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MECHANICS OF METAL CUTTING
(feed
force)
Main
Cutting
force
Radial
force
Tool feed
direction
Need for calculating forces, velocities and
angles during machining??
• We need to determine the cutting forces in turning for
Estimation of cutting power consumption, which also enables
selection of the power source (e.g. motors) during design of the
machine tools.
• Structural design of the machine – fixture – tool system.
• Evaluation of role of the various machining parameters (tool
material and geometry) on cutting forces to make machining
process more efficient and economical.
• Condition monitoring of the cutting tools and machine tools.
 Cutting Edge is normal to tool feed.
 Here only two force components are
considered i.e. cutting force and thrust
force. Hence known as two dimensional
cutting.
 Shear force acts on smaller area.
 Cutting Edge is inclined at an acute
angle to tool feed.
 Here three force components are
considered i.e. cutting force, radial force
and thrust force. Hence known as three
dimensional cutting.
 Shear force acts on larger area.
Metal Cutting is the process of removing unwanted material from the workpiece
in the form of chips
Assumptions
(Orthogonal Cutting Model)
 The cutting edge is a straight line extending perpendicular
to the direction of motion, and it generates a plane surface
as the work moves past it.
 The tool is perfectly sharp (no contact along the clearance
face).
 The shearing surface is a plane extending upward from
the cutting edge.
 The chip does not flow to either side
 The depth of cut/chip thickness is constant uniform
relative to velocity between work and tool
 Continuous chip, no built-up-edge (BUE)
TERMINOLOGY
 α : Rake angle
 b : Frictional angle
 ϕ : Shear angle
 Ft : Thrust Force
Fc: Cutting Force
Fs: Shear Force
 Fn: Normal Shear Force
F: Frictional Force
 N: Normal Frictional Force
 V: Cutting velocity
Vc: Chip velocity
Vs: Shear velocity
FL
FC
Fr
DIRECTION OF ROTATION
WORKPIECE
CUTTING TOOL
DIRECTION OF FEED
Velocity of
Tool relative to
workpiece V
Longitudinal Force
Radial Force
‘Thrust’ Force
Tangential Force
'Cutting' Force
‘Facing’ Forces For Orthogonal Model
End view
Note: For the 2D Orthogonal Mechanistic
Model we will ignore the Longitudinal
component
Orthogonal Cutting Model
(Simple 2D mechanistic model)
Mechanism: Chips produced by the shearing process along the shear plane
a
t0
f
+
Rake
Angle
Chip
Workpiece
Clearance Angle
Shear Angle
t c
depth of cut
Chip thickness
Tool
Velocity V
tool
-
Orthogonal Cutting
r 
to
tc

ls sinf
ls cos(f  a)
tan f 
r cosa
1  rsin a
 
AC
BD

AD  DC
BD
 tan(f a)  cotf
tool
Cutting Ratio
(or chip thickness ratio)
As Sinf =
to
AB
and Cosf-a) =
tc
AB
Chip thickness ratio (r) =
t0
tc
=
sinf
cos(fa)
f
tc
to
fa)
A
B
Chip
Workpiece
Cutting Forces
(2D Orthogonal Cutting)
Free Body Diagram
Tool
Workpiece
Chip
Dynamometer
R
R
R
Fc
Ft
f
s
F
F
n
N
F
 Fs , Resistance to shear of the metal in forming the chip. It
acts along the shear plane.
 Fn , ‘Backing up’ force on the chip provided by the
workpiece. Acts normal to the shear plane.
 N, It is at the tool chip interface normal to the cutting face of
the tool and is provided by the tool.
 F, It is the frictional resistance of the tool acting on the chip.
It acts downward against the motion of the chip as it glides
upwards along the tool face.
Cutting Forces
(2D Orthogonal Cutting)
Fn
Ft
Fs
Fc
F
R
α
α
ϕ
β
ϕ
β-α
N
V
Knowing Fc , Ft , α and ϕ, all other component forces can be calculated.
Force Circle Diagram
(Merchants Circle)
R
F
t
Fc
Tool
F
N
a
b  a
b
a
a
Fs
f
b  a
f
F
n
Cutting Forces
• Forces considered in orthogonal cutting include
– Cutting, friction (tool face), and shear forces
• Cutting force,Fc acts in the direction of the cutting
speed V, and supplies the energy required for cutting
– Ratio of Fc to cross-sectional area being cut (i.e. product of
width and depth of cut, t0) is called: specific cutting force
• Thrust force,Ft acts in a direction normal to the cutting
force
• These two forces produces the resultant force, R
• On tool face, resultant force can be resolved into:
– Friction force, F along the tool-chip interface
– Normal force, N to  to friction force
15
Cutting Forces
• It can also be shown that (b is friction angle)
• Resultant force, R is balanced by an equal and
opposite force along the shear plane
• It is resolved into shear force, Fs and normal force, Fn
• Thus,
• The magnitude of coefficient of friction,  is
16
b
b cos
sin R
N
R
F 


f
f
f
f
cos
sin
sin
cos
t
c
n
t
c
s
F
F
F
F
F
F




a
a

tan
tan
t
c
c
t
F
F
F
F
N
F




Cutting Forces
• The tool holder, work-holding devices, and machine tool
must be stiff to support thrust force with minimal
deflections
– If Ft is too high ⇒ tool will be pushed away from workpiece
– this will reduce depth of cut and dimensional accuracy
• The effect of rake angle and friction angle on the direction
of thrust force is
• Magnitude of the cutting force, Fc is always positive as the
force that supplies the work required in cutting
• However, Ft can be +ve or –ve; i.e. Ft can be upward with
a) high rake angle, b) low tool-chip friction, or c) both
17
 )
a
b 
 sin
R
Ft
Forces from Merchant's Circle
Friction Force F = Fcsina + Ftcosa
Normal Force N = Fccosa - Ftsina
Shear Force Fs = Fccosf - Ftsinf
 = F/N and  = tanb typically 0.5 - 2.0)
Force Normal to Shear plane Fn = Fcsinf + Ftcosf
Stresses
On the Shear plane:
Normal Stress = s = Normal Force / Area =
Fn
AB w
=
Fnsinf
tow
Shear Stress = s = Shear Force / Area =
Fs
AB w
=
Fssinf
tow
On the tool rake face:
 = Normal Force / Area =
N
tc w
(often assume tc = contact length)
 = Shear Force / Area =
F
tc w
Power
•Power (or energy consumed per unit time) is the product of force and
velocity. Power at the cutting spindle:
•Power is dissipated mainly in the shear zone and on the rake face:
•Actual Motor Power requirements will depend on machine efficiency
E (%):
Cutting Power Pc = FcV
Power for Shearing Ps = FsVs
Friction Power Pf = FVc
Motor Power Required =
Pc
E
x 100
Cutting Forces and Power measurement
Measuring Cutting Forces and Power
• Cutting forces can be measured using a force
transducer, a dynamometer or a load cell mounted
on the cutting-tool holder
• It is also possible to calculate the cutting force from the
power consumption during cutting (provided
mechanical efficiency of the tool can be determined)
• The specific energy (u) in cutting can be used to
calculate cutting forces
21
Cutting Forces and Power
Power
22
 Prediction of forces is
based largely on
experimental data (right)
 Wide ranges of values
is due to differences in
material strengths
 Sharpness of the tool tip
also influences forces
and power
 Duller tools require
higher forces and power

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Merchant circle.pptx

  • 1. MECHANICS OF METAL CUTTING (feed force) Main Cutting force Radial force Tool feed direction
  • 2. Need for calculating forces, velocities and angles during machining?? • We need to determine the cutting forces in turning for Estimation of cutting power consumption, which also enables selection of the power source (e.g. motors) during design of the machine tools. • Structural design of the machine – fixture – tool system. • Evaluation of role of the various machining parameters (tool material and geometry) on cutting forces to make machining process more efficient and economical. • Condition monitoring of the cutting tools and machine tools.
  • 3.  Cutting Edge is normal to tool feed.  Here only two force components are considered i.e. cutting force and thrust force. Hence known as two dimensional cutting.  Shear force acts on smaller area.  Cutting Edge is inclined at an acute angle to tool feed.  Here three force components are considered i.e. cutting force, radial force and thrust force. Hence known as three dimensional cutting.  Shear force acts on larger area. Metal Cutting is the process of removing unwanted material from the workpiece in the form of chips
  • 4. Assumptions (Orthogonal Cutting Model)  The cutting edge is a straight line extending perpendicular to the direction of motion, and it generates a plane surface as the work moves past it.  The tool is perfectly sharp (no contact along the clearance face).  The shearing surface is a plane extending upward from the cutting edge.  The chip does not flow to either side  The depth of cut/chip thickness is constant uniform relative to velocity between work and tool  Continuous chip, no built-up-edge (BUE)
  • 6.  α : Rake angle  b : Frictional angle  ϕ : Shear angle  Ft : Thrust Force Fc: Cutting Force Fs: Shear Force  Fn: Normal Shear Force F: Frictional Force  N: Normal Frictional Force  V: Cutting velocity Vc: Chip velocity Vs: Shear velocity
  • 7. FL FC Fr DIRECTION OF ROTATION WORKPIECE CUTTING TOOL DIRECTION OF FEED Velocity of Tool relative to workpiece V Longitudinal Force Radial Force ‘Thrust’ Force Tangential Force 'Cutting' Force ‘Facing’ Forces For Orthogonal Model End view Note: For the 2D Orthogonal Mechanistic Model we will ignore the Longitudinal component
  • 8. Orthogonal Cutting Model (Simple 2D mechanistic model) Mechanism: Chips produced by the shearing process along the shear plane a t0 f + Rake Angle Chip Workpiece Clearance Angle Shear Angle t c depth of cut Chip thickness Tool Velocity V tool -
  • 9. Orthogonal Cutting r  to tc  ls sinf ls cos(f  a) tan f  r cosa 1  rsin a   AC BD  AD  DC BD  tan(f a)  cotf
  • 10. tool Cutting Ratio (or chip thickness ratio) As Sinf = to AB and Cosf-a) = tc AB Chip thickness ratio (r) = t0 tc = sinf cos(fa) f tc to fa) A B Chip Workpiece
  • 11. Cutting Forces (2D Orthogonal Cutting) Free Body Diagram Tool Workpiece Chip Dynamometer R R R Fc Ft f s F F n N F
  • 12.  Fs , Resistance to shear of the metal in forming the chip. It acts along the shear plane.  Fn , ‘Backing up’ force on the chip provided by the workpiece. Acts normal to the shear plane.  N, It is at the tool chip interface normal to the cutting face of the tool and is provided by the tool.  F, It is the frictional resistance of the tool acting on the chip. It acts downward against the motion of the chip as it glides upwards along the tool face. Cutting Forces (2D Orthogonal Cutting)
  • 13. Fn Ft Fs Fc F R α α ϕ β ϕ β-α N V Knowing Fc , Ft , α and ϕ, all other component forces can be calculated.
  • 14. Force Circle Diagram (Merchants Circle) R F t Fc Tool F N a b  a b a a Fs f b  a f F n
  • 15. Cutting Forces • Forces considered in orthogonal cutting include – Cutting, friction (tool face), and shear forces • Cutting force,Fc acts in the direction of the cutting speed V, and supplies the energy required for cutting – Ratio of Fc to cross-sectional area being cut (i.e. product of width and depth of cut, t0) is called: specific cutting force • Thrust force,Ft acts in a direction normal to the cutting force • These two forces produces the resultant force, R • On tool face, resultant force can be resolved into: – Friction force, F along the tool-chip interface – Normal force, N to  to friction force 15
  • 16. Cutting Forces • It can also be shown that (b is friction angle) • Resultant force, R is balanced by an equal and opposite force along the shear plane • It is resolved into shear force, Fs and normal force, Fn • Thus, • The magnitude of coefficient of friction,  is 16 b b cos sin R N R F    f f f f cos sin sin cos t c n t c s F F F F F F     a a  tan tan t c c t F F F F N F    
  • 17. Cutting Forces • The tool holder, work-holding devices, and machine tool must be stiff to support thrust force with minimal deflections – If Ft is too high ⇒ tool will be pushed away from workpiece – this will reduce depth of cut and dimensional accuracy • The effect of rake angle and friction angle on the direction of thrust force is • Magnitude of the cutting force, Fc is always positive as the force that supplies the work required in cutting • However, Ft can be +ve or –ve; i.e. Ft can be upward with a) high rake angle, b) low tool-chip friction, or c) both 17  ) a b   sin R Ft
  • 18. Forces from Merchant's Circle Friction Force F = Fcsina + Ftcosa Normal Force N = Fccosa - Ftsina Shear Force Fs = Fccosf - Ftsinf  = F/N and  = tanb typically 0.5 - 2.0) Force Normal to Shear plane Fn = Fcsinf + Ftcosf
  • 19. Stresses On the Shear plane: Normal Stress = s = Normal Force / Area = Fn AB w = Fnsinf tow Shear Stress = s = Shear Force / Area = Fs AB w = Fssinf tow On the tool rake face:  = Normal Force / Area = N tc w (often assume tc = contact length)  = Shear Force / Area = F tc w
  • 20. Power •Power (or energy consumed per unit time) is the product of force and velocity. Power at the cutting spindle: •Power is dissipated mainly in the shear zone and on the rake face: •Actual Motor Power requirements will depend on machine efficiency E (%): Cutting Power Pc = FcV Power for Shearing Ps = FsVs Friction Power Pf = FVc Motor Power Required = Pc E x 100
  • 21. Cutting Forces and Power measurement Measuring Cutting Forces and Power • Cutting forces can be measured using a force transducer, a dynamometer or a load cell mounted on the cutting-tool holder • It is also possible to calculate the cutting force from the power consumption during cutting (provided mechanical efficiency of the tool can be determined) • The specific energy (u) in cutting can be used to calculate cutting forces 21
  • 22. Cutting Forces and Power Power 22  Prediction of forces is based largely on experimental data (right)  Wide ranges of values is due to differences in material strengths  Sharpness of the tool tip also influences forces and power  Duller tools require higher forces and power