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 Brief introduction to Merchant’s Circle.
Assumptions for Merchant’s Circle Diagram.
 Construction of Merchant’s Circle.
 Solutions of Merchant’s Circle.
 Advantages of Merchant’s Circle.
 Need for the analysis of cutting forces.
 Limitations of Merchant’s Circle.
 Conclusion
 Merchant’s Circle Diagram is
constructed to ease the analysis of
cutting forces acting during
orthogonal (Two Dimensional)
cutting of work piece.
 Ernst and Merchant do this
scientific analysis for the first time
in 1941 and gives the following
relation in 1944
 It is convenient to determine
various force and angles.
 Cutting Edge is normal to tool feed.
 Here only two force components are
considered i.e. cutting force and thrust
force. Hence known as two dimensional
cutting.
 Shear force acts on smaller area.
 Cutting Edge is inclined at an acute
angle to tool feed.
 Here only three force components are
considered i.e. cutting force, radial force
and thrust force. Hence known as three
dimensional cutting.
 Shear force acts on larger area.
Metal Cutting is the process of removing unwanted material from the workpiece
in the form of chips
 α : Rack angle
 λ : Frictional angle
 ϕ : Shear angle
 Ft : Thrust Force
 Fn: Normal Shear Force
Fc: Cutting Force
 Fs: Shear Force
 F: Frictional Force
 N: Normal Frictional Force
 V: Feed velocity
RAKE ANGLE
 Back Rake Angle: It is the angle
between the face of the tool and
measured in a plane perpendicular
to the side cutting edge
 Side Rake Angle: It is the angle
between the face of the tool and
measured in a plane perpendicular
to the base
Front View
Back Rake Angle
Side Rake Angle
Frictional Angle
 It is the angle between the
resultant ,of the Frictional Force &
Normal Force, and Normal
Reaction.
 λ = tan
-1
μ
μ: coefficient of friction
P
F
R
N
λ
Shear Angle
 It is the angle made by the shear
plane with the direction of the tool
travel.
Fs
Ft
Fc
Fn
F
N
V
φ
Shear Force
 Resistance to shear of the metal in
forming the chip. It acts along the
shear plane.
Normal Shear Force
 Force on the chip provided by the
workpiece. Acts normal to the shear
plane.
Friction Force
 Resisting force acted at the tool
workpiece interface to resist the
motion of tool.
Thrust Force
 This force acts normal to the
cutting force or the velocity of the
tool.
Normal Friction Force
 It act at the tool chip interface
normal to the cutting face of the tool
and is provided by the tool.
Cutting Force
 Force acted along the velocity of
tool
 Cutting force increases as speed
increases and decreases as rake
angle decreases
 Tool edge is sharp.
 The work material undergoes deformation across a
thin shear plane.
 There is uniform distribution of normal and shear
stress on shear plane.
The work material is rigid and perfectly plastic.
 The shear angle ϕ adjusts itself to minimum work.
 The friction angle λ remains constant and is
independent of ϕ.
 The chip width remains constant.
 The chip does not flow to side, or there is no side
spread.
Fn
Ft
Fs
Fc
F
R
α
α
φ
λ
φ
λ-α
N
V
 Fs , Resistance to shear of the metal in forming the chip. It
acts along the shear plane.
 Fn , ‘Backing up’ force on the chip provided by the
workpiece. Acts normal to the shear plane.
 N, It at the tool chip interface normal to the cutting face of
the tool and is provided by the tool.
 F, It is the frictional resistance of the tool acting on the chip.
It acts downward against the motion of the chip as it glides
upwards along the tool face.
Knowing Fc , Ft , α and ϕ, all other component forces
can be calculated as:
The coefficient of friction will be then given as :
On Shear plane,
α
α
φ
λ-α
λ
φ
Fs
Ft
Fc
Fn
F
N
R
V
Now,
Now shear plane angle
The average stresses on the
shear plane area are:
α
α
φ
λ-α
λ
φ
Fs
Ft
Fc
Fn
F
N
R
V
Let ϕ be the shear angle
Where,
Assuming that λ is independent of ϕ ,
for max. shear stress
α
α
φ
λ-α
λ
φ
Fs
Ft
Fc
Fn
F
N
R
V
Now the shear force can be written as:
and
Analysis of cutting forces is helpful as:-
 Design of stiffness etc. for the machine tolerance.
Whether work piece can withstand the cutting force
can be predicted.
 In study of behavior and machinability
characterization of the work piece.
 Estimation of cutting power consumption, which
also enables selection of the power source(s) during
design of the machine tool.
 Condition monitoring of the cutting tools and
machine tool.
Proper use of MCD enables the followings :-
 Easy, quick and reasonably accurate determination
of several other forces from a few forces involved in
machining.
 Friction at chip-tool interface and dynamic yield
shear strength can be easily determined.
 Equations relating the different forces are easily
developed.
Some limitations of use of MCD are :-
 Merchant’s Circle Diagram (MCD) is valid only for
orthogonal cutting.
 By the ratio, F/N, the MCD gives apparent (not
actual) coefficient of friction.
 It is based on single shear plane theory.
Following conclusions/results are drawn from MCD :-
 Shear angle is given by
 For practical purpose, the following values of ϕ has
been suggested:
ϕ = α for α>15o
ϕ = 15o for α<15o
Merchant circle.ppt

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Merchant circle.ppt

  • 1.
  • 2.  Brief introduction to Merchant’s Circle. Assumptions for Merchant’s Circle Diagram.  Construction of Merchant’s Circle.  Solutions of Merchant’s Circle.  Advantages of Merchant’s Circle.  Need for the analysis of cutting forces.  Limitations of Merchant’s Circle.  Conclusion
  • 3.  Merchant’s Circle Diagram is constructed to ease the analysis of cutting forces acting during orthogonal (Two Dimensional) cutting of work piece.  Ernst and Merchant do this scientific analysis for the first time in 1941 and gives the following relation in 1944  It is convenient to determine various force and angles.
  • 4.  Cutting Edge is normal to tool feed.  Here only two force components are considered i.e. cutting force and thrust force. Hence known as two dimensional cutting.  Shear force acts on smaller area.  Cutting Edge is inclined at an acute angle to tool feed.  Here only three force components are considered i.e. cutting force, radial force and thrust force. Hence known as three dimensional cutting.  Shear force acts on larger area. Metal Cutting is the process of removing unwanted material from the workpiece in the form of chips
  • 5.  α : Rack angle  λ : Frictional angle  ϕ : Shear angle  Ft : Thrust Force  Fn: Normal Shear Force Fc: Cutting Force  Fs: Shear Force  F: Frictional Force  N: Normal Frictional Force  V: Feed velocity RAKE ANGLE  Back Rake Angle: It is the angle between the face of the tool and measured in a plane perpendicular to the side cutting edge  Side Rake Angle: It is the angle between the face of the tool and measured in a plane perpendicular to the base Front View Back Rake Angle Side Rake Angle Frictional Angle  It is the angle between the resultant ,of the Frictional Force & Normal Force, and Normal Reaction.  λ = tan -1 μ μ: coefficient of friction P F R N λ Shear Angle  It is the angle made by the shear plane with the direction of the tool travel. Fs Ft Fc Fn F N V φ Shear Force  Resistance to shear of the metal in forming the chip. It acts along the shear plane. Normal Shear Force  Force on the chip provided by the workpiece. Acts normal to the shear plane. Friction Force  Resisting force acted at the tool workpiece interface to resist the motion of tool. Thrust Force  This force acts normal to the cutting force or the velocity of the tool. Normal Friction Force  It act at the tool chip interface normal to the cutting face of the tool and is provided by the tool. Cutting Force  Force acted along the velocity of tool  Cutting force increases as speed increases and decreases as rake angle decreases
  • 6.  Tool edge is sharp.  The work material undergoes deformation across a thin shear plane.  There is uniform distribution of normal and shear stress on shear plane. The work material is rigid and perfectly plastic.  The shear angle ϕ adjusts itself to minimum work.  The friction angle λ remains constant and is independent of ϕ.  The chip width remains constant.  The chip does not flow to side, or there is no side spread.
  • 8.  Fs , Resistance to shear of the metal in forming the chip. It acts along the shear plane.  Fn , ‘Backing up’ force on the chip provided by the workpiece. Acts normal to the shear plane.  N, It at the tool chip interface normal to the cutting face of the tool and is provided by the tool.  F, It is the frictional resistance of the tool acting on the chip. It acts downward against the motion of the chip as it glides upwards along the tool face.
  • 9. Knowing Fc , Ft , α and ϕ, all other component forces can be calculated as: The coefficient of friction will be then given as : On Shear plane, α α φ λ-α λ φ Fs Ft Fc Fn F N R V Now,
  • 10. Now shear plane angle The average stresses on the shear plane area are: α α φ λ-α λ φ Fs Ft Fc Fn F N R V Let ϕ be the shear angle Where,
  • 11. Assuming that λ is independent of ϕ , for max. shear stress α α φ λ-α λ φ Fs Ft Fc Fn F N R V Now the shear force can be written as: and
  • 12. Analysis of cutting forces is helpful as:-  Design of stiffness etc. for the machine tolerance. Whether work piece can withstand the cutting force can be predicted.  In study of behavior and machinability characterization of the work piece.  Estimation of cutting power consumption, which also enables selection of the power source(s) during design of the machine tool.  Condition monitoring of the cutting tools and machine tool.
  • 13. Proper use of MCD enables the followings :-  Easy, quick and reasonably accurate determination of several other forces from a few forces involved in machining.  Friction at chip-tool interface and dynamic yield shear strength can be easily determined.  Equations relating the different forces are easily developed.
  • 14. Some limitations of use of MCD are :-  Merchant’s Circle Diagram (MCD) is valid only for orthogonal cutting.  By the ratio, F/N, the MCD gives apparent (not actual) coefficient of friction.  It is based on single shear plane theory.
  • 15. Following conclusions/results are drawn from MCD :-  Shear angle is given by  For practical purpose, the following values of ϕ has been suggested: ϕ = α for α>15o ϕ = 15o for α<15o