1. Statisticshelpdesk
2014
Statistics Assignment Help Statistics Homework Help Alex Gerg

2. Statisticshelpdesk
Copyright © 2012 Statisticshelpdesk.com, All rights reserved
Statistics Assignment Help | Statistics Homework Help
About Statistics: Statisticshelpdesk provides solution to all kind of problems related to statistics, as it is a dedicated site of statistics so it provides all sorts of help i.e Assignment help, Homework help, Project help, Dissertation help, Live online tutoring, Statistical analysis, All sorts of software help that are being used in statistics. Statistics assignment help will be viewed in numerous ways that. Normally it's thought-about to subsume graphs, charts, percentages, and averages. It consists of rules and strategies of collecting and presenting numerical data. It conjointly consists of constructing inferences from a given knowledge. The statistical data will be used to elucidate unexplained things, to form and justify a claim, to form comparisons, to seek out unknown quantities, to predict data regarding future and to ascertain relationship between quantities. Thus, it's a subject matter that consists of quite numbers. Methods of Simple Regression Analysis: Q 1. From the following data from the regression equations, Y푒 = a + bX and 푋푒 = a + bY Use the normal equation method:
X: Y:
1 15
3 18
5 21
7 23
9 22
Also, estimate the value of Y when X=4, and the value of X when Y=24.

3. Statisticshelpdesk
Copyright © 2012 Statisticshelpdesk.com, All rights reserved
Solution: Formulation of the regression equations
X
Y
푋2
푌2
XY
1 3 5 7 9
15 18 21 23 22
1 9 25 49 81
225 324 441 529 484
15 54 105 161 198
Total
ΣX=25
ΣY=99
Σ푋2=165
Σ푌2=2003
ΣXY=533 N=5
(i) Regression equation of X on Y. This is given by
푋푒 = a + bY To find the value of the constants a and b in the above formula, the following two normal equation are to the simultaneously solved. ΣX=Na+bΣY ΣXY=aΣY+bΣ푌2 Substituting the respective values in the above formula we get, 25=5a+99b 533=99a+2003b Multiplying the equation (i) by 99 and eqn. (ii) by 5 and presenting them in the form of a subtraction we get, 2475=495a+9801b
(-) 2665=495a+10015b

4. Statisticshelpdesk
Copyright © 2012 Statisticshelpdesk.com, All rights reserved
_______________________________________ Thus -190= -214b Or 214=190 b=190/214= .888 approx. Putting the above values of b in the equ.(i) we get, 25=5a+99(.888) Or 5a=25-87.912=-62.912 a= -62.912/5=-12.5824=-12.5824 Thus, Substituting the above values of the constants a and b, we get the regression equation of X on Y as, 퐗퐞 = -12.5824 + 0.888Y Thus, when Y=24, 푋푒 = -12.5824 + 0.888(24) =-12.5824+21.312 =8.7296
(ii) Regression equation of Y on X. this is given by
퐘푒 = a + bX as under: To find the values of the constants a and b in the above formula, the following two normal equations are to be simultaneously solved as under: ΣY=Na+bΣX ΣXY=aΣX+bΣX2 Substituting the respective values in the above formula we get, 99=5a+25b 533=25a+165b

5. Statisticshelpdesk
Copyright © 2012 Statisticshelpdesk.com, All rights reserved
Multiplying the equation (1) by 5 and getting the same subtracted from the equation (ii) we get, 533=25a+165b (-) 495=25a+125b _______________________________________ Thus 38= 40b Or b=38/40=15.05 Putting the above values of b in the equ.(i) we get, 99=5a+25(0.95) Or 5a=99-23.75=75.25 a= 75.25/5=15.05 thus, a=15.05 and b=0.95 Substituting the above values of the constants a and b, we get the regression equation of Y on x as, 푌푒 = 15.05 + 0.95X Thus, when X=4, 푌푒 = 15.05 + 0.95(24) =15.05+3.80 =18.85. Note: It may be noted that the above normal equation method of formulating the two regression equation is verity lengthy and tedious. In order to do away with such difficulties, any of the following two method of deviation may be used advantageously.

6. Statisticshelpdesk
Copyright © 2012 Statisticshelpdesk.com, All rights reserved
Contact Us: Phone: +44-793-744-3379
E: info@statisticshelpdesk.com
W: www.statisticshelpdesk.com
Facebook: https://www.facebook.com/Statshelpdesk
Twitter: https://twitter.com/statshelpdesk