Classical Mech-2

1. 1
A body is at rest at a location
on the Earth’s equator. Find
its acceleration due to the
Earth’s rotation.
(Take the Earth’s radius at the
equator to be 6400 km.)
Find also the acceleration of the
Earth
10
in its orbit around the Sun.
(Take the Sun to be fixed and
regard the Earth as a particle
following a circular path with
center the Sun and radius
15 x 10 m.)

2. 2
Solution
Distance (s) = velocity (u or v) x time (t), s = vt

3. 3
It takes the Earth 24 hours to rotate on
its axis and one year to revolve around
the Sun. The Moon revolves around the
Earth in an average of 27.3 days.
One Day = 1X24X60X60
= 86400 seconds
One Year = 1X365X24X60X60
= 31536000 seconds

4. 4
( )
2
2 3.14 6400000
86400
40192000
86400
465.18
i
S vt
S R
v
t t
X X m
s
m
s
m
s


  




5. 5
2
2
2
2
2
,
(465.18 )
6400000
216397.26
6400000
0.034
c
Now
v
a
R
m
s
m
m
s
m
m
s





6. 6
10
6 10
4
( )
2
2 3.14 15 10
31536000
2.99 10 10
2.99 10
29900
ii
S vt
S R
v
t t
X X X m
s
m
X X
s
m
X
s
m
s



  





7. 7
2
2
10
2 2
2 2
10 6
6
2
2
,
(29900 )
15 10
894010000 89401
15 10 15 10
5960.07 10
0.00596
c
Now
m
v s
a
R X m
m m
s s
X m X m
m
X
s
m
s

  
 

