เฉลย คณิต 1 นาทีกับอ.มด วันที่ 2 มกราคม 2557

1. เฉลยคณิต 1 นาที
2 ม.ค. 57
a* = ((a+4)*)* เมื่อ a น้อยกว่า 50
32* = ((32+4)*)* = (36*)*
36* = ((36+4)*)* = (40*)* ; (36*)* = ((40*)*)*
40* = ((40+4)*)* = (44*)* ; ((40*)*)* = (((44*)*)*)*
44* = ((44+4)*)* = (48*)* ; (((44*)*)*)* = ((((48*)*)*)*)*
48* = ((48+4)*)* = (52*)* ; ((((48*)*)*)*)* = (((((52*)*)*)*)*)*
a* = a-2 เมื่อ a ไม่น้อยกว่า 50
52* = 52-2 = 50 ; (((((52*)*)*)*)*)* = ((((50*)*)*)*)*
50* = 50-2 = 48 ; ((((50*)*)*)*)* = (((48*)*)*)*
48* = ((48+4)*)* = (52*)* ; (((48*)*)*)* = ((((52*)*)*)*)*
52* = 52-2 = 50 ; ((((52*)*)*)*)* = (((50*)*)*)*
50* = 50-2 = 48 ; (((50*)*)*)* = ((48*)*)*

2. เฉลยคณิต 1 นาที
48* = ((48+4)*)* = (52*)* ; ((48*)*)* = (((52*)*)*)*
52* = 52-2 = 50 ; (((52*)*)*)* = ((50*)*)*
50* = 50-2 = 48 ; ((50*)*)* = (48*)*
48* = ((48+4)*)* = (52*)* ; (48*)* = ((52*)*)*
52* = 52-2 = 50 ; ((52*)*)* = (50*)*
50* = 50-2 = 48 ; (50*)* = 48*
48* = ((48+4)*)* = (52*)*
52* = 52-2 = 50 ; (52*)* = 50*
50* = 50-2 = 48 ; 50* = 48
ดังนั้น 32* หมายถึงจานวน 48
2 ม.ค. 57