1. PRIMARY 3 MATHEMATICS
MATH PRACTICE PAPER 3
ANSWER KEY
Section A (2 marks each)
No. Answers No. Answers No. Answers No. Answers
1. 3 6. 4 11. 2 16. 4
2. 1 7. 3 12. 1 17. 3
3. 2 8. 3 13. 4 18. 3
4. 4 9. 3 14. 3 19. 4
5. 3 10. 2 15. 4 20. 1
Section B (2 marks each)
No. Answers
Seven thousand, four hundred and twelve
21.
22. hundreds
23. 9 926
24. 9
25. $1.35
26. 1
27. 250
28. Red
29. 1 420
30. 3 837
31. 36
32. 190
33. 25
34. 136
35. $36
36. 7
(a) James
37.
(b) 100
38. 5
39. 9
40. 140
Section C (4 marks each)
S/N Answers Remarks
41. 2 684 − 152 = 2 532
1

2. 2 532 visitors visited the zoo on Sunday.
2 684 + 2 532 = 5 216
5 216 visitors visited the zoo on both days.
Alternative method
2684 x 2 = 5368
5368 − 152 = 5216
5 216 visitors visited the zoo on both days.
42. Susan and Camy Su (73) C (26)
(ii) ?
Vanessa
(i) ?
i) 73 + 26 = 99
99 x 2 = 198
Vanessa baked 198 muffins .
ii) 198 + 99 = 297
They baked 297 muffins altogether .
Alternative method
73 x 3 = 219
26 x 3 = 78
219 + 78 = 297
They baked 297 muffins altogether
43. $88 − $16 = $72
Lily was still short of $72.
72 ÷ 4 = 18
She would need to save for another 18 days.
Or
She would need to save for 18 days more.
Alternative method
This method based on assumption that Lily had been saving $4
2

3. daily for 4 days to reach $16.
$88 ÷ $4 = 22 days
$16 ÷ $4 = 4 days
22 - 4 = 18 days
She would need to save for 18 days more.
44. 28 x 3 = 84
Jaye bought 84 egg tarts.
84 ÷ 7 = 12
Each friend received 12 egg tarts.
45.
pink clips
In each packet Total 7 clips in each packet
blue
clips 3 more
35 ÷ 5 = 7
There are 7 hair clips in each packet.
7–3=4
4÷2=2
There are 2 blue clips in each packet.
45 Alternative methods
A)
35 – 15 = 20
20 ÷ 2 = 10
10 ÷ 5 = 2
B)
3 x 5 = 15
35 – 15 = 20
20 ÷ 10 = 2
C) Using number bonds / Listing
35 ÷ 5 = 7
3

4. 1 and 6
X
4 and 3
X
2 and 5
√
3 and 4
X
4