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UNIT: - II
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UNIT: - II
QTBD
I MBA I SEM
QISET COLLEGE
@ K.V.RAMESHBABU
ASSISTANT PROFESSOR IN STATISTICS
QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 2
Decision theory
“Decision making” is an ‘integral part’ of
1. Management planning
2. Organizing
3. Controlling
4. Motivation process
The “Decision maker” selects one strategy (course of action) over others
depending on some criteria like utility, sales, cost or rate of return
The specific combination of ‘goals’ is not entirely depending on the
decision-maker i.e. the value of system is usually modified to other
interested groups, like stock holders, employers, unions, creditors,
government etc
Definition:-
“Decision theory” provides a method for rational ‘decision- making’ when
the consequences are not fully “deterministic” Decision maker has to apply
various methods to decision problems.
The ‘Decision theory’ identifies the best alternative or course of action for
specific ‘activity’
The Decision theory provides a frame work for better understanding of the
decision situation and for evaluating alternatives, when the alternatives criteria
are not defined
The relationship between ‘decision theory’ and ‘decision making’ can be
represented in the following diagram
Define theDefine the problems
Search for Alternatives
Evaluate Alternatives
Abstraction
Decision Theory
Asses Consequences
Apply Decision CriteriaSelect an Alternative
QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 3
Decision:-
If a “decision” is to be made on the basis of one of the “decision criteria”
then the selection of an alternative course of action is a direct effect of “decision
theory” But, if alternative course of actions is compared with the
considerations other than so called “pure criteria” then the “decision theory”
helps us in the evaluation of alternatives.
Types of decisions:-
In general decisions can be classified into 3 categories
1. Strategic decisions
2. Administrative decision
3. Operating decision
1. Strategic decisions:-
These decisions are concerned with external environment of the
organization
Example:- Decision of selection of product-mix which a firm will produce and
the markets to which it with sell are under strategic decisions
2. Administrative decisions:-
This is concerned with structuring and accusation of the organization
resources, so as to optimize the performance of the organization
Example: - 1. Selection of distribution 2. Location of facilities
3. Operating Decision :-
This is the primary concerned with ‘day-to-day’ operations of the
organization
Examples: - 1. Pricing 2.Production scheduling 3. Inventory levels etc
Components of Decision Making:-
Various components of the problem which a problem person should
know are briefly discussed as follows
1. The decision maker
2. Objectives
3. The system or environment
QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 4
4. Alternative course of action
5. Choices
1. Decision Maker (or) Policy-Maker (or) Executive:-
Most obvious component is the fact that someone belonging ‘some group’
must have ‘some problem’ this individual or group is dissatisfied with some
aspect of the state of affairs and consequently wants to make a decision with
regarding to altering it, which is known as ‘decision maker’ if the ‘decision
maker’ controls the operations of an organized system of men or machines then
he is referred to as “policy maker” or “executive”.
2. Objectives
In order to have a problem the “decision maker” he must know
something other than what he has i.e. he must have some objectives which he
has not obtained to the degree he desires
3. System (or) environment:-
The ‘decision maker’ has the problem in an environment or setting that
constraints or lacks various resources
“Environment” is an “organized system” usually embracing machines as
well as man
4. Alternative Course of Action:-
A problem cannot exist unless the ‘decision maker’ has a choice from
among at least 2 alternative courses of ‘action or policies’ A problem always
involved a question what to do this question becomes a problem only when
alternative courses of action are available
 Decision Models
One of the primary functions of management is to make decisions
that determine the future course of action for the organization involving short
term or long-term consequences
Decision models are classified into various categories, depending upon
their nature and complexity, such as allocation so as to optimize the given
objective function subject to certain restrictions
QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 5
I. Goals to be achieved:-
The objective which the decision maker wants to achieve by his
action
II. The Decision-Maker:-
The decision-maker refers to an individual or a group of
individuals responsible for making a choice of an appropriate course of
action amongst the available course of action
III. Course of Action (or) Decision- Alternatives:-
For a specified problem all possible course of action should be included the number of
possible courses of action may be large or small but these are under control of
decision-maker
Example: - A course of action has a numerical description such as stocking of 150
units of a particular item or non-numerical description.
IV. States of Action:-
Before applying decision theory we must develop an exhaustive list of
possible future events. Forever decision maker has no direct control over the
occurrence of particular event such future events are referred to as “states of nature”
and it is assumed but these are mutually exclusive collectively exhaustive
Examples:- the state of nature can be a numerical description such as demand of
some units of a given item or a non- numerical description like employeesstrike.
V. Preference (or) Value System
This refers to the criteria that the decision maker uses in making a choice of the best
course of action. It could include maximization of income utility profit etc.
VI. Pay of (or)Profit (or)Conditional Value
It is the effectiveness associated with specified with combination of a course of action
and state of nature. These are also known as profit or conditional value.
Example: -The conditional profit can also be of Rs 15 associated with the action of
stocking 20units of an item when the outcome is a demand of 17 units of that item.
costs can be considered as negative profits.
VII. Opportunity Loss Table :-Opportunity loss is incurred due to failure of not
adopting most favorable course of action or strategy the opportunity los values
are determined separately for each state of nature or outcome by 1stfinding the
most favorable course of action for that state for nature or outcome. And then
QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 6
taking the difference between pay off value for given course of action and the
payoff value for the best possible course of action which would be chosen.
VIII. Pay off Table
For a problem a payoff table exists the states of nature which are
mutually exclusive and collectively exhaustive and as set of given courses of
action (strategies). For each combination of state of nature and course of action
the payoff is determined
Course of Action
States of
Nature
𝑆1 𝑆2 ………… 𝑆𝑗 ………… 𝑆 𝑛
𝑂1 𝑎11 𝑎12 ………… 𝑎1𝑗 ………… 𝑎1𝑛
𝑂2 𝑎21 𝑎22 ………… 𝑎2𝑗 ………… 𝑎2𝑛
:
:
:
:
:
:
………… :
:
…………
𝑂𝑖 𝑎 𝑖1 𝑎 𝑖2 ………… 𝑎 𝑖𝑗 ………… 𝑎 𝑖𝑛
:
:
:
:
:
:
………… :
:
………… :
:
𝑂 𝑚 𝑎 𝑚1 𝑎 𝑚2 ………… 𝑎 𝑚𝑗 ………… 𝑎 𝑚𝑛
The weighted profit associated with the given combination of state of nature and
course of action is obtained by multiplying the payoff the state of nature and
course of action by the probability of occurrence of the specified state of nature
The table shown in the above is one such type of pay off table in this
table ‘m’ states of nature and denoted by O, O2 … Om with respect to ‘n’ course of
action S1 S2 …. Sn for a specified combination of state of nature and course of
action the corresponding payoff is represented by ai j.
Types of Environment
Decision theory helps the decision maker in selecting the best course of
action from the available course of action. The decision models are classified such that
the type of information which is given about the occurrence of the various state of
nature as well as depending upon the decision environment basically there are 4
different states of decision environment
i. Decision making under certainty
ii. Decision making under un-certainty
iii. Decision making under risk
iv. Decision making under conflict
QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 7
I. Decision Making Under Certainty
This is all easiest form of ‘decision making’ the outcome resulting from
the selecting of a particular course of action given with certainty. There is just one
state of nature for each course of action and has probability ‘I’ we are given
complete and accurate knowledge of the consequence of each choice. Since the
decision maker has perfect knowledge of the future and the outcome, he simply
selects that course of action for which the payoff is optimum
Example
The analysis of cost profit and volume is a “decision problem under
certainty”
Where the information regarding costs and profits is given with respect to volume of
sales. Similarly in L.P.P the amount of resources required and the corresponding unit
profit (cost) is given with certainty the other techniques used for solving problems
under certainty are
I. Input –output analysis
II. Break- even analysis
III. Goal programming
IV. Transportation and assignment methods
V. Inventory models
1. Decision Making Under Uncertainty:-
In the absence of knowledge about the probability of any state of nature
occurring, the decision maker must arrive at a decision only on the actual conditional
pay off values, together with a policy. There are several different criteria of decision-
making in this situations
Types of criteria
1. Optimism criterion or maximum criterion or minimum criterion
2. Pessimism criterion or maximum criterion or minimum criterion
3. Laplace criterion or equal probabilities criterion
4. Hurwitz criterion or coefficient of optimism
5. Regret criterion or salvage criterion
1. Optimism Criterion:-
In this criterion the decision-maker ensures that he should not miss
the opportunity to achieve the largest possible profit (maximum) or the lowest possible
QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 8
cost (minimum). Thus, he selects the alternative that represents the maximum of the
maximum payoff. The working method is summarized as follows.
Step-1 locate the maximum (minimum) payoff values corresponding to each
alternative
Step-2 Select an alternative with best anticipated payoff value (maximum for profit)
and minimum for cost)
Since in this criterion the decision-maker selects an alternative with largest (or
lowest) possible payoff value, It is also called an “optimistic decision criterion”
2. Pessimism Criterion
In this criterion the decision-maker ensures that he would earn no less
than some specified amount. Thus, he selects the alternative that represents the
maximum of the minimum payoff in the case of profits. The working method is
summarized as follows
Step-1 Locate the minimum (or maximum in the case of profit). Payoff value in the
case of loss data corresponding to each alternative.
Step-2 Select an alternative with the best anticipated pay off value (maximum for
profit and minimum for loss)
Since in this criterion the “decision –maker” is conservative about the
future and always anticipates the “worst possible” outcome. Then it is called a
“pessimistic decision criterion”. This criterionis also known as “wald’s criterion”
3. Laplace Criterion
Since the probabilities of states of nature are not known, it is assumed that all states
of a nature will occur with equal probability .i.e. each state of nature is assigned an
equal probability. As states of nature are mutually exclusive and collectively
exhaustive, so the probability of each of these must be
1
(𝑛𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑠𝑡𝑎𝑡𝑒𝑠 𝑜𝑓 𝑛𝑎𝑡𝑢𝑟𝑒)
the
working method is summarized as follows.
Step-1 Assign equal probability value to each state of nature by using formula
1
(𝑛𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑠𝑡𝑎𝑡𝑒𝑠 𝑜𝑓 𝑛𝑎𝑡𝑢𝑟𝑒)
Step -2 Compute the expected (average) pay off for each alternative by adding all the
payoffs and dividing by the number of possible states of nature by applying the
formula ⟹ ( Probability of state of nature ) X
(Payoff value for the combinations of alternative ‘i’ and state of nature ‘j’)
QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 9
Step-3 Select the best expected pay off value (maximum for profit and minimum for
cost)
This criterion is also known as the criterion of “insufficient reason” this is because
except in a few cases, some information of the likelihood of occurrence of states of
nature is available
4. Hurwitz Criterion:
This criterion suggest that a rational decision- maker should be neither
completely optimistic nor pessimistic and must display a mixture of both Hurwitz also
suggested this criterion, introduced the idea of a coefficient of optimism which is
denoted to measure the decision maker’s degree of optimism. This coefficient lies
between o & 1.
Where 0= A complete pessimistic attitude about the future
1= A complete optimisticattitude about the future
𝛼 = Coefficient of optimism attitude about the future
(1- 𝛼 )= Coefficient of pessimism
The Hurwitz approach suggests that the decision-maker must select alternative that
maximizes
H (Criterion of realism) = (maximum in column) + (1- 𝛼 )(minimum in column the
working method is summarized as follows.
Step-1 Decide the coefficient of optimism. And the coefficient of pessimism (1-𝛼 )
Step-2 For each alternative select the largest and lowest pay off value and multiply
these with and (1-𝛼 ) values respectively. Thencalculate the weighted average H by
using above formula
Step-3 Select the course of action with the smallest anticipated opportunity loss value
Step-3 Select an alternative with best anticipated weighted average payoff value.
5. Regret Criterion
This criterion is also known as opportunity loss decision” criterion or
“Minimax Regret decision” criterion. This is because decision- making regretsthe fact
that he adopted a wrong course of action resulting in an opportunity loss of payoff.
Thus, he always intends to minimize this regret the working method is summarized as
follows
QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 10
Step-1 From the given payoff matrix, developan opportunity loss matrix as follows
1. Find the best pay off corresponding to each sate of nature
2. Subtract all other entriesin that row form this value
Step-2 For each course of action identify the worst or maximum regret value record
this number in a new row
Step -3 Select the course of action with the smallest anticipated opportunity loss
value
Problems on – Decision Making Under Uncertainty
Problem -1
A food products company is contemplating the introducing of a revolutionarynew
product with new packaging or replacing the existing product at much higher price
(s1). It may even make a moderate change in the composition of the existing product,
with a new packaging at a small increase in price (s2) or may be a small change in the
composition of the existing product, backing it with the word “new” and a negligible
increase in price (S3) the 3 possible states of nature or events are high increase in
sales (N1), No change in sales(N2), Decrease in sales (N3)
The marketing department of the company worked out of payoffs in terms of yearly net
profits for each of the strategies of ‘3’ eventsthis is presented in the following table
States of nature strategies
N1 N2 N3
S1
S2
S3
7,00,000
5,00,000
3,00,000
3,00,000
4,50,000
3,00,000
1,50,000
0
3,00,000
Which strategy should the concerned executive choose on the basis of
I. Maximum criterion
II. Maximax criterion
III. Minimax criterion
IV. Laplace criterion
QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 11
Solution
The payoff matrix is rewritten as follows
a) Maximin criterion or (pessimistic criterion)
States of nature strategies
S1 S2 S3
N1
N2
N3
7,00,000
3,00,000
1,50,000
5,00,000
4,50,000
0
3,00,000
3,00,000
3,00,000
Column Minimum
1,50,000 0 3,00,000
The maximum of column minima is 3,00,000. Hence, the company should adopt
strategy S3
b) Maximax criterion or (optimistic criterion)
States of nature Strategies
S1 S2 S3
N
N
N
7,00,000
3,00,000
1,50,000
5,00,000
4,50,000
0
3,00,000
3,00,000
3,00,000
Column maximum 7,00,000 5,00,000 3,00,000
The maximum of column maxima is 7, 00,000. Hence the company should adopt
strategy S1
QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 12
C) Minimax Regret Criterion or (Regret Criterion :
States of
nature
Strategies
S1 S2 S3
N1 7,00,000-7,00,000=0 7,00,000-5,00,000= 2,00,000 7,00,000-
3,00,000=4,00,000
N2 4,50,000-
3,00,000=1,50,000
4,50,000-4,50,000=0 4,50,000-
3,00,000=1,50,000
N3 3,00,000-
1,50,000=1,50,000
3,00,000-0=3,00,000 3,00,000-
3,00,000=4,00,000
Column
maximum
1,50,000 3,00,000 4,00,000
Hence the company should adopt minimum opportunity loss strategy of ‘S1’
D) Laplace Criterion or (Equal Probability Criterion):
Since we do not know the probabilities of states of nature, assume that they
are equal. For example we should assume that state of nature has probability
1
3
of
occurrence. Thus
Strategy Expected return (Rs)
S1 (7,00,000+3,00,000+1,50,000)/3 = 3,83,333.33
S2 (5,00,000+4,50,000+0)/3 = 3,16,666.66
S3 (3,00,000+3,00,000+3,00,000)/3 = 3,00,000
Since the largest expected return is from strategy S1 then the executive most select
strategy S1
QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 13
Conclusion:-
1. Maximin criterion is strategy S3 ( pessimistic criterion)
2. Maximax criterion is strategy S1 ( optimistic criterion )
3. Minimax criterion is strategy S1 (regret criterion)
4. Laplace criterion is strategy S1 ( equal probability criterion)
Problem-2
A manufacturer manufactures a product, of which the principal ingredient is a
chemical ‘X’. At the moment the manufacturer spends Rs 1,000/- per year on supply
of ‘X’ but there is a possibility that the price may soon increase to ‘4’ time it’s another
chemical ‘Y’ which the manufacturer could use in conjunction with a 3rd chemical Z,
in order to give the same effect as chemical ‘X’ chemicals Y and Z would together cost
the manufacturer Rs 3,000 for year, but their pricesare unlikely to rise. What action
should the manufacturer taken? Apply the maximin and minimax criteria for decision-
making and give ‘2’ sets of solution. If the coefficient of optimism is 0.4, then find the
course of action that minimizesthe cost
Solution :-
The data of the problem is summarized in the following table
States of nature Courses of action
S1 ( use Y and Z) S2 ( use X)
N1 ( price of X increases) -3,000 -4,000
N2 ( price of X does not
increase )
-3,000 -1,000
1. Maximin Criterion or ( Pessimistic Criterion):
States of nature Courses of action
S1 S2
N1
N2
-3,000
-3,000
-4,000
-1,000
Column minimum -3,000 -4,000
The maximum of column minimum is -3,000. Hence the manufacture should adopt
the action ‘S1’
QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 14
2. Minmax Criterion or ( Pessimistic Criterion )
States of nature Course of action
S1 S2
N1
N2
-3,000-(-3,000)=0
-1,000-(-3,000)= 2,000
-3,000-(-4,000) =1,000
-1,000-(-1,000)=0
Maximum opportunity 2,000 1,000
Hence, manufacturer should adopt minimum opportunity less course of action
3. Hurnicz criterion or ( Coefficient of Optimistic)
Given that coefficient of optimism = = 0.4
Coefficient of pessimism = (1- 𝛼 ) = 1-0.4=0.6
Then according to Hurwitz, select course of action that optimizes (maximum for
profit and minimum for loss) the payoff value.
H= (best pay off) + (1- 𝛼 ) (Worst payoff)
= (maximum in column) + (1- 𝛼 ) (minimum in column)
States of nature Courses of action
S1 S2
N1 -3,000 -4,000
N 2 -3,000 -1,000
Column maximum -3,000 -1,000
Column minimum -3,000 -4,000
QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 15
Course of action Best payoff Worst pay off H= 0.4 (best payoff) +0.6 (worst
payoff)
S1 -3,000 -3,000 = 0.4 (-3,000) +0.6 (-3,000) = (1200)
–(1800)= - (3,000)
S2 -1,000 -4,000 = 0.4 (-1000) +0.6 (-4,000) = - 400-
2400= - (2800)
Since course of action S2 has the least cost (maximum profit) = Rs 2,800. The
manufacturer should adopt strategy ‘S2’
I. Decision Making – Under Certainty
Decision Tree Analysis Problems
Problem-1
You are given the following estimates concerning a and development programmer
Decision Di
Probability of
decision (Di)
given (R) P
(Di/R)
Outcome Probability of
given research
(R) P(Xi/Di)
Pay off value of
outcome Xi (Rs’
000)
Develop
0.5
1 0.6 600
2 0.3 -100
3 0.1 0
Do not develop
0.5
1 0.0 600
2 0.0 -100
3 1.0 0
QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 16
P(x3/D2)
Construct and evaluate the decision tree diagram for the above data. Show working for
evaluation
Solution The “decision tree” of the given problem along with necessary calculations is
shown in the following diagram
2
3
4
5
6
7
8
D1
Develop
Do not
develop
D2
=0.6
P(x2/di)
0.3
D(x3/Di)
=0.1
P(xi/D2)
=0
D(x2/D2)
=0
P (xi/di)
1
=1.0
QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 17
Probability Pay off in (Rs’ 000) Expected pay off (in Rs’ 000)
0.5 x 0.6 =0.3
0.5 x 0.3= 0.15
0.5 x0.1= 0.05
600
-100
0
=0.3 x 600= 180
=0.15 x -100=-15
=0.05 x 0=0
Total 165
0.5 x 0= 0
0.5 x 0 = 0
0.5 x 1.0= 0.05
600
-100
0
=0 x 600 =0
= 0 x (-100) =0
=(0.05) x 0 = 0
Total 0
Problem -2
A businessman has 2 independent investment portfolios A and B available to him,
but he lacks the capital to undertake both of them simultaneously. He can either
choose a first and then stop, or if A is not successful, then take.B or vice versa the
probability of success of A is 0.6 white for B it is 0.4. Both investment schemes require
are initial capital outlay of Rs 10,000 and both return nothing if the venture process to
unsuccessful.Successful completion of A will returnRs 20,000 and Successful
completion of B will return Rs 24,000 Draw a decision tree in order to determine the
best strategy.
Solution: - The decision tree corresponding to the given information is as followed
QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 18
DECISION POINT OUT COME PROBABILITY CONDITIONAL
VALUE (RS/-)
EXCEPTED VALUE
𝑫 𝟑
1.ACCPT A
SUCCESS/
FAILURE
0.6
0.4
23,000/-
-10,000/-
12,000/-
-4,000
8,000
2.STOP 0
𝑫 𝟐
1.ACCEPT B
SUCCESS/
FAILURE
0.4
0.6
24,000/-
-10,000/-
9,600/-
-6,000/-
3,6000/-
2.STOP 0
𝑫 𝟏
1.ACCPT A
SUCCESS/
FAILURE
0.6
0.4
20,000+3,600 =
23600 × (0.6)
-10,000× (0.4)
14,160
-4,000
10,160
2.ACCEPT B SUCCESS/
FAILURE
0.4
0.6
24000+8000=
32000 ×(0.4)
-10,000 ×(0.6)
12800
-6,000
6,800
QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 19
(0.6) EMV=3600 SUCCESS
EMV =10,160 0.6 FAILURE
RS/10,000
EMV=6,800 RS/-24000 ACCEPT A
SUCCESS
RS/-0
4. Decision – Making with Utilities
The previous problems were analyzed with probabilistic statesof nature,
where the selection of an optimal course of action was on the criterion of expected
profit (loss) expressed in monetary terms
However,in many situations such criterion that involves expected
monetary payoff may not be appropriate. This is because of the fact that different
individuals attachdifferent utility to money, under different conditions.
D1
1
D2
3
4
8
9
5
2
D3
6
7
10
11
12
ACCEPT A
SUCCES
S
Rs/- 3600
0.4
STOP
RS/-0
RS/-20,000
ACCEPT
B
FAILUR
E
RS/-10,000
0.4×24,000=9600
0.6 × -10,000 =-6,000
ACCEPTB
FAILURE
(0.4)
RS/-8000
EMV=8000
SUCCESS (0.6)
FAILURE (0.4)
RS/-20000
-19000
0.6 × 20,000=12,000
0.4 × -10,000 = -4000
QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 20
The term utility is the “measure of preference”for various alternativesin terms
money. The utility of a given alternative is unique to the individual decision- maker
and unlike a simple monetary amount, can incorporate intangible factorsor
subjective standards form their own value system.
Example
Mr. Ran has won Rs 1,000 in a quiz programme. In the last round he is asked
either to complete or quit now he has alternatives.
Quit and take his winnings
Take a least chance in which he has 50.50 chance of winning Rs 4,000 or nothing
The question now is: what should he do? On EMV basis he has
EMV (b) =0.50 (4,000) + 0.50 (0) = Rs 2,000
The amount is twice what he was already won. But would he really give up Rs
1,000 for 50-50 chance or Rs 4,000 or nothing? Many individuals would not
because they would think of all the alternatives they could do with Rs 1,000 and
how they would regret it if they end up with nothing hence a new payoff measure
utility reflecting the decision- makers attitude and preference has to be introduced.
The basis axioms of utility may be stated as follows.
1. If outcome A is proffered to outcome B, they the utility U(A) of outcome A is
greater than the utility u(B) of outcome B vice versa
If both are equally proffered thenu(A) = u(B)
2. If the decision-maker is different between the ‘2’ alternatives and outcome ‘A’ is
received with probability P1 and outcome C with probability (1-P) then
U (B) = P [U (A)] + (1-P) [U/C)]
Under this alternative criterion, it is assumed that a rational decision-maker
will choose that alternative which optimize the “expected utility” rather than
expected monetary value. Once we know that individual’s utility function,along
with the probability assigned to outcome in a particular situation then the total
expected utilityfor each course of action can be obtained by multiplying the
utility values with their probabilities the strategy that corresponds to the
optimum utility function is called that equal strategy”
Utility function
“Utility function” is a formula or method that is used to describe the
relative preference value that individualshave for a given criterion such as money,
goods etc.
QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 21
Once derive, a “utility function”can be used to convert a decision criteria value into
utilities so that a decision can be made on the bass of maximizing the expected “utility
value” (EUV) rather than, say the “EMV”
Example
Preference are oftendetermined by proposing a situation where by decision- maker
must choose between receiving a given amount, say Rs 20,000 for a certain thing
versus a 50-50 chance of gambling a larger amount or nothing say Rs 60,000 or Zero.
The gamble amount of Rs 60,000 is then adjusted upward or down ward until the
individual is indifferent to whether decision – maker receivesthe certainamount of Rs
20,000 or the gamble
Utility Curve
A utility curve that relates utility valuesto rupee value is construction such a curve
is usually obtained by placing the decisionmaker in various hypothetical decision
situations and plotting the decision makers pattern of choices in terms of risk and
utilities.
Suppose the relationshipbetween monetary gains,losses and utilities for gains and
for small negative lossesis established. The following diagram shows that if the curve
is bent down non- linearly thenwe assign,to large lossesa disproportionately large
negative utility. It is important not to make the curve bend down too steeply or to start
the bending too quickly since this could lead individualsinto a situation where they
attach such a heavy to the possibility of loss they never take any risk and tell us never
masse any gains
Once the +ve side of the curve, it is usual for the curve to eventually
bend away from the straight line. This indicates that increasingunits of money are
resulting in smaller additional gainsin utility
𝑈 𝑀𝐴𝑋
RISK AVERSION (AVOIDERS)
UTILITY RISK INDIFFERENCE (NEUTRALITY)
RISK AFFINITY (SEEKERS)
MONEY RS/- MAX
QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 22
Problem 1
A manager must choose between 2 investmentsA&B that are calculated to yield net
profit of Rs 1,200 and Rs 1,600 respectively.With probabilities subjectively estimated
at 0.75 and 0.60. Assume the manager’s utility function revealsthat utilities for Rs
1,200 and Rs 1,600 are 45 and 50 units respectively what is the best choice on the
basis of the expected utility value (EUV)?
Solution
The except utility value (EUV) is expressed as
EUV = ∑ 𝑢𝑖
𝑚
𝑖=1 𝑝𝑖 where 𝑢𝑖 = utility value of state of nature i
𝑝𝑖 = probability value of state of nature i
EUV (A) = (𝑈𝐴 ) (𝑝 𝐴) = (0.75) (45) =33.75 = EUV (A) =33.75 utilities
EUV (B) = (𝑈 𝐵) (𝑝 𝐵) = (0.60) (50) =30.00 = EUV (B) =30 utilities ⟹ 30< 33.75
Since EUV (A) > EUV (B)
The best choice is investment “A”
Problem 2
Mr. X has an after –tax annual of Rs 90,000 and is considering to buy accident
insurance for his car. The probability of accident during the year is 0% (Assume that
at most one accident will occur) in which case the damage to the car will be Rs 11,600
which a utility function U(x)=√ 𝑥 ,what is the insurance premium he will be willing to
pay?
Solution: Let A = Venture whenMr. X does not buy the accident insurance for his
car. Then in that case of accident he would spend Rs. 11,600 on damages and will be
left with Rs. 78,400. In the case for no accident he retainsRs. 90,000. Then we have
𝑈𝐴 = (𝑈78,400 X 0.1) + (𝑈90,000 X 0.9) →1
U (x) = 𝑈 𝑋 = √ 𝑋 →2
𝑈78,400 = √78,400 = 280 utilities→ 3 𝑈90,000 = √90,000 = 300 utilities→ 4
𝑈𝐴 = (280 X 0.1) + (300 X 0.9) = 298 utilities → 5
QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 23
So the amount Rs. X which will give the same utility of the venture
A = (298)2 = Rs. 88,804 [∵ U (x) = √ 𝑋 ⟹X = [ U (x) ]2 ]
Thus Mr. X will be indifferent to an amount of Rs.88, 804 with certainty and the
venture A. The amount he is willing to pay as car premium would be
90,000 – 88,804 = Rs. 1,196
3) Decision Making Under Risk:
Decision making under risk is a probabilistic decision situation in which more
than one state of nature exists. And the decision maker has sufficient information to
assign probability values to the likely occurrence of each of these states. Knowing the
probability distribution of these states of nature, the best decision is to select that
course of action which has the largest expected payoff value.
The expected (average) payoff of an alternative is the sum of all possible payoffs of
that alternative, weight by the probabilities of the occurrence of those payoffs.
The most widely used criterion for evaluating various course of action (alternatives)
under risk is the “expected monetary value (EMV)” or “expected utility”
Expected Monetary Value (EMV)
The expected monetary value (EMV) for a given course of action is the
weighted sum of possible payoffs for each alternative. The expected value is the long-
run average value that would result if the decision were repeated a large number of
times. MathematicallyEMV is stated as follows.
EMV [ Course of avtion, Sj ] = ∑ 𝑝𝑖𝑗. 𝑃𝑖
𝑛
𝑖−1
Where m = number of possible statesof nature
Pi = probability of occurrence of nature, N:
Pij= payoff associated with state of nature Ni and course of action, Sj
Steps for calculating EMV
The various steps involved in the calculation of EMV are as follows
1. Construct of payoff matrix listing all possible courses of action and states of
nature. Enter the conditional payoff values associated with each possible
combination of courses of action and state of nature along with the probabilities
of the occurrence of each state of nature
QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 24
2. Calculate the EMV for each course of action by multiplying the conditional
payoff by the associated probabilities and adding these weighted valuesfor each
of action
3. Select the course of action that yields the optimal EMV
Expected Profit with Perfect Information (EPPI )
The expected profit with perfect information (EPPI) is the maximum
attainable expected money value (EMV) based on perfect information about the state of
nature that will occur. The expected profit with perfect information may be defined as
the sum of the product of best state of nature corresponding to each optimal course of
action and its probability
Expected Value of PerfectInformation ( EVPI)
The expected value of perfect information (EVPI) may now be defined as the maximum
amount one would be willing to pay to obtain perfect information about the state of
nature that would be willingto pay to obtain perfect information about the state of
nature that would occur. EMV Representsthe maximum attainable expected monetary
value given only the prior outcome probabilities with no information as to which state
of nature will actually occur. Therefore perfect information would increase profit from
EMV up to the value of EPPI. This increased amount is termed as EVPI.
i.e. EVPI= EPP1- EMV
Expected Opportunity Loss ( EOL):
Another useful way of maximizing monetary value is to minimize the expected loss
or expected value of regret.The conditional opportunity los (COL) or regret function for
a particular course of action is determined by taking the difference between payoff
values of the most favorable course of action. And some other course of action .Which
may be considered as loss due to loosing the opportunity of choosing the most
favorable course of action, thus opportunity loss can be obtained separately for each
course of action by 1St obtaining the best state of nature for the prescribed course of
action and then taking the difference betweenthat best outcome and each outcome for
those courses of action. The opportunity loss for each course of action is known as the
conditional opportunity loss
After calculating the opportunity loss value for each course of action,
the E0L for ith course of action Si is then computed by
EOL (S𝑖,) = ∑ 𝐶𝑂𝐿 (𝑛
𝑗=1 S𝑖,O𝑗). P (O𝑗)
QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 25
Where (S𝑖,O𝑗)= Conditional Opportunity loss associated with the course of action S𝑖
And state of nature O𝑗.
P (O𝑗 ) = Probability of occurrence of state of nature O𝑗.
In other words EOL denotesthe expected difference between the payoff of right
decision and the payoff of actual decision.
Problem-1
A modern home appliances dealer finds that the cost of holding a mini cooking
range is stock for a month is Rs 200 (Insurance,minor deterioration, interest on
borrowed capital, etc) customer who cannot obtain a working range immediately tends
to go to other dealer and he estimates that for every customer who cannot get
immediate delivery,he loses an average of Rs 500 the probabilities of a demand of
0,1,2,3,4,5 mini cooking rangesin a month are 0.05, 0.10, 0.20, 0.30, 0.20, 0.15
respectively determine the optimum stock level of consuming rangers. Also find EVPI
Solution:
The cost function =Rs 500(D-S); If D>S
= Rs 200 (S-D); If D < S
Where S= The number of units purchased and D= the number of units demanded.
QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 26
Since the expected cost is minimum if 4 cooking ranges are stocked each month.
The optimum act is to stock 4 looking ranges.
Problem -2
Under an employment promotion programming, it is proposed to allow sale of
newspapers on the buses during of peak hours. The vendor can purchase the
Event
Demanded
(D)
Probability Conditional Cost (Rs/-) (S) Expected Cost (Rs/-)
0 1 2 3 4 5 0 1 2 3 4 5
0 0.05 0 200 400 600 800 1000 0 10 20 30 40 50
1 0.10 500 0 200 400 600 800 50 0 20 40 60 80
2 0.20 1000 500 0 200 400 600 200 100 0 40 80 120
3 0.30 1500 1000 500 0 200 400 450 300 200 100 0 40
4 0.20 2000 1500 1000 500 0 200 400 300 200 100 0 40
5 0.15 2500 2000 1500 1000 500 0 375 300 225 150 7 50
Expected cost 1475 1010 615 360 315 410
QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 27
newspaper at a special concessional rate of 25 paisa per copy against the selling price
of 40 paise. Unsold copies are however a dead loss. A vendor has estimated the
following probability distribution for the number of copies demanded
No of copies demanded 15 16 17 18 19 20
Probability 0.04 0.19 0.33 0.26 0.11 0.07
How many copies should he order so that his expected profit will be maximum?
Solution:-
The vendor does not purchase less than 15 copies or more than 20 copies
Let n = The number of copies of newspaper demanded
The vendor would loss 25 paise on each copy in case of demand is less than ‘n’
otherwise , if the demand is more than or equal to ‘n’ then he would gain 15 paise on
each newspaper copy .
The incremental profit =( Excepted profit –Expected loss), for each value on ‘n’ is
given in the following table
QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 28
Expected profit
Demand (n) Probability
(<n)
Probability
(>n)
Expected
incremental
Profit (Rs-/)
Total profit
15 0.00 1.00 =0(0)+1(0.15)=0.15 0.15×15=2.25
16 0.04 0.96 =0.04
(-0.25)+0.96(0.15)=0.13
0.13×16=2.38
17 0.23 0.77 =0.23
(-0.25)+0.77(0.15)=0.06
0.06×17=2.44
18 0.56 0.44 =0.56
(-0.25)+0.44(0.15)=
(-0.07)
0.07×18=2.37
19 0.82 0.18 =0.82
(-0.25)+0.07(0.15)=
(-0.18)
0.18×19=2.19
20 0.93 0.07 =0.93
(-0.25)+0.07(0.15)=
(-0.22)
00.22× 20
=1.97

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UNIT II - DECISION THEORY - QTBD - I MBA - I SEM

  • 2. QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 2 Decision theory “Decision making” is an ‘integral part’ of 1. Management planning 2. Organizing 3. Controlling 4. Motivation process The “Decision maker” selects one strategy (course of action) over others depending on some criteria like utility, sales, cost or rate of return The specific combination of ‘goals’ is not entirely depending on the decision-maker i.e. the value of system is usually modified to other interested groups, like stock holders, employers, unions, creditors, government etc Definition:- “Decision theory” provides a method for rational ‘decision- making’ when the consequences are not fully “deterministic” Decision maker has to apply various methods to decision problems. The ‘Decision theory’ identifies the best alternative or course of action for specific ‘activity’ The Decision theory provides a frame work for better understanding of the decision situation and for evaluating alternatives, when the alternatives criteria are not defined The relationship between ‘decision theory’ and ‘decision making’ can be represented in the following diagram Define theDefine the problems Search for Alternatives Evaluate Alternatives Abstraction Decision Theory Asses Consequences Apply Decision CriteriaSelect an Alternative
  • 3. QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 3 Decision:- If a “decision” is to be made on the basis of one of the “decision criteria” then the selection of an alternative course of action is a direct effect of “decision theory” But, if alternative course of actions is compared with the considerations other than so called “pure criteria” then the “decision theory” helps us in the evaluation of alternatives. Types of decisions:- In general decisions can be classified into 3 categories 1. Strategic decisions 2. Administrative decision 3. Operating decision 1. Strategic decisions:- These decisions are concerned with external environment of the organization Example:- Decision of selection of product-mix which a firm will produce and the markets to which it with sell are under strategic decisions 2. Administrative decisions:- This is concerned with structuring and accusation of the organization resources, so as to optimize the performance of the organization Example: - 1. Selection of distribution 2. Location of facilities 3. Operating Decision :- This is the primary concerned with ‘day-to-day’ operations of the organization Examples: - 1. Pricing 2.Production scheduling 3. Inventory levels etc Components of Decision Making:- Various components of the problem which a problem person should know are briefly discussed as follows 1. The decision maker 2. Objectives 3. The system or environment
  • 4. QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 4 4. Alternative course of action 5. Choices 1. Decision Maker (or) Policy-Maker (or) Executive:- Most obvious component is the fact that someone belonging ‘some group’ must have ‘some problem’ this individual or group is dissatisfied with some aspect of the state of affairs and consequently wants to make a decision with regarding to altering it, which is known as ‘decision maker’ if the ‘decision maker’ controls the operations of an organized system of men or machines then he is referred to as “policy maker” or “executive”. 2. Objectives In order to have a problem the “decision maker” he must know something other than what he has i.e. he must have some objectives which he has not obtained to the degree he desires 3. System (or) environment:- The ‘decision maker’ has the problem in an environment or setting that constraints or lacks various resources “Environment” is an “organized system” usually embracing machines as well as man 4. Alternative Course of Action:- A problem cannot exist unless the ‘decision maker’ has a choice from among at least 2 alternative courses of ‘action or policies’ A problem always involved a question what to do this question becomes a problem only when alternative courses of action are available  Decision Models One of the primary functions of management is to make decisions that determine the future course of action for the organization involving short term or long-term consequences Decision models are classified into various categories, depending upon their nature and complexity, such as allocation so as to optimize the given objective function subject to certain restrictions
  • 5. QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 5 I. Goals to be achieved:- The objective which the decision maker wants to achieve by his action II. The Decision-Maker:- The decision-maker refers to an individual or a group of individuals responsible for making a choice of an appropriate course of action amongst the available course of action III. Course of Action (or) Decision- Alternatives:- For a specified problem all possible course of action should be included the number of possible courses of action may be large or small but these are under control of decision-maker Example: - A course of action has a numerical description such as stocking of 150 units of a particular item or non-numerical description. IV. States of Action:- Before applying decision theory we must develop an exhaustive list of possible future events. Forever decision maker has no direct control over the occurrence of particular event such future events are referred to as “states of nature” and it is assumed but these are mutually exclusive collectively exhaustive Examples:- the state of nature can be a numerical description such as demand of some units of a given item or a non- numerical description like employeesstrike. V. Preference (or) Value System This refers to the criteria that the decision maker uses in making a choice of the best course of action. It could include maximization of income utility profit etc. VI. Pay of (or)Profit (or)Conditional Value It is the effectiveness associated with specified with combination of a course of action and state of nature. These are also known as profit or conditional value. Example: -The conditional profit can also be of Rs 15 associated with the action of stocking 20units of an item when the outcome is a demand of 17 units of that item. costs can be considered as negative profits. VII. Opportunity Loss Table :-Opportunity loss is incurred due to failure of not adopting most favorable course of action or strategy the opportunity los values are determined separately for each state of nature or outcome by 1stfinding the most favorable course of action for that state for nature or outcome. And then
  • 6. QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 6 taking the difference between pay off value for given course of action and the payoff value for the best possible course of action which would be chosen. VIII. Pay off Table For a problem a payoff table exists the states of nature which are mutually exclusive and collectively exhaustive and as set of given courses of action (strategies). For each combination of state of nature and course of action the payoff is determined Course of Action States of Nature 𝑆1 𝑆2 ………… 𝑆𝑗 ………… 𝑆 𝑛 𝑂1 𝑎11 𝑎12 ………… 𝑎1𝑗 ………… 𝑎1𝑛 𝑂2 𝑎21 𝑎22 ………… 𝑎2𝑗 ………… 𝑎2𝑛 : : : : : : ………… : : ………… 𝑂𝑖 𝑎 𝑖1 𝑎 𝑖2 ………… 𝑎 𝑖𝑗 ………… 𝑎 𝑖𝑛 : : : : : : ………… : : ………… : : 𝑂 𝑚 𝑎 𝑚1 𝑎 𝑚2 ………… 𝑎 𝑚𝑗 ………… 𝑎 𝑚𝑛 The weighted profit associated with the given combination of state of nature and course of action is obtained by multiplying the payoff the state of nature and course of action by the probability of occurrence of the specified state of nature The table shown in the above is one such type of pay off table in this table ‘m’ states of nature and denoted by O, O2 … Om with respect to ‘n’ course of action S1 S2 …. Sn for a specified combination of state of nature and course of action the corresponding payoff is represented by ai j. Types of Environment Decision theory helps the decision maker in selecting the best course of action from the available course of action. The decision models are classified such that the type of information which is given about the occurrence of the various state of nature as well as depending upon the decision environment basically there are 4 different states of decision environment i. Decision making under certainty ii. Decision making under un-certainty iii. Decision making under risk iv. Decision making under conflict
  • 7. QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 7 I. Decision Making Under Certainty This is all easiest form of ‘decision making’ the outcome resulting from the selecting of a particular course of action given with certainty. There is just one state of nature for each course of action and has probability ‘I’ we are given complete and accurate knowledge of the consequence of each choice. Since the decision maker has perfect knowledge of the future and the outcome, he simply selects that course of action for which the payoff is optimum Example The analysis of cost profit and volume is a “decision problem under certainty” Where the information regarding costs and profits is given with respect to volume of sales. Similarly in L.P.P the amount of resources required and the corresponding unit profit (cost) is given with certainty the other techniques used for solving problems under certainty are I. Input –output analysis II. Break- even analysis III. Goal programming IV. Transportation and assignment methods V. Inventory models 1. Decision Making Under Uncertainty:- In the absence of knowledge about the probability of any state of nature occurring, the decision maker must arrive at a decision only on the actual conditional pay off values, together with a policy. There are several different criteria of decision- making in this situations Types of criteria 1. Optimism criterion or maximum criterion or minimum criterion 2. Pessimism criterion or maximum criterion or minimum criterion 3. Laplace criterion or equal probabilities criterion 4. Hurwitz criterion or coefficient of optimism 5. Regret criterion or salvage criterion 1. Optimism Criterion:- In this criterion the decision-maker ensures that he should not miss the opportunity to achieve the largest possible profit (maximum) or the lowest possible
  • 8. QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 8 cost (minimum). Thus, he selects the alternative that represents the maximum of the maximum payoff. The working method is summarized as follows. Step-1 locate the maximum (minimum) payoff values corresponding to each alternative Step-2 Select an alternative with best anticipated payoff value (maximum for profit) and minimum for cost) Since in this criterion the decision-maker selects an alternative with largest (or lowest) possible payoff value, It is also called an “optimistic decision criterion” 2. Pessimism Criterion In this criterion the decision-maker ensures that he would earn no less than some specified amount. Thus, he selects the alternative that represents the maximum of the minimum payoff in the case of profits. The working method is summarized as follows Step-1 Locate the minimum (or maximum in the case of profit). Payoff value in the case of loss data corresponding to each alternative. Step-2 Select an alternative with the best anticipated pay off value (maximum for profit and minimum for loss) Since in this criterion the “decision –maker” is conservative about the future and always anticipates the “worst possible” outcome. Then it is called a “pessimistic decision criterion”. This criterionis also known as “wald’s criterion” 3. Laplace Criterion Since the probabilities of states of nature are not known, it is assumed that all states of a nature will occur with equal probability .i.e. each state of nature is assigned an equal probability. As states of nature are mutually exclusive and collectively exhaustive, so the probability of each of these must be 1 (𝑛𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑠𝑡𝑎𝑡𝑒𝑠 𝑜𝑓 𝑛𝑎𝑡𝑢𝑟𝑒) the working method is summarized as follows. Step-1 Assign equal probability value to each state of nature by using formula 1 (𝑛𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑠𝑡𝑎𝑡𝑒𝑠 𝑜𝑓 𝑛𝑎𝑡𝑢𝑟𝑒) Step -2 Compute the expected (average) pay off for each alternative by adding all the payoffs and dividing by the number of possible states of nature by applying the formula ⟹ ( Probability of state of nature ) X (Payoff value for the combinations of alternative ‘i’ and state of nature ‘j’)
  • 9. QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 9 Step-3 Select the best expected pay off value (maximum for profit and minimum for cost) This criterion is also known as the criterion of “insufficient reason” this is because except in a few cases, some information of the likelihood of occurrence of states of nature is available 4. Hurwitz Criterion: This criterion suggest that a rational decision- maker should be neither completely optimistic nor pessimistic and must display a mixture of both Hurwitz also suggested this criterion, introduced the idea of a coefficient of optimism which is denoted to measure the decision maker’s degree of optimism. This coefficient lies between o & 1. Where 0= A complete pessimistic attitude about the future 1= A complete optimisticattitude about the future 𝛼 = Coefficient of optimism attitude about the future (1- 𝛼 )= Coefficient of pessimism The Hurwitz approach suggests that the decision-maker must select alternative that maximizes H (Criterion of realism) = (maximum in column) + (1- 𝛼 )(minimum in column the working method is summarized as follows. Step-1 Decide the coefficient of optimism. And the coefficient of pessimism (1-𝛼 ) Step-2 For each alternative select the largest and lowest pay off value and multiply these with and (1-𝛼 ) values respectively. Thencalculate the weighted average H by using above formula Step-3 Select the course of action with the smallest anticipated opportunity loss value Step-3 Select an alternative with best anticipated weighted average payoff value. 5. Regret Criterion This criterion is also known as opportunity loss decision” criterion or “Minimax Regret decision” criterion. This is because decision- making regretsthe fact that he adopted a wrong course of action resulting in an opportunity loss of payoff. Thus, he always intends to minimize this regret the working method is summarized as follows
  • 10. QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 10 Step-1 From the given payoff matrix, developan opportunity loss matrix as follows 1. Find the best pay off corresponding to each sate of nature 2. Subtract all other entriesin that row form this value Step-2 For each course of action identify the worst or maximum regret value record this number in a new row Step -3 Select the course of action with the smallest anticipated opportunity loss value Problems on – Decision Making Under Uncertainty Problem -1 A food products company is contemplating the introducing of a revolutionarynew product with new packaging or replacing the existing product at much higher price (s1). It may even make a moderate change in the composition of the existing product, with a new packaging at a small increase in price (s2) or may be a small change in the composition of the existing product, backing it with the word “new” and a negligible increase in price (S3) the 3 possible states of nature or events are high increase in sales (N1), No change in sales(N2), Decrease in sales (N3) The marketing department of the company worked out of payoffs in terms of yearly net profits for each of the strategies of ‘3’ eventsthis is presented in the following table States of nature strategies N1 N2 N3 S1 S2 S3 7,00,000 5,00,000 3,00,000 3,00,000 4,50,000 3,00,000 1,50,000 0 3,00,000 Which strategy should the concerned executive choose on the basis of I. Maximum criterion II. Maximax criterion III. Minimax criterion IV. Laplace criterion
  • 11. QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 11 Solution The payoff matrix is rewritten as follows a) Maximin criterion or (pessimistic criterion) States of nature strategies S1 S2 S3 N1 N2 N3 7,00,000 3,00,000 1,50,000 5,00,000 4,50,000 0 3,00,000 3,00,000 3,00,000 Column Minimum 1,50,000 0 3,00,000 The maximum of column minima is 3,00,000. Hence, the company should adopt strategy S3 b) Maximax criterion or (optimistic criterion) States of nature Strategies S1 S2 S3 N N N 7,00,000 3,00,000 1,50,000 5,00,000 4,50,000 0 3,00,000 3,00,000 3,00,000 Column maximum 7,00,000 5,00,000 3,00,000 The maximum of column maxima is 7, 00,000. Hence the company should adopt strategy S1
  • 12. QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 12 C) Minimax Regret Criterion or (Regret Criterion : States of nature Strategies S1 S2 S3 N1 7,00,000-7,00,000=0 7,00,000-5,00,000= 2,00,000 7,00,000- 3,00,000=4,00,000 N2 4,50,000- 3,00,000=1,50,000 4,50,000-4,50,000=0 4,50,000- 3,00,000=1,50,000 N3 3,00,000- 1,50,000=1,50,000 3,00,000-0=3,00,000 3,00,000- 3,00,000=4,00,000 Column maximum 1,50,000 3,00,000 4,00,000 Hence the company should adopt minimum opportunity loss strategy of ‘S1’ D) Laplace Criterion or (Equal Probability Criterion): Since we do not know the probabilities of states of nature, assume that they are equal. For example we should assume that state of nature has probability 1 3 of occurrence. Thus Strategy Expected return (Rs) S1 (7,00,000+3,00,000+1,50,000)/3 = 3,83,333.33 S2 (5,00,000+4,50,000+0)/3 = 3,16,666.66 S3 (3,00,000+3,00,000+3,00,000)/3 = 3,00,000 Since the largest expected return is from strategy S1 then the executive most select strategy S1
  • 13. QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 13 Conclusion:- 1. Maximin criterion is strategy S3 ( pessimistic criterion) 2. Maximax criterion is strategy S1 ( optimistic criterion ) 3. Minimax criterion is strategy S1 (regret criterion) 4. Laplace criterion is strategy S1 ( equal probability criterion) Problem-2 A manufacturer manufactures a product, of which the principal ingredient is a chemical ‘X’. At the moment the manufacturer spends Rs 1,000/- per year on supply of ‘X’ but there is a possibility that the price may soon increase to ‘4’ time it’s another chemical ‘Y’ which the manufacturer could use in conjunction with a 3rd chemical Z, in order to give the same effect as chemical ‘X’ chemicals Y and Z would together cost the manufacturer Rs 3,000 for year, but their pricesare unlikely to rise. What action should the manufacturer taken? Apply the maximin and minimax criteria for decision- making and give ‘2’ sets of solution. If the coefficient of optimism is 0.4, then find the course of action that minimizesthe cost Solution :- The data of the problem is summarized in the following table States of nature Courses of action S1 ( use Y and Z) S2 ( use X) N1 ( price of X increases) -3,000 -4,000 N2 ( price of X does not increase ) -3,000 -1,000 1. Maximin Criterion or ( Pessimistic Criterion): States of nature Courses of action S1 S2 N1 N2 -3,000 -3,000 -4,000 -1,000 Column minimum -3,000 -4,000 The maximum of column minimum is -3,000. Hence the manufacture should adopt the action ‘S1’
  • 14. QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 14 2. Minmax Criterion or ( Pessimistic Criterion ) States of nature Course of action S1 S2 N1 N2 -3,000-(-3,000)=0 -1,000-(-3,000)= 2,000 -3,000-(-4,000) =1,000 -1,000-(-1,000)=0 Maximum opportunity 2,000 1,000 Hence, manufacturer should adopt minimum opportunity less course of action 3. Hurnicz criterion or ( Coefficient of Optimistic) Given that coefficient of optimism = = 0.4 Coefficient of pessimism = (1- 𝛼 ) = 1-0.4=0.6 Then according to Hurwitz, select course of action that optimizes (maximum for profit and minimum for loss) the payoff value. H= (best pay off) + (1- 𝛼 ) (Worst payoff) = (maximum in column) + (1- 𝛼 ) (minimum in column) States of nature Courses of action S1 S2 N1 -3,000 -4,000 N 2 -3,000 -1,000 Column maximum -3,000 -1,000 Column minimum -3,000 -4,000
  • 15. QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 15 Course of action Best payoff Worst pay off H= 0.4 (best payoff) +0.6 (worst payoff) S1 -3,000 -3,000 = 0.4 (-3,000) +0.6 (-3,000) = (1200) –(1800)= - (3,000) S2 -1,000 -4,000 = 0.4 (-1000) +0.6 (-4,000) = - 400- 2400= - (2800) Since course of action S2 has the least cost (maximum profit) = Rs 2,800. The manufacturer should adopt strategy ‘S2’ I. Decision Making – Under Certainty Decision Tree Analysis Problems Problem-1 You are given the following estimates concerning a and development programmer Decision Di Probability of decision (Di) given (R) P (Di/R) Outcome Probability of given research (R) P(Xi/Di) Pay off value of outcome Xi (Rs’ 000) Develop 0.5 1 0.6 600 2 0.3 -100 3 0.1 0 Do not develop 0.5 1 0.0 600 2 0.0 -100 3 1.0 0
  • 16. QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 16 P(x3/D2) Construct and evaluate the decision tree diagram for the above data. Show working for evaluation Solution The “decision tree” of the given problem along with necessary calculations is shown in the following diagram 2 3 4 5 6 7 8 D1 Develop Do not develop D2 =0.6 P(x2/di) 0.3 D(x3/Di) =0.1 P(xi/D2) =0 D(x2/D2) =0 P (xi/di) 1 =1.0
  • 17. QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 17 Probability Pay off in (Rs’ 000) Expected pay off (in Rs’ 000) 0.5 x 0.6 =0.3 0.5 x 0.3= 0.15 0.5 x0.1= 0.05 600 -100 0 =0.3 x 600= 180 =0.15 x -100=-15 =0.05 x 0=0 Total 165 0.5 x 0= 0 0.5 x 0 = 0 0.5 x 1.0= 0.05 600 -100 0 =0 x 600 =0 = 0 x (-100) =0 =(0.05) x 0 = 0 Total 0 Problem -2 A businessman has 2 independent investment portfolios A and B available to him, but he lacks the capital to undertake both of them simultaneously. He can either choose a first and then stop, or if A is not successful, then take.B or vice versa the probability of success of A is 0.6 white for B it is 0.4. Both investment schemes require are initial capital outlay of Rs 10,000 and both return nothing if the venture process to unsuccessful.Successful completion of A will returnRs 20,000 and Successful completion of B will return Rs 24,000 Draw a decision tree in order to determine the best strategy. Solution: - The decision tree corresponding to the given information is as followed
  • 18. QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 18 DECISION POINT OUT COME PROBABILITY CONDITIONAL VALUE (RS/-) EXCEPTED VALUE 𝑫 𝟑 1.ACCPT A SUCCESS/ FAILURE 0.6 0.4 23,000/- -10,000/- 12,000/- -4,000 8,000 2.STOP 0 𝑫 𝟐 1.ACCEPT B SUCCESS/ FAILURE 0.4 0.6 24,000/- -10,000/- 9,600/- -6,000/- 3,6000/- 2.STOP 0 𝑫 𝟏 1.ACCPT A SUCCESS/ FAILURE 0.6 0.4 20,000+3,600 = 23600 × (0.6) -10,000× (0.4) 14,160 -4,000 10,160 2.ACCEPT B SUCCESS/ FAILURE 0.4 0.6 24000+8000= 32000 ×(0.4) -10,000 ×(0.6) 12800 -6,000 6,800
  • 19. QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 19 (0.6) EMV=3600 SUCCESS EMV =10,160 0.6 FAILURE RS/10,000 EMV=6,800 RS/-24000 ACCEPT A SUCCESS RS/-0 4. Decision – Making with Utilities The previous problems were analyzed with probabilistic statesof nature, where the selection of an optimal course of action was on the criterion of expected profit (loss) expressed in monetary terms However,in many situations such criterion that involves expected monetary payoff may not be appropriate. This is because of the fact that different individuals attachdifferent utility to money, under different conditions. D1 1 D2 3 4 8 9 5 2 D3 6 7 10 11 12 ACCEPT A SUCCES S Rs/- 3600 0.4 STOP RS/-0 RS/-20,000 ACCEPT B FAILUR E RS/-10,000 0.4×24,000=9600 0.6 × -10,000 =-6,000 ACCEPTB FAILURE (0.4) RS/-8000 EMV=8000 SUCCESS (0.6) FAILURE (0.4) RS/-20000 -19000 0.6 × 20,000=12,000 0.4 × -10,000 = -4000
  • 20. QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 20 The term utility is the “measure of preference”for various alternativesin terms money. The utility of a given alternative is unique to the individual decision- maker and unlike a simple monetary amount, can incorporate intangible factorsor subjective standards form their own value system. Example Mr. Ran has won Rs 1,000 in a quiz programme. In the last round he is asked either to complete or quit now he has alternatives. Quit and take his winnings Take a least chance in which he has 50.50 chance of winning Rs 4,000 or nothing The question now is: what should he do? On EMV basis he has EMV (b) =0.50 (4,000) + 0.50 (0) = Rs 2,000 The amount is twice what he was already won. But would he really give up Rs 1,000 for 50-50 chance or Rs 4,000 or nothing? Many individuals would not because they would think of all the alternatives they could do with Rs 1,000 and how they would regret it if they end up with nothing hence a new payoff measure utility reflecting the decision- makers attitude and preference has to be introduced. The basis axioms of utility may be stated as follows. 1. If outcome A is proffered to outcome B, they the utility U(A) of outcome A is greater than the utility u(B) of outcome B vice versa If both are equally proffered thenu(A) = u(B) 2. If the decision-maker is different between the ‘2’ alternatives and outcome ‘A’ is received with probability P1 and outcome C with probability (1-P) then U (B) = P [U (A)] + (1-P) [U/C)] Under this alternative criterion, it is assumed that a rational decision-maker will choose that alternative which optimize the “expected utility” rather than expected monetary value. Once we know that individual’s utility function,along with the probability assigned to outcome in a particular situation then the total expected utilityfor each course of action can be obtained by multiplying the utility values with their probabilities the strategy that corresponds to the optimum utility function is called that equal strategy” Utility function “Utility function” is a formula or method that is used to describe the relative preference value that individualshave for a given criterion such as money, goods etc.
  • 21. QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 21 Once derive, a “utility function”can be used to convert a decision criteria value into utilities so that a decision can be made on the bass of maximizing the expected “utility value” (EUV) rather than, say the “EMV” Example Preference are oftendetermined by proposing a situation where by decision- maker must choose between receiving a given amount, say Rs 20,000 for a certain thing versus a 50-50 chance of gambling a larger amount or nothing say Rs 60,000 or Zero. The gamble amount of Rs 60,000 is then adjusted upward or down ward until the individual is indifferent to whether decision – maker receivesthe certainamount of Rs 20,000 or the gamble Utility Curve A utility curve that relates utility valuesto rupee value is construction such a curve is usually obtained by placing the decisionmaker in various hypothetical decision situations and plotting the decision makers pattern of choices in terms of risk and utilities. Suppose the relationshipbetween monetary gains,losses and utilities for gains and for small negative lossesis established. The following diagram shows that if the curve is bent down non- linearly thenwe assign,to large lossesa disproportionately large negative utility. It is important not to make the curve bend down too steeply or to start the bending too quickly since this could lead individualsinto a situation where they attach such a heavy to the possibility of loss they never take any risk and tell us never masse any gains Once the +ve side of the curve, it is usual for the curve to eventually bend away from the straight line. This indicates that increasingunits of money are resulting in smaller additional gainsin utility 𝑈 𝑀𝐴𝑋 RISK AVERSION (AVOIDERS) UTILITY RISK INDIFFERENCE (NEUTRALITY) RISK AFFINITY (SEEKERS) MONEY RS/- MAX
  • 22. QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 22 Problem 1 A manager must choose between 2 investmentsA&B that are calculated to yield net profit of Rs 1,200 and Rs 1,600 respectively.With probabilities subjectively estimated at 0.75 and 0.60. Assume the manager’s utility function revealsthat utilities for Rs 1,200 and Rs 1,600 are 45 and 50 units respectively what is the best choice on the basis of the expected utility value (EUV)? Solution The except utility value (EUV) is expressed as EUV = ∑ 𝑢𝑖 𝑚 𝑖=1 𝑝𝑖 where 𝑢𝑖 = utility value of state of nature i 𝑝𝑖 = probability value of state of nature i EUV (A) = (𝑈𝐴 ) (𝑝 𝐴) = (0.75) (45) =33.75 = EUV (A) =33.75 utilities EUV (B) = (𝑈 𝐵) (𝑝 𝐵) = (0.60) (50) =30.00 = EUV (B) =30 utilities ⟹ 30< 33.75 Since EUV (A) > EUV (B) The best choice is investment “A” Problem 2 Mr. X has an after –tax annual of Rs 90,000 and is considering to buy accident insurance for his car. The probability of accident during the year is 0% (Assume that at most one accident will occur) in which case the damage to the car will be Rs 11,600 which a utility function U(x)=√ 𝑥 ,what is the insurance premium he will be willing to pay? Solution: Let A = Venture whenMr. X does not buy the accident insurance for his car. Then in that case of accident he would spend Rs. 11,600 on damages and will be left with Rs. 78,400. In the case for no accident he retainsRs. 90,000. Then we have 𝑈𝐴 = (𝑈78,400 X 0.1) + (𝑈90,000 X 0.9) →1 U (x) = 𝑈 𝑋 = √ 𝑋 →2 𝑈78,400 = √78,400 = 280 utilities→ 3 𝑈90,000 = √90,000 = 300 utilities→ 4 𝑈𝐴 = (280 X 0.1) + (300 X 0.9) = 298 utilities → 5
  • 23. QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 23 So the amount Rs. X which will give the same utility of the venture A = (298)2 = Rs. 88,804 [∵ U (x) = √ 𝑋 ⟹X = [ U (x) ]2 ] Thus Mr. X will be indifferent to an amount of Rs.88, 804 with certainty and the venture A. The amount he is willing to pay as car premium would be 90,000 – 88,804 = Rs. 1,196 3) Decision Making Under Risk: Decision making under risk is a probabilistic decision situation in which more than one state of nature exists. And the decision maker has sufficient information to assign probability values to the likely occurrence of each of these states. Knowing the probability distribution of these states of nature, the best decision is to select that course of action which has the largest expected payoff value. The expected (average) payoff of an alternative is the sum of all possible payoffs of that alternative, weight by the probabilities of the occurrence of those payoffs. The most widely used criterion for evaluating various course of action (alternatives) under risk is the “expected monetary value (EMV)” or “expected utility” Expected Monetary Value (EMV) The expected monetary value (EMV) for a given course of action is the weighted sum of possible payoffs for each alternative. The expected value is the long- run average value that would result if the decision were repeated a large number of times. MathematicallyEMV is stated as follows. EMV [ Course of avtion, Sj ] = ∑ 𝑝𝑖𝑗. 𝑃𝑖 𝑛 𝑖−1 Where m = number of possible statesof nature Pi = probability of occurrence of nature, N: Pij= payoff associated with state of nature Ni and course of action, Sj Steps for calculating EMV The various steps involved in the calculation of EMV are as follows 1. Construct of payoff matrix listing all possible courses of action and states of nature. Enter the conditional payoff values associated with each possible combination of courses of action and state of nature along with the probabilities of the occurrence of each state of nature
  • 24. QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 24 2. Calculate the EMV for each course of action by multiplying the conditional payoff by the associated probabilities and adding these weighted valuesfor each of action 3. Select the course of action that yields the optimal EMV Expected Profit with Perfect Information (EPPI ) The expected profit with perfect information (EPPI) is the maximum attainable expected money value (EMV) based on perfect information about the state of nature that will occur. The expected profit with perfect information may be defined as the sum of the product of best state of nature corresponding to each optimal course of action and its probability Expected Value of PerfectInformation ( EVPI) The expected value of perfect information (EVPI) may now be defined as the maximum amount one would be willing to pay to obtain perfect information about the state of nature that would be willingto pay to obtain perfect information about the state of nature that would occur. EMV Representsthe maximum attainable expected monetary value given only the prior outcome probabilities with no information as to which state of nature will actually occur. Therefore perfect information would increase profit from EMV up to the value of EPPI. This increased amount is termed as EVPI. i.e. EVPI= EPP1- EMV Expected Opportunity Loss ( EOL): Another useful way of maximizing monetary value is to minimize the expected loss or expected value of regret.The conditional opportunity los (COL) or regret function for a particular course of action is determined by taking the difference between payoff values of the most favorable course of action. And some other course of action .Which may be considered as loss due to loosing the opportunity of choosing the most favorable course of action, thus opportunity loss can be obtained separately for each course of action by 1St obtaining the best state of nature for the prescribed course of action and then taking the difference betweenthat best outcome and each outcome for those courses of action. The opportunity loss for each course of action is known as the conditional opportunity loss After calculating the opportunity loss value for each course of action, the E0L for ith course of action Si is then computed by EOL (S𝑖,) = ∑ 𝐶𝑂𝐿 (𝑛 𝑗=1 S𝑖,O𝑗). P (O𝑗)
  • 25. QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 25 Where (S𝑖,O𝑗)= Conditional Opportunity loss associated with the course of action S𝑖 And state of nature O𝑗. P (O𝑗 ) = Probability of occurrence of state of nature O𝑗. In other words EOL denotesthe expected difference between the payoff of right decision and the payoff of actual decision. Problem-1 A modern home appliances dealer finds that the cost of holding a mini cooking range is stock for a month is Rs 200 (Insurance,minor deterioration, interest on borrowed capital, etc) customer who cannot obtain a working range immediately tends to go to other dealer and he estimates that for every customer who cannot get immediate delivery,he loses an average of Rs 500 the probabilities of a demand of 0,1,2,3,4,5 mini cooking rangesin a month are 0.05, 0.10, 0.20, 0.30, 0.20, 0.15 respectively determine the optimum stock level of consuming rangers. Also find EVPI Solution: The cost function =Rs 500(D-S); If D>S = Rs 200 (S-D); If D < S Where S= The number of units purchased and D= the number of units demanded.
  • 26. QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 26 Since the expected cost is minimum if 4 cooking ranges are stocked each month. The optimum act is to stock 4 looking ranges. Problem -2 Under an employment promotion programming, it is proposed to allow sale of newspapers on the buses during of peak hours. The vendor can purchase the Event Demanded (D) Probability Conditional Cost (Rs/-) (S) Expected Cost (Rs/-) 0 1 2 3 4 5 0 1 2 3 4 5 0 0.05 0 200 400 600 800 1000 0 10 20 30 40 50 1 0.10 500 0 200 400 600 800 50 0 20 40 60 80 2 0.20 1000 500 0 200 400 600 200 100 0 40 80 120 3 0.30 1500 1000 500 0 200 400 450 300 200 100 0 40 4 0.20 2000 1500 1000 500 0 200 400 300 200 100 0 40 5 0.15 2500 2000 1500 1000 500 0 375 300 225 150 7 50 Expected cost 1475 1010 615 360 315 410
  • 27. QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 27 newspaper at a special concessional rate of 25 paisa per copy against the selling price of 40 paise. Unsold copies are however a dead loss. A vendor has estimated the following probability distribution for the number of copies demanded No of copies demanded 15 16 17 18 19 20 Probability 0.04 0.19 0.33 0.26 0.11 0.07 How many copies should he order so that his expected profit will be maximum? Solution:- The vendor does not purchase less than 15 copies or more than 20 copies Let n = The number of copies of newspaper demanded The vendor would loss 25 paise on each copy in case of demand is less than ‘n’ otherwise , if the demand is more than or equal to ‘n’ then he would gain 15 paise on each newspaper copy . The incremental profit =( Excepted profit –Expected loss), for each value on ‘n’ is given in the following table
  • 28. QIS COLLEGE OF ENGINEERING & TECHNOLOGY Page 28 Expected profit Demand (n) Probability (<n) Probability (>n) Expected incremental Profit (Rs-/) Total profit 15 0.00 1.00 =0(0)+1(0.15)=0.15 0.15×15=2.25 16 0.04 0.96 =0.04 (-0.25)+0.96(0.15)=0.13 0.13×16=2.38 17 0.23 0.77 =0.23 (-0.25)+0.77(0.15)=0.06 0.06×17=2.44 18 0.56 0.44 =0.56 (-0.25)+0.44(0.15)= (-0.07) 0.07×18=2.37 19 0.82 0.18 =0.82 (-0.25)+0.07(0.15)= (-0.18) 0.18×19=2.19 20 0.93 0.07 =0.93 (-0.25)+0.07(0.15)= (-0.22) 00.22× 20 =1.97