onomatomato

1. GROUP 4 (P87)
“The Same by
Slightly Different”

2. FIRST,
We need to determine the P87 class and the
class interval it is contained in.
2

3. 3
87
100
𝑁 =
87
100
50 = 43.5
*NOTE that 41st-47th scores belong to the class interval
46-50
Solution:
43.5th

4. NEXT,
Determine the other values for the formula
4

5. Solution:
5
LB= 45.5
N=50
cfb=40
fp=7
i=5
43.5th
𝑃87 = 𝐿𝐵 +
𝐾
100
𝑁 − 𝑐𝑓𝑏
𝑓𝑝
i

6. THEN,
SOLVE.

7. Solution:
7
𝑃87 = 𝐿𝐵 +
𝐾
100
𝑁 − 𝑐𝑓𝑏
𝑓
𝑝
i
𝑃87 = 45.5 +
43.5 − 40
7
5
𝑃87 = 45.5 +
3.5
7
5

8. Solution:
8
𝑃87 = 45.5 + 2.5
𝑃87 = 48 (87th percentile)
This implies that 87% of the data is equal or less
than 48
87%
48

9. THANKYOU PO!
9