HERE ARE THE PROBLEMS SETS PRESENT ON THE SQL QUERY SOLVE USING THE ORACLE DATABASE

1. SQL> INSERT INTO PRODUCT VALUES(1,'MANGO',60,5);
1 row created.
SQL> INSERT INTO PRODUCT VALUES (2,'APPLE',100,10)
2 ;
1 row created.
SQL> INSERT INTO PRODUCT VALUES (3,'PENEAPPLE',50,NULL);
1 row created.
SQL> INSERT INTO PRODUCT VALUES (4,'BANANA',40,NULL);
1 row created.
SQL> SELECT * FROM PRODUCT;
PID PNAME PRICE DISCOUNT
---------- ---------- ---------- ----------
1 MANGO 60 5
2 APPLE 100 10
3 PENEAPPLE 50
4 BANANA 40
================================================================================
=
SQL> INSERT INTO PRODUCT (PID,PNAME,PRICE,DISCOUNT)
2 VALUES (5,'CHERRY',80,8);
1 row created.
================================================================================
==
SQL> ;
1 INSERT INTO PRODUCT (PID,PNAME,PRICE,DISCOUNT)
2* VALUES(&PID,&PNAME,&PRICE,&DISCOUNT)
SQL> /
Enter value for pid: 6
Enter value for pname: 'ORANGE'
Enter value for price: 80
Enter value for discount: 20
old 2: VALUES(&PID,&PNAME,&PRICE,&DISCOUNT)
new 2: VALUES(6,'ORANGE',80,20)
1 row created.
SQL> ED
Wrote file afiedt.buf
1 INSERT INTO PRODUCT (PID,PNAME,PRICE,DISCOUNT)
2* VALUES(&PID,&PNAME,&PRICE,&DISCOUNT)
SQL> /
Enter value for pid: 7
Enter value for pname: 'ORANGE'
Enter value for price: 80
Enter value for discount: 20
old 2: VALUES(&PID,&PNAME,&PRICE,&DISCOUNT)
new 2: VALUES(7,'ORANGE',80,20)
1 row created.

2. SQL>
SQL> SELECT * FROM PRODUCT;
PID PNAME PRICE DISCOUNT
---------- ---------- ---------- ----------
1 MANGO 60 5
2 APPLE 100 10
3 PENEAPPLE 50
4 BANANA 40
5 CHERRY 80 8
6 ORANGE 80 20
7 ORANGE 80 20
7 rows selected.
================================================================================
===========
SQL> UPDATE PRODUCT SET PNAME = 'GRAPES',PRICE=60,DISCOUNT= NULL
2 WHERE PID=7;
1 row updated.
SQL> SELECT * FROM PRODUCT;
PID PNAME PRICE DISCOUNT
---------- ---------- ---------- ----------
1 MANGO 60 5
2 APPLE 100 10
3 PENEAPPLE 50
4 BANANA 40
5 CHERRY 80 8
6 ORANGE 80 20
7 GRAPES 60
7 rows selected.