Submit Search
Upload
will updateSolutionwill update.pdf
•
0 likes
•
2 views
A
ANJALIENTERPRISES1
Follow
will update Solution will update.
Read less
Read more
Education
Report
Share
Report
Share
1 of 1
Download now
Download to read offline
Recommended
to minimise the length, term with \'m\' should be reduced so first to absolute values must be opened with negative sign S2 = -4m+1 - 5m+6 + 10m-3 S2 = m+4 Solution to minimise the length, term with \'m\' should be reduced so first to absolute values must be opened with negative sign S2 = -4m+1 - 5m+6 + 10m-3 S2 = m+4.
H2SO4 may act as 1) an acidexample 2NaOH + H2SO4 - Na2SO4 +.pdf
H2SO4 may act as 1) an acidexample 2NaOH + H2SO4 - Na2SO4 +.pdf
ANJALIENTERPRISES1
no. of sand grains in 1 truck = 10/0.1 x 10 ^-6=10^8 sand grains total time taken= (10 X 6.02x10^23 x 10 )/10^8= 6.02 x 10^17 min= 6.872 x 10^ 13 years Solution no. of sand grains in 1 truck = 10/0.1 x 10 ^-6=10^8 sand grains total time taken= (10 X 6.02x10^23 x 10 )/10^8= 6.02 x 10^17 min= 6.872 x 10^ 13 years.
Computer graphics are pictures and movies produced use computers fre.pdf
Computer graphics are pictures and movies produced use computers fre.pdf
ANJALIENTERPRISES1
NaCl - sodium chloride MgO - magnesium oxide AgI - silver iodiode check its not L CuSO4 - copper sulphate Solution NaCl - sodium chloride MgO - magnesium oxide AgI - silver iodiode check its not L CuSO4 - copper sulphate.
Circle.javaimport java.text.DecimalFormat;public class Circle {.pdf
Circle.javaimport java.text.DecimalFormat;public class Circle {.pdf
ANJALIENTERPRISES1
mol L-1 s-1 is the answer Solution mol L-1 s-1 is the answer.
C is correct. Only the host that the unicast message is addressed to.pdf
C is correct. Only the host that the unicast message is addressed to.pdf
ANJALIENTERPRISES1
empirical formula of C2H4 is CH2 empirical formula mass = 12+2 = 14 Solution empirical formula of C2H4 is CH2 empirical formula mass = 12+2 = 14.
According to the seriousness level, the following organs areThymu.pdf
According to the seriousness level, the following organs areThymu.pdf
ANJALIENTERPRISES1
First substance = Ionic solid Second substance = Covalent solid Solution First substance = Ionic solid Second substance = Covalent solid.
Among 40 subjects randomly choose 20 subjects and assign themSol.pdf
Among 40 subjects randomly choose 20 subjects and assign themSol.pdf
ANJALIENTERPRISES1
ex-1-enol: CH3 - CH2 - CH2 - CH2 - CH2 = CH2-OH hexanal CH3 - CH2 - CH2 - CH2 - CH2 - CH2=O Solution ex-1-enol: CH3 - CH2 - CH2 - CH2 - CH2 = CH2-OH hexanal CH3 - CH2 - CH2 - CH2 - CH2 - CH2=O.
AdvantagesThe main objective of business combination is to elimina.pdf
AdvantagesThe main objective of business combination is to elimina.pdf
ANJALIENTERPRISES1
coordination no is the no of ligands in the coordination sphere and in this case it is 6 Solution coordination no is the no of ligands in the coordination sphere and in this case it is 6.
a. Germ cell speciication in Drosophila is primarily a maternlly con.pdf
a. Germ cell speciication in Drosophila is primarily a maternlly con.pdf
ANJALIENTERPRISES1
Recommended
to minimise the length, term with \'m\' should be reduced so first to absolute values must be opened with negative sign S2 = -4m+1 - 5m+6 + 10m-3 S2 = m+4 Solution to minimise the length, term with \'m\' should be reduced so first to absolute values must be opened with negative sign S2 = -4m+1 - 5m+6 + 10m-3 S2 = m+4.
H2SO4 may act as 1) an acidexample 2NaOH + H2SO4 - Na2SO4 +.pdf
H2SO4 may act as 1) an acidexample 2NaOH + H2SO4 - Na2SO4 +.pdf
ANJALIENTERPRISES1
no. of sand grains in 1 truck = 10/0.1 x 10 ^-6=10^8 sand grains total time taken= (10 X 6.02x10^23 x 10 )/10^8= 6.02 x 10^17 min= 6.872 x 10^ 13 years Solution no. of sand grains in 1 truck = 10/0.1 x 10 ^-6=10^8 sand grains total time taken= (10 X 6.02x10^23 x 10 )/10^8= 6.02 x 10^17 min= 6.872 x 10^ 13 years.
Computer graphics are pictures and movies produced use computers fre.pdf
Computer graphics are pictures and movies produced use computers fre.pdf
ANJALIENTERPRISES1
NaCl - sodium chloride MgO - magnesium oxide AgI - silver iodiode check its not L CuSO4 - copper sulphate Solution NaCl - sodium chloride MgO - magnesium oxide AgI - silver iodiode check its not L CuSO4 - copper sulphate.
Circle.javaimport java.text.DecimalFormat;public class Circle {.pdf
Circle.javaimport java.text.DecimalFormat;public class Circle {.pdf
ANJALIENTERPRISES1
mol L-1 s-1 is the answer Solution mol L-1 s-1 is the answer.
C is correct. Only the host that the unicast message is addressed to.pdf
C is correct. Only the host that the unicast message is addressed to.pdf
ANJALIENTERPRISES1
empirical formula of C2H4 is CH2 empirical formula mass = 12+2 = 14 Solution empirical formula of C2H4 is CH2 empirical formula mass = 12+2 = 14.
According to the seriousness level, the following organs areThymu.pdf
According to the seriousness level, the following organs areThymu.pdf
ANJALIENTERPRISES1
First substance = Ionic solid Second substance = Covalent solid Solution First substance = Ionic solid Second substance = Covalent solid.
Among 40 subjects randomly choose 20 subjects and assign themSol.pdf
Among 40 subjects randomly choose 20 subjects and assign themSol.pdf
ANJALIENTERPRISES1
ex-1-enol: CH3 - CH2 - CH2 - CH2 - CH2 = CH2-OH hexanal CH3 - CH2 - CH2 - CH2 - CH2 - CH2=O Solution ex-1-enol: CH3 - CH2 - CH2 - CH2 - CH2 = CH2-OH hexanal CH3 - CH2 - CH2 - CH2 - CH2 - CH2=O.
AdvantagesThe main objective of business combination is to elimina.pdf
AdvantagesThe main objective of business combination is to elimina.pdf
ANJALIENTERPRISES1
coordination no is the no of ligands in the coordination sphere and in this case it is 6 Solution coordination no is the no of ligands in the coordination sphere and in this case it is 6.
a. Germ cell speciication in Drosophila is primarily a maternlly con.pdf
a. Germ cell speciication in Drosophila is primarily a maternlly con.pdf
ANJALIENTERPRISES1
At the beginning of the 11th year, there would be 1,024,000 rabbits. Solution At the beginning of the 11th year, there would be 1,024,000 rabbits..
A is correct. The packets to be filtered would be heading into the r.pdf
A is correct. The packets to be filtered would be heading into the r.pdf
ANJALIENTERPRISES1
1). A) ipsilateral Below the point of spinal cord, the nerve paths belong to the same side (no crossing over occurs). So, the nociceptive information can be found on the same side of the body. Solution 1). A) ipsilateral Below the point of spinal cord, the nerve paths belong to the same side (no crossing over occurs). So, the nociceptive information can be found on the same side of the body..
1). A) ipsilateralBelow the point of spinal cord, the nerve paths .pdf
1). A) ipsilateralBelow the point of spinal cord, the nerve paths .pdf
ANJALIENTERPRISES1
-F Solution -F.
-FSolution-F.pdf
-FSolution-F.pdf
ANJALIENTERPRISES1
17-The Y-Chromosome DNA testing helps in the examination of the male specific portion of the biological evidence. This is useful where small amount of male DNA is found amidst a large amount of female DNA , as in the sexual assault cases.It can also help in the missing person investigation as it extends the range of potential reference samples. Sine the Y chromosome is passed on from the fathers to their sone (unchanged, except in the case of some mutations), therefore all the males of the same paternal lineage will possess common Y chromosome haplotype. A set of Short tandem repeats (STR) are found on the male specific Y chromosome.The coding genes found on the short arm of the Ychromosome are vital to male sex determination, spermatogenesis andother male related functions. The Y-STRs are polymorphic among the nonrelated males. Sometimes when sepoarating the mal ecomponent and the female component becomes difficult, then the YSTRs help in the determination. Since The Y-STRs are not present in the females, therefore in a case where the male and female are involved, it becomes clear that as the Y-STRs are present the male component is easily detected as only this part will be amplified in the PCR. The YSTRs are also helpful when a number of males are involved. As regular STRs cause masking effect the YSTR will help to identify all the males who have contributed to the evidence. ADVANTAGES- 1. extremely discriminating. 2. Extremely sensitive.e. low amounts of DNA can be used for determination. 3. Not onlu body fluids, but alsp touched materials or handled surfaces, where skinn cells ahev been left can be used for DNA profiling. 4. Multiple testing systems ar available, which increases the likelyhood of successfully generating DNA profiles. 5. Apart from standart=d STR enem mt DNA or YSTRs are used for profiling. 6. With the presence of the current technologies, from amidst mixed DNA samples, the DNA of a particular individual can be profiled. LIMITATIONS 1. Random match probability cannot be excluded. 2. Sometimes even when crime is not committed, we do get ,low levels of DNA on surfaces. 3.The important question while dealing with low DNA quantity is that whether the DNA that was deposited was deposited during the crime or at some other time. 4.Searching evidence is challenging. 5.Sometimes finding the evidence is altogether impossibl. 6. In case of mtDNA /T STRs , as they are passed on from generation to generation either from fathers to sons or mothers to daughters and son, therefore sometimes unrelated persons are also share the same profile. 7. DNA mixtures are very complex. 8.Interpretation is required in many cases. 16- from Cyanobacterial to humans, many terristrial organisms have acquired the circadian rhythms to adapt to sunlight to increase their survival rate.Circadian Rhythm is a biological clock that displays an endogenous, entrainable oscillation of 24 hours.Thesse oscillations are driven by circadian clocks. PULSE CHASE EXPERIME.
17-The Y-Chromosome DNA testing helps in the examination of the male.pdf
17-The Y-Chromosome DNA testing helps in the examination of the male.pdf
ANJALIENTERPRISES1
#include #include #include #define MAX_STR_LEN 80 //decalring the structure struct link_node { //declaring the variables char node_str[ MAX_STR_LEN ]; struct link_node *next; }; //method declaration typedef struct link_node link_node; struct link_node *add_node( struct link_node *list,struct link_node *node ); int compare_node( struct link_node *n1, struct link_node *n2 ); void display_list( struct link_node *head ); //implementing the method main int main() { //declaring the main variables link_node * head=NULL,*temp; char str[MAX_STR_LEN]; do { //getting the STRING input printf(\"Enter the string : \"); gets(str); //malloc() is implemented for memory temp=(link_node*)malloc(sizeof(link_node)); temp->next=NULL; strcpy(temp->node_str,str); head=add_node(head,temp); }while(strlen(str)>1); display_list(head); return 0; } //method definition for compare node int compare_node( struct link_node *n1, struct link_node *n2 ) { if(strcmp(n1->node_str,n2->node_str)==0) return 0; if(strcmp(n1->node_str,n2->node_str)<0) return -1; else return 1; } //method definition for adding the node struct link_node *add_node( struct link_node *list,struct link_node *node ) { link_node *temp=list; if(list==NULL) { return node; } if(compare_node(node,list)==-1) { node->next=list; list=node; return list; } else { link_node *prev=list; while(temp!=NULL&&compare_node(node,temp)>=0) { prev=temp; temp=temp->next; } prev->next=node; node->next=temp; return list; } } //method definition for displaying the list void display_list( struct link_node *head ) { link_node *temp; while(head) { printf(\"%s\ \",head->node_str); temp=head; head=head->next; free(temp); } } Sample output: Enter the string: Geneva America Solution #include #include #include #define MAX_STR_LEN 80 //decalring the structure struct link_node { //declaring the variables char node_str[ MAX_STR_LEN ]; struct link_node *next; }; //method declaration typedef struct link_node link_node; struct link_node *add_node( struct link_node *list,struct link_node *node ); int compare_node( struct link_node *n1, struct link_node *n2 ); void display_list( struct link_node *head ); //implementing the method main int main() { //declaring the main variables link_node * head=NULL,*temp; char str[MAX_STR_LEN]; do { //getting the STRING input printf(\"Enter the string : \"); gets(str); //malloc() is implemented for memory temp=(link_node*)malloc(sizeof(link_node)); temp->next=NULL; strcpy(temp->node_str,str); head=add_node(head,temp); }while(strlen(str)>1); display_list(head); return 0; } //method definition for compare node int compare_node( struct link_node *n1, struct link_node *n2 ) { if(strcmp(n1->node_str,n2->node_str)==0) return 0; if(strcmp(n1->node_str,n2->node_str)<0) return -1; else return 1; } //method definition for adding the node struct link_node *add_node( struct link_node *list,struct link_node *node ) { link_node *temp=list; if(list==NULL) { return node; } if(compare_node(node,list)==-1) { node->next=list; list=no.
#includestdio.h#includestring.h#includestdlib.h#define M.pdf
#includestdio.h#includestring.h#includestdlib.h#define M.pdf
ANJALIENTERPRISES1
The pH and pOH of a solution are defined as: pH = -log[H+] pOH = -log[OH-] and pH + pOH = 14.00 [H+] = 0.055 Conversions: [OH-] = 1.00 x 10^-14 / [H+] = 1.00 x 10-14 /0.055= 1.8x10^-13 pOH = -log[OH-]=12.74 Solution The pH and pOH of a solution are defined as: pH = -log[H+] pOH = -log[OH-] and pH + pOH = 14.00 [H+] = 0.055 Conversions: [OH-] = 1.00 x 10^-14 / [H+] = 1.00 x 10-14 /0.055= 1.8x10^-13 pOH = -log[OH-]=12.74.
The pH and pOH of a solution are defined as pH .pdf
The pH and pOH of a solution are defined as pH .pdf
ANJALIENTERPRISES1
goal_state = [1, 8, 7, 2, 0, 6, 3, 4, 5] #goal_state = [1, 0, 7, 2, 8, 6, 3, 4, 5] import sys global count def display_board( state ): #print \"-------------\" print \" %i %i %i \" % (state[0], state[3], state[6]) #print \"-------------\" print \" %i %i %i \" % (state[1], state[4], state[7]) #print \"-------------\" print \" %i %i %i \" % (state[2], state[5], state[8]) #print \"-------------\" def move_up( state ): new_state = state[:] index = new_state.index( 0 ) if index not in [0, 3, 6]: temp = new_state[index - 1] new_state[index - 1] = new_state[index] new_state[index] = temp return new_state else: return None def move_down( state ): new_state = state[:] index = new_state.index( 0 ) if index not in [2, 5, 8]: temp = new_state[index + 1] new_state[index + 1] = new_state[index] new_state[index] = temp return new_state else: return None def move_left( state ): new_state = state[:] index = new_state.index( 0 ) if index not in [0, 1, 2]: temp = new_state[index - 3] new_state[index - 3] = new_state[index] new_state[index] = temp return new_state else: return None def move_right( state ): new_state = state[:] index = new_state.index( 0 ) if index not in [6, 7, 8]: temp = new_state[index + 3] new_state[index + 3] = new_state[index] new_state[index] = temp return new_state else: return None def create_node( state, parent, operator, depth, cost ): return Node( state, parent, operator, depth, cost ) def expand_node( node, nodes ): expanded_nodes = [] expanded_nodes.append( create_node( move_up( node.state ), node, \"u\", node.depth + 1, 0 ) ) expanded_nodes.append( create_node( move_down( node.state ), node, \"d\", node.depth + 1, 0 ) ) expanded_nodes.append( create_node( move_left( node.state ), node, \"l\", node.depth + 1, 0 ) ) expanded_nodes.append( create_node( move_right( node.state), node, \"r\", node.depth + 1, 0 ) ) # Filter the list and remove the nodes that are impossible (move function returned None) expanded_nodes = [node for node in expanded_nodes if node.state != None] #list comprehension! expanded_nodes = [node for node in expanded_nodes if node not in nodes] #list comprehension! #expanded_nodes = [node for node in expanded_nodes if node.state!= ((node.parent).parent).state] #list comprehension! expanded_nodes1 = [] for node in expanded_nodes: temp=node temp=temp.parent temp=temp.parent if temp==None: expanded_nodes1.extend(expanded_nodes) break if node.state !=temp.state: expanded_nodes1.append(node) return expanded_nodes1 def bfs( start, goal ): nodes = [] count=0 # Create the queue with the root node in it. nodes.append( create_node( start, None, None, 0, 0 ) ) while True: # We\'ve run out of states, no solution. if len( nodes ) == 0: return None # take the node from the front of the queue node = nodes.pop(0) count=count+1 #display_board(node.state) # Append the move we made to moves # if this node is the goal, return the moves it took to get here. if node.state == goal: #display_board(node.state) moves = [] temp = node print cou.
goal_state = [1, 8, 7, 2, 0, 6, 3, 4, 5] #goal_state = [1, 0, 7, 2, .pdf
goal_state = [1, 8, 7, 2, 0, 6, 3, 4, 5] #goal_state = [1, 0, 7, 2, .pdf
ANJALIENTERPRISES1
7 steps are required as 9 is the 7th element and the search is linear Solution 7 steps are required as 9 is the 7th element and the search is linear.
7 steps are required as 9 is the 7th element and the search is line.pdf
7 steps are required as 9 is the 7th element and the search is line.pdf
ANJALIENTERPRISES1
(D) the number of moles of hydroxide ion added and the number of moles of monoprotic acid initially present Solution (D) the number of moles of hydroxide ion added and the number of moles of monoprotic acid initially present.
(D) the number of moles of hydroxide ion added and the number of mol.pdf
(D) the number of moles of hydroxide ion added and the number of mol.pdf
ANJALIENTERPRISES1
Look for changes in oxidation numbers. These occur in reactions (c) and (e) only. Thus, reactions (c) and (e) are REDOX reactions. Solution Look for changes in oxidation numbers. These occur in reactions (c) and (e) only. Thus, reactions (c) and (e) are REDOX reactions..
Look for changes in oxidation numbers. These occ.pdf
Look for changes in oxidation numbers. These occ.pdf
ANJALIENTERPRISES1
D) Insulin Solution D) Insulin.
D) Insulin .pdf
D) Insulin .pdf
ANJALIENTERPRISES1
Use Dalton\'s Law of partial pressures. P(Total)=P(H2)+P(H20) p(H2)=P(Total)- P(H20) Look up the partial pressure of water at the given temperature. It comes out to be 0.0351 atm. P(H2)=1-0.0351 = 0.9649 atm Solution Use Dalton\'s Law of partial pressures. P(Total)=P(H2)+P(H20) p(H2)=P(Total)- P(H20) Look up the partial pressure of water at the given temperature. It comes out to be 0.0351 atm. P(H2)=1-0.0351 = 0.9649 atm.
Use Daltons Law of partial pressures. P(Total).pdf
Use Daltons Law of partial pressures. P(Total).pdf
ANJALIENTERPRISES1
The Br was originally neutral, but picks up an extra electron from the N and becomes Br-. The Br- leaves the molecule The O was originally negative, but gives up an electron to form a double bond with C1 and becomes neutral. Leaving O=C=N-C as a neutral molecule. Keeping the labeling of the two carbons it would be O=C1=N-C2. With the double bonds on both sides of C1, the O, C1, N backbone is linear. Solution The Br was originally neutral, but picks up an extra electron from the N and becomes Br-. The Br- leaves the molecule The O was originally negative, but gives up an electron to form a double bond with C1 and becomes neutral. Leaving O=C=N-C as a neutral molecule. Keeping the labeling of the two carbons it would be O=C1=N-C2. With the double bonds on both sides of C1, the O, C1, N backbone is linear..
The Br was originally neutral, but picks up an ex.pdf
The Br was originally neutral, but picks up an ex.pdf
ANJALIENTERPRISES1
Step1 firstly balance the Phophorous atoms by multiplying Right hand side by 4 Step 2 now balance oxygen atoms by multiplying H2O by 6 Step3 P4O10 +6 H2O-------> 4H3PO4 Solution Step1 firstly balance the Phophorous atoms by multiplying Right hand side by 4 Step 2 now balance oxygen atoms by multiplying H2O by 6 Step3 P4O10 +6 H2O-------> 4H3PO4.
Step1 firstly balance the Phophorous atoms by mul.pdf
Step1 firstly balance the Phophorous atoms by mul.pdf
ANJALIENTERPRISES1
Year 2000 is the period when the productivity growth rate was at minimum ie., 0.7. Degrowth refers to those years where productivity growth rate was in negative. Minimum growth rate refers to the minimum positive growth rate achieved. Solution Year 2000 is the period when the productivity growth rate was at minimum ie., 0.7. Degrowth refers to those years where productivity growth rate was in negative. Minimum growth rate refers to the minimum positive growth rate achieved..
Year 2000 is the period when the productivity growth rate was at min.pdf
Year 2000 is the period when the productivity growth rate was at min.pdf
ANJALIENTERPRISES1
You have tab characters in your text file which is making console to display following both lines aligned at middle. dress across the porch as the There are two ways of doing it. Solution You have tab characters in your text file which is making console to display following both lines aligned at middle. dress across the porch as the There are two ways of doing it..
You have tab characters in your text file which is making console to.pdf
You have tab characters in your text file which is making console to.pdf
ANJALIENTERPRISES1
the frequency of the allele I^A in this population-0.22 the frequency of the allele I^B in this population-0.08 Solution the frequency of the allele I^A in this population-0.22 the frequency of the allele I^B in this population-0.08.
the frequency of the allele I^A in this population-0.22the frequen.pdf
the frequency of the allele I^A in this population-0.22the frequen.pdf
ANJALIENTERPRISES1
The reaction is: Sr(s) + 2 H2O(l) => Sr(OH)2(s) + H2(g) Solution The reaction is: Sr(s) + 2 H2O(l) => Sr(OH)2(s) + H2(g).
The reaction isSr(s) + 2 H2O(l) = Sr(OH)2(s) + H2(g)Solution.pdf
The reaction isSr(s) + 2 H2O(l) = Sr(OH)2(s) + H2(g)Solution.pdf
ANJALIENTERPRISES1
Solution IDENameCostOpen SourceDestinationNETBEANSFreeyescross platform IDEINTELLIJ IDEA$199noit has great moderen UIECLIPSEfreeyesit features huge library of pluginsJDEVELOPERfreeyesit has fully loades tool set for creating javaDR. JAVAFreeyesit supports cross platformBLUEJFreeyesit suitable for small software projectsJCREATORfreeyesit is fast and efficient ideJGRASPfreeyesit is super lightweight ideGREENFOOTfreeyesit supports designing for 2D games CODEENVY$1(month)nocloud based ide.
Solution!DOCTYPE html html head style type=textcss.pdf
Solution!DOCTYPE html html head style type=textcss.pdf
ANJALIENTERPRISES1
TCP/IP is mostly uaed network protocol in Linux and Mac os. But appletalk also used in both the os. Solution TCP/IP is mostly uaed network protocol in Linux and Mac os. But appletalk also used in both the os..
TCPIP is mostly uaed network protocol in Linux and Mac os.But app.pdf
TCPIP is mostly uaed network protocol in Linux and Mac os.But app.pdf
ANJALIENTERPRISES1
People are more triggered by positive news than negative news. Audience does not want to hear, read or receive any kind of bad news. So these slides show how to convey negative news to someone without affecting their emotions.
COMMUNICATING NEGATIVE NEWS - APPROACHES .pptx
COMMUNICATING NEGATIVE NEWS - APPROACHES .pptx
annathomasp01
Fictional Salesman/Saleswoman
FICTIONAL SALESMAN/SALESMAN SNSW 2024.pdf
FICTIONAL SALESMAN/SALESMAN SNSW 2024.pdf
Pondicherry University
More Related Content
More from ANJALIENTERPRISES1
At the beginning of the 11th year, there would be 1,024,000 rabbits. Solution At the beginning of the 11th year, there would be 1,024,000 rabbits..
A is correct. The packets to be filtered would be heading into the r.pdf
A is correct. The packets to be filtered would be heading into the r.pdf
ANJALIENTERPRISES1
1). A) ipsilateral Below the point of spinal cord, the nerve paths belong to the same side (no crossing over occurs). So, the nociceptive information can be found on the same side of the body. Solution 1). A) ipsilateral Below the point of spinal cord, the nerve paths belong to the same side (no crossing over occurs). So, the nociceptive information can be found on the same side of the body..
1). A) ipsilateralBelow the point of spinal cord, the nerve paths .pdf
1). A) ipsilateralBelow the point of spinal cord, the nerve paths .pdf
ANJALIENTERPRISES1
-F Solution -F.
-FSolution-F.pdf
-FSolution-F.pdf
ANJALIENTERPRISES1
17-The Y-Chromosome DNA testing helps in the examination of the male specific portion of the biological evidence. This is useful where small amount of male DNA is found amidst a large amount of female DNA , as in the sexual assault cases.It can also help in the missing person investigation as it extends the range of potential reference samples. Sine the Y chromosome is passed on from the fathers to their sone (unchanged, except in the case of some mutations), therefore all the males of the same paternal lineage will possess common Y chromosome haplotype. A set of Short tandem repeats (STR) are found on the male specific Y chromosome.The coding genes found on the short arm of the Ychromosome are vital to male sex determination, spermatogenesis andother male related functions. The Y-STRs are polymorphic among the nonrelated males. Sometimes when sepoarating the mal ecomponent and the female component becomes difficult, then the YSTRs help in the determination. Since The Y-STRs are not present in the females, therefore in a case where the male and female are involved, it becomes clear that as the Y-STRs are present the male component is easily detected as only this part will be amplified in the PCR. The YSTRs are also helpful when a number of males are involved. As regular STRs cause masking effect the YSTR will help to identify all the males who have contributed to the evidence. ADVANTAGES- 1. extremely discriminating. 2. Extremely sensitive.e. low amounts of DNA can be used for determination. 3. Not onlu body fluids, but alsp touched materials or handled surfaces, where skinn cells ahev been left can be used for DNA profiling. 4. Multiple testing systems ar available, which increases the likelyhood of successfully generating DNA profiles. 5. Apart from standart=d STR enem mt DNA or YSTRs are used for profiling. 6. With the presence of the current technologies, from amidst mixed DNA samples, the DNA of a particular individual can be profiled. LIMITATIONS 1. Random match probability cannot be excluded. 2. Sometimes even when crime is not committed, we do get ,low levels of DNA on surfaces. 3.The important question while dealing with low DNA quantity is that whether the DNA that was deposited was deposited during the crime or at some other time. 4.Searching evidence is challenging. 5.Sometimes finding the evidence is altogether impossibl. 6. In case of mtDNA /T STRs , as they are passed on from generation to generation either from fathers to sons or mothers to daughters and son, therefore sometimes unrelated persons are also share the same profile. 7. DNA mixtures are very complex. 8.Interpretation is required in many cases. 16- from Cyanobacterial to humans, many terristrial organisms have acquired the circadian rhythms to adapt to sunlight to increase their survival rate.Circadian Rhythm is a biological clock that displays an endogenous, entrainable oscillation of 24 hours.Thesse oscillations are driven by circadian clocks. PULSE CHASE EXPERIME.
17-The Y-Chromosome DNA testing helps in the examination of the male.pdf
17-The Y-Chromosome DNA testing helps in the examination of the male.pdf
ANJALIENTERPRISES1
#include #include #include #define MAX_STR_LEN 80 //decalring the structure struct link_node { //declaring the variables char node_str[ MAX_STR_LEN ]; struct link_node *next; }; //method declaration typedef struct link_node link_node; struct link_node *add_node( struct link_node *list,struct link_node *node ); int compare_node( struct link_node *n1, struct link_node *n2 ); void display_list( struct link_node *head ); //implementing the method main int main() { //declaring the main variables link_node * head=NULL,*temp; char str[MAX_STR_LEN]; do { //getting the STRING input printf(\"Enter the string : \"); gets(str); //malloc() is implemented for memory temp=(link_node*)malloc(sizeof(link_node)); temp->next=NULL; strcpy(temp->node_str,str); head=add_node(head,temp); }while(strlen(str)>1); display_list(head); return 0; } //method definition for compare node int compare_node( struct link_node *n1, struct link_node *n2 ) { if(strcmp(n1->node_str,n2->node_str)==0) return 0; if(strcmp(n1->node_str,n2->node_str)<0) return -1; else return 1; } //method definition for adding the node struct link_node *add_node( struct link_node *list,struct link_node *node ) { link_node *temp=list; if(list==NULL) { return node; } if(compare_node(node,list)==-1) { node->next=list; list=node; return list; } else { link_node *prev=list; while(temp!=NULL&&compare_node(node,temp)>=0) { prev=temp; temp=temp->next; } prev->next=node; node->next=temp; return list; } } //method definition for displaying the list void display_list( struct link_node *head ) { link_node *temp; while(head) { printf(\"%s\ \",head->node_str); temp=head; head=head->next; free(temp); } } Sample output: Enter the string: Geneva America Solution #include #include #include #define MAX_STR_LEN 80 //decalring the structure struct link_node { //declaring the variables char node_str[ MAX_STR_LEN ]; struct link_node *next; }; //method declaration typedef struct link_node link_node; struct link_node *add_node( struct link_node *list,struct link_node *node ); int compare_node( struct link_node *n1, struct link_node *n2 ); void display_list( struct link_node *head ); //implementing the method main int main() { //declaring the main variables link_node * head=NULL,*temp; char str[MAX_STR_LEN]; do { //getting the STRING input printf(\"Enter the string : \"); gets(str); //malloc() is implemented for memory temp=(link_node*)malloc(sizeof(link_node)); temp->next=NULL; strcpy(temp->node_str,str); head=add_node(head,temp); }while(strlen(str)>1); display_list(head); return 0; } //method definition for compare node int compare_node( struct link_node *n1, struct link_node *n2 ) { if(strcmp(n1->node_str,n2->node_str)==0) return 0; if(strcmp(n1->node_str,n2->node_str)<0) return -1; else return 1; } //method definition for adding the node struct link_node *add_node( struct link_node *list,struct link_node *node ) { link_node *temp=list; if(list==NULL) { return node; } if(compare_node(node,list)==-1) { node->next=list; list=no.
#includestdio.h#includestring.h#includestdlib.h#define M.pdf
#includestdio.h#includestring.h#includestdlib.h#define M.pdf
ANJALIENTERPRISES1
The pH and pOH of a solution are defined as: pH = -log[H+] pOH = -log[OH-] and pH + pOH = 14.00 [H+] = 0.055 Conversions: [OH-] = 1.00 x 10^-14 / [H+] = 1.00 x 10-14 /0.055= 1.8x10^-13 pOH = -log[OH-]=12.74 Solution The pH and pOH of a solution are defined as: pH = -log[H+] pOH = -log[OH-] and pH + pOH = 14.00 [H+] = 0.055 Conversions: [OH-] = 1.00 x 10^-14 / [H+] = 1.00 x 10-14 /0.055= 1.8x10^-13 pOH = -log[OH-]=12.74.
The pH and pOH of a solution are defined as pH .pdf
The pH and pOH of a solution are defined as pH .pdf
ANJALIENTERPRISES1
goal_state = [1, 8, 7, 2, 0, 6, 3, 4, 5] #goal_state = [1, 0, 7, 2, 8, 6, 3, 4, 5] import sys global count def display_board( state ): #print \"-------------\" print \" %i %i %i \" % (state[0], state[3], state[6]) #print \"-------------\" print \" %i %i %i \" % (state[1], state[4], state[7]) #print \"-------------\" print \" %i %i %i \" % (state[2], state[5], state[8]) #print \"-------------\" def move_up( state ): new_state = state[:] index = new_state.index( 0 ) if index not in [0, 3, 6]: temp = new_state[index - 1] new_state[index - 1] = new_state[index] new_state[index] = temp return new_state else: return None def move_down( state ): new_state = state[:] index = new_state.index( 0 ) if index not in [2, 5, 8]: temp = new_state[index + 1] new_state[index + 1] = new_state[index] new_state[index] = temp return new_state else: return None def move_left( state ): new_state = state[:] index = new_state.index( 0 ) if index not in [0, 1, 2]: temp = new_state[index - 3] new_state[index - 3] = new_state[index] new_state[index] = temp return new_state else: return None def move_right( state ): new_state = state[:] index = new_state.index( 0 ) if index not in [6, 7, 8]: temp = new_state[index + 3] new_state[index + 3] = new_state[index] new_state[index] = temp return new_state else: return None def create_node( state, parent, operator, depth, cost ): return Node( state, parent, operator, depth, cost ) def expand_node( node, nodes ): expanded_nodes = [] expanded_nodes.append( create_node( move_up( node.state ), node, \"u\", node.depth + 1, 0 ) ) expanded_nodes.append( create_node( move_down( node.state ), node, \"d\", node.depth + 1, 0 ) ) expanded_nodes.append( create_node( move_left( node.state ), node, \"l\", node.depth + 1, 0 ) ) expanded_nodes.append( create_node( move_right( node.state), node, \"r\", node.depth + 1, 0 ) ) # Filter the list and remove the nodes that are impossible (move function returned None) expanded_nodes = [node for node in expanded_nodes if node.state != None] #list comprehension! expanded_nodes = [node for node in expanded_nodes if node not in nodes] #list comprehension! #expanded_nodes = [node for node in expanded_nodes if node.state!= ((node.parent).parent).state] #list comprehension! expanded_nodes1 = [] for node in expanded_nodes: temp=node temp=temp.parent temp=temp.parent if temp==None: expanded_nodes1.extend(expanded_nodes) break if node.state !=temp.state: expanded_nodes1.append(node) return expanded_nodes1 def bfs( start, goal ): nodes = [] count=0 # Create the queue with the root node in it. nodes.append( create_node( start, None, None, 0, 0 ) ) while True: # We\'ve run out of states, no solution. if len( nodes ) == 0: return None # take the node from the front of the queue node = nodes.pop(0) count=count+1 #display_board(node.state) # Append the move we made to moves # if this node is the goal, return the moves it took to get here. if node.state == goal: #display_board(node.state) moves = [] temp = node print cou.
goal_state = [1, 8, 7, 2, 0, 6, 3, 4, 5] #goal_state = [1, 0, 7, 2, .pdf
goal_state = [1, 8, 7, 2, 0, 6, 3, 4, 5] #goal_state = [1, 0, 7, 2, .pdf
ANJALIENTERPRISES1
7 steps are required as 9 is the 7th element and the search is linear Solution 7 steps are required as 9 is the 7th element and the search is linear.
7 steps are required as 9 is the 7th element and the search is line.pdf
7 steps are required as 9 is the 7th element and the search is line.pdf
ANJALIENTERPRISES1
(D) the number of moles of hydroxide ion added and the number of moles of monoprotic acid initially present Solution (D) the number of moles of hydroxide ion added and the number of moles of monoprotic acid initially present.
(D) the number of moles of hydroxide ion added and the number of mol.pdf
(D) the number of moles of hydroxide ion added and the number of mol.pdf
ANJALIENTERPRISES1
Look for changes in oxidation numbers. These occur in reactions (c) and (e) only. Thus, reactions (c) and (e) are REDOX reactions. Solution Look for changes in oxidation numbers. These occur in reactions (c) and (e) only. Thus, reactions (c) and (e) are REDOX reactions..
Look for changes in oxidation numbers. These occ.pdf
Look for changes in oxidation numbers. These occ.pdf
ANJALIENTERPRISES1
D) Insulin Solution D) Insulin.
D) Insulin .pdf
D) Insulin .pdf
ANJALIENTERPRISES1
Use Dalton\'s Law of partial pressures. P(Total)=P(H2)+P(H20) p(H2)=P(Total)- P(H20) Look up the partial pressure of water at the given temperature. It comes out to be 0.0351 atm. P(H2)=1-0.0351 = 0.9649 atm Solution Use Dalton\'s Law of partial pressures. P(Total)=P(H2)+P(H20) p(H2)=P(Total)- P(H20) Look up the partial pressure of water at the given temperature. It comes out to be 0.0351 atm. P(H2)=1-0.0351 = 0.9649 atm.
Use Daltons Law of partial pressures. P(Total).pdf
Use Daltons Law of partial pressures. P(Total).pdf
ANJALIENTERPRISES1
The Br was originally neutral, but picks up an extra electron from the N and becomes Br-. The Br- leaves the molecule The O was originally negative, but gives up an electron to form a double bond with C1 and becomes neutral. Leaving O=C=N-C as a neutral molecule. Keeping the labeling of the two carbons it would be O=C1=N-C2. With the double bonds on both sides of C1, the O, C1, N backbone is linear. Solution The Br was originally neutral, but picks up an extra electron from the N and becomes Br-. The Br- leaves the molecule The O was originally negative, but gives up an electron to form a double bond with C1 and becomes neutral. Leaving O=C=N-C as a neutral molecule. Keeping the labeling of the two carbons it would be O=C1=N-C2. With the double bonds on both sides of C1, the O, C1, N backbone is linear..
The Br was originally neutral, but picks up an ex.pdf
The Br was originally neutral, but picks up an ex.pdf
ANJALIENTERPRISES1
Step1 firstly balance the Phophorous atoms by multiplying Right hand side by 4 Step 2 now balance oxygen atoms by multiplying H2O by 6 Step3 P4O10 +6 H2O-------> 4H3PO4 Solution Step1 firstly balance the Phophorous atoms by multiplying Right hand side by 4 Step 2 now balance oxygen atoms by multiplying H2O by 6 Step3 P4O10 +6 H2O-------> 4H3PO4.
Step1 firstly balance the Phophorous atoms by mul.pdf
Step1 firstly balance the Phophorous atoms by mul.pdf
ANJALIENTERPRISES1
Year 2000 is the period when the productivity growth rate was at minimum ie., 0.7. Degrowth refers to those years where productivity growth rate was in negative. Minimum growth rate refers to the minimum positive growth rate achieved. Solution Year 2000 is the period when the productivity growth rate was at minimum ie., 0.7. Degrowth refers to those years where productivity growth rate was in negative. Minimum growth rate refers to the minimum positive growth rate achieved..
Year 2000 is the period when the productivity growth rate was at min.pdf
Year 2000 is the period when the productivity growth rate was at min.pdf
ANJALIENTERPRISES1
You have tab characters in your text file which is making console to display following both lines aligned at middle. dress across the porch as the There are two ways of doing it. Solution You have tab characters in your text file which is making console to display following both lines aligned at middle. dress across the porch as the There are two ways of doing it..
You have tab characters in your text file which is making console to.pdf
You have tab characters in your text file which is making console to.pdf
ANJALIENTERPRISES1
the frequency of the allele I^A in this population-0.22 the frequency of the allele I^B in this population-0.08 Solution the frequency of the allele I^A in this population-0.22 the frequency of the allele I^B in this population-0.08.
the frequency of the allele I^A in this population-0.22the frequen.pdf
the frequency of the allele I^A in this population-0.22the frequen.pdf
ANJALIENTERPRISES1
The reaction is: Sr(s) + 2 H2O(l) => Sr(OH)2(s) + H2(g) Solution The reaction is: Sr(s) + 2 H2O(l) => Sr(OH)2(s) + H2(g).
The reaction isSr(s) + 2 H2O(l) = Sr(OH)2(s) + H2(g)Solution.pdf
The reaction isSr(s) + 2 H2O(l) = Sr(OH)2(s) + H2(g)Solution.pdf
ANJALIENTERPRISES1
Solution IDENameCostOpen SourceDestinationNETBEANSFreeyescross platform IDEINTELLIJ IDEA$199noit has great moderen UIECLIPSEfreeyesit features huge library of pluginsJDEVELOPERfreeyesit has fully loades tool set for creating javaDR. JAVAFreeyesit supports cross platformBLUEJFreeyesit suitable for small software projectsJCREATORfreeyesit is fast and efficient ideJGRASPfreeyesit is super lightweight ideGREENFOOTfreeyesit supports designing for 2D games CODEENVY$1(month)nocloud based ide.
Solution!DOCTYPE html html head style type=textcss.pdf
Solution!DOCTYPE html html head style type=textcss.pdf
ANJALIENTERPRISES1
TCP/IP is mostly uaed network protocol in Linux and Mac os. But appletalk also used in both the os. Solution TCP/IP is mostly uaed network protocol in Linux and Mac os. But appletalk also used in both the os..
TCPIP is mostly uaed network protocol in Linux and Mac os.But app.pdf
TCPIP is mostly uaed network protocol in Linux and Mac os.But app.pdf
ANJALIENTERPRISES1
More from ANJALIENTERPRISES1
(20)
A is correct. The packets to be filtered would be heading into the r.pdf
A is correct. The packets to be filtered would be heading into the r.pdf
1). A) ipsilateralBelow the point of spinal cord, the nerve paths .pdf
1). A) ipsilateralBelow the point of spinal cord, the nerve paths .pdf
-FSolution-F.pdf
-FSolution-F.pdf
17-The Y-Chromosome DNA testing helps in the examination of the male.pdf
17-The Y-Chromosome DNA testing helps in the examination of the male.pdf
#includestdio.h#includestring.h#includestdlib.h#define M.pdf
#includestdio.h#includestring.h#includestdlib.h#define M.pdf
The pH and pOH of a solution are defined as pH .pdf
The pH and pOH of a solution are defined as pH .pdf
goal_state = [1, 8, 7, 2, 0, 6, 3, 4, 5] #goal_state = [1, 0, 7, 2, .pdf
goal_state = [1, 8, 7, 2, 0, 6, 3, 4, 5] #goal_state = [1, 0, 7, 2, .pdf
7 steps are required as 9 is the 7th element and the search is line.pdf
7 steps are required as 9 is the 7th element and the search is line.pdf
(D) the number of moles of hydroxide ion added and the number of mol.pdf
(D) the number of moles of hydroxide ion added and the number of mol.pdf
Look for changes in oxidation numbers. These occ.pdf
Look for changes in oxidation numbers. These occ.pdf
D) Insulin .pdf
D) Insulin .pdf
Use Daltons Law of partial pressures. P(Total).pdf
Use Daltons Law of partial pressures. P(Total).pdf
The Br was originally neutral, but picks up an ex.pdf
The Br was originally neutral, but picks up an ex.pdf
Step1 firstly balance the Phophorous atoms by mul.pdf
Step1 firstly balance the Phophorous atoms by mul.pdf
Year 2000 is the period when the productivity growth rate was at min.pdf
Year 2000 is the period when the productivity growth rate was at min.pdf
You have tab characters in your text file which is making console to.pdf
You have tab characters in your text file which is making console to.pdf
the frequency of the allele I^A in this population-0.22the frequen.pdf
the frequency of the allele I^A in this population-0.22the frequen.pdf
The reaction isSr(s) + 2 H2O(l) = Sr(OH)2(s) + H2(g)Solution.pdf
The reaction isSr(s) + 2 H2O(l) = Sr(OH)2(s) + H2(g)Solution.pdf
Solution!DOCTYPE html html head style type=textcss.pdf
Solution!DOCTYPE html html head style type=textcss.pdf
TCPIP is mostly uaed network protocol in Linux and Mac os.But app.pdf
TCPIP is mostly uaed network protocol in Linux and Mac os.But app.pdf
Recently uploaded
People are more triggered by positive news than negative news. Audience does not want to hear, read or receive any kind of bad news. So these slides show how to convey negative news to someone without affecting their emotions.
COMMUNICATING NEGATIVE NEWS - APPROACHES .pptx
COMMUNICATING NEGATIVE NEWS - APPROACHES .pptx
annathomasp01
Fictional Salesman/Saleswoman
FICTIONAL SALESMAN/SALESMAN SNSW 2024.pdf
FICTIONAL SALESMAN/SALESMAN SNSW 2024.pdf
Pondicherry University
This presentation was provided by William Mattingly of the Smithsonian Institution, during the sixth segment of the NISO training series "AI & Prompt Design." Session Six: Text Classification with LLMs, was held on May 9, 2024.
Mattingly "AI and Prompt Design: LLMs with NER"
Mattingly "AI and Prompt Design: LLMs with NER"
National Information Standards Organization (NISO)
The Graduate Outcomes survey exists to improve the experience of future students.
Graduate Outcomes Presentation Slides - English (v3).pptx
Graduate Outcomes Presentation Slides - English (v3).pptx
neillewis46
https://app.box.com/s/71kthbth9ww0fyjrppmh1p2gasinqj5z
ĐỀ THAM KHẢO KÌ THI TUYỂN SINH VÀO LỚP 10 MÔN TIẾNG ANH FORM 50 CÂU TRẮC NGHI...
ĐỀ THAM KHẢO KÌ THI TUYỂN SINH VÀO LỚP 10 MÔN TIẾNG ANH FORM 50 CÂU TRẮC NGHI...
Nguyen Thanh Tu Collection
Photos from our Spring Gala 2024. Thank you for making our 2024 Spring Gala unforgettable! Whether you attended or supported us with a donation, we extend our heartfelt thanks for celebrating School-Community Partnerships alongside ExpandED Schools. Special appreciation to our honorees, Rachel Skaistis and Cravath, Swaine, & Moore LLP, for their unwavering support in advancing educational equity. Your contributions have profoundly impacted countless young New Yorkers, and we’re proud to have you as part of our community. Our gratitude also extends to our Board of Directors, sponsors, city partners, community-based organizations, and the inspiring young people who joined us. Your support fuels our mission, and we’re endlessly thankful for your dedication. While we celebrate our gala’s success, our work continues. As you view the evening’s highlights, consider how you can further empower young New Yorkers and educators with your donation, no matter the size. Donate today: https://www.expandedschools.org/support-our-work/donate/
Spring gala 2024 photo slideshow - Celebrating School-Community Partnerships
Spring gala 2024 photo slideshow - Celebrating School-Community Partnerships
expandedwebsite
Supporting Newcomer Multilingual Learners
Supporting Newcomer Multilingual Learners
Supporting Newcomer Multilingual Learners
David Douglas School District
https://app.box.com/s/xplac2t6bphx6pe1mofyfj0fvrjx1f3i
24 ĐỀ THAM KHẢO KÌ THI TUYỂN SINH VÀO LỚP 10 MÔN TIẾNG ANH SỞ GIÁO DỤC HẢI DƯ...
24 ĐỀ THAM KHẢO KÌ THI TUYỂN SINH VÀO LỚP 10 MÔN TIẾNG ANH SỞ GIÁO DỤC HẢI DƯ...
Nguyen Thanh Tu Collection
Students will be able to know the anatomy & physiology of the liver and gallbladder its metabolic functions etc.
The Liver & Gallbladder (Anatomy & Physiology).pptx
The Liver & Gallbladder (Anatomy & Physiology).pptx
Vishal Singh
The Department of Emergency Medicine at Carolinas Medical Center is passionate about education! Dr. Michael Gibbs is a world-renowned clinician and educator and has helped guide numerous young clinicians on the long path of Mastery of Emergency Medical Care. With his oversight, the EMGuideWire team aim to help augment our understanding of emergent imaging. You can follow along with the EMGuideWire.com team as they post these educational, self-guided radiology slides or you can also use this section to learn more in-depth about specific conditions and diseases. This Radiology Reading Room pertains to Sternal Fractures and Dislocations and is brought to you by Carrie Bissell, MD, Aaron Fox, MD, Kendrick Lim, MD, Stephanie Jensen, MD, and Olivia Rice, MD. It is has special guest editor: Sean Dieffenbaugher, MD and Laurence Kempton, MD
Sternal Fractures & Dislocations - EMGuidewire Radiology Reading Room
Sternal Fractures & Dislocations - EMGuidewire Radiology Reading Room
Sean M. Fox
Class 07, Database, ESSENTIAL of (CS/IT/IS), for 1st level students of College of Computers, ESSENTIAL of (CS/IT/IS) class 07 (Networks)
ESSENTIAL of (CS/IT/IS) class 07 (Networks)
ESSENTIAL of (CS/IT/IS) class 07 (Networks)
Dr. Mazin Mohamed alkathiri
spellinga
Spellings Wk 4 and Wk 5 for Grade 4 at CAPS
Spellings Wk 4 and Wk 5 for Grade 4 at CAPS
AnaAcapella
會考英聽
會考英聽會考英聽會考英聽會考英聽會考英聽會考英聽會考英聽會考英聽會考英聽會考英聽
會考英聽會考英聽會考英聽會考英聽會考英聽會考英聽會考英聽會考英聽會考英聽會考英聽
中 央社
LESSON PLAN IN ENGLISH 4 MATATAG CURRICULUM
DEMONSTRATION LESSON IN ENGLISH 4 MATATAG CURRICULUM
DEMONSTRATION LESSON IN ENGLISH 4 MATATAG CURRICULUM
ELOISARIVERA8
EADTU-EU Summit 2024
Personalisation of Education by AI and Big Data - Lourdes Guàrdia
Personalisation of Education by AI and Big Data - Lourdes Guàrdia
EADTU
The best commit messages from the Spring 2024 edition of CMSC 23320 Foundations of Computer Networks
UChicago CMSC 23320 - The Best Commit Messages of 2024
UChicago CMSC 23320 - The Best Commit Messages of 2024
Borja Sotomayor
8 Tips for Effective Working Capital Management.pdf" This comprehensive guide, "8 Tips for Effective Working Capital Management", serves as a valuable resource for businesses aiming to optimize their financial operations. 💼 In this PDF, you will find practical tips and strategies to effectively manage your working capital, ensuring a healthy and sustainable financial position for your organization. for more information visit now https://www.mbaassignmentexperts.com/management-assignment-help
8 Tips for Effective Working Capital Management
8 Tips for Effective Working Capital Management
MBA Assignment Experts
Program code examples (known also as worked examples) play a crucial role in learning how to program. Instructors use examples extensively to demonstrate the semantics of the programming language being taught and to highlight the fundamental coding patterns. Programming textbooks allocate considerable space to present and explain code examples. To make the process of studying code examples more interactive, CS education researchers developed a range of tools to engage students in the study of code examples. These tools include codecasts (codemotion,codecast,elicasts), interactive example explorers (WebEx, PCEX), and tutoring systems (DeepTutor). An important component in all types of worked examples is code explanations associated with specific code lines or code chunks of an example. The explanations connect examples with general programming knowledge explaining the role and function of code fragments or their behavior. In textbooks, these explanations are usually presented as comments in the code or as explanations on the margins. The example explorer tools allow students to examine these explanations interactively. Tutoring systems, which engage students in explaining the code, use these model explanations to check student responses and provide scaffolding. In all these cases, to make a worked example re-usable beyond its presentation in a lecture, the explanations have to be authored by instructors or domain experts i.e., produced and integrated into a specific system. As the experience of the last 10 years demonstrated, these explanations are hard to obtain. Those already collected are usually “locked” in a specific example-focused system and can’t be reused. The purpose of this working group is to support broader re-used of worked examples augmented with explanations. Our current plan is to develop а standard approach to represent explained examples. This approach will enable an example created for any of the existing systems to be explored in a standard format and imported into any other example-focused system. We plan to follow a successful experience of the PEML working group focused on re-using programming exercises.
SPLICE Working Group:Reusable Code Examples
SPLICE Working Group:Reusable Code Examples
Peter Brusilovsky
Andreas Schleicher presents at the launch of ‘What does child empowerment mean today? Implications for education and well-being’ on the 15 May 2024. The report was launched by Mathias Cormann, OECD Secretary-General and can be found here: https://www.oecd-ilibrary.org/education/what-does-child-empowerment-mean-today_8f80ce38-en
Andreas Schleicher presents at the launch of What does child empowerment mean...
Andreas Schleicher presents at the launch of What does child empowerment mean...
EduSkills OECD
Learn how to efficiently manage your website using the powerful features of Odoo 17 Studio App. Discover step-by-step guides and expert tips for creating, editing, and optimizing your website content with ease. Unlock the full potential of Odoo 17 Studio App to enhance your online presence and drive greater engagement with your audience.
How to Manage Website in Odoo 17 Studio App.pptx
How to Manage Website in Odoo 17 Studio App.pptx
Celine George
Recently uploaded
(20)
COMMUNICATING NEGATIVE NEWS - APPROACHES .pptx
COMMUNICATING NEGATIVE NEWS - APPROACHES .pptx
FICTIONAL SALESMAN/SALESMAN SNSW 2024.pdf
FICTIONAL SALESMAN/SALESMAN SNSW 2024.pdf
Mattingly "AI and Prompt Design: LLMs with NER"
Mattingly "AI and Prompt Design: LLMs with NER"
Graduate Outcomes Presentation Slides - English (v3).pptx
Graduate Outcomes Presentation Slides - English (v3).pptx
ĐỀ THAM KHẢO KÌ THI TUYỂN SINH VÀO LỚP 10 MÔN TIẾNG ANH FORM 50 CÂU TRẮC NGHI...
ĐỀ THAM KHẢO KÌ THI TUYỂN SINH VÀO LỚP 10 MÔN TIẾNG ANH FORM 50 CÂU TRẮC NGHI...
Spring gala 2024 photo slideshow - Celebrating School-Community Partnerships
Spring gala 2024 photo slideshow - Celebrating School-Community Partnerships
Supporting Newcomer Multilingual Learners
Supporting Newcomer Multilingual Learners
24 ĐỀ THAM KHẢO KÌ THI TUYỂN SINH VÀO LỚP 10 MÔN TIẾNG ANH SỞ GIÁO DỤC HẢI DƯ...
24 ĐỀ THAM KHẢO KÌ THI TUYỂN SINH VÀO LỚP 10 MÔN TIẾNG ANH SỞ GIÁO DỤC HẢI DƯ...
The Liver & Gallbladder (Anatomy & Physiology).pptx
The Liver & Gallbladder (Anatomy & Physiology).pptx
Sternal Fractures & Dislocations - EMGuidewire Radiology Reading Room
Sternal Fractures & Dislocations - EMGuidewire Radiology Reading Room
ESSENTIAL of (CS/IT/IS) class 07 (Networks)
ESSENTIAL of (CS/IT/IS) class 07 (Networks)
Spellings Wk 4 and Wk 5 for Grade 4 at CAPS
Spellings Wk 4 and Wk 5 for Grade 4 at CAPS
會考英聽會考英聽會考英聽會考英聽會考英聽會考英聽會考英聽會考英聽會考英聽會考英聽
會考英聽會考英聽會考英聽會考英聽會考英聽會考英聽會考英聽會考英聽會考英聽會考英聽
DEMONSTRATION LESSON IN ENGLISH 4 MATATAG CURRICULUM
DEMONSTRATION LESSON IN ENGLISH 4 MATATAG CURRICULUM
Personalisation of Education by AI and Big Data - Lourdes Guàrdia
Personalisation of Education by AI and Big Data - Lourdes Guàrdia
UChicago CMSC 23320 - The Best Commit Messages of 2024
UChicago CMSC 23320 - The Best Commit Messages of 2024
8 Tips for Effective Working Capital Management
8 Tips for Effective Working Capital Management
SPLICE Working Group:Reusable Code Examples
SPLICE Working Group:Reusable Code Examples
Andreas Schleicher presents at the launch of What does child empowerment mean...
Andreas Schleicher presents at the launch of What does child empowerment mean...
How to Manage Website in Odoo 17 Studio App.pptx
How to Manage Website in Odoo 17 Studio App.pptx
will updateSolutionwill update.pdf
1.
will update Solution will update
Download now