1. Clifford and Alvin: Don’t Lose Your Marbles
Lloyd has one less than 4 times Eli’s marbles and 5 times Akim's marbles.
So, let Lloyd be l, Eli be e and Akim be a.
Lloyd has one less than 4, so l +1 = 4e = 5a.
To find out the MINIMUM of L’s marbles, we search for the LCM of 4 and 5 to get 20.
So l + 1 = 20, and l = 19.
Lloyd’s minimum amount of marbles is 19.