PROBLEMS ON GEOMETRY GRE MATHEMATICS

1. GRE GEOMETRY
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2. 4cm
3 cm
2cm
x
Calculate area of the shaded portion
By Pythagoras theorem x = 5 cm
A(rectangle)= 5(2)=10 cm
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3. A
B
C
D
Diameter of the circle is 10 cm
Quantity A Quantity B
A(quadrilateral ABCD)
40
a) Quantity A is greater
b) Quantity B is greater
c) The 2 quantities are equal
d) The relationship cannot be determined from the information given.
Answer is d
Even if AC were the diameter of the circle,
to determine the area , we need more than
1 side of the figure
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4. 𝑥2
𝑦 > 0, 𝑥𝑦2
< 0
Quantity A
x
Quantity B
y
if 𝑥2 𝑦 > 0, 𝑦 > 0
If x𝑦2
< 0, 𝑥 < 0
Hence y is greater.
Answer = B
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5. Given 3 rectangles A, B, C, The length of rectangle A IS 10 % more than the length of C and
the breadth of
A is 10 % lesser than the breadth of C. The length of rectangle B is 20 % more than
the length of rectangle C
The breadth of rectangle B is 20 % lesser than the breadth of rectangle C.
Quantity A
A(rectangle A)
Quantity B
A(rectangle B)
C
x
y
A
1.1x
0.9y
B
1.2x
0.8y
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6. A(rectangle A ) = 1.1x(0.9y)=0.99xy
A(rectangle B)= 1.2x (0.8y) = .96xy
A (rectangle A ) is greater
Ans : = Quantity A
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