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8.3.3 Example 1b
- 1. Xc =
V
Ic
Xc =
240 = 77.4 Ω
3.1
- 4. C =
1
2 π x 50 x 77.4
= 41 x 10¯⁶ F
Answer: Capacitance
required is 41µF
- 6. A = 240 x 3.1
= 744 VA
Answer: VA rating of
the required capacitor
is 744 VA