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Chapter 6
Quadrilaterals
Created at wordle.net
Tuesday, April 10, 2012
Section 6-1
Angles of Polygons
Tuesday, April 10, 2012
Essential Questions
How do you find and use the sum of the measures of the interior
angles of a polygon?
How do you find and use the sum of the measures of the exterior
angles of a polygon?
Tuesday, April 10, 2012
Vocabulary
1. Diagonal:
Tuesday, April 10, 2012
Vocabulary
1. Diagonal: A segment in a polygon that connects a vertex with
another vertex that is nonconsecutive
Tuesday, April 10, 2012
Theorems
6.1 - Polygon Interior Angles Sum:
6.2 - Polygon Exterior Angles Sum:
Tuesday, April 10, 2012
Theorems
6.1 - Polygon Interior Angles Sum: The sum of the interior angle
measures of a convex polygon with n sides is found with the formula
S =(n−2)180
6.2 - Polygon Exterior Angles Sum:
Tuesday, April 10, 2012
Theorems
6.1 - Polygon Interior Angles Sum: The sum of the interior angle
measures of a convex polygon with n sides is found with the formula
S =(n−2)180
6.2 - Polygon Exterior Angles Sum: The sum of the exterior angle
measures of a convex polygon, one at each vertex, is 360°
Tuesday, April 10, 2012
Polygons and Sides
Tuesday, April 10, 2012
Polygons and Sides
Types of PolygonsTypes of PolygonsTypes of PolygonsTypes of PolygonsTypes of PolygonsTypes of Polygons
# sides 3 4 5 6 7
Name Triangle Quadrilateral Pentagon Hexagon Heptagon
Tuesday, April 10, 2012
Polygons and Sides
Types of PolygonsTypes of PolygonsTypes of PolygonsTypes of PolygonsTypes of PolygonsTypes of Polygons
# sides 3 4 5 6 7
Name Triangle Quadrilateral Pentagon Hexagon Heptagon
Tuesday, April 10, 2012
Polygons and Sides
Types of PolygonsTypes of PolygonsTypes of PolygonsTypes of PolygonsTypes of PolygonsTypes of Polygons
# sides 3 4 5 6 7
Name Triangle Quadrilateral Pentagon Hexagon Heptagon
Tuesday, April 10, 2012
Polygons and Sides
Types of PolygonsTypes of PolygonsTypes of PolygonsTypes of PolygonsTypes of PolygonsTypes of Polygons
# sides 3 4 5 6 7
Name Triangle Quadrilateral Pentagon Hexagon Heptagon
Types of PolygonsTypes of PolygonsTypes of PolygonsTypes of PolygonsTypes of PolygonsTypes of Polygons
# sides 8 9 10 12 n
Name Octagon Nonagon Decagon Dodecagon n-gon
Tuesday, April 10, 2012
Polygons and Sides
Types of PolygonsTypes of PolygonsTypes of PolygonsTypes of PolygonsTypes of PolygonsTypes of Polygons
# sides 3 4 5 6 7
Name Triangle Quadrilateral Pentagon Hexagon Heptagon
Types of PolygonsTypes of PolygonsTypes of PolygonsTypes of PolygonsTypes of PolygonsTypes of Polygons
# sides 8 9 10 12 n
Name Octagon Nonagon Decagon Dodecagon n-gon
Tuesday, April 10, 2012
Polygons and Sides
Types of PolygonsTypes of PolygonsTypes of PolygonsTypes of PolygonsTypes of PolygonsTypes of Polygons
# sides 3 4 5 6 7
Name Triangle Quadrilateral Pentagon Hexagon Heptagon
Types of PolygonsTypes of PolygonsTypes of PolygonsTypes of PolygonsTypes of PolygonsTypes of Polygons
# sides 8 9 10 12 n
Name Octagon Nonagon Decagon Dodecagon n-gon
Tuesday, April 10, 2012
Example 1
Find the sum of the measures of the interior angles of the following.
a. Nonagon b. 17-gon
Tuesday, April 10, 2012
Example 1
Find the sum of the measures of the interior angles of the following.
a. Nonagon b. 17-gon
S =(n−2)180
Tuesday, April 10, 2012
Example 1
Find the sum of the measures of the interior angles of the following.
a. Nonagon b. 17-gon
S =(n−2)180
S =(9−2)180
Tuesday, April 10, 2012
Example 1
Find the sum of the measures of the interior angles of the following.
a. Nonagon b. 17-gon
S =(n−2)180
S =(9−2)180
=(7)180
Tuesday, April 10, 2012
Example 1
Find the sum of the measures of the interior angles of the following.
a. Nonagon b. 17-gon
S =(n−2)180
S =(9−2)180
=(7)180
=1260°
Tuesday, April 10, 2012
Example 1
Find the sum of the measures of the interior angles of the following.
a. Nonagon b. 17-gon
S =(n−2)180
S =(9−2)180
=(7)180
=1260°
S =(n−2)180
Tuesday, April 10, 2012
Example 1
Find the sum of the measures of the interior angles of the following.
a. Nonagon b. 17-gon
S =(n−2)180
S =(9−2)180
=(7)180
=1260°
S =(n−2)180
S =(17−2)180
Tuesday, April 10, 2012
Example 1
Find the sum of the measures of the interior angles of the following.
a. Nonagon b. 17-gon
S =(n−2)180
S =(9−2)180
=(7)180
=1260°
S =(n−2)180
S =(17−2)180
=(15)180
Tuesday, April 10, 2012
Example 1
Find the sum of the measures of the interior angles of the following.
a. Nonagon b. 17-gon
S =(n−2)180
S =(9−2)180
=(7)180
=1260°
S =(n−2)180
S =(17−2)180
=(15)180
= 2700°
Tuesday, April 10, 2012
Example 2
Find the measure of each interior angle of parallelogram RSTU.
Tuesday, April 10, 2012
Example 2
Find the measure of each interior angle of parallelogram RSTU.
S =(n−2)180
Tuesday, April 10, 2012
Example 2
Find the measure of each interior angle of parallelogram RSTU.
S =(n−2)180
S =(4−2)180
Tuesday, April 10, 2012
Example 2
Find the measure of each interior angle of parallelogram RSTU.
S =(n−2)180
S =(4−2)180
=(2)180
Tuesday, April 10, 2012
Example 2
Find the measure of each interior angle of parallelogram RSTU.
S =(n−2)180
S =(4−2)180
=(2)180
=360°
Tuesday, April 10, 2012
Example 2
Find the measure of each interior angle of parallelogram RSTU.
S =(n−2)180
S =(4−2)180
=(2)180
=360°
11x +4+5x +11x +4+5x =360
Tuesday, April 10, 2012
Example 2
Find the measure of each interior angle of parallelogram RSTU.
S =(n−2)180
S =(4−2)180
=(2)180
=360°
11x +4+5x +11x +4+5x =360
32x +8 =360
Tuesday, April 10, 2012
Example 2
Find the measure of each interior angle of parallelogram RSTU.
S =(n−2)180
S =(4−2)180
=(2)180
=360°
11x +4+5x +11x +4+5x =360
32x +8 =360
−8 −8
Tuesday, April 10, 2012
Example 2
Find the measure of each interior angle of parallelogram RSTU.
S =(n−2)180
S =(4−2)180
=(2)180
=360°
11x +4+5x +11x +4+5x =360
32x +8 =360
−8 −8
32x =352
Tuesday, April 10, 2012
Example 2
Find the measure of each interior angle of parallelogram RSTU.
S =(n−2)180
S =(4−2)180
=(2)180
=360°
11x +4+5x +11x +4+5x =360
32x +8 =360
−8 −8
32x =352
32 32
Tuesday, April 10, 2012
Example 2
Find the measure of each interior angle of parallelogram RSTU.
S =(n−2)180
S =(4−2)180
=(2)180
=360°
11x +4+5x +11x +4+5x =360
32x +8 =360
−8 −8
32x =352
32 32
x =11
Tuesday, April 10, 2012
Example 2
Find the measure of each interior angle of parallelogram RSTU.
S =(n−2)180
S =(4−2)180
=(2)180
=360°
11x +4+5x +11x +4+5x =360
32x +8 =360
−8 −8
32x =352
32 32
x =11
m∠R = m∠T =5(11)
Tuesday, April 10, 2012
Example 2
Find the measure of each interior angle of parallelogram RSTU.
S =(n−2)180
S =(4−2)180
=(2)180
=360°
11x +4+5x +11x +4+5x =360
32x +8 =360
−8 −8
32x =352
32 32
x =11
m∠R = m∠T =5(11) =55°
Tuesday, April 10, 2012
Example 2
Find the measure of each interior angle of parallelogram RSTU.
S =(n−2)180
S =(4−2)180
=(2)180
=360°
11x +4+5x +11x +4+5x =360
32x +8 =360
−8 −8
32x =352
32 32
x =11
m∠R = m∠T =5(11) =55°
m∠S = m∠U =11(11)+4
Tuesday, April 10, 2012
Example 2
Find the measure of each interior angle of parallelogram RSTU.
S =(n−2)180
S =(4−2)180
=(2)180
=360°
11x +4+5x +11x +4+5x =360
32x +8 =360
−8 −8
32x =352
32 32
x =11
m∠R = m∠T =5(11) =55°
m∠S = m∠U =11(11)+4
=121+4
Tuesday, April 10, 2012
Example 2
Find the measure of each interior angle of parallelogram RSTU.
S =(n−2)180
S =(4−2)180
=(2)180
=360°
11x +4+5x +11x +4+5x =360
32x +8 =360
−8 −8
32x =352
32 32
x =11
m∠R = m∠T =5(11) =55°
m∠S = m∠U =11(11)+4
=121+4 =125°
Tuesday, April 10, 2012
Example 3
Park City Mall is designed so that eight walkways meet in a central area in
the shape of a regular octagon. Find the measure of one of the interior
angles of the octagon.
http://www.parkcitycenter.com/directory
Tuesday, April 10, 2012
Example 3
Park City Mall is designed so that eight walkways meet in a central area in
the shape of a regular octagon. Find the measure of one of the interior
angles of the octagon.
http://www.parkcitycenter.com/directory
S =(n−2)180
Tuesday, April 10, 2012
Example 3
Park City Mall is designed so that eight walkways meet in a central area in
the shape of a regular octagon. Find the measure of one of the interior
angles of the octagon.
http://www.parkcitycenter.com/directory
S =(n−2)180
S =(8−2)180
Tuesday, April 10, 2012
Example 3
Park City Mall is designed so that eight walkways meet in a central area in
the shape of a regular octagon. Find the measure of one of the interior
angles of the octagon.
http://www.parkcitycenter.com/directory
S =(n−2)180
S =(8−2)180
=(6)180
Tuesday, April 10, 2012
Example 3
Park City Mall is designed so that eight walkways meet in a central area in
the shape of a regular octagon. Find the measure of one of the interior
angles of the octagon.
http://www.parkcitycenter.com/directory
S =(n−2)180
S =(8−2)180
=(6)180
=1080°
Tuesday, April 10, 2012
Example 3
Park City Mall is designed so that eight walkways meet in a central area in
the shape of a regular octagon. Find the measure of one of the interior
angles of the octagon.
http://www.parkcitycenter.com/directory
S =(n−2)180
S =(8−2)180
=(6)180
=1080°
1080°
8
Tuesday, April 10, 2012
Example 3
Park City Mall is designed so that eight walkways meet in a central area in
the shape of a regular octagon. Find the measure of one of the interior
angles of the octagon.
http://www.parkcitycenter.com/directory
S =(n−2)180
S =(8−2)180
=(6)180
=1080°
1080°
8
=135°
Tuesday, April 10, 2012
Example 4
The measure of an interior angle of a regular polygon is 150°. Find the
number of sides in the polygon.
Tuesday, April 10, 2012
Example 4
The measure of an interior angle of a regular polygon is 150°. Find the
number of sides in the polygon.
150n =(n−2)180
Tuesday, April 10, 2012
Example 4
The measure of an interior angle of a regular polygon is 150°. Find the
number of sides in the polygon.
150n =(n−2)180
150n =180n−360
Tuesday, April 10, 2012
Example 4
The measure of an interior angle of a regular polygon is 150°. Find the
number of sides in the polygon.
150n =(n−2)180
150n =180n−360
−180n −180n
Tuesday, April 10, 2012
Example 4
The measure of an interior angle of a regular polygon is 150°. Find the
number of sides in the polygon.
150n =(n−2)180
150n =180n−360
−180n −180n
−30n = −360
Tuesday, April 10, 2012
Example 4
The measure of an interior angle of a regular polygon is 150°. Find the
number of sides in the polygon.
150n =(n−2)180
150n =180n−360
−180n −180n
−30n = −360
−30 −30
Tuesday, April 10, 2012
Example 4
The measure of an interior angle of a regular polygon is 150°. Find the
number of sides in the polygon.
150n =(n−2)180
150n =180n−360
−180n −180n
−30n = −360
−30 −30
n =12
Tuesday, April 10, 2012
Example 4
The measure of an interior angle of a regular polygon is 150°. Find the
number of sides in the polygon.
150n =(n−2)180
150n =180n−360
−180n −180n
−30n = −360
−30 −30
n =12
There are 12 sides to the polygon
Tuesday, April 10, 2012
Example 5
Find the value of x in the diagram.
m∠1=5x +5, m∠2 =5x, m∠3= 4x −6,
m∠4 =5x −5, m∠5= 4x +3, m∠6= 6x −12,
m∠7 = 2x +3
Tuesday, April 10, 2012
Example 5
Find the value of x in the diagram.
m∠1=5x +5, m∠2 =5x, m∠3= 4x −6,
m∠4 =5x −5, m∠5= 4x +3, m∠6= 6x −12,
m∠7 = 2x +3
5x +5+5x +4x −6+5x −5+4x +3+6x −12+2x +3=360
Tuesday, April 10, 2012
Example 5
Find the value of x in the diagram.
m∠1=5x +5, m∠2 =5x, m∠3= 4x −6,
m∠4 =5x −5, m∠5= 4x +3, m∠6= 6x −12,
m∠7 = 2x +3
5x +5+5x +4x −6+5x −5+4x +3+6x −12+2x +3=360
31x −12 =360
Tuesday, April 10, 2012
Example 5
Find the value of x in the diagram.
m∠1=5x +5, m∠2 =5x, m∠3= 4x −6,
m∠4 =5x −5, m∠5= 4x +3, m∠6= 6x −12,
m∠7 = 2x +3
5x +5+5x +4x −6+5x −5+4x +3+6x −12+2x +3=360
31x −12 =360
31x =372
Tuesday, April 10, 2012
Example 5
Find the value of x in the diagram.
m∠1=5x +5, m∠2 =5x, m∠3= 4x −6,
m∠4 =5x −5, m∠5= 4x +3, m∠6= 6x −12,
m∠7 = 2x +3
5x +5+5x +4x −6+5x −5+4x +3+6x −12+2x +3=360
31x −12 =360
31x =372
x =12
Tuesday, April 10, 2012
Check Your Understanding
Review #1-11 on p. 393
Tuesday, April 10, 2012
Problem Set
Tuesday, April 10, 2012
Problem Set
p. 394 #13-37 odd, 49, 59
"They can because they think they can." - Virgil
Tuesday, April 10, 2012

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Geosection6 1-120409231912-phpapp01

  • 1. Chapter 6 Quadrilaterals Created at wordle.net Tuesday, April 10, 2012
  • 2. Section 6-1 Angles of Polygons Tuesday, April 10, 2012
  • 3. Essential Questions How do you find and use the sum of the measures of the interior angles of a polygon? How do you find and use the sum of the measures of the exterior angles of a polygon? Tuesday, April 10, 2012
  • 5. Vocabulary 1. Diagonal: A segment in a polygon that connects a vertex with another vertex that is nonconsecutive Tuesday, April 10, 2012
  • 6. Theorems 6.1 - Polygon Interior Angles Sum: 6.2 - Polygon Exterior Angles Sum: Tuesday, April 10, 2012
  • 7. Theorems 6.1 - Polygon Interior Angles Sum: The sum of the interior angle measures of a convex polygon with n sides is found with the formula S =(n−2)180 6.2 - Polygon Exterior Angles Sum: Tuesday, April 10, 2012
  • 8. Theorems 6.1 - Polygon Interior Angles Sum: The sum of the interior angle measures of a convex polygon with n sides is found with the formula S =(n−2)180 6.2 - Polygon Exterior Angles Sum: The sum of the exterior angle measures of a convex polygon, one at each vertex, is 360° Tuesday, April 10, 2012
  • 10. Polygons and Sides Types of PolygonsTypes of PolygonsTypes of PolygonsTypes of PolygonsTypes of PolygonsTypes of Polygons # sides 3 4 5 6 7 Name Triangle Quadrilateral Pentagon Hexagon Heptagon Tuesday, April 10, 2012
  • 11. Polygons and Sides Types of PolygonsTypes of PolygonsTypes of PolygonsTypes of PolygonsTypes of PolygonsTypes of Polygons # sides 3 4 5 6 7 Name Triangle Quadrilateral Pentagon Hexagon Heptagon Tuesday, April 10, 2012
  • 12. Polygons and Sides Types of PolygonsTypes of PolygonsTypes of PolygonsTypes of PolygonsTypes of PolygonsTypes of Polygons # sides 3 4 5 6 7 Name Triangle Quadrilateral Pentagon Hexagon Heptagon Tuesday, April 10, 2012
  • 13. Polygons and Sides Types of PolygonsTypes of PolygonsTypes of PolygonsTypes of PolygonsTypes of PolygonsTypes of Polygons # sides 3 4 5 6 7 Name Triangle Quadrilateral Pentagon Hexagon Heptagon Types of PolygonsTypes of PolygonsTypes of PolygonsTypes of PolygonsTypes of PolygonsTypes of Polygons # sides 8 9 10 12 n Name Octagon Nonagon Decagon Dodecagon n-gon Tuesday, April 10, 2012
  • 14. Polygons and Sides Types of PolygonsTypes of PolygonsTypes of PolygonsTypes of PolygonsTypes of PolygonsTypes of Polygons # sides 3 4 5 6 7 Name Triangle Quadrilateral Pentagon Hexagon Heptagon Types of PolygonsTypes of PolygonsTypes of PolygonsTypes of PolygonsTypes of PolygonsTypes of Polygons # sides 8 9 10 12 n Name Octagon Nonagon Decagon Dodecagon n-gon Tuesday, April 10, 2012
  • 15. Polygons and Sides Types of PolygonsTypes of PolygonsTypes of PolygonsTypes of PolygonsTypes of PolygonsTypes of Polygons # sides 3 4 5 6 7 Name Triangle Quadrilateral Pentagon Hexagon Heptagon Types of PolygonsTypes of PolygonsTypes of PolygonsTypes of PolygonsTypes of PolygonsTypes of Polygons # sides 8 9 10 12 n Name Octagon Nonagon Decagon Dodecagon n-gon Tuesday, April 10, 2012
  • 16. Example 1 Find the sum of the measures of the interior angles of the following. a. Nonagon b. 17-gon Tuesday, April 10, 2012
  • 17. Example 1 Find the sum of the measures of the interior angles of the following. a. Nonagon b. 17-gon S =(n−2)180 Tuesday, April 10, 2012
  • 18. Example 1 Find the sum of the measures of the interior angles of the following. a. Nonagon b. 17-gon S =(n−2)180 S =(9−2)180 Tuesday, April 10, 2012
  • 19. Example 1 Find the sum of the measures of the interior angles of the following. a. Nonagon b. 17-gon S =(n−2)180 S =(9−2)180 =(7)180 Tuesday, April 10, 2012
  • 20. Example 1 Find the sum of the measures of the interior angles of the following. a. Nonagon b. 17-gon S =(n−2)180 S =(9−2)180 =(7)180 =1260° Tuesday, April 10, 2012
  • 21. Example 1 Find the sum of the measures of the interior angles of the following. a. Nonagon b. 17-gon S =(n−2)180 S =(9−2)180 =(7)180 =1260° S =(n−2)180 Tuesday, April 10, 2012
  • 22. Example 1 Find the sum of the measures of the interior angles of the following. a. Nonagon b. 17-gon S =(n−2)180 S =(9−2)180 =(7)180 =1260° S =(n−2)180 S =(17−2)180 Tuesday, April 10, 2012
  • 23. Example 1 Find the sum of the measures of the interior angles of the following. a. Nonagon b. 17-gon S =(n−2)180 S =(9−2)180 =(7)180 =1260° S =(n−2)180 S =(17−2)180 =(15)180 Tuesday, April 10, 2012
  • 24. Example 1 Find the sum of the measures of the interior angles of the following. a. Nonagon b. 17-gon S =(n−2)180 S =(9−2)180 =(7)180 =1260° S =(n−2)180 S =(17−2)180 =(15)180 = 2700° Tuesday, April 10, 2012
  • 25. Example 2 Find the measure of each interior angle of parallelogram RSTU. Tuesday, April 10, 2012
  • 26. Example 2 Find the measure of each interior angle of parallelogram RSTU. S =(n−2)180 Tuesday, April 10, 2012
  • 27. Example 2 Find the measure of each interior angle of parallelogram RSTU. S =(n−2)180 S =(4−2)180 Tuesday, April 10, 2012
  • 28. Example 2 Find the measure of each interior angle of parallelogram RSTU. S =(n−2)180 S =(4−2)180 =(2)180 Tuesday, April 10, 2012
  • 29. Example 2 Find the measure of each interior angle of parallelogram RSTU. S =(n−2)180 S =(4−2)180 =(2)180 =360° Tuesday, April 10, 2012
  • 30. Example 2 Find the measure of each interior angle of parallelogram RSTU. S =(n−2)180 S =(4−2)180 =(2)180 =360° 11x +4+5x +11x +4+5x =360 Tuesday, April 10, 2012
  • 31. Example 2 Find the measure of each interior angle of parallelogram RSTU. S =(n−2)180 S =(4−2)180 =(2)180 =360° 11x +4+5x +11x +4+5x =360 32x +8 =360 Tuesday, April 10, 2012
  • 32. Example 2 Find the measure of each interior angle of parallelogram RSTU. S =(n−2)180 S =(4−2)180 =(2)180 =360° 11x +4+5x +11x +4+5x =360 32x +8 =360 −8 −8 Tuesday, April 10, 2012
  • 33. Example 2 Find the measure of each interior angle of parallelogram RSTU. S =(n−2)180 S =(4−2)180 =(2)180 =360° 11x +4+5x +11x +4+5x =360 32x +8 =360 −8 −8 32x =352 Tuesday, April 10, 2012
  • 34. Example 2 Find the measure of each interior angle of parallelogram RSTU. S =(n−2)180 S =(4−2)180 =(2)180 =360° 11x +4+5x +11x +4+5x =360 32x +8 =360 −8 −8 32x =352 32 32 Tuesday, April 10, 2012
  • 35. Example 2 Find the measure of each interior angle of parallelogram RSTU. S =(n−2)180 S =(4−2)180 =(2)180 =360° 11x +4+5x +11x +4+5x =360 32x +8 =360 −8 −8 32x =352 32 32 x =11 Tuesday, April 10, 2012
  • 36. Example 2 Find the measure of each interior angle of parallelogram RSTU. S =(n−2)180 S =(4−2)180 =(2)180 =360° 11x +4+5x +11x +4+5x =360 32x +8 =360 −8 −8 32x =352 32 32 x =11 m∠R = m∠T =5(11) Tuesday, April 10, 2012
  • 37. Example 2 Find the measure of each interior angle of parallelogram RSTU. S =(n−2)180 S =(4−2)180 =(2)180 =360° 11x +4+5x +11x +4+5x =360 32x +8 =360 −8 −8 32x =352 32 32 x =11 m∠R = m∠T =5(11) =55° Tuesday, April 10, 2012
  • 38. Example 2 Find the measure of each interior angle of parallelogram RSTU. S =(n−2)180 S =(4−2)180 =(2)180 =360° 11x +4+5x +11x +4+5x =360 32x +8 =360 −8 −8 32x =352 32 32 x =11 m∠R = m∠T =5(11) =55° m∠S = m∠U =11(11)+4 Tuesday, April 10, 2012
  • 39. Example 2 Find the measure of each interior angle of parallelogram RSTU. S =(n−2)180 S =(4−2)180 =(2)180 =360° 11x +4+5x +11x +4+5x =360 32x +8 =360 −8 −8 32x =352 32 32 x =11 m∠R = m∠T =5(11) =55° m∠S = m∠U =11(11)+4 =121+4 Tuesday, April 10, 2012
  • 40. Example 2 Find the measure of each interior angle of parallelogram RSTU. S =(n−2)180 S =(4−2)180 =(2)180 =360° 11x +4+5x +11x +4+5x =360 32x +8 =360 −8 −8 32x =352 32 32 x =11 m∠R = m∠T =5(11) =55° m∠S = m∠U =11(11)+4 =121+4 =125° Tuesday, April 10, 2012
  • 41. Example 3 Park City Mall is designed so that eight walkways meet in a central area in the shape of a regular octagon. Find the measure of one of the interior angles of the octagon. http://www.parkcitycenter.com/directory Tuesday, April 10, 2012
  • 42. Example 3 Park City Mall is designed so that eight walkways meet in a central area in the shape of a regular octagon. Find the measure of one of the interior angles of the octagon. http://www.parkcitycenter.com/directory S =(n−2)180 Tuesday, April 10, 2012
  • 43. Example 3 Park City Mall is designed so that eight walkways meet in a central area in the shape of a regular octagon. Find the measure of one of the interior angles of the octagon. http://www.parkcitycenter.com/directory S =(n−2)180 S =(8−2)180 Tuesday, April 10, 2012
  • 44. Example 3 Park City Mall is designed so that eight walkways meet in a central area in the shape of a regular octagon. Find the measure of one of the interior angles of the octagon. http://www.parkcitycenter.com/directory S =(n−2)180 S =(8−2)180 =(6)180 Tuesday, April 10, 2012
  • 45. Example 3 Park City Mall is designed so that eight walkways meet in a central area in the shape of a regular octagon. Find the measure of one of the interior angles of the octagon. http://www.parkcitycenter.com/directory S =(n−2)180 S =(8−2)180 =(6)180 =1080° Tuesday, April 10, 2012
  • 46. Example 3 Park City Mall is designed so that eight walkways meet in a central area in the shape of a regular octagon. Find the measure of one of the interior angles of the octagon. http://www.parkcitycenter.com/directory S =(n−2)180 S =(8−2)180 =(6)180 =1080° 1080° 8 Tuesday, April 10, 2012
  • 47. Example 3 Park City Mall is designed so that eight walkways meet in a central area in the shape of a regular octagon. Find the measure of one of the interior angles of the octagon. http://www.parkcitycenter.com/directory S =(n−2)180 S =(8−2)180 =(6)180 =1080° 1080° 8 =135° Tuesday, April 10, 2012
  • 48. Example 4 The measure of an interior angle of a regular polygon is 150°. Find the number of sides in the polygon. Tuesday, April 10, 2012
  • 49. Example 4 The measure of an interior angle of a regular polygon is 150°. Find the number of sides in the polygon. 150n =(n−2)180 Tuesday, April 10, 2012
  • 50. Example 4 The measure of an interior angle of a regular polygon is 150°. Find the number of sides in the polygon. 150n =(n−2)180 150n =180n−360 Tuesday, April 10, 2012
  • 51. Example 4 The measure of an interior angle of a regular polygon is 150°. Find the number of sides in the polygon. 150n =(n−2)180 150n =180n−360 −180n −180n Tuesday, April 10, 2012
  • 52. Example 4 The measure of an interior angle of a regular polygon is 150°. Find the number of sides in the polygon. 150n =(n−2)180 150n =180n−360 −180n −180n −30n = −360 Tuesday, April 10, 2012
  • 53. Example 4 The measure of an interior angle of a regular polygon is 150°. Find the number of sides in the polygon. 150n =(n−2)180 150n =180n−360 −180n −180n −30n = −360 −30 −30 Tuesday, April 10, 2012
  • 54. Example 4 The measure of an interior angle of a regular polygon is 150°. Find the number of sides in the polygon. 150n =(n−2)180 150n =180n−360 −180n −180n −30n = −360 −30 −30 n =12 Tuesday, April 10, 2012
  • 55. Example 4 The measure of an interior angle of a regular polygon is 150°. Find the number of sides in the polygon. 150n =(n−2)180 150n =180n−360 −180n −180n −30n = −360 −30 −30 n =12 There are 12 sides to the polygon Tuesday, April 10, 2012
  • 56. Example 5 Find the value of x in the diagram. m∠1=5x +5, m∠2 =5x, m∠3= 4x −6, m∠4 =5x −5, m∠5= 4x +3, m∠6= 6x −12, m∠7 = 2x +3 Tuesday, April 10, 2012
  • 57. Example 5 Find the value of x in the diagram. m∠1=5x +5, m∠2 =5x, m∠3= 4x −6, m∠4 =5x −5, m∠5= 4x +3, m∠6= 6x −12, m∠7 = 2x +3 5x +5+5x +4x −6+5x −5+4x +3+6x −12+2x +3=360 Tuesday, April 10, 2012
  • 58. Example 5 Find the value of x in the diagram. m∠1=5x +5, m∠2 =5x, m∠3= 4x −6, m∠4 =5x −5, m∠5= 4x +3, m∠6= 6x −12, m∠7 = 2x +3 5x +5+5x +4x −6+5x −5+4x +3+6x −12+2x +3=360 31x −12 =360 Tuesday, April 10, 2012
  • 59. Example 5 Find the value of x in the diagram. m∠1=5x +5, m∠2 =5x, m∠3= 4x −6, m∠4 =5x −5, m∠5= 4x +3, m∠6= 6x −12, m∠7 = 2x +3 5x +5+5x +4x −6+5x −5+4x +3+6x −12+2x +3=360 31x −12 =360 31x =372 Tuesday, April 10, 2012
  • 60. Example 5 Find the value of x in the diagram. m∠1=5x +5, m∠2 =5x, m∠3= 4x −6, m∠4 =5x −5, m∠5= 4x +3, m∠6= 6x −12, m∠7 = 2x +3 5x +5+5x +4x −6+5x −5+4x +3+6x −12+2x +3=360 31x −12 =360 31x =372 x =12 Tuesday, April 10, 2012
  • 61. Check Your Understanding Review #1-11 on p. 393 Tuesday, April 10, 2012
  • 63. Problem Set p. 394 #13-37 odd, 49, 59 "They can because they think they can." - Virgil Tuesday, April 10, 2012