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Thermodynamics
First Law of Thermodynamics Energy Conservation  U =  Q   -  W Heat flow  into  system Increase  in internal energy of system Equivalent ways of writing 1st Law: Q =   U + W  The change in internal energy of a system (  U ) is equal to the heat flow into the system ( Q ) minus the work done by the system ( W) Work done  by  system V P 1 2 3 V 1  V 2 P 1 P 3
Signs Example ,[object Object],[object Object],[object Object],[object Object]
Work Done  by  a System ACT W = p   V :For constant Pressure The work done by the gas as it contracts is A) Positive B) Zero C) Negative M M  y
Thermodynamic Systems and P-V Diagrams ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],V P A B C V 1  V 2 P 1 P 3
First Law of Thermodynamics Isobaric  Example 2 moles  of monatomic ideal gas is taken from state  1  to state  2  at  constant pressure p=1000 Pa , where  V 1  =2m 3  and  V 2  =3m 3 .  Find T 1 , T 2 ,   U, W, Q. V P 1 2 V 1  V 2 P
First Law of Thermodynamics Isochoric  Example 2 moles  of monatomic ideal gas is taken from state  1  to state  2  at  constant volume V=2m 3 , where  T 1 =120K  and  T 2  =180K .  Find Q. V P 2 1 V P 2 P 1
Homework Problem: Thermo I V P 1 2 3 4  W tot  = ?? V P 1 2 3 4 V P 1 2 3 4  V P 1 2 3 4  V 1 2 3 4 P 
PV ACTs ,[object Object],[object Object],[object Object],[object Object],A B 4 2 3 9 V(m 3 ) Case 1 A B 4 2 3 9 V(m 3 ) P(atm) Case 2 P(atm)
PV ACT 2 ,[object Object],[object Object],[object Object],[object Object],A B 4 2 3 9 V(m 3 ) Case 1 A B 4 2 3 9 V(m 3 ) P(atm) Case 2 P(atm)
PV ACT3 ,[object Object],[object Object],[object Object],[object Object],A B 4 2 3 9 V(m 3 ) Case 1 A B 4 2 3 9 V(m 3 ) P(atm) Case 2 P(atm)
First Law Questions Q   =   U +  W ,[object Object],[object Object],[object Object],[object Object],Some questions: Heat flow  into  system Increase  in internal energy of system Work done  by  system V P 1 2 3 V 1  V 2 P 1 P 3
Special PV Cases ,[object Object],[object Object],[object Object],[object Object],V P W = P  V (>0) 1 2 3 4  V > 0 V P W = P  V = 0 1 2 3 4  V = 0
Preflights 3 - 5 Consider a hypothetical device that takes 1000 J of heat from a hot reservoir at 300K, ejects 200 J of heat to a cold reservoir at 100K, and produces 800 J of work. Does this device violate the first law of thermodynamics ?   1. Yes   2. No
Reversible? ,[object Object],[object Object],[object Object],[object Object],[object Object]
Summary: ,[object Object],Q   =   U +  W V P ,[object Object],[object Object],[object Object],[object Object],Heat flow  into  system Increase  in internal energy of system Work done  by  system

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1law thermodynamics

  • 2. First Law of Thermodynamics Energy Conservation  U = Q - W Heat flow into system Increase in internal energy of system Equivalent ways of writing 1st Law: Q =  U + W The change in internal energy of a system (  U ) is equal to the heat flow into the system ( Q ) minus the work done by the system ( W) Work done by system V P 1 2 3 V 1 V 2 P 1 P 3
  • 3.
  • 4. Work Done by a System ACT W = p  V :For constant Pressure The work done by the gas as it contracts is A) Positive B) Zero C) Negative M M  y
  • 5.
  • 6. First Law of Thermodynamics Isobaric Example 2 moles of monatomic ideal gas is taken from state 1 to state 2 at constant pressure p=1000 Pa , where V 1 =2m 3 and V 2 =3m 3 . Find T 1 , T 2 ,  U, W, Q. V P 1 2 V 1 V 2 P
  • 7. First Law of Thermodynamics Isochoric Example 2 moles of monatomic ideal gas is taken from state 1 to state 2 at constant volume V=2m 3 , where T 1 =120K and T 2 =180K . Find Q. V P 2 1 V P 2 P 1
  • 8. Homework Problem: Thermo I V P 1 2 3 4  W tot = ?? V P 1 2 3 4 V P 1 2 3 4  V P 1 2 3 4  V 1 2 3 4 P 
  • 9.
  • 10.
  • 11.
  • 12.
  • 13.
  • 14. Preflights 3 - 5 Consider a hypothetical device that takes 1000 J of heat from a hot reservoir at 300K, ejects 200 J of heat to a cold reservoir at 100K, and produces 800 J of work. Does this device violate the first law of thermodynamics ? 1. Yes 2. No
  • 15.
  • 16.

Editor's Notes

  1. 1
  2. Note that equation only works for contant pressure!
  3. Note homework has diagonal line in PV, just get area. Key is work is area “under” curve. Could do ACT with three “identical” cycles, one rotated 90 degrees, one raised up.
  4. Look at Eric’s isothermal