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What comes next?
                          A geometric
3, 6, 12, 24 48 96
          __, __, __     sequence is a
                           pattern of
x2 x2 x2 x2   x2   x2
                          numbers in
 Common ratio             which each
     r=2                   number is
 a1 = 3                     found by
                          multiplying a
 a2 = 6                 constant by the
                        number before
 a3 = 12
                                it.
What’s the common ratio?


8, 4, 2, 1, …
r = 0.5


2, -6, 18, -54, …   Alternating sequence
r = -3
3, 6, 12, 24, 48, 96, …
 x2 x2 x2

a1 = 3
a2 = 6      3 x 21
a3 = 12     3 x 22
a4 = 24     3 x 23
   an = a1 x r (n – 1)
Write an equation for the nth term of the
geometric sequence 7, 14, 28, ….

            an = a1 r (n – 1)
            an = 7 2(n-1)


Find the 80th term of the sequence

     an = 7 2 (n – 1)
     a80 = 7 279
Complete the statement for the geometric sequence:

     1536 is the ____ term of 3, 6, 12, …
              an = a1 r (n – 1)
              1536 = 3 2 (n – 1)
              ____ _
                  3      3
              512 = 2(n – 1)
              29 = 2(n – 1)
              9=n–1
              n = 10
The terms between any two nonconsecutive
terms of a geometric sequence are geometric
means.
Find the three geometric means between 12 and
3072.

          12, ___, 192 768 3072, ...,
              48 ___, ___,

              xr   xr   xr   xr

        12 x r4 = 3072
        r4 = 256
        r=4

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Geometric sequence pattern and terms

  • 1. What comes next? A geometric 3, 6, 12, 24 48 96 __, __, __ sequence is a pattern of x2 x2 x2 x2 x2 x2 numbers in Common ratio which each r=2 number is a1 = 3 found by multiplying a a2 = 6 constant by the number before a3 = 12 it.
  • 2. What’s the common ratio? 8, 4, 2, 1, … r = 0.5 2, -6, 18, -54, … Alternating sequence r = -3
  • 3. 3, 6, 12, 24, 48, 96, … x2 x2 x2 a1 = 3 a2 = 6 3 x 21 a3 = 12 3 x 22 a4 = 24 3 x 23 an = a1 x r (n – 1)
  • 4. Write an equation for the nth term of the geometric sequence 7, 14, 28, …. an = a1 r (n – 1) an = 7 2(n-1) Find the 80th term of the sequence an = 7 2 (n – 1) a80 = 7 279
  • 5. Complete the statement for the geometric sequence: 1536 is the ____ term of 3, 6, 12, … an = a1 r (n – 1) 1536 = 3 2 (n – 1) ____ _ 3 3 512 = 2(n – 1) 29 = 2(n – 1) 9=n–1 n = 10
  • 6. The terms between any two nonconsecutive terms of a geometric sequence are geometric means. Find the three geometric means between 12 and 3072. 12, ___, 192 768 3072, ..., 48 ___, ___, xr xr xr xr 12 x r4 = 3072 r4 = 256 r=4