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DistributiveProperty 4(x + 3) = 4x + 12 Factoring 4x + 12 = 4(x + 3)  GCF of 4x and 12
Factor GCF of 10y and 25 10y = 2 · 5 · y   25 = 5 · 5 GCF =    5 Factor 10y – 25 	= 5(2y – 5)  GCF: Example 2-1a
     3x2y = 3·x·x·y 12xy2 = 2·2·3·x·y·y  Factor = 3xy (x + 4y) GCF:   3xy
Factor GCF: Example 2-1a
( 7 )( 0 ) = 0 ( 51 )( 0 )= 0 ( 0 )( 31 ) = 0 ( 79 )( 0 ) = 0 ( 42 )( 0 ) = 0 ( 0 )( 0 ) = 0
Solve:  (x + 1)(x – 2) = 0   x + 1 = 0    or    x – 2 = 0      - 1  - 1             + 2     +2         x = -1   or     x = 2 Check  2: (x + 1)(x – 2) = 0 (2 + 1)(2 – 2) = 0 (3)(0) = 0   Check  -1: (x + 1)(x – 2) = 0 (-1 + 1)(-1 – 2) = 0 (0)(-3) = 0
Solve:  (x + 3)(x – 5) = 0   x + 3 = 0    or    x – 5 = 0      - 3  - 3             + 5     +5         x = -3   or     x = 5
Solve		 or +2    +2 +1    +1 4      4 Example 2-4a
Solve: x2 – 4x = 12 	x2 – 4x – 12 = 0 -12     -12 Solve:  (x + 2)(x – 6) = 0   x + 2 = 0    or    x – 6 = 0      - 2  - 2             + 6     +6         x = -2   or     x = 6
Solve -12y2     -12y2 or 4       4 -1               -1 -3y = -1 -3       -3

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Alg1 lesson 9-2

  • 1. DistributiveProperty 4(x + 3) = 4x + 12 Factoring 4x + 12 = 4(x + 3) GCF of 4x and 12
  • 2. Factor GCF of 10y and 25 10y = 2 · 5 · y 25 = 5 · 5 GCF = 5 Factor 10y – 25 = 5(2y – 5) GCF: Example 2-1a
  • 3. 3x2y = 3·x·x·y 12xy2 = 2·2·3·x·y·y Factor = 3xy (x + 4y) GCF: 3xy
  • 5. ( 7 )( 0 ) = 0 ( 51 )( 0 )= 0 ( 0 )( 31 ) = 0 ( 79 )( 0 ) = 0 ( 42 )( 0 ) = 0 ( 0 )( 0 ) = 0
  • 6. Solve: (x + 1)(x – 2) = 0 x + 1 = 0 or x – 2 = 0 - 1 - 1 + 2 +2 x = -1 or x = 2 Check 2: (x + 1)(x – 2) = 0 (2 + 1)(2 – 2) = 0 (3)(0) = 0 Check -1: (x + 1)(x – 2) = 0 (-1 + 1)(-1 – 2) = 0 (0)(-3) = 0
  • 7. Solve: (x + 3)(x – 5) = 0 x + 3 = 0 or x – 5 = 0 - 3 - 3 + 5 +5 x = -3 or x = 5
  • 8. Solve or +2 +2 +1 +1 4 4 Example 2-4a
  • 9. Solve: x2 – 4x = 12 x2 – 4x – 12 = 0 -12 -12 Solve: (x + 2)(x – 6) = 0 x + 2 = 0 or x – 6 = 0 - 2 - 2 + 6 +6 x = -2 or x = 6
  • 10. Solve -12y2 -12y2 or 4 4 -1 -1 -3y = -1 -3 -3