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# Alg2 lesson 13-4

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### Alg2 lesson 13-4

1. 1. B Find the area of triangle ABCA C A b A A sin h c
2. 2. B Find the area of triangle ABC hA C A b A A sin h c
3. 3. B Find the area of c triangle ABC hA C A b A A sin h c
4. 4. B Find the area of c triangle ABC hA C A b A A sin h c
5. 5. B Find the area of c triangle ABC hA C A b A A sin h c
6. 6. B Find the area of c triangle ABC hA C A b A A sin h c
7. 7. B Find the area of c triangle ABC hA C A b A A sin h c
8. 8. B Find the area of c triangle ABC hA C A b A A sin h c
9. 9. B Find the area of c triangle ABC hA C b
10. 10. Find the area of to the nearesttenth.
11. 11. Find the area of to the nearesttenth. Included angle b= =c
12. 12. Find the area of to the nearesttenth. Included angle b= =c
13. 13. Find the area of to the nearesttenth. Included angle b= =c square centimeters
14. 14. LawofSines
15. 15. Solve .This is NOT a righttriangle!!!
16. 16. Suppose you are given a, b and A for a triangle.Is it always possible to create a triangle usingthe given angle and two sides?Is there always only one possible angle that youcan create?Pg. 727
17. 17. In Determinewhether has no solution, one solution or twosolutions. Then solve sin 25o = h 12 h = 12 sin 25o h = 5.07 b = 12 h a = 13 25o one solution A B
18. 18. C b = 12 a = 13 25oA c B
19. 19. C b = 12 a = 13 25oA c B
20. 20. C b = 12 a = 13 25oA c B
21. 21. C b = 12 a = 13 25oA c B
22. 22. C b = 12 a = 13 25oA c B
23. 23. C b = 12 a = 13 25o 23oA c B
24. 24. C = 180 – (25 + 23) = 132o C b = 12 132o a = 13 25o 23o A c B
25. 25. C b = 12 132o a = 13 25o 23oA c B
26. 26. or about 22.9 C b = 12 132o a = 13 25o 23oA c = 22.9 B
27. 27. In Determinewhether has no solution, one solution or twosolutions. Then solve a = 32 b = 35 125o A no solution
28. 28. In Determinewhether has no solution, one solution or twosolutions. Then solve b = 10 25o A B B
29. 29. In Determinewhether has no solution, one solution or twosolutions. Then solve b = 10 h 25o A B B
30. 30. In Determinewhether has no solution, one solution or twosolutions. Then solve sin 25o = h 10 b = 10 h 25o A B B
31. 31. In Determinewhether has no solution, one solution or twosolutions. Then solve sin 25o = h 10 h = 10 sin 25o b = 10 h 25o A B B
32. 32. In Determinewhether has no solution, one solution or twosolutions. Then solve sin 25o = h 10 h = 10 sin 25o h = 4.23 b = 10 h 25o A B B
33. 33. In Determinewhether has no solution, one solution or twosolutions. Then solve sin 25o = h 10 h = 10 sin 25o h = 4.23 b = 10 a = 5 and a<b h 25o two solutions A B B
34. 34. C b = 10 a=5 25oA B
35. 35. C b = 10 97o a=5 25oA B C = 180 – 25 – 58 = 97o
36. 36. C b = 10 97o a=5 25oA B C = 180 – 25 – 58 = 97o
37. 37. C b = 10 97o a=5 25oA B C = 180 – 25 – 58 = 97o
38. 38. C b = 10 97o a=5 25oA B C = 180 – 25 – 58 = 97o
39. 39. C b = 10 97o a=5 25o 58oA B C = 180 – 25 – 58 = 97o
40. 40. C b = 10 97o a=5 25o 58oA B C = 180 – 25 – 58 = 97o
41. 41. C b = 10 97o a=5 25o 58oA B C = 180 – 25 – 58 = 97o
42. 42. C b = 10 97o a=5 25o 58oA c = 11.7 B C = 180 – 25 – 58 = 97o
43. 43. C b = 10 97o a=5 25o 58oA c = 11.7 B C = 180 – 25 – 58 = 97o
44. 44. C b = 10 97o a=5 25o 58oA c = 11.7 B
45. 45. C b = 10 a=5 25o 58oA B
46. 46. isosceles triangle C b = 10 a=5 25o 58o 58oA B
47. 47. isosceles triangle C b = 10 a=5 25o 58o 58oA B 122o
48. 48. C b = 10 a=5 25o 122oA c B
49. 49. C = 180 – 25 – 122 = 33 C b = 10 33o a=5 25o 122oA c B
50. 50. C = 180 – 25 – 122 = 33 C b = 10 33o a=5 25o 122oA c B
51. 51. C = 180 – 25 – 122 = 33 C b = 10 33o a=5 25o 122oA c B
52. 52. C = 180 – 25 – 122 = 33 C b = 10 33o a=5 25o 122oA c = 6.4 B