Alg2 lesson 13-4

326 views

Published on

Published in: Education
0 Comments
0 Likes
Statistics
Notes
  • Be the first to comment

  • Be the first to like this

No Downloads
Views
Total views
326
On SlideShare
0
From Embeds
0
Number of Embeds
16
Actions
Shares
0
Downloads
0
Comments
0
Likes
0
Embeds 0
No embeds

No notes for slide

Alg2 lesson 13-4

  1. 1. B Find the area of triangle ABCA C A b A A sin h c
  2. 2. B Find the area of triangle ABC hA C A b A A sin h c
  3. 3. B Find the area of c triangle ABC hA C A b A A sin h c
  4. 4. B Find the area of c triangle ABC hA C A b A A sin h c
  5. 5. B Find the area of c triangle ABC hA C A b A A sin h c
  6. 6. B Find the area of c triangle ABC hA C A b A A sin h c
  7. 7. B Find the area of c triangle ABC hA C A b A A sin h c
  8. 8. B Find the area of c triangle ABC hA C A b A A sin h c
  9. 9. B Find the area of c triangle ABC hA C b
  10. 10. Find the area of to the nearesttenth.
  11. 11. Find the area of to the nearesttenth. Included angle b= =c
  12. 12. Find the area of to the nearesttenth. Included angle b= =c
  13. 13. Find the area of to the nearesttenth. Included angle b= =c square centimeters
  14. 14. LawofSines
  15. 15. Solve .This is NOT a righttriangle!!!
  16. 16. Suppose you are given a, b and A for a triangle.Is it always possible to create a triangle usingthe given angle and two sides?Is there always only one possible angle that youcan create?Pg. 727
  17. 17. In Determinewhether has no solution, one solution or twosolutions. Then solve sin 25o = h 12 h = 12 sin 25o h = 5.07 b = 12 h a = 13 25o one solution A B
  18. 18. C b = 12 a = 13 25oA c B
  19. 19. C b = 12 a = 13 25oA c B
  20. 20. C b = 12 a = 13 25oA c B
  21. 21. C b = 12 a = 13 25oA c B
  22. 22. C b = 12 a = 13 25oA c B
  23. 23. C b = 12 a = 13 25o 23oA c B
  24. 24. C = 180 – (25 + 23) = 132o C b = 12 132o a = 13 25o 23o A c B
  25. 25. C b = 12 132o a = 13 25o 23oA c B
  26. 26. or about 22.9 C b = 12 132o a = 13 25o 23oA c = 22.9 B
  27. 27. In Determinewhether has no solution, one solution or twosolutions. Then solve a = 32 b = 35 125o A no solution
  28. 28. In Determinewhether has no solution, one solution or twosolutions. Then solve b = 10 25o A B B
  29. 29. In Determinewhether has no solution, one solution or twosolutions. Then solve b = 10 h 25o A B B
  30. 30. In Determinewhether has no solution, one solution or twosolutions. Then solve sin 25o = h 10 b = 10 h 25o A B B
  31. 31. In Determinewhether has no solution, one solution or twosolutions. Then solve sin 25o = h 10 h = 10 sin 25o b = 10 h 25o A B B
  32. 32. In Determinewhether has no solution, one solution or twosolutions. Then solve sin 25o = h 10 h = 10 sin 25o h = 4.23 b = 10 h 25o A B B
  33. 33. In Determinewhether has no solution, one solution or twosolutions. Then solve sin 25o = h 10 h = 10 sin 25o h = 4.23 b = 10 a = 5 and a<b h 25o two solutions A B B
  34. 34. C b = 10 a=5 25oA B
  35. 35. C b = 10 97o a=5 25oA B C = 180 – 25 – 58 = 97o
  36. 36. C b = 10 97o a=5 25oA B C = 180 – 25 – 58 = 97o
  37. 37. C b = 10 97o a=5 25oA B C = 180 – 25 – 58 = 97o
  38. 38. C b = 10 97o a=5 25oA B C = 180 – 25 – 58 = 97o
  39. 39. C b = 10 97o a=5 25o 58oA B C = 180 – 25 – 58 = 97o
  40. 40. C b = 10 97o a=5 25o 58oA B C = 180 – 25 – 58 = 97o
  41. 41. C b = 10 97o a=5 25o 58oA B C = 180 – 25 – 58 = 97o
  42. 42. C b = 10 97o a=5 25o 58oA c = 11.7 B C = 180 – 25 – 58 = 97o
  43. 43. C b = 10 97o a=5 25o 58oA c = 11.7 B C = 180 – 25 – 58 = 97o
  44. 44. C b = 10 97o a=5 25o 58oA c = 11.7 B
  45. 45. C b = 10 a=5 25o 58oA B
  46. 46. isosceles triangle C b = 10 a=5 25o 58o 58oA B
  47. 47. isosceles triangle C b = 10 a=5 25o 58o 58oA B 122o
  48. 48. C b = 10 a=5 25o 122oA c B
  49. 49. C = 180 – 25 – 122 = 33 C b = 10 33o a=5 25o 122oA c B
  50. 50. C = 180 – 25 – 122 = 33 C b = 10 33o a=5 25o 122oA c B
  51. 51. C = 180 – 25 – 122 = 33 C b = 10 33o a=5 25o 122oA c B
  52. 52. C = 180 – 25 – 122 = 33 C b = 10 33o a=5 25o 122oA c = 6.4 B

×