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Trigonometric Functions
4.4         of Any Angle




       Copyright © Cengage Learning. All rights reserved.
What You Should Learn
•   Evaluate trigonometric functions of any angle

•   Find reference angles


•   Evaluate trigonometric functions of real
    numbers




                                                    2
Introduction




               3
Introduction
Following is the definition of trigonometric functions of Any
Angle.




                                                                4
Introduction
Because r =          cannot be zero, it follows that the sine
and cosine functions are defined for any real value of θ .

However, when x = 0, the tangent and secant of θ are
undefined.

For example, the tangent of 90 ° is undefined. Similarly,
when y = 0, the cotangent and cosecant of θ are undefined.




                                                                5
Example 1 – Evaluating Trigonometric Functions

Let (–3, 4) be a point on the terminal side of θ
(see Figure 4.34).
Find the sine, cosine, and tangent of θ.




                            Figure 4.34
                                                   6
Example 1 – Solution
Referring to Figure 4.34, you can see that x = –3, y = 4,
and




                                                            7
Example 1 – Solution   cont’d


So, you have




       and




                          8
Introduction
The signs of the trigonometric functions in the four
quadrants can be determined easily from the definitions of
the functions. For instance, because




it follows that cos θ is positive
wherever x > 0, which is in
Quadrants I and IV.




                                                             9
Reference Angles




                   10
Reference Angles
The values of the trigonometric functions of angles greater
than 90 ° (or less than 0 °) can be determined from their
values at corresponding acute angles called reference
angles.




                                                              11
Reference Angles
Figure 4.37 shows the reference angles for θ in Quadrants
II, III, and IV.




                        Figure 4.37




                                                            12
Example 4 – Finding Reference Angles
Find the reference angle θ ′.

a. θ = 300 °    b. θ = 2.3       c. θ = –135 °

Solution:
a. Because 300 ° lies in Quadrant IV, the angle it makes
   with the x-axis is

           θ ′ = 360 ° – 300 °            Degrees

               = 60 °.


                                                           13
Example 4 – Solution                                         cont’d


b. Because 2.3 lies between π /2 ≈ 1.5708 and π ≈ 3.1416,
   it follows that it is in Quadrant II and its reference angle
   is
            θ ′ = π – 2.3                 Radians

             ≈ 0.8416.

c. First, determine that –135 ° is coterminal with 225 °,
   which lies in Quadrant III. So, the reference angle is
           θ ′ = 225 ° – 180 °          Degrees


              = 45 °.
                                                                  14
Example 4 – Solution                                     cont’d


Figure 4.38 shows each angle θ and its reference angle θ ′.




       (a)                   (b)               (c)


                         Figure 4.38




                                                              15
Trigonometric Functions of Real Numbers




                                      16
Trigonometric Functions of Real Numbers

To see how a reference angle is used to evaluate a
trigonometric function, consider the point (x, y) on the
terminal side of θ, as shown in Figure 4.39.




                          Figure 4.39
                                                           17
Trigonometric Functions of Real Numbers

By definition, you know that



and



For the right triangle with acute angle θ ′ and sides of
lengths | x | and | y |, you have

                            and


                                                           18
Trigonometric Functions of Real Numbers

So, it follows that sin θ and sin θ ′ are equal, except possibly
in sign. The same is true for tan θ and tan θ ′ and for the
other four trigonometric functions. In all cases, the sign of
the function value can be determined by the quadrant in
which θ lies.




                                                               19
Trigonometric Functions of Real Numbers

For convenience, the following table shows the exact
values of the trigonometric functions of special angles and
quadrant angles.




                       Trigonometric Values of Common Angles
                                                               20
Example 5 – Trigonometric Functions of Nonacute Angles


Evaluate each trigonometric function.

a.              b. tan = (–210 °)   c.

Solution:
a. Because θ = 4π /3 lies in Quadrant III, the
   reference angle is θ ′ = (4π /3) – π = π /3,
   as shown in Figure 4.40.
     Moreover, the cosine is negative in
     Quadrant III, so

                                                  Figure 4.40



                                                                21
Example 5 – Solution                                        cont’d


b. Because –210 ° + 360 ° = 150 °, it follows that –210 ° is
   coterminal with the second-quadrant angle 150 °.
   Therefore, the reference angle is θ ′ = 180 ° – 150 ° = 30
°,
   as shown in Figure 4.41.

  Finally, because the tangent is
  negative in Quadrant II, you have.



                                              Figure 4.41




                                                                22
Example 5 – Solution                                             cont’d


c. Because (11π /4) – 2π = 3π /4, it follows that 11π /4 is
   coterminal with the second-quadrant angle 3π/4.
   Therefore, the reference angle is θ ′ = π – (3π /4) = π /4,
   as shown in Figure 4.42.

  Because the cosecant is positive
  in Quadrant II, you have




                                                   Figure 4.42




                                                                    23

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Larson 4.4

  • 1. Trigonometric Functions 4.4 of Any Angle Copyright © Cengage Learning. All rights reserved.
  • 2. What You Should Learn • Evaluate trigonometric functions of any angle • Find reference angles • Evaluate trigonometric functions of real numbers 2
  • 4. Introduction Following is the definition of trigonometric functions of Any Angle. 4
  • 5. Introduction Because r = cannot be zero, it follows that the sine and cosine functions are defined for any real value of θ . However, when x = 0, the tangent and secant of θ are undefined. For example, the tangent of 90 ° is undefined. Similarly, when y = 0, the cotangent and cosecant of θ are undefined. 5
  • 6. Example 1 – Evaluating Trigonometric Functions Let (–3, 4) be a point on the terminal side of θ (see Figure 4.34). Find the sine, cosine, and tangent of θ. Figure 4.34 6
  • 7. Example 1 – Solution Referring to Figure 4.34, you can see that x = –3, y = 4, and 7
  • 8. Example 1 – Solution cont’d So, you have and 8
  • 9. Introduction The signs of the trigonometric functions in the four quadrants can be determined easily from the definitions of the functions. For instance, because it follows that cos θ is positive wherever x > 0, which is in Quadrants I and IV. 9
  • 11. Reference Angles The values of the trigonometric functions of angles greater than 90 ° (or less than 0 °) can be determined from their values at corresponding acute angles called reference angles. 11
  • 12. Reference Angles Figure 4.37 shows the reference angles for θ in Quadrants II, III, and IV. Figure 4.37 12
  • 13. Example 4 – Finding Reference Angles Find the reference angle θ ′. a. θ = 300 ° b. θ = 2.3 c. θ = –135 ° Solution: a. Because 300 ° lies in Quadrant IV, the angle it makes with the x-axis is θ ′ = 360 ° – 300 ° Degrees = 60 °. 13
  • 14. Example 4 – Solution cont’d b. Because 2.3 lies between π /2 ≈ 1.5708 and π ≈ 3.1416, it follows that it is in Quadrant II and its reference angle is θ ′ = π – 2.3 Radians ≈ 0.8416. c. First, determine that –135 ° is coterminal with 225 °, which lies in Quadrant III. So, the reference angle is θ ′ = 225 ° – 180 ° Degrees = 45 °. 14
  • 15. Example 4 – Solution cont’d Figure 4.38 shows each angle θ and its reference angle θ ′. (a) (b) (c) Figure 4.38 15
  • 16. Trigonometric Functions of Real Numbers 16
  • 17. Trigonometric Functions of Real Numbers To see how a reference angle is used to evaluate a trigonometric function, consider the point (x, y) on the terminal side of θ, as shown in Figure 4.39. Figure 4.39 17
  • 18. Trigonometric Functions of Real Numbers By definition, you know that and For the right triangle with acute angle θ ′ and sides of lengths | x | and | y |, you have and 18
  • 19. Trigonometric Functions of Real Numbers So, it follows that sin θ and sin θ ′ are equal, except possibly in sign. The same is true for tan θ and tan θ ′ and for the other four trigonometric functions. In all cases, the sign of the function value can be determined by the quadrant in which θ lies. 19
  • 20. Trigonometric Functions of Real Numbers For convenience, the following table shows the exact values of the trigonometric functions of special angles and quadrant angles. Trigonometric Values of Common Angles 20
  • 21. Example 5 – Trigonometric Functions of Nonacute Angles Evaluate each trigonometric function. a. b. tan = (–210 °) c. Solution: a. Because θ = 4π /3 lies in Quadrant III, the reference angle is θ ′ = (4π /3) – π = π /3, as shown in Figure 4.40. Moreover, the cosine is negative in Quadrant III, so Figure 4.40 21
  • 22. Example 5 – Solution cont’d b. Because –210 ° + 360 ° = 150 °, it follows that –210 ° is coterminal with the second-quadrant angle 150 °. Therefore, the reference angle is θ ′ = 180 ° – 150 ° = 30 °, as shown in Figure 4.41. Finally, because the tangent is negative in Quadrant II, you have. Figure 4.41 22
  • 23. Example 5 – Solution cont’d c. Because (11π /4) – 2π = 3π /4, it follows that 11π /4 is coterminal with the second-quadrant angle 3π/4. Therefore, the reference angle is θ ′ = π – (3π /4) = π /4, as shown in Figure 4.42. Because the cosecant is positive in Quadrant II, you have Figure 4.42 23