Compute the probability of event E if the odds in favor of E are 31.pdf

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Compute the probability of event E if the odds in favor of E are 3/19 14/27 6/11 11/7 P(E) = (Type the probability as a fraction. Simplify your answer) Solution (A) Given odds in the favour of event E are 3/19 Therefore, probability = 3/(3+19) = 3/22 (B) Given odds in favour of event E are 14/27. Therefore, probability = 14/(14+27) = 14/41 (c) Given odds in favour of event E are 6/11. Therefore, probability = 6/(6+11) = 6/17 (d) Given odds in favour of event E are 11/7. Therefore, probability =11/(11+7) = 11/18.

$Compute the probability of event E if the odds in favor of E are 3/19 14/27 6/11 11/7 P(E) = (Type the probability as a fraction. Simplify your answer) Solution (A) Given odds in the favour of event E are 3/19 Therefore, probability = 3/(3+19) = 3/22 (B) Given odds in favour of event E are 14/27. Therefore, probability = 14/(14+27) = 14/41 (c) Given odds in favour of event E are 6/11. Therefore, probability = 6/(6+11) = 6/17 (d) Given odds in favour of event E are 11/7. Therefore, probability =11/(11+7) = 11/18$

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What is an Accountable Care Organizations (ACO)? How does an ACO\'s economics work to manage costs and quality? Solution Accountable Care Organizations (ACOs) are groups of doctors, hospitals, and other health care providers, who come together voluntarily to give coordinated high quality care to their Medicare patients. An accountable care organization (ACO) is a healthcare organization characterized by a payment and care delivery model that seeks to tie provider reimbursements to quality metrics and reductions in the total cost of care for an assigned population of patients. A group of coordinated health care providers forms an ACO, which then provides care to a group of patients. The ACO may use a range of payment models (capitation, fee-for-service with asymmetric or symmetric shared savings, etc.). The ACO is accountable to the patients and the third-party payer for the quality, appropriateness and efficiency of the health care provided. According to the Centers for Medicare and Medicaid Services (CMS), an ACO is \"an organization of health care providers that agrees to be accountable for the quality, cost, and overall care of Medicare beneficiaries who are enrolled in the traditional fee-for-service program who are assigned to it. Design and Structure There is no single organizational model for developing an ACO. ACOs may be formed and organized by health systems using employed and contracted physicians, by integrated delivery systems, by physician groups (either primary care or multispecialty) or through joint ventures or contractual relationships among providers. Regardless of the organizational structure, an ACO must be physician-led and physician-driven. Physician leadership is critical because an ACO is primarily a vehicle for clinical integration, not financial or risk integration. Only physicians are able to develop, monitor and adjust clinical care protocols that can more efficiently use resources based on documented effectiveness. Qualifying ACOs will be assigned a pool of patients whose care the ACO will be responsible for managing in a cost-effective and clinically appropriate manner. The ACO will need to develop internal mechanisms for monitoring and managing costs and quality that cut across traditional reporting lines and result in a higher degree of clinical interdependence than is typical in a less- integrated medical community. The PPACA states that any of the following groups of providers of services and suppliers that have established a mechanism for shared governance are eligible to participate, in accordance with regulations to be developed by the Secretary of Health and Human Services (HHS): ACOs Under Health Reform Section 3022 of PPACA requires HHS to establish a shared savings program under which qualifying ACOs may be eligible for incentive payments. The criteria in the statute, which will need to be further defined by regulation, include: ACOs will be required to measure and report their progress to HHS, includ.

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True or false: A selective force (such as antibiotics) must be present for DNA mutations to occur. Solution Answer: False Reason: Selective forces are not going to exert any impact on the alterations of genome mainly via causing DNA mutations. For example, antibiotics are going to cause change in the RNA structure or change in enzyme moieties inside the cells of microbial species result in inhibition of growth without causing damage or random change (mutation) in the DNA. Natural selection always trying to eliminate any deleterious alleles in the host cells but do not cause any selective DNA mutation when taking antibiotics.

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The UV spectrum of the hot B0V star is significantly below the continuum level due to a large number of absorption lines caused by highly ionized heavy elements. Can you explain why the B0V star, rather than the cooler stars, has all those lines? http://i67.tinypic.com/2u9hn2v.jpg Solution In B0V stars have these emission and absorption lines due to radiative recombination between Hydrogen and Helium ions with electrons and other excitd metal ions present withine the star. Hot and young stars are able to ionize the gas around them which then produces emission spectra. This region is known as H|| region. This occurs only around hot stars as UV photons are required to ionize hydrogen atoms..

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Prove asymptotic upper and lower hounds for each of the following specified otherwise, assume that in each case, T(n) = 1 (or any small constant) for small value You may assume that n = c^k for some constant c that you choose. Make your bounds as tight as (No need to specify the origin of your guess.) T(n0 = 8T(n/3) + n^1.83838383... T(n) = T(n - 1) = 1/n T(n) = 16T(n/2) + (n log n)^4. T(n) = 2T(n/2) + n/lg n. T(n) = T(n - 1) + T(n - 2) + 1 with base case of T(1) = 1 and T(2) = 2 Solution A statement are often outlined as a declaratory sentence, or a part of a sentence, that\'s capable of getting a truth-value, like being true or false. So, as an example, the subsequent area unit statements: George W. Bush is that the forty third President of the us. Paris is that the capital of France. Everyone born on Monday has purple hair. Sometimes, a press release will contain one or a lot of alternative statements as elements. contemplate as an example, the subsequent statement: Either Ganymede may be a moon of Jupiter or Ganymede may be a moon of Saturn. While the on top of sentence is itself a press release, as a result of it\'s true, the 2 elements, \"Ganymede may be a moon of Jupiter\" and \"Ganymede may be a moon of Saturn\", area unit themselves statements, as a result of the primary is true and therefore the second is fake. The term proposition is typically used synonymously with statement. However, it\'s typically accustomed name one thing abstract that 2 totally different statements with an equivalent which means area unit each aforementioned to \"express\". during this usage, nation sentence, \"It is raining\", and therefore the French sentence \"Il pleut\", would be thought-about to specific an equivalent proposition; equally, the 2 English sentences, \"Callisto orbits Jupiter\" and \"Jupiter is orbitted by Callisto\" would even be thought-about to specific an equivalent proposition. However, the character or existence of propositions as abstract meanings continues to be a matter of philosophical dispute, and for the needs of this text, the phrases \"statement\" and \"proposition\" area unit used interchangeably. Propositional logic, conjointly referred to as linguistic string logic, is that branch of logic that studies ways that of mixing or neutering statements or propositions to create a lot of difficult statements or propositions. change of integrity 2 easier propositions with the word \"and\" is one common approach of mixing statements. once 2 statements area unit joined along side \"and\", the advanced statement fashioned by them is true if and as long as each the element statements area unit true. owing to this, associate argument of the subsequent kind is logically valid: Paris is that the capital of France and Paris contains a population of over 2 million. Therefore, Paris contains a population of over 2 million. Propositional logic for the most part involves learning logical connectives like the words \"and\" and \"or\" and therefo.

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\"PCAOB\" Please respond to the following: Go to the PCAOB Website. Next, analyze the role of the PCAOB to protect the public. Based on your analysis, give your opinion as to whether you believe they possess enough of the requisite power to be effective in accomplishing their mission. Provide support for your opinion. Solution The Public Company Accounting Oversight Board is a nonprofit corporation set up to protect investors and the public interest by providing informative, accurate, and independent audit reports and to oversee the audits of public companies and broker-dealers. ROLE OF PCAOB 1.It explore ways to improve its audit requirements and their implementation by audit firms, while preserving the intended benefits. 2. It helps to inform a current standards setting project dealing with firms’ systems of quality controls. 3. helps in setting standard for the project on the supervision of other auditors that strengthen the standards in that area. 4.looks after auditing requirements that will aid users and investors of financial statements to make informed decisions and assist in restoring the confidence 5.The ultimate mission of PCAOB is to protect public interest and to protect investors by overseeing whether set out norms are being adhered to or not. OPINION There has been a period of extreme economic stress, triggered and then compounded by a meltdown of financial system.PCAOB shall succeed in meeting its goal by Improving the transparency of the financial condition of registered accounting firms .Another way to enhance transparency is to improve the reporting model for financial statements which would contribute to the investor’s understanding of the financial statements and the audit process..

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wasemanivytreenrco51

pleaase I want manual solution for Data Structures and Algorithm Analysis in C++, Third Edition By Clifford A. Shaffer because my question from this book.page270 ,question 7.4 The implementation for Mergesort given in Section 7.4 takes an array as input and sorts that array. At the beginning of Section 7.4 there is a simple pseudocode implementation for sorting a linked list using Mergesort. Implement both a linked list-based version of Mergesort and the array-based version of Mergesort, and compare and analyze their running times. Solution Linked list: #include #include struct node { int data; struct node* next; }; struct node* SortedMerge(struct node* a, struct node* b); void FrontBackSplit(struct node* source, struct node** frontRef, struct node** backRef); void MergeSort(struct node** headRef) { struct node* head = *headRef; struct node* a; struct node* b; if ((head == NULL) || (head->next == NULL)) { return; } FrontBackSplit(head, &a, &b); MergeSort(&a); MergeSort(&b); *headRef = SortedMerge(a, b); } struct node* SortedMerge(struct node* a, struct node* b) { struct node* result = NULL; if (a == NULL) return(b); else if (b==NULL) return(a); if (a->data <= b->data) { result = a; result->next = SortedMerge(a->next, b); } else { result = b; result->next = SortedMerge(a, b->next); } return(result); } void FrontBackSplit(struct node* source, struct node** frontRef, struct node** backRef) { struct node* fast; struct node* slow; if (source==NULL || source->next==NULL) { *frontRef = source; *backRef = NULL; } else { slow = source; fast = source->next; while (fast != NULL) { fast = fast->next; if (fast != NULL) { slow = slow->next; fast = fast->next; } } *frontRef = source; *backRef = slow->next; slow->next = NULL; } } void printList(struct node *node) { while(node!=NULL) { printf(\"%d \", node->data); node = node->next; } } void push(struct node** head_ref, int new_data) { struct node* new_node = (struct node*) malloc(sizeof(struct node)); new_node->data = new_data; new_node->next = (*head_ref); (*head_ref) = new_node; } int main() { struct node* res = NULL; struct node* a = NULL; push(&a, 15); push(&a, 10); push(&a, 5); push(&a, 20); push(&a, 3); push(&a, 2); MergeSort(&a); printf(\"\ Sorted Linked List is: \ \"); printList(a); getchar(); return 0; } Time complexity:o(nlogn) Array : #include #include void merge(int arr[], int l, int m, int r) { int i, j, k; int n1 = m - l + 1; int n2 = r - m; int L[n1], R[n2]; for (i = 0; i < n1; i++) L[i] = arr[l + i]; for (j = 0; j < n2; j++) R[j] = arr[m + 1+ j]; i = 0; // Initial index of first subarray j = 0; k = l; while (i < n1 && j < n2) { if (L[i] <= R[j]) { arr[k] = L[i]; i++; } else { arr[k] = R[j]; j++; } k++; } while (i < n1) { arr[k] = L[i]; i++; k++; } while (j < n2) { arr[k] = R[j]; j++; k++; } } void mergeSort(int arr[], int l, int r) { if (l < r) { int m = l+(r-l)/2; // Sort first and second halves mergeSort(arr, l, m); mergeSort(arr, m+1, r); merge(arr, l, m, r); } } void printArray(int A[], i.

pleaase I want manual solution forData Structures and Algorithm An.pdf

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Part A Select the TRUE statement regarding plasma cells. They live for many years and function as memory cells. The antibodies they produce can remain in circulation for years. They are descended from activated T cells. They can produce large quantities of antibodies on a daily basis. They secrete a variety of antibody molecules specific for multiple epitopes. Solution True statement regarding plasma cells is They produce and secrete antibodies; they produce large quantities of antibodies on a daily basis.

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On the code which has a class in which I implementing a binary tree using an array. This array, named store, stores Node in entries corresponding to nodes in the tree and null if the node does not exist. Complete the countLeavesmethod so that it returns the number of leaves in this tree. Code: Solution import java.util.AbstractSet; import java.util.Arrays; import java.util.Iterator; import java.util.NoSuchElementException; /** * Implementation of an abstract set using an array- based binary tree. This is * used to help teach binary tree\'s and will have more details explained in * future lectures. * * @author William J. Collins * @author Matthew Hertz * @param Data type (which must be Comparable) of the elements in this tree. */ public class ArrayBinaryTree> extends AbstractSet { /** Entry in the data store where the root node can be found. */ private static final int ROOT = 0; /** Array used to store the nodes which consist of this binary tree. */ protected Node[] store; /** Number of elements within the tree. */ protected int size; /** * Initializes this ArrayBinaryTree object to be empty. This creates the array * in which items will be stored. */ @SuppressWarnings(\"unchecked\") public ArrayBinaryTree() { store = new Node[63]; size = 0; } /** * Initializes this ArrayBinaryTree object to contain a shallow copy of a * specified ArrayBinaryTree object. The worstTime(n) is O(n), where n is the * number of elements in the specified ArrayBinaryTree object. * * @param otherTree The tree which will be copied to create our new tree, */ @SuppressWarnings(\"unchecked\") public ArrayBinaryTree(ArrayBinaryTree otherTree) { store = (Node[]) Arrays.copyOf(otherTree.store, otherTree.store.length); size = otherTree.size; } public int countLeaves() { } /** * Returns the size of this ArrayBinaryTree object. * * @return the size of this ArrayBinaryTree object. */ @Override public int size() { return size; } /** * Returns an iterator that will return the elements in this ArrayBinaryTree, * but without any specific ordering. * * @return Iterator positioned at the smallest element in this ArrayBinaryTree * object. */ @Override public Iterator iterator() { return new ArrayTreeIterator(); } /** * Determines if there is at least one element in this ArrayBinaryTree object * that equals a specified element. The worstTime(n) is O(n) and * averageTime(n) is O(log n). * * @param obj - the element sought in this ArrayBinaryTree object. * @return true - if there is an element in this ArrayBinaryTree object that * equals obj; otherwise, return false. * @throws ClassCastException - if obj cannot be compared to the elements in * this ArrayBinaryTree object. * @throws NullPointerException - if obj is null. */ @Override public boolean contains(Object obj) { return getEntry(obj) != null; } /** * Ensures that this ArrayBinaryTree object contains a specified element. The * worstTime(n) is O(n) for this addition. * * @param element Element we want to be certain is contained within.

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Not sure why my program wont run. //Programmer: S.Villegas helper Noah //File name: PP88ArrayList.java //Description: //**************************** import java.io.File; import java.io.FileNotFoundException; import java.util.ArrayList; import java.util.Scanner; public class PP88ArrayList { public static void main(String[]args) { ArrayList persons = new ArrayList(25); String fileName = \"Zips.dat\"; int i; Scanner filescasnner = null; try { filescasnner=new Scanner(new File(fileName)); for(i=0;i persons) { for (int i = 0; i < persons.size(); i++) { for (int j = 0; j < persons.size()-1; j++) { if((persons.get(j).getFirstName().compareTo(persons.get(j+1).getFirstName()))>0) { Person temp= persons.get(j); persons.set(j, persons.get(j+1)); persons.set(j+1, temp); } } } } public static void sortByZipCode(ArrayList persons) { for (int i = 0; i < persons.size(); i++) { for (int j = 0; j < persons.size()-1; j++) { if(persons.get(j).getZipCode()>persons.get(j+1).getZipCode()) { Person temp= persons.get(j); persons.set(j, persons.get(j+1)); persons.set(j+1, temp); } } } } } //Programmer: S.Villegas helper Noah //File name: PersonList.java //Description: //****************************** public class PersonList { private String firstName, lastName; private int Zip; public PersonList(String firstName,String lastName, int Zip) { this.firstName = firstName; this.lastName = lastName; this.Zip = Zip; } public String getFirstName() { return firstName; } public int getZipCode() { return Zip; } public String toString() { return String.format(\"%-15s%-15s%-10d\",firstName,lastName,Zip); } } Solution //File name: PersonList.java public class PersonList { private String firstName, lastName; private int Zip; public PersonList(String firstName,String lastName, int Zip) { this.firstName = firstName; this.lastName = lastName; this.Zip = Zip; } public String getFirstName() { return firstName; } public int getZipCode() { return Zip; } public String toString() { return String.format(\"%-15s%-15s%-10d\",firstName,lastName,Zip); } } //File name: PP88ArrayList.java import java.io.File; import java.io.FileNotFoundException; import java.util.ArrayList; import java.util.Scanner; public class PP88ArrayList { public static void main(String[]args) { ArrayList persons = new ArrayList(25); String fileName = \"Zips.dat\"; int i; Scanner filescasnner = null; try { filescasnner=new Scanner(new File(fileName)); while(filescasnner.hasNextLine()) { String firstName = filescasnner.next(); String lastName = filescasnner.next(); int Zip = filescasnner.nextInt(); persons.add(new PersonList(firstName, lastName, Zip)); } filescasnner.close(); } catch (FileNotFoundException e) { System.out.println(e.getMessage()); } System.out.println(\"\ List of names and zip codes: \"); System.out.printf(\"%-15s%-15s%-15s\ \",\"First Name\",\"Last Name\",\"Zip\"); for (int j = 0; j < persons.size(); j++) { System.out.println(persons.get(j)); } System.out.println(\"\ List of names sort by first name\"); sortByNa.

Not sure why my program wont run.Programmer S.Villegas helper N.pdf

Not sure why my program wont run.Programmer S.Villegas helper N.pdf

Not sure why my program wont run.Programmer S.Villegas helper N.pdf

wasemanivytreenrco51

Let X be a random variable with cumulative distribution function Is X a discrete or continuous random variable? Explain clearly in terms of the property of a discrete or continuous random variable. Solution If a variable is defined at specific values and it cannot take values between the values then it will be discrete random variable. Given CDF is defined at 0.1, 0.2, 0.3 and 0.4 and not in between values. So it is discrete distribution..

Let X be a random variable with cumulative distribution function Is .pdf

Let X be a random variable with cumulative distribution function Is .pdf

Let X be a random variable with cumulative distribution function Is .pdf

wasemanivytreenrco51

Java Question: Consider a maze made up of a rectangular array of squares. The maze will contain a character (either +, -, or |) to represent a blocked square, and to form the walls of the maze. Mazes will have only one entrance at the Coordinate (0, 1), with only one exit in the lower right hand corner of the maze. Beginning at the entrance to the maze, find a path to the exit at the bottom right of the maze. You may only move up, down, left, and right. Each square in the maze can be in one of four states: clear (space), blocked (X), path (.), or visited (*). Initially, after the maze has been read in from the file, each square will be either clear or blocked. If a square lies on a successful path, mark it with a period. If you visit a square but it does not lead to a successful path, mark it as visited with an asterisk. Solution import java.io.*; class Maze { // Any MazeSquare field is true if the corresponding // wall exists, and false otherwise. class MazeSquare { public boolean hasTopWall; public boolean hasRightWall; public boolean hasLeftWall; public boolean hasBottomWall; public MazeSquare() { hasTopWall = hasRightWall = hasLeftWall = hasBottomWall = false; } } // This Exception class will help pinpoint format errors in the data file. class MazeFormatException extends Exception { public final static int noError = 0; public final static int badRowAndColumnCounts = 1; public final static int wrongNumberOfEntriesInRow = 2; public final static int badEntry = 3; public int lineNumber; public int problem; public MazeFormatException( int line, int prob ) { lineNumber = line; problem = prob; } } // Number of rows and columns in the maze. private int nRows; private int nColumns; // The array of maze squares themselves. MazeSquare[][] square; public static void main( String[] args ) { if( args.length != 1 ) { System.err.println( \"Usage: java Maze mazeFileName\" ); System.exit( 1 ); } Maze knosos = null; try { knosos = new Maze( args[0] ); } catch( FileNotFoundException e ) { System.err.println( \"Can\'t open \" + args[0] + \". Check your spelling.\" ); System.exit( 1 ); } catch( IOException e ) { System.err.println( \"Severe input error. I give up.\" ); System.exit( 1 ); } catch( MazeFormatException e ) { switch( e.problem ) { case MazeFormatException.badRowAndColumnCounts: System.err.println( args[0] + \", line \" + e.lineNumber + \": row and column counts expected\" ); break; case MazeFormatException.wrongNumberOfEntriesInRow: System.err.println( args[0] + \", line \" + e.lineNumber + \": wrong number of entries\" ); break; case MazeFormatException.badEntry: System.err.println( args[0] + \", line \" + e.lineNumber + \": non-hexadecimal digit detected\" ); break; default: System.err.println( \"This should never get printed.\" ); break; } System.exit( 1 ); } knosos.print( System.out ); } public Maze() { square = null; nRows = nColumns = 0; } public Maze( String fileName ) throws FileNotFoundException, IOException, MazeFormatException { Buffered.

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wasemanivytreenrco51

In terms of IT Infrastructure: What is binding and why is it important. Is it different from a remote procedure call and why? Solution Binding is to make an association between two or more programming objects or value items for some scope of time and place. It is important due to substitute a real for a variable value in the program or to ensure that additional programming will be loaded into storage along with the compiled program. Yes, it is different from a remote procedure call because Remote Procedure Call (RPC) provides a different paradigm for accessing network services. Instead of accessing remote services by sending and receiving messages, a client invokes services by making a local procedure call. The local procedure hides the details of the network communication..

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wasemanivytreenrco51

In nature, how is most carbon dioxide replaceda. plant photosynth.pdf

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wasemanivytreenrco51

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wasemanivytreenrco51

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