﻤﺤﻠﻮﻝ‬
‫ﻠﻮﻝ‬
‫ﻴﻦ‬
3as.ency-education.com

4. 0
‫ﻣﻥ‬
06 4 ‫ﺍﻟﺻﻔﺣﺔ‬
‫ﺍﻟﺜﺎﻧﻲ‬ ‫ﻣﻮﺿﻮﻉ‬
‫اﳉﺰ‬
‫ء‬
‫اﻻول‬
:
‫ﻋﻠﻰ‬
13
‫ﻧﻘﻄﺔ‬
‫ﻳ‬‫ﺰ‬‫اﻟﻔﻴ‬ )
‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬
(‫ﺎء‬
‫اﻟ‬
‫ﻳﻦ‬‫ﺮ‬‫ﺘﻤ‬
‫اﻻول‬
:
)
06
(‫ﻧﻘﻄﺔ‬
I
.
): ‫ﻣﻜﺜﻔﺔ‬ ‫ﻭﺗﻔﺮﻳﻎ‬ ‫ﺷﺤﻦ‬ ‫ﺩﺭﺍﺳﺔ‬
04
( ‫ﻧﻘﺎﻁ‬
‫ﺳﻌﺘﻬﺎ‬ ‫ﻣﻜﺜﻔﺔ‬
C
) ‫ﺛﺎﺑﺖ‬ ‫ﺗﻮﺗﺮ‬ ‫ﺗﺤﺖ‬ ‫ﺷﺤﻨﻬﺎ‬ ‫ﺗﻢ‬
E = 12V
‫ﺛﻢ‬ . (
‫ﻣﻘﺎﻭﻣﺘﻪ‬ ‫ﺃﻭﻣﻲ‬ ‫ﻧﺎﻗﻞ‬ ‫ﻓﻲ‬ ‫ﺗﻔﺮﻳﻐﻬﺎ‬ ‫ﺃﻋﻴﺪ‬
:
5
R = 10
.
1
-
/
‫ﺍﻟﻘﺎﻁﻌﺔ‬ ‫ﻧﻌﺘﺒﺮ‬
) ‫ﻭﺿﻊ‬ ‫ﻓﻲ‬
1
(
‫ﺣﻘﻴﻘﻲ‬ ‫ﺑﻞ‬ ‫ﻣﺜﺎﻟﻲ‬ ‫ﻟﻴﺲ‬ ‫ﻭﺍﻟﻤﻮﻟﺪ‬
)
Ω
r=10
(
.
1
-
1
‫ﻟﺘﻮﺗﺮ‬ ‫ﺍﻟﺘﻔﺎﺿﻠﻴﺔ‬ ‫ﺍﻟﻤﻌﺎﺩﻟﺔ‬ ‫ﺍﻋﻂ‬ ‫ﺗﻮﺗﺮﺍﺕ‬ ‫ﻗﺎﻧﻮﻥ‬ ‫ﺑﺎﺳﺘﻌﻤﺎﻝ‬
Uc
‫؟‬ ‫ﺍﻟﻤﻜﺜﻔﺔ‬ ‫ﻁﺮﻓﻲ‬ ‫ﺑﻴﻦ‬
1
-
2
‫ﻋﻨﺪ‬
t=0
‫ﺍﻟﺘﻴﺎﺭ‬ ‫ﺷﺪﺓ‬ ‫ﺗﻜﻮﻥ‬ ‫ﻛﻢ‬
0
I
‫؟‬ ‫ﺩﺍﺭﺓ‬ ‫ﻓﻲ‬
2
-
/
) ‫ﻭﺿﻊ‬ ‫ﻓﻲ‬ ‫ﺍﻟﻘﺎﻁﻌﺔ‬ ‫ﻧﻌﺘﺒﺮ‬
2
‫ﺍﻟﺴﺎﺑﻖ‬ ‫ﺍﻟﺸﻜﻞ‬ ‫ﻓﻲ‬ (
.
2
-
1
‫ﺑﺪﻻﻟﺔ‬ ‫ﻟﻠﺪﺍﺭﺓ‬ ‫ﺍﻟﺘﻔﺎﺿﻠﻴﺔ‬ ‫ﺍﻟﻤﻌﺎﺩﻟﺔ‬ ‫ﺃﻛﺘﺐ‬
q ( t )
‫ﺍﻟﺘﻔﺮﻳﻎ‬ ‫ﺧﻼﻝ‬
‫؟‬
2
-
2
‫ﻫﻮ‬ ‫ﺣﻠﻬﺎ‬ ‫ﺃﻥ‬ ‫ﺑﻴﻦ‬
W
t/
-
e
0
= Q
q( t )
‫؟‬
2
-
3
‫؟‬ ‫ﺍﻟﺰﻣﻦ‬ ‫ﺛﺎﺑﺖ‬ ‫ﺑﻴﺎﻧﻴﺎ‬ ‫ﻋﻴﻦ‬
2
-
4
‫ﺍﻟﻤﻜﺜﻔﺔ‬ ‫ﺳﻌﺔ‬ ‫ﺃﺣﺴﺐ‬
C
‫؟‬
6
‫ﺍﻟﻠﺤﻈﺔ‬ ‫ﻋﻨﺪ‬ ‫ﺍﻟﻤﻜﺜﻔﺔ‬ ‫ﺷﺤﻨﺔ‬ ‫ﺃﺣﺴﺐ‬ ‫ـ‬ (
t = 0
‫؟‬
7
‫ﺃ‬ ‫ـ‬ (
‫ﺍﻟﻠﺤﻈ‬ ‫ﻧﻔﺲ‬ ‫ﻋﻨﺪ‬ ‫ﺍﻟﺘﻴﺎﺭ‬ ‫ﺷﺪﺓ‬ ‫ﺣﺴﺐ‬
‫ﺔ‬
‫؟‬
‫ﺩﺭﺍﺳﺔ‬
‫ﺍﻟﻬﻴﺪﺭﻭﺟﻴﻦ‬ ‫ﻧﻈﺎﺋﺮ‬ ‫ﻧﻮﺍﺗﻲ‬ ‫ﺍﻧﺪﻣﺎﺝ‬
):
03
( ‫ﻧﻘﺎﻁ‬
. ‫ﺍﻟﻬﻴﺪﺭﻭﺟﻴﻦ‬ ‫ﻣﻦ‬ ‫ﺃﺳﺎﺳﺎ‬ ‫ﺗﺘﻜﻮﻥ‬ ‫ﺍﻟﺸﻤﺲ‬ ‫ﻣﺜﻞ‬ ‫ﺍﻟﺼﻔﺮﺍء‬ ‫ﺍﻟﻨﺠﻮﻡ‬
‫ﺗﻘﺎﺭﺏ‬ ‫ﺍﻟﻨﺠﻮﻡ‬ ‫ﻫﺬﻩ‬ ‫ﺣﺮﺍﺭﺓ‬ ‫ﺩﺭﺟﺔ‬ ‫ﺗﻜﻮﻥ‬ ‫ﻋﻨﺪﻣﺎ‬
K
7
10
5
.
1 u
‫ﺍﻧﺪﻣﺎﺝ‬ ‫ﺗﻔﺎﻋﻼﺕ‬ ‫ﺗﺤﺪﺙ‬
‫ﻧﻮﺍﺓ‬ ‫ﻓﺘﻌﻄﻲ‬ ‫ﺍﻟﺒﺮﻭﺗﻮﻧﺎﺕ‬ ‫ﺑﻴﻦ‬
Y
A
Z
/
/
‫ﺣﺴﺐ‬
: ‫ﺍﻟﺘﺎﻟﻴﺔ‬ ‫ﺍﻟﺴﻠﺴﻠﺔ‬
)
3
........(
2
)
2
.....(
..........
)
1
.......(
.......... 1
1
/
/
3
2
3
2
3
2
1
1
0
1
1
1
1
1 H
Y
H
H
H
X
H
e
X
H
H A
Z
e
e
e
A
Z
A
Z
o
o
o
J
1
/
-
‫ﺍ‬
‫ﺍﻟﻨﻮﺍﺗﻴﻦ‬ ‫ﻋﻠﻰ‬ ‫ﺗﻌﺮﻑ‬ ‫ﺍﻟﻤﻌﺎﺩﻻﺕ‬ ‫ﻫﺬﻩ‬ ‫ﻣﻦ‬ ‫ﻧﻄﻼﻗﺎ‬
Y
‫ﻭ‬
X A
Z
A
Z
/
/
2
/
-
‫ﺍ‬
‫ﺍﻟﻨﻮﺍﺓ‬ ‫ﻟﺘﺸﻜﻞ‬ ‫ﺍﻹﺟﻤﺎﻟﻲ‬ ‫ﺍﻟﺘﻔﺎﻋﻞ‬ ‫ﻣﻌﺎﺩﻟﺔ‬ ‫ﻛﺘﺐ‬
Y
A
Z
/
/
‫ﺍﻻﻧﺪﻣﺎﺝ‬ ‫ﺗﻔﺎﻋﻞ‬ ‫ﻋﺮﻑ‬ . ‫ﺍﻟﻬﻴﺪﺭﻭﺟﻴﻦ‬ ‫ﺍﻧﻮﻳﺔ‬ ‫ﻣﻦ‬ ‫ﺍﻧﻄﻼﻗﺎ‬
.
3
/
-
‫ﺗ‬ ‫ﺍﻻﻥ‬ ‫ﻧﻌﺘﺒﺮ‬
: ‫ﺍﻟﺘﺎﻟﻲ‬ ‫ﺍﻻﻧﺪﻣﺎﺝ‬ ‫ﻔﺎﻋﻞ‬
J
2
2
4 0
1
4
2
1
1
o e
H
H e
‫ﺃ‬
-
‫ﺍﻟﻜﺘﻠﺔ‬ ‫ﻓﻲ‬ ‫ﺍﻟﻨﻘﺺ‬ ‫ﺍﺣﺴﺐ‬
‫ﻟ‬
‫ﻠﺘﻔﺎﻋﻞ‬
‫ﻧﻜﻠﻴﻮﻥ‬ ‫ﻟﻜﻞ‬ ‫ﺍﻟﻤﺤﺮﺭﺓ‬ ‫ﺍﻟﻄﺎﻗﺔ‬ ‫ﺍﺳﺘﻨﺘﺞ‬ ‫ﻭ‬ ‫ﺍﻟﻤﺤﺮﺭﺓ‬ ‫ﺍﻟﻄﺎﻗﺔ‬ ‫ﺛﻢ‬
‫ﺍﻻﻧﺪ‬ ‫ﺗﻔﺎﻋﻞ‬ ‫ﺍﺛﻨﺎء‬
‫ﻫﺬﺍ‬ ‫ﻣﺎﺝ‬
‫ﺑـ‬
Mev
.
‫ﺏ‬
-
‫ﺍﻟﻤ‬ ‫ﺍﻟﻄﺎﻗﺔ‬ ‫ﺍﺣﺴﺐ‬
‫ﻋﻠﻰ‬ ‫ﻟﻠﺤﺼﻮﻝ‬ ‫ﺤﺮﺭﺓ‬
1g
‫ﺍﻟﻬﻠﻴﻮﻡ‬ ‫ﻣﻦ‬
4
‫ﺑـ‬
Mev
‫ﺑـ‬ ‫ﺛﻢ‬ ‫ﺍﻟﺠﻮﻝ‬ ‫ﺑـ‬ ،
(T.e.p)
‫ﺍﻟﺒﺘﺮﻭﻝ‬ ‫ﻣﻦ‬ ‫ﺍﻟﻤﻜﺎﻓﺊ‬ ‫)ﺍﻟﻄﻦ‬
(T.e.p)
‫ﺍﻟﺼﻨﺎﻋﺔ‬ ‫ﻣﺠﺎﻝ‬ ‫ﻓﻲ‬ ‫ﺗﺴﺘﻌﻤﻞ‬ ، ‫ﺍﻟﻄﺎﻗﺔ‬ ‫ﻟﻘﻴﺎﺱ‬ ‫ﻭﺣﺪﺓ‬ ‫ﻫﻲ‬
(
‫ﺝ‬
-
‫ﺍ‬
‫؟‬ ‫ﺗﺴﺘﻨﺘﺞ‬ ‫ﻣﺎﺫﺍ‬ . ‫ﺍﻟﻄﺎﻗﺔ‬ ‫ﻧﻔﺲ‬ ‫ﺗﺤﺮﺭ‬ ‫ﺍﻟﺘﻲ‬ ‫ﺍﻟﺒﺘﺮﻭﻝ‬ ‫ﻛﺘﻠﺔ‬ ‫ﺣﺴﺐ‬
e
H
4
2
e
H
3
2
H
2
1
H
1
1
e
0
1
‫ﺍﻟﻨﻮﺍﺓ‬
4.0015
3.0149
2.0134
1.0073
0.0006
)
(u
m
X
A
Z
2
Kg = 931.5Mev/c
27
-
u = 1.661.10
1
1
-
mol
23
=6.02 . 10
A
N
,
J
13
-
10
.
Mev = 1.6
1
,
J
9
T.e.p = 42 10
1
e
n
c
y
-
e
d
u
c
a
t
i
o
n
.
c
o
m
/
e
x
a
m
s
‫ﻣﻜﺜﻔﺔ‬
‫ﻣﻜ‬
‫ﺗﻔﺮﻳﻐﻬ‬ ‫ﺃﻋﻴﺪ‬
‫ﺗﻔﺮ‬ ‫ﺃﻋﻴﺪ‬
1
1
-
-
/
/
‫ﺍﻟﻘﺎﻁ‬ ‫ﻧﻌﺘﺒﺮ‬
‫ﻧﻌﺘﺒﺮ‬
)
Ω
Ω
r=10
r=10
(
(
.
1
-
1
‫ﺗﻮ‬ ‫ﻗﺎﻧﻮﻥ‬ ‫ﺑﺎﺳﺘﻌﻤﺎﻝ‬
‫ﻗﺎﻧ‬ ‫ﺑﺎﺳﺘﻌﻤﺎﻝ‬
‫؟‬ ‫ﺍﻟﻤﻜﺜﻔﺔ‬ ‫ﻁﺮﻓﻲ‬
‫؟‬ ‫ﺍﻟﻤﻜﺜﻔﺔ‬ ‫ﻲ‬
t=0
t
‫ﺍﻟﺘﻴﺎ‬ ‫ﺷﺪﺓ‬ ‫ﺗﻜﻮﻥ‬ ‫ﻛﻢ‬
‫ﺷﺪﺓ‬ ‫ﺗﻜﻮﻥ‬ ‫ﻛﻢ‬
) ‫ﻭﺿﻊ‬ ‫ﻓﻲ‬ ‫ﻁﻌﺔ‬
) ‫ﻭﺿﻊ‬ ‫ﻓﻲ‬
2
2
‫ﻓﻲ‬ (
‫ﻓ‬ (
‫ﺑﺪﻻﻟ‬ ‫ﻟﻠﺪﺍﺭﺓ‬ ‫ﺍﻟﺘﻔﺎﺿﻠﻴﺔ‬ ‫ﻟﺔ‬
‫ﻟﻠﺪﺍﺭﺓ‬ ‫ﺘﻔﺎﺿﻠﻴﺔ‬
= Q
=
q( t )
q( t )
‫؟‬
‫؟‬
t = 0
t
‫؟‬
‫؟‬
. ‫ﺭﻭﺟﻴﻦ‬
. ‫ﻦ‬
‫ﺍﻧﺪﻣﺎ‬ ‫ﺗﻔﺎﻋﻼﺕ‬ ‫ﺗﺤﺪﺙ‬
‫ﺗﻔﺎﻋﻼﺕ‬ ‫ﺙ‬
)
)
1
1
.......(
....(
.. 1
1H
‫ﺍﻻﻧﺪﻣ‬ ‫ﺗﻔﺎﻋﻞ‬ ‫ﻋﺮﻑ‬ . ‫ﺟﻴﻦ‬
‫ﺗﻔﺎﻋ‬ ‫ﻋﺮﻑ‬
‫ﻥ‬
‫ﺍﻻﻧﺪ‬ ‫ﺗﻔﺎﻋﻞ‬ ‫ﺍﺛﻨﺎء‬
‫ﺍﻻﻧ‬ ‫ﺗﻔﺎﻋﻞ‬ ‫ﻨﺎء‬
‫ﻫ‬ ‫ﻣﺎﺝ‬
(T
3as.ency-education.com

5. 0
‫ﻣﻥ‬
06 5 ‫ﺍﻟﺻﻔﺣﺔ‬
): ‫اﻟﺜﺎﱐ‬ ‫ﻳﻦ‬‫ﺮ‬‫اﻟﺘﻤ‬
07
(‫ﻧﻘﻄﺔ‬
I
.
‫ﺩﺭﺍﺳﺔ‬
‫ﺣﺮﻛﺔ‬
‫ﻁﻔﻞ‬
‫ﻣﺎﺋﻠﺔ‬ ‫ﻁﺮﻳﻖ‬ ‫ﻋﻠﻰ‬ ‫ﻳﻨﺰﻟﻖ‬
:
)
.5
2
0
( ‫ﻧﻘﺎﻁ‬
‫ﻋﻄﺎﻟﺘﻪ‬ ‫ﻣﺮﻛﺰ‬ ‫ﻁﻔﻞ‬ ‫ﻳﻨﺰﻟﻖ‬
G
‫ﻭﻛﺘﻠﺘﻪ‬
m
‫ﺟﺰء‬ ‫ﻣﻦ‬ ‫ﻣﻜﻮﻧﺔ‬ ‫ﻣﺴﺒﺢ‬ ‫ﻣﺰﻟﻘﺔ‬ ‫ﻓﻮﻕ‬
AB
‫ﺑﺰﺍﻭﻳﺔ‬ ‫ﺍﻷﻓﻖ‬ ‫ﻋﻦ‬ ‫ﻣﺎﺋﻞ‬ ‫ﻣﺴﺘﻮ‬
α
‫ﻭﺟ‬
‫ﺰء‬
BC
‫ﺍﻻﺭﺗﻔﺎﻉ‬ ‫ﻋﻠﻰ‬ ‫ﻳﻮﺟﺪ‬ ‫ﺃﻓﻘﻲ‬ ‫ﻣﺴﺘﻮ‬
h
‫ﺍﻟﺸﻜﻞ‬ ) ‫ﺍﻟﻤﺴﺒﺢ‬ ‫ﻣﺎء‬ ‫ﺳﻄﺢ‬ ‫ﻣﻦ‬
-
1
.(
:‫ﺍﻟﻤﻌﻄﻴﺎﺕ‬
، ‫ﻣﻬﻤﻠﺔ‬ ‫ﺍﻻﺣﺘﻜﺎﻛﺎﺕ‬
g=10(si)
،
AB=10m
،
CE=h=1,8m
.
‫ﺍﻟﻠﺤﻈﺔ‬ ‫ﻋﻨﺪ‬ ‫ﺍﻟﻄﻔﻞ‬ ‫ﻳﻨﻄﻠﻖ‬
t=0
‫ﺍﻟﻤﻮﺿﻊ‬ ‫ﻣﻦ‬ ‫ﺍﺑﺘﺪﺍﺋﻴﺔ‬ ‫ﺳﺮﻋﺔ‬ ‫ﺑﺪﻭﻥ‬
A
‫ﻋﻠﻰ‬ ‫ﻓﻴﻨﺰﻟﻖ‬ ،
AB
‫ﺣﺮﻛﺔ‬ ‫ﻟﺪﺭﺍﺳﺔ‬ ،
G
‫ﻧﺨﺘﺎﺭ‬ ،
‫ﻣ‬
‫ﻌﻠﻤﺎ‬
ሺ‫ܣ‬ǡ ଓ
Ԧሻ
‫ﺣﻴﺚ‬ ‫ﺑﺎﻷﺭﺽ‬ ‫ﻣﺮﺗﺒﻄﺎ‬
=0
A
=X
G
X
‫ﻋﻨﺪ‬
)
t=0
(
.
1
(
‫ﺍﻟﻤﻌﺎﺩﻟﺔ‬ ‫ﺃﻥ‬ ‫ﺃﺛﺒﺖ‬ ،‫ﻟﻨﻴﻮﺗﻦ‬ ‫ﺍﻟﺜﺎﻧﻲ‬ ‫ﺍﻟﻘﺎﻧﻮﻥ‬ ‫ﺑﺘﻄﺒﻴﻖ‬
‫ﺍﻟﻔﺎﺻﻠﺔ‬ ‫ﺗﺤﻘﻘﻬﺎ‬ ‫ﺍﻟﺘﻲ‬ ‫ﺍﻟﺘﻔﺎﺿﻠﻴﺔ‬
G
X
‫ﻋﻄﺎﻟﺔ‬ ‫ﻟﻤﺮﻛﺰ‬
:‫ﻳﻠﻲ‬ ‫ﻛﻤﺎ‬ ‫ﺗﻜﺘﺐ‬ ‫ﺍﻟﻄﻔﻞ‬
ௗమ௑ಸ
ௗ௧మ
ൌ ‰Ǥ •‹α
‫ﺣﺮﻛﺔ‬ ‫ﻁﺒﻴﻌﺔ‬ ‫ﺍﺳﺘﻨﺘﺞ‬ .
G
.
2
(
‫ﺭﻗﻤﻴﺔ‬ ‫ﻛﺎﻣﻴﺮﺍ‬ ‫ﺑﻮﺍﺳﻄﺔ‬ ‫ﺍﻟﻄﻔﻞ‬ ‫ﺣﺮﻛﺔ‬ ‫ﺗﺼﻮﻳﺮ‬ ‫ﺑﻌﺪ‬
‫ﺗﻢ‬ ‫ﻣﻨﺎﺳﺐ‬ ‫ﺑﺮﻧﺎﻣﺞ‬ ‫ﺑﻮﺍﺳﻄﺔ‬ ‫ﺍﻟﻤﻌﻄﻴﺎﺕ‬ ‫ﻭﻣﻌﺎﻟﺠﺔ‬
‫ﺍﻟﻌﻄﺎﻟﺔ‬ ‫ﻟﻤﺮﻛﺰ‬ ‫ﺍﻟﺴﺮﻋﺔ‬ ‫ﻣﺨﻄﻂ‬ ‫ﻋﻠﻰ‬ ‫ﺍﻟﺤﺼﻮﻝ‬
G
‫)ﺍﻟﺸﻜﻞ‬
-
2
.(
‫ﺃ‬
.
‫ﺍﻟﺘﺴﺎﺭﻉ‬ ‫ﻗﻴﻤﺔ‬ ‫ﺑﻴﺎﻧﻴﺎ‬ ‫ﺃﻭﺟﺪ‬
G
a
.
‫ﺏ‬
.
‫ﺍﻟﺠﺰء‬ ‫ﻋﻠﻰ‬ ‫ﺍﻟﻤﺴﺘﻐﺮﻗﺔ‬ ‫ﺍﻟﺰﻣﻨﻴﺔ‬ ‫ﺍﻟﻤﺪﺓ‬ ‫ﺣﺪﺩ‬
AB
.
II
.
‫ﻗﺬﻳﻔﺔ‬ ‫ﺷﻜﻞ‬ ‫ﻋﻠﻰ‬ ‫ﻁﻔﻞ‬ ‫ﺣﺮﻛﺔ‬ ‫ﺩﺭﺍﺳﺔ‬
):
.5
4
0
( ‫ﻧﻘﺎﻁ‬
e
n
c
y
-
e
d
u
c
a
t
i
o
n
.
c
o
m
/
C
CE=h=1,8m
E=h=1,8
.
.
A
a
m
s
‫ﻳﻨﺰ‬
‫ﺃﻓ‬ ‫ﻣﺴﺘﻮ‬
‫ﻣﺴ‬
‫ﻋﻠﻰ‬ ‫ﻓﻴﻨﺰﻟﻖ‬ ،
‫ﻋﻠﻰ‬ ‫ﻓﻴﻨﺰﻟﻖ‬
AB
B
،
3as.ency-education.com

6. 0
‫ﻣﻥ‬
06 6 ‫ﺍﻟﺻﻔﺣﺔ‬
‫ﺍﻟﻤﻮﺿﻊ‬ ‫ﻓﻲ‬ ‫ﺍﻟﻤﺰﻟﻘﺔ‬ ‫ﺍﻟﻄﻔﻞ‬ ‫ﻋﻄﺎﻟﺔ‬ ‫ﻣﺮﻛﺰ‬ ‫ﻳﻐﺎﺩﺭ‬
C
‫ﺑﺎﻟﺴﺮﻋﺔ‬
1
-
=11 m.s
c
V
‫ﻣﺎء‬ ‫ﻓﻲ‬ ‫ﻟﻴﺴﻘﻂ‬ ‫ﺍﻷﺯﻣﻨﺔ‬ ‫ﻣﺒﺪﺃ‬ ‫ﻫﺎ‬ ‫ﻧﻌﺘﺒﺮ‬ ‫ﻟﺤﻈﺔ‬ ‫ﻋﻨﺪ‬
‫ﺣﺮﻛﺔ‬ ‫ﻧﺪﺭﺱ‬ .‫ﺍﻟﻤﺴﺒﺢ‬
G
‫ﺍﻟﻤﻌﻠﻢ‬ ‫ﻓﻲ‬
ሺ‫ܥ‬ǡ ଓ
Ԧǡ ଔ
Ԧሻ
.
1
(
‫ﺍﻟﺰﻣﻨﻴﺘﻴﻦ‬ ‫ﺍﻟﻤﻌﺎﺩﻟﺘﻴﻦ‬ ‫ﻋﺒﺎﺭﺓ‬ ‫ﺃﻭﺟﺪ‬ ،‫ﺍﻟﺜﺎﻧﻲ‬ ‫ﻧﻴﻮﺗﻦ‬ ‫ﻗﺎﻧﻮﻥ‬ ‫ﺑﺘﻄﺒﻴﻖ‬
x(t)
‫ﻭ‬
y(t)
‫ﻟﺤﺮﻛﺔ‬
G
‫ﺍﺳﺘﻨﺘﺞ‬ .
‫ﻣﻌﺎﺩ‬
.‫ﺍﻟﻤﺴﺎﺭ‬ ‫ﻟﺔ‬
2
(
‫ﻳﺼﻞ‬
G
‫ﺍﻟﻤﻮﺿﻊ‬ ‫ﻓﻲ‬ ‫ﺍﻟﻤﺎء‬ ‫ﺳﻄﺢ‬ ‫ﺇﻟﻰ‬
I
‫ﺑﺎﻟﺴﺮﻋﺔ‬
‫ݒ‬ூ
ሬሬሬԦ
.
‫ﻭﺻﻮﻝ‬ ‫ﻟﺤﻈﺔ‬ ‫ﺃﻥ‬ ‫ﺗﺤﻘﻖ‬ .‫ﺃ‬
G
‫ﺇﻟﻰ‬
I
‫ﻫﻲ‬
=0,6s
I
t
.
‫ﺍ‬ .‫ﺏ‬
‫ﺣ‬
‫ﻗﻴﻤﺔ‬ ‫ﺴﺐ‬
‫ݒ‬ூ
‫ﺍﻟﻤﺴﺎﻓﺔ‬ ‫ﻗﻴﻤﺔ‬ ‫ﺣﺪﺩ‬ .
EI
.
3
(
‫ﻳﻨﺰﻟﻖ‬
‫ﻛﺘﻠﺘﻪ‬ ‫ﺁﺧﺮ‬ ‫ﻁﻔﻞ‬
m’
‫ﻣﻦ‬ ‫ﺃﻛﺒﺮ‬
m
‫ﺍﻟﻤﺴﺎﺭ‬ ‫ﻧﻔﺲ‬ ‫ﻋﻠﻰ‬
‫ﺍﻟﻤﺴﺎﻓﺔ‬ ‫ﻗﻴﻤﺔ‬ ‫ﺗﺘﻐﻴﺮ‬ ‫ﻫﻞ‬
EI
.‫ﻋﻠﻞ‬ ‫؟‬
‫اﳉﺰ‬
‫ء‬
‫اﻟﺜﺎﱐ‬
‫ﻋﻠﻰ‬ :
)
7
‫ﻧﻘﺎط‬
(
‫ـ‬‫ـ‬‫ـ‬‫ﻴ‬‫اﻟﻜﻤ‬ )
‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬
‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬
‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬
‫ـ‬‫ـ‬‫ـ‬‫ـ‬
(‫ـﺎء‬
‫اﻟﺜﺎﻟﺚ‬ ‫ﻳﻦ‬‫ﺮ‬‫اﻟﺘﻤ‬
:
I
.
): ‫ﻛﺮﺑﻮﻛﺴﻴﻠﻲ‬ ‫ﻟﺤﻤﺾ‬ ‫ﺗﻮﺍﺯﻥ‬ ‫ﺛﺎﺑﺖ‬ ‫ﺩﺭﺍﺳﺔ‬
04
( ‫ﻧﻘﺎﻁ‬
‫ﺍﻟﻤﻮﻟﻲ‬ ‫ﺗﺮﻛﻴﺰﻩ‬ ‫ﺍﻹﻳﺜﺎﻧﻮﻳﻚ‬ ‫ﻟﺤﻤﺾ‬ ‫ﻣﺤﻠﻮﻻ‬ ‫ﻧﻌﺘﺒﺮ‬
0
C
.
1
‫ﻣﻊ‬ ‫ﺍﻹﻳﺜﺎﻧﻮﻳﻚ‬ ‫ﺣﻤﺾ‬ ‫ﺗﻔﺎﻋﻞ‬ ‫ﻣﻌﺎﺩﻟﺔ‬ ‫ﺃﻛﺘﺐ‬ ‫ـ‬ (
‫؟‬ ‫ﺍﻟﻤﺎء‬
2
‫ﻋﻦ‬ ‫ﻋﺒﺮ‬ ‫ـ‬ (
f
@
+
O
3
H
‫ﻭ‬
f
@
-
COO
3
CH
‫ﺑﺪﻻﻟﺔ‬
0
C
‫ﺍﻟﻨﻬﺎﺋﻴﺔ‬ ‫ﺍﻟﻨﺴﺒﺔ‬ ‫ﻭ‬
W
‫؟‬ ‫ﺍﻟﺘﻔﺎﻋﻞ‬ ‫ﻟﺘﻘﺪﻡ‬
3
‫ﺇﺳﺘﻨﺘﺞ‬ ‫ـ‬ (
f
@
COOH
3
CH
‫ﺑﺪﻻﻟﺔ‬
0
C
‫ﻭ‬
W
‫؟‬
4
‫ﻟﻠﺜﻨﺎﺋﻴﺔ‬ ‫ﺍﻟﺤﻤﻮﺿﺔ‬ ‫ﺛﺎﺑﺖ‬ ‫ﺃﻥ‬ ‫ﺑﻴﻦ‬ ‫ـ‬ (
τ
τ
-
1
C
=
K
2
0
A
5
‫ﻟـ‬ ‫ﻣﺨﺘﻠﻔﺔ‬ ‫ﻗﻴﻢ‬ ‫ﺃﺟﻞ‬ ‫ﻣﻦ‬ ‫ـ‬ (
0
C
‫ﻗﻴﻤﺔ‬ ‫ﺍﻟﻨﺎﻗﻠﻴﺔ‬ ‫ﻗﻴﺎﺱ‬ ‫ﻁﺮﻳﻖ‬ ‫ﻋﻦ‬ ‫ﻧﻌﻴﻦ‬
W
.
‫؟‬ ‫ﺍﻟﺘﺎﻟﻲ‬ ‫ﺍﻟﺠﺪﻭﻝ‬ ‫ﺃﻛﻤﻞ‬ ‫ـ‬ ‫ﺃ‬
‫ﺍﻟﺒﻴﺎﻥ‬ ‫ﺃﺭﺳﻢ‬ ‫ـ‬ ‫ﺏ‬
y = f ( x )
‫؟‬
‫ﺠ‬
‫ﻗﻴﻤﺔ‬ ‫ﺇﺳﺘﻨﺘﺞ‬ ‫ـ‬
K
‫؟‬
II
.
‫ﺍﻻﺳﺘﺮ‬ ‫ﺻﻨﺎﻋﺔ‬
):
03
( ‫ﻧﻘﺎﻁ‬
‫ﻣ‬ ‫ﻋﻠﻴﻬﺎ‬ ‫ﺍﻟﺤﺼﻮﻝ‬ ‫ﻳﻤﻜﻦ‬ .... ‫ﺍﻟﻐﺬﺍﺋﻴﺔ‬ ‫ﺍﻟﻤﻮﺍﺩ‬ ‫ﻓﻲ‬ ، ‫ﺍﻟﻤﻌﻄﺮﺍﺕ‬ ‫ﻓﻲ‬ : ‫ﺍﻟﻴﻮﻣﻴﺔ‬ ‫ﺣﻴﺎﺗﻨﺎ‬ ‫ﻓﻲ‬ ‫ﺗﻮﺟﺪ‬ ‫ﺍﻻﺳﺘﺮﺍﺕ‬
‫ﺍﻟﻨﺒ‬ ‫ﻦ‬
‫ﻳﻤﻜ‬ ‫ﻛﻤﺎ‬ ‫ﺎﺕ‬
‫ﻦ‬
‫ﺍﻟﻤﺨﺎﺑﺮ‬ ‫ﻓﻲ‬ ‫ﺇﺻﻄﻨﺎﻋﻬﺎ‬
‫ﻳﺼﻄﻨﻊ‬
‫ﺍﻻﺳﺘﺮ‬
. ( ‫ﺍﻟﻤﻴﺜﺎﻧﻮﻝ‬ ، ‫ﺍﻟﺒﻨﺰﻭﻳﻚ‬ ‫ﺣﻤﺾ‬ ) ‫ﻟﻠﺠﻤﻠﺔ‬ ‫ﻛﻴﻤﻴﺎﺋﻲ‬ ‫ﺗﺤﻮﻝ‬ ‫ﻣﻦ‬ ‫ﺇﻧﻄﻼﻗﺎ‬ ‫ﺩﺭﺍﺳﺘﻪ‬ ‫ﻧﺮﻳﺪ‬ ‫ﺍﻟﺬﻱ‬
‫ﺫﻟﻚ‬ ‫ﺃﺟﻞ‬ ‫ﻣﻦ‬
‫ﻧ‬
‫ﻤ‬
‫ﺰﺝ‬
4
-
10
u
5
3
-
10
u
1
3
-
10
u
5
2
-
10
u
1
( mol / L )
0
C
2
-
10
u
16
2
-
10
u
12.5
2
-
10
u
5.6
2
-
10
u
4
W
0
C
1
=
x
τ
τ
-
1
C
=
y
2
0
e
n
c
y
-
e
d
u
c
a
t
i
o
n
.
c
o
m
/
e
x
a
m
s
3
3
(
(
‫ﻳﻨﺰ‬
‫اﳉﺰ‬
‫ﺰء‬
‫اﻟﺜﺎﱐ‬
‫ﻟﺜﺎﱐ‬
‫ﻋﻠﻰ‬ :
‫ﻋﻠﻰ‬ :
)
7
x
a
‫ﺚ‬‫اﻟﺜﺎﻟ‬ ‫ﻦ‬
‫ﺎﻟﺚ‬
:
x
‫ﻟﺤﻤﺾ‬ ‫ﺗﻮﺍﺯﻥ‬ ‫ﺛﺎﺑﺖ‬ ‫ﺭﺍﺳﺔ‬
‫ﻟﺤﻤﺾ‬ ‫ﺗﻮﺍﺯﻥ‬ ‫ﺛﺎﺑﺖ‬ ‫ﺔ‬
/
e
x
‫ﺗﺮﻛﻴﺰ‬ ‫ﺍﻹﻳﺜﺎﻧﻮﻳﻚ‬ ‫ﻟﺤﻤﺾ‬
‫ﺗ‬ ‫ﺍﻹﻳﺜﺎﻧﻮﻳﻚ‬ ‫ﺾ‬
‫ﺍﻹﻳﺜﺎﻧﻮﻳﻚ‬ ‫ﺣﻤﺾ‬ ‫ﺗﻔﺎﻋﻞ‬ ‫ﺔ‬
‫ﺍﻹﻳﺜ‬ ‫ﺣﻤﺾ‬ ‫ﻋﻞ‬
H
‫ﻭ‬
f
f
@
@
-
-
COO
CO
3
3
CH
H
CH
‫ﺑﺪﻻﻟﺔ‬
‫ﺑﺪﻻﻟﺔ‬
0
0
C
C
‫ﻭ‬
‫ﻭ‬
W
W
‫؟‬
‫ﺋﻴﺔ‬
c
oτ
τ
τ
-
o
1
1
o
C
C
c
o
=
=
c
o
K
c 2
2
o
0
0
c
o
A
A
c
‫ﻗﻴ‬ ‫ﺍﻟﻨﺎﻗﻠﻴﺔ‬ ‫ﻗﻴﺎﺱ‬ ‫ﻁﺮﻳﻖ‬ ‫ﻦ‬
‫ﺍﻟﻨﺎﻗﻠ‬ ‫ﻗﻴﺎﺱ‬ ‫ﺮﻳﻖ‬
‫ﻳﻤﻜ‬ ‫ﺎ‬
‫ﻦ‬
‫ﻜﻦ‬
3
3
-
10
10
u
u
5
5
o
n
2
-
10
10
u
u
5.6
5.6
t
i
o
t
t
t
t
i
o
a
t
c
a
a
a
d
d
d
d
u
a
3as.ency-education.com

7. 0
‫ﻣﻥ‬
06 7 ‫ﺍﻟﺻﻔﺣﺔ‬
= 12.2 g
1
m
‫ﺣﺠﻢ‬ ‫ﻣﻊ‬ ‫ﺍﻟﺒﻨﺰﻭﻳﻚ‬ ‫ﺣﻤﺾ‬ ‫ﻣﻦ‬
= 30 mL
2
V
‫ﺍﻟﻤﺮﻛﺰ‬ ‫ﺍﻟﻜﺒﺮﻳﺖ‬ ‫ﺣﻤﺾ‬ ‫ﻣﻦ‬ ‫ﻗﻄﺮﺍﺕ‬ ‫ﺑﻮﺟﻮﺩ‬ ‫ﺍﻟﻤﻴﺜﺎﻧﻮﻝ‬ ‫ﻣﻦ‬
‫ﻟﻤﺪﺓ‬ ‫ﺍﻟﻤﺮﺗﺪ‬ ‫ﺑﺎﻟﺘﻘﻄﻴﺮ‬ ‫ﻧﺴﺨﻦ‬
60 min
‫ﺍﻟﺘﺒﺮﻳ‬ ‫ﺑﻌﺪ‬
‫ﺪ‬
‫ﺟ‬ + ‫ﻣﺎء‬ ) ‫ﻋﻠﻰ‬ ‫ﺗﺤﺘﻮﻱ‬ ‫ﺣﺒﺎﺑﺔ‬ ‫ﻓﻲ‬ ‫ﺍﻟﺒﺎﻟﻮﻧﺔ‬ ‫ﻣﺤﺘﻮﻯ‬ ‫ﻧﺴﻜﺐ‬
‫ﻋﻠﻰ‬ ‫ﻟﻨﺤﺼﻞ‬ ( ‫ﻠﻴﺪ‬
‫ﻛﺘﻠﺔ‬ ‫ﻋﻠﻰ‬ ‫ﺍﻷﺧﻴﺮ‬ ‫ﻓﻲ‬ ‫ﻟﻨﺤﺼﻞ‬ ‫ﺍﻹﺳﺘﺮ‬ ‫ﻋﻠﻰ‬ ‫ﻳﺤﺘﻮﻱ‬ ‫ﺍﻟﺬﻱ‬ ‫ﺍﻟﻄﻮﺭ‬ ‫ﻧﻌﺰﻝ‬ . ‫ﻣﺨﺘﻠﻔﻴﻦ‬ ‫ﻁﻮﺭﻳﻦ‬
9.52 g
‫ﻣﻦ‬
‫ﺍﻻﺳﺘﺮ‬
.
: ‫ﺍﻟﻤﻌﻄﻴﺎﺕ‬
‫ﺍﻟﺤﺠﻤﻴﺔ‬ ‫ﺍﻟﻜﺘﻠﺔ‬
)
1
-
g.L
(
‫ﺍﻟﻤﻮﻟﻴﺔ‬ ‫ﺍﻟﻜﺘﻠﺔ‬
)
1
-
g.mol
(
‫ﺍﻟﺼﻴﻐﺔ‬
‫ﺍﻟﻜﻴﻤﻴﺎﺋﻲ‬ ‫ﺍﻟﻨﻮﻉ‬
1.3
122
COOH
5
H
6
C
‫ﺍﻟﺒﻨﺰﻭﻳﻚ‬ ‫ﺣﻤﺾ‬
0.80
32
OH
-
3
CH
‫ﺍﻟﻤﻴﺜﺎﻧﻮﻝ‬
1.1
136
‫ﺩﺭﺍﺳﺘﻪ‬ ‫ﻣﺮﺍﺩ‬ ‫ﺍﻻﺳﺘﺮ‬
1
‫ﺍﻟﺒﻨﺰﻭﻳﻚ‬ ‫ﻟﺤﻤﺾ‬ ‫ﺍﻟﻤﺎﺩﺓ‬ ‫ﻛﻤﻴﺔ‬ ‫ﻋﻴﻦ‬ ‫ـ‬
‫ﻭ‬
‫؟‬ ‫ﺍﻟﻤﺴﺘﻌﻤﻞ‬ ‫ﻟﻠﻤﻴﺜﺎﻧﻮﻝ‬ ‫ﺍﻟﻤﺎﺩﺓ‬ ‫ﻛﻤﻴﺔ‬
2
‫؟‬ ‫ﺍﻟﺘﻔﺎﻋﻞ‬ ‫ﻟﺘﺴﺮﻳﻊ‬ ‫ﺃﺳﺘﻌﻤﻠﺖ‬ ‫ﺍﻟﺘﻲ‬ ‫ﺍﻟﺤﺮﻛﻴﺔ‬ ‫ﺍﻟﻌﻮﺍﻣﻞ‬ ‫ﻋﻴﻦ‬ ‫ـ‬
3
‫؟‬ ‫ﺍﻟﻤﺮﺗﺪ‬ ‫ﺍﻟﺘﻘﻄﻴﺮ‬ ‫ﻣﻊ‬ ‫ﺍﻟﺘﺴﺨﻴﻦ‬ ‫ﺃﺳﺘﻌﻤﻞ‬ ‫ﻟﻤﺎﺫﺍ‬ ‫ـ‬
4
‫ﺇﺻﻄﻨﺎﻉ‬ ‫ﺗﻔﺎﻋﻞ‬ ‫ﻣﻌﺎﺩﻟﺔ‬ ‫ﺃﻛﺘﺐ‬ ‫ـ‬
‫ﺍﻻﺳﺘﺮ‬
‫؟‬
‫؟‬ ‫ﺍﺳﻤﻪ‬ ‫ﺍﻋﻂ‬
5
‫ـ‬
‫؟‬ ‫ﺍﻟﺘﺤﻮﻝ‬ ‫ﻫﺬﺍ‬ ‫ﺧﺼﺎﺋﺺ‬ ‫ﺍﻋﻂ‬
6
‫؟‬ ‫ﺍﻟﺘﻔﺎﻋﻞ‬ ‫ﻣﺮﺩﻭﺩ‬ ‫ﺃﺣﺴﺐ‬ ‫ﺛﻢ‬ ‫ﻋﺮﻑ‬ ‫ـ‬
e
n
c
y
-
e
d
u
c
a
t
i
o
n
.
c
o
m
/
e
x
a
m
s
s
s
s
s
s
s
s
s
s
s
s
s
s
s
m
s
m
s
1
m
s
m
s
m
s
m
s
m
s
m
s
m
s
m
m
m
s
m
s
m
m
m
1
1
‫ﻛﻤ‬ ‫ﻋﻴﻦ‬ ‫ـ‬
‫ﻋﻴ‬ ‫ـ‬
2
2
‫ﺍﻟﻌﻮﺍﻣﻞ‬ ‫ﻋﻴﻦ‬ ‫ـ‬
‫ﺍﻟﻌ‬ ‫ﻋﻴﻦ‬ ‫ـ‬
3
‫ﺍﻟﺘﺴ‬ ‫ﺃﺳﺘﻌﻤﻞ‬ ‫ﻟﻤﺎﺫﺍ‬ ‫ـ‬
‫ﺃﺳﺘﻌﻤ‬ ‫ﻟﻤﺎﺫﺍ‬ ‫ـ‬
‫ﺇﺻ‬ ‫ﺗﻔﺎﻋﻞ‬ ‫ﻣﻌﺎﺩﻟﺔ‬ ‫ﺃﻛﺘﺐ‬ ‫ـ‬
‫ﺇ‬ ‫ﺗﻔﺎﻋﻞ‬ ‫ﻣﻌﺎﺩﻟﺔ‬ ‫ﺐ‬
‫ﺍﻟﺘﺤﻮ‬ ‫ﻫﺬﺍ‬ ‫ﺧﺼﺎﺋﺺ‬ ‫ﻋﻂ‬
‫ﻫﺬﺍ‬ ‫ﺧﺼﺎﺋﺺ‬
‫ﺍﻟﺘﻔﺎﻋﻞ‬ ‫ﻣﺮﺩﻭﺩ‬ ‫ﺃﺣﺴﺐ‬ ‫ﺛﻢ‬ ‫ﻑ‬
‫ﺍﻟ‬ ‫ﻣﺮﺩﻭﺩ‬ ‫ﺴﺐ‬
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