Acetylene and dry air enter an isobaric combustion chamber at 298K and latm. There is a 10% excess of air (a lean mixture) at the inlet A) What is the adiabatic flame temperature (K) of the mixture? B) What is the equilibrium concentration (by volume) of NO, Yno, in the products when considering the reaction M2 + ??2 ? O at the adiabatic flame temperature\'? C) Now consider a reaction with a 100% excess of air (a lean mixture) at the inlet. What is concentration (by volume) of NO? the new adiabatic flame tempe rature and equilibrium
Solution
1. In adibatic flame temperature formula the molar heat capacity of the products at constant pressure has equation for each compound.
(Sensible heat in air + fuel) + heat of combustion - heat absorbed due to dissociation of products of combustion = sensible heat in poc + heat losses to surrounding
Delta H = CP dT
2. The assumption of complete combustion is an approximation because it disregards the possibility of dissociation of combustion products. More products will be formed.
3. Use equation mentioned in step 1 to solve it
.
Acetylene and dry air enter an isobaric combustion chamber at 298K and.docx
1. Acetylene and dry air enter an isobaric combustion chamber at 298K and latm. There is a 10%
excess of air (a lean mixture) at the inlet A) What is the adiabatic flame temperature (K) of the
mixture? B) What is the equilibrium concentration (by volume) of NO, Yno, in the products
when considering the reaction M2 + ??2 ? O at the adiabatic flame temperature'? C) Now
consider a reaction with a 100% excess of air (a lean mixture) at the inlet. What is concentration
(by volume) of NO? the new adiabatic flame tempe rature and equilibrium
Solution
1. In adibatic flame temperature formula the molar heat capacity of the products at constant
pressure has equation for each compound.
(Sensible heat in air + fuel) + heat of combustion - heat absorbed due to dissociation of products
of combustion = sensible heat in poc + heat losses to surrounding
Delta H = CP dT
2. The assumption of complete combustion is an approximation because it disregards the
possibility of dissociation of combustion products. More products will be formed.
3. Use equation mentioned in step 1 to solve it
